3.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 422 Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard

Convert decimal 3.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 422(10) to 64 bit double precision IEEE 754 binary floating point representation standard (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

What are the steps to convert decimal number
3.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 422(10) to 64 bit double precision IEEE 754 binary floating point representation (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

1. First, convert to binary (in base 2) the integer part: 3.
Divide the number repeatedly by 2.

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

2. Construct the base 2 representation of the integer part of the number.

Take all the remainders starting from the bottom of the list constructed above.

3(10) =

11(2)


3. Convert to binary (base 2) the fractional part: 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 422.

Multiply it repeatedly by 2.

Keep track of each integer part of the results.

Stop when we get a fractional part that is equal to zero.


  • #) multiplying = integer + fractional part;
  • 1) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 422 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 844;
  • 2) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 844 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 688;
  • 3) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 688 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 667 376;
  • 4) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 667 376 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 334 752;
  • 5) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 334 752 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 669 504;
  • 6) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 669 504 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 339 008;
  • 7) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 339 008 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 678 016;
  • 8) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 678 016 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 356 032;
  • 9) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 356 032 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 712 064;
  • 10) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 712 064 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 424 128;
  • 11) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 424 128 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 848 256;
  • 12) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 848 256 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 696 512;
  • 13) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 696 512 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 667 393 024;
  • 14) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 667 393 024 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 334 786 048;
  • 15) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 334 786 048 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 669 572 096;
  • 16) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 669 572 096 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 339 144 192;
  • 17) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 339 144 192 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 678 288 384;
  • 18) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 678 288 384 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 356 576 768;
  • 19) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 356 576 768 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 713 153 536;
  • 20) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 713 153 536 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 426 307 072;
  • 21) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 426 307 072 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 852 614 144;
  • 22) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 852 614 144 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 705 228 288;
  • 23) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 705 228 288 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 667 410 456 576;
  • 24) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 667 410 456 576 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 334 820 913 152;
  • 25) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 334 820 913 152 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 669 641 826 304;
  • 26) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 669 641 826 304 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 339 283 652 608;
  • 27) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 339 283 652 608 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 678 567 305 216;
  • 28) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 678 567 305 216 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 357 134 610 432;
  • 29) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 357 134 610 432 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 714 269 220 864;
  • 30) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 714 269 220 864 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 428 538 441 728;
  • 31) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 428 538 441 728 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 857 076 883 456;
  • 32) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 857 076 883 456 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 714 153 766 912;
  • 33) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 714 153 766 912 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 667 428 307 533 824;
  • 34) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 667 428 307 533 824 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 334 856 615 067 648;
  • 35) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 334 856 615 067 648 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 669 713 230 135 296;
  • 36) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 669 713 230 135 296 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 339 426 460 270 592;
  • 37) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 339 426 460 270 592 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 678 852 920 541 184;
  • 38) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 678 852 920 541 184 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 357 705 841 082 368;
  • 39) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 357 705 841 082 368 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 715 411 682 164 736;
  • 40) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 715 411 682 164 736 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 430 823 364 329 472;
  • 41) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 430 823 364 329 472 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 861 646 728 658 944;
  • 42) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 861 646 728 658 944 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 723 293 457 317 888;
  • 43) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 723 293 457 317 888 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 667 446 586 914 635 776;
  • 44) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 667 446 586 914 635 776 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 334 893 173 829 271 552;
  • 45) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 334 893 173 829 271 552 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 669 786 347 658 543 104;
  • 46) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 669 786 347 658 543 104 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 339 572 695 317 086 208;
  • 47) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 339 572 695 317 086 208 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 679 145 390 634 172 416;
  • 48) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 679 145 390 634 172 416 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 358 290 781 268 344 832;
  • 49) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 358 290 781 268 344 832 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 716 581 562 536 689 664;
  • 50) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 716 581 562 536 689 664 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 433 163 125 073 379 328;
  • 51) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 433 163 125 073 379 328 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 866 326 250 146 758 656;
  • 52) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 866 326 250 146 758 656 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 732 652 500 293 517 312;
  • 53) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 732 652 500 293 517 312 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 667 465 305 000 587 034 624;

We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit) and at least one integer that was different from zero => FULL STOP (Losing precision - the converted number we get in the end will be just a very good approximation of the initial one).


4. Construct the base 2 representation of the fractional part of the number.

Take all the integer parts of the multiplying operations, starting from the top of the constructed list above:


0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 422(10) =

0.0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0(2)

5. Positive number before normalization:

3.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 422(10) =

11.0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0(2)

6. Normalize the binary representation of the number.

Shift the decimal mark 1 positions to the left, so that only one non zero digit remains to the left of it:


3.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 422(10) =

11.0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0(2) =

11.0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0(2) × 20 =

1.1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 10(2) × 21


7. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

Sign 0 (a positive number)

Exponent (unadjusted): 1

Mantissa (not normalized):
1.1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 10


8. Adjust the exponent.

Use the 11 bit excess/bias notation:


Exponent (adjusted) =

Exponent (unadjusted) + 2(11-1) - 1 =

1 + 2(11-1) - 1 =

(1 + 1 023)(10) =

1 024(10)


9. Convert the adjusted exponent from the decimal (base 10) to 11 bit binary.

Use the same technique of repeatedly dividing by 2:


  • division = quotient + remainder;
  • 1 024 ÷ 2 = 512 + 0;
  • 512 ÷ 2 = 256 + 0;
  • 256 ÷ 2 = 128 + 0;
  • 128 ÷ 2 = 64 + 0;
  • 64 ÷ 2 = 32 + 0;
  • 32 ÷ 2 = 16 + 0;
  • 16 ÷ 2 = 8 + 0;
  • 8 ÷ 2 = 4 + 0;
  • 4 ÷ 2 = 2 + 0;
  • 2 ÷ 2 = 1 + 0;
  • 1 ÷ 2 = 0 + 1;

10. Construct the base 2 representation of the adjusted exponent.

Take all the remainders starting from the bottom of the list constructed above.


Exponent (adjusted) =

1024(10) =

100 0000 0000(2)


11. Normalize the mantissa.

a) Remove the leading (the leftmost) bit, since it's allways 1, and the decimal point, if the case.

b) Adjust its length to 52 bits, by removing the excess bits, from the right (if any of the excess bits is set on 1, we are losing precision...).


Mantissa (normalized) =

1. 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 10 =

1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010


12. The three elements that make up the number's 64 bit double precision IEEE 754 binary floating point representation:

Sign (1 bit) =
0 (a positive number)

Exponent (11 bits) =
100 0000 0000

Mantissa (52 bits) =
1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010


Decimal number 3.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 422 converted to 64 bit double precision IEEE 754 binary floating point representation:

0 - 100 0000 0000 - 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010

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How to convert numbers from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point standard

Follow the steps below to convert a base 10 decimal number to 64 bit double precision IEEE 754 binary floating point:

  • 1. If the number to be converted is negative, start with its the positive version.
  • 2. First convert the integer part. Divide repeatedly by 2 the positive representation of the integer number that is to be converted to binary, until we get a quotient that is equal to zero, keeping track of each remainder.
  • 3. Construct the base 2 representation of the positive integer part of the number, by taking all the remainders from the previous operations, starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Then convert the fractional part. Multiply the number repeatedly by 2, until we get a fractional part that is equal to zero, keeping track of each integer part of the results.
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the multiplying operations, starting from the top of the list constructed above (they should appear in the binary representation, from left to right, in the order they have been calculated).
  • 6. Normalize the binary representation of the number, shifting the decimal mark (the decimal point) "n" positions either to the left, or to the right, so that only one non zero digit remains to the left of the decimal mark.
  • 7. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary, by using the same technique of repeatedly dividing by 2, as shown above:
    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1
  • 8. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal mark, if the case) and adjust its length to 52 bits, either by removing the excess bits from the right (losing precision...) or by adding extra bits set on '0' to the right.
  • 9. Sign (it takes 1 bit) is either 1 for a negative or 0 for a positive number.

Example: convert the negative number -31.640 215 from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point:

  • 1. Start with the positive version of the number:

    |-31.640 215| = 31.640 215

  • 2. First convert the integer part, 31. Divide it repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 31 ÷ 2 = 15 + 1;
    • 15 ÷ 2 = 7 + 1;
    • 7 ÷ 2 = 3 + 1;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
    • We have encountered a quotient that is ZERO => FULL STOP
  • 3. Construct the base 2 representation of the integer part of the number by taking all the remainders of the previous dividing operations, starting from the bottom of the list constructed above:

    31(10) = 1 1111(2)

  • 4. Then, convert the fractional part, 0.640 215. Multiply repeatedly by 2, keeping track of each integer part of the results, until we get a fractional part that is equal to zero:
    • #) multiplying = integer + fractional part;
    • 1) 0.640 215 × 2 = 1 + 0.280 43;
    • 2) 0.280 43 × 2 = 0 + 0.560 86;
    • 3) 0.560 86 × 2 = 1 + 0.121 72;
    • 4) 0.121 72 × 2 = 0 + 0.243 44;
    • 5) 0.243 44 × 2 = 0 + 0.486 88;
    • 6) 0.486 88 × 2 = 0 + 0.973 76;
    • 7) 0.973 76 × 2 = 1 + 0.947 52;
    • 8) 0.947 52 × 2 = 1 + 0.895 04;
    • 9) 0.895 04 × 2 = 1 + 0.790 08;
    • 10) 0.790 08 × 2 = 1 + 0.580 16;
    • 11) 0.580 16 × 2 = 1 + 0.160 32;
    • 12) 0.160 32 × 2 = 0 + 0.320 64;
    • 13) 0.320 64 × 2 = 0 + 0.641 28;
    • 14) 0.641 28 × 2 = 1 + 0.282 56;
    • 15) 0.282 56 × 2 = 0 + 0.565 12;
    • 16) 0.565 12 × 2 = 1 + 0.130 24;
    • 17) 0.130 24 × 2 = 0 + 0.260 48;
    • 18) 0.260 48 × 2 = 0 + 0.520 96;
    • 19) 0.520 96 × 2 = 1 + 0.041 92;
    • 20) 0.041 92 × 2 = 0 + 0.083 84;
    • 21) 0.083 84 × 2 = 0 + 0.167 68;
    • 22) 0.167 68 × 2 = 0 + 0.335 36;
    • 23) 0.335 36 × 2 = 0 + 0.670 72;
    • 24) 0.670 72 × 2 = 1 + 0.341 44;
    • 25) 0.341 44 × 2 = 0 + 0.682 88;
    • 26) 0.682 88 × 2 = 1 + 0.365 76;
    • 27) 0.365 76 × 2 = 0 + 0.731 52;
    • 28) 0.731 52 × 2 = 1 + 0.463 04;
    • 29) 0.463 04 × 2 = 0 + 0.926 08;
    • 30) 0.926 08 × 2 = 1 + 0.852 16;
    • 31) 0.852 16 × 2 = 1 + 0.704 32;
    • 32) 0.704 32 × 2 = 1 + 0.408 64;
    • 33) 0.408 64 × 2 = 0 + 0.817 28;
    • 34) 0.817 28 × 2 = 1 + 0.634 56;
    • 35) 0.634 56 × 2 = 1 + 0.269 12;
    • 36) 0.269 12 × 2 = 0 + 0.538 24;
    • 37) 0.538 24 × 2 = 1 + 0.076 48;
    • 38) 0.076 48 × 2 = 0 + 0.152 96;
    • 39) 0.152 96 × 2 = 0 + 0.305 92;
    • 40) 0.305 92 × 2 = 0 + 0.611 84;
    • 41) 0.611 84 × 2 = 1 + 0.223 68;
    • 42) 0.223 68 × 2 = 0 + 0.447 36;
    • 43) 0.447 36 × 2 = 0 + 0.894 72;
    • 44) 0.894 72 × 2 = 1 + 0.789 44;
    • 45) 0.789 44 × 2 = 1 + 0.578 88;
    • 46) 0.578 88 × 2 = 1 + 0.157 76;
    • 47) 0.157 76 × 2 = 0 + 0.315 52;
    • 48) 0.315 52 × 2 = 0 + 0.631 04;
    • 49) 0.631 04 × 2 = 1 + 0.262 08;
    • 50) 0.262 08 × 2 = 0 + 0.524 16;
    • 51) 0.524 16 × 2 = 1 + 0.048 32;
    • 52) 0.048 32 × 2 = 0 + 0.096 64;
    • 53) 0.096 64 × 2 = 0 + 0.193 28;
    • We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit = 52) and at least one integer part that was different from zero => FULL STOP (losing precision...).
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the previous multiplying operations, starting from the top of the constructed list above:

    0.640 215(10) = 0.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 6. Summarizing - the positive number before normalization:

    31.640 215(10) = 1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 7. Normalize the binary representation of the number, shifting the decimal mark 4 positions to the left so that only one non-zero digit stays to the left of the decimal mark:

    31.640 215(10) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 20 =
    1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 24

  • 8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

    Sign: 1 (a negative number)

    Exponent (unadjusted): 4

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

  • 9. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary (base 2), by using the same technique of repeatedly dividing it by 2, as shown above:

    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1 = (4 + 1023)(10) = 1027(10) =
    100 0000 0011(2)

  • 10. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal sign) and adjust its length to 52 bits, by removing the excess bits, from the right (losing precision...):

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

    Mantissa (normalized): 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Conclusion:

    Sign (1 bit) = 1 (a negative number)

    Exponent (8 bits) = 100 0000 0011

    Mantissa (52 bits) = 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Number -31.640 215, converted from decimal system (base 10) to 64 bit double precision IEEE 754 binary floating point =
    1 - 100 0000 0011 - 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100