2. Multiply each bit by its corresponding power of 2 and add all the terms up.
1 0100 0010 1010 0100 1000 0010 0000 1000(2) =
(1 × 232 + 0 × 231 + 1 × 230 + 0 × 229 + 0 × 228 + 0 × 227 + 0 × 226 + 1 × 225 + 0 × 224 + 1 × 223 + 0 × 222 + 1 × 221 + 0 × 220 + 0 × 219 + 1 × 218 + 0 × 217 + 0 × 216 + 1 × 215 + 0 × 214 + 0 × 213 + 0 × 212 + 0 × 211 + 0 × 210 + 1 × 29 + 0 × 28 + 0 × 27 + 0 × 26 + 0 × 25 + 0 × 24 + 1 × 23 + 0 × 22 + 0 × 21 + 0 × 20)(10) =
(4 294 967 296 + 0 + 1 073 741 824 + 0 + 0 + 0 + 0 + 33 554 432 + 0 + 8 388 608 + 0 + 2 097 152 + 0 + 0 + 262 144 + 0 + 0 + 32 768 + 0 + 0 + 0 + 0 + 0 + 512 + 0 + 0 + 0 + 0 + 0 + 8 + 0 + 0 + 0)(10) =
(4 294 967 296 + 1 073 741 824 + 33 554 432 + 8 388 608 + 2 097 152 + 262 144 + 32 768 + 512 + 8)(10) =
5 413 044 744(10)
The number 1 0100 0010 1010 0100 1000 0010 0000 1000(2) converted from an unsigned binary (in base 2) and written as a positive integer (with no sign) in decimal system (in base ten):
1 0100 0010 1010 0100 1000 0010 0000 1000(2) = 5 413 044 744(10)
Spaces were used to group digits: for binary, by 4, for decimal, by 3.