266.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 684 24 Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard

Convert decimal 266.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 684 24(10) to 64 bit double precision IEEE 754 binary floating point representation standard (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

What are the steps to convert decimal number
266.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 684 24(10) to 64 bit double precision IEEE 754 binary floating point representation (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

1. First, convert to binary (in base 2) the integer part: 266.
Divide the number repeatedly by 2.

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 266 ÷ 2 = 133 + 0;
  • 133 ÷ 2 = 66 + 1;
  • 66 ÷ 2 = 33 + 0;
  • 33 ÷ 2 = 16 + 1;
  • 16 ÷ 2 = 8 + 0;
  • 8 ÷ 2 = 4 + 0;
  • 4 ÷ 2 = 2 + 0;
  • 2 ÷ 2 = 1 + 0;
  • 1 ÷ 2 = 0 + 1;

2. Construct the base 2 representation of the integer part of the number.

Take all the remainders starting from the bottom of the list constructed above.

266(10) =


1 0000 1010(2)


3. Convert to binary (base 2) the fractional part: 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 684 24.

Multiply it repeatedly by 2.


Keep track of each integer part of the results.


Stop when we get a fractional part that is equal to zero.


  • #) multiplying = integer + fractional part;
  • 1) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 684 24 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 368 48;
  • 2) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 368 48 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 736 96;
  • 3) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 736 96 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 473 92;
  • 4) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 473 92 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 947 84;
  • 5) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 947 84 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 895 68;
  • 6) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 895 68 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 667 791 36;
  • 7) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 667 791 36 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 335 582 72;
  • 8) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 335 582 72 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 671 165 44;
  • 9) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 671 165 44 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 342 330 88;
  • 10) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 342 330 88 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 684 661 76;
  • 11) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 684 661 76 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 369 323 52;
  • 12) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 369 323 52 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 738 647 04;
  • 13) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 738 647 04 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 477 294 08;
  • 14) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 477 294 08 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 954 588 16;
  • 15) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 954 588 16 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 909 176 32;
  • 16) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 909 176 32 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 667 818 352 64;
  • 17) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 667 818 352 64 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 335 636 705 28;
  • 18) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 335 636 705 28 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 671 273 410 56;
  • 19) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 671 273 410 56 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 342 546 821 12;
  • 20) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 342 546 821 12 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 685 093 642 24;
  • 21) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 685 093 642 24 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 370 187 284 48;
  • 22) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 370 187 284 48 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 740 374 568 96;
  • 23) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 740 374 568 96 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 480 749 137 92;
  • 24) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 480 749 137 92 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 961 498 275 84;
  • 25) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 961 498 275 84 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 922 996 551 68;
  • 26) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 333 922 996 551 68 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 667 845 993 103 36;
  • 27) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 667 845 993 103 36 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 335 691 986 206 72;
  • 28) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 335 691 986 206 72 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 671 383 972 413 44;
  • 29) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 671 383 972 413 44 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 342 767 944 826 88;
  • 30) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 342 767 944 826 88 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 685 535 889 653 76;
  • 31) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 685 535 889 653 76 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 371 071 779 307 52;
  • 32) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 371 071 779 307 52 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 742 143 558 615 04;
  • 33) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 742 143 558 615 04 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 484 287 117 230 08;
  • 34) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 484 287 117 230 08 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 968 574 234 460 16;
  • 35) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 968 574 234 460 16 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 937 148 468 920 32;
  • 36) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 333 937 148 468 920 32 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 667 874 296 937 840 64;
  • 37) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 667 874 296 937 840 64 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 335 748 593 875 681 28;
  • 38) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 335 748 593 875 681 28 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 671 497 187 751 362 56;
  • 39) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 671 497 187 751 362 56 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 342 994 375 502 725 12;
  • 40) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 342 994 375 502 725 12 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 685 988 751 005 450 24;
  • 41) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 685 988 751 005 450 24 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 371 977 502 010 900 48;
  • 42) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 371 977 502 010 900 48 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 743 955 004 021 800 96;
  • 43) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 743 955 004 021 800 96 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 487 910 008 043 601 92;
  • 44) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 487 910 008 043 601 92 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 666 975 820 016 087 203 84;
  • 45) 0.666 666 666 666 666 666 666 666 666 666 666 666 666 975 820 016 087 203 84 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 333 951 640 032 174 407 68;
  • 46) 0.333 333 333 333 333 333 333 333 333 333 333 333 333 951 640 032 174 407 68 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 667 903 280 064 348 815 36;
  • 47) 0.666 666 666 666 666 666 666 666 666 666 666 666 667 903 280 064 348 815 36 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 335 806 560 128 697 630 72;
  • 48) 0.333 333 333 333 333 333 333 333 333 333 333 333 335 806 560 128 697 630 72 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 671 613 120 257 395 261 44;
  • 49) 0.666 666 666 666 666 666 666 666 666 666 666 666 671 613 120 257 395 261 44 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 343 226 240 514 790 522 88;
  • 50) 0.333 333 333 333 333 333 333 333 333 333 333 333 343 226 240 514 790 522 88 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 686 452 481 029 581 045 76;
  • 51) 0.666 666 666 666 666 666 666 666 666 666 666 666 686 452 481 029 581 045 76 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 372 904 962 059 162 091 52;
  • 52) 0.333 333 333 333 333 333 333 333 333 333 333 333 372 904 962 059 162 091 52 × 2 = 0 + 0.666 666 666 666 666 666 666 666 666 666 666 666 745 809 924 118 324 183 04;
  • 53) 0.666 666 666 666 666 666 666 666 666 666 666 666 745 809 924 118 324 183 04 × 2 = 1 + 0.333 333 333 333 333 333 333 333 333 333 333 333 491 619 848 236 648 366 08;

We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit) and at least one integer that was different from zero => FULL STOP (Losing precision - the converted number we get in the end will be just a very good approximation of the initial one).


4. Construct the base 2 representation of the fractional part of the number.

Take all the integer parts of the multiplying operations, starting from the top of the constructed list above:


0.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 684 24(10) =


0.1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1(2)

5. Positive number before normalization:

266.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 684 24(10) =


1 0000 1010.1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1(2)

6. Normalize the binary representation of the number.

Shift the decimal mark 8 positions to the left, so that only one non zero digit remains to the left of it:


266.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 684 24(10) =


1 0000 1010.1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1(2) =


1 0000 1010.1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1(2) × 20 =


1.0000 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1(2) × 28


7. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

Sign 0 (a positive number)


Exponent (unadjusted): 8


Mantissa (not normalized):
1.0000 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1


8. Adjust the exponent.

Use the 11 bit excess/bias notation:


Exponent (adjusted) =


Exponent (unadjusted) + 2(11-1) - 1 =


8 + 2(11-1) - 1 =


(8 + 1 023)(10) =


1 031(10)


9. Convert the adjusted exponent from the decimal (base 10) to 11 bit binary.

Use the same technique of repeatedly dividing by 2:


  • division = quotient + remainder;
  • 1 031 ÷ 2 = 515 + 1;
  • 515 ÷ 2 = 257 + 1;
  • 257 ÷ 2 = 128 + 1;
  • 128 ÷ 2 = 64 + 0;
  • 64 ÷ 2 = 32 + 0;
  • 32 ÷ 2 = 16 + 0;
  • 16 ÷ 2 = 8 + 0;
  • 8 ÷ 2 = 4 + 0;
  • 4 ÷ 2 = 2 + 0;
  • 2 ÷ 2 = 1 + 0;
  • 1 ÷ 2 = 0 + 1;

10. Construct the base 2 representation of the adjusted exponent.

Take all the remainders starting from the bottom of the list constructed above.


Exponent (adjusted) =


1031(10) =


100 0000 0111(2)


11. Normalize the mantissa.

a) Remove the leading (the leftmost) bit, since it's allways 1, and the decimal point, if the case.


b) Adjust its length to 52 bits, by removing the excess bits, from the right (if any of the excess bits is set on 1, we are losing precision...).


Mantissa (normalized) =


1. 0000 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1 0101 0101 =


0000 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010


12. The three elements that make up the number's 64 bit double precision IEEE 754 binary floating point representation:

Sign (1 bit) =
0 (a positive number)


Exponent (11 bits) =
100 0000 0111


Mantissa (52 bits) =
0000 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010


Decimal number 266.666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 684 24 converted to 64 bit double precision IEEE 754 binary floating point representation:

0 - 100 0000 0111 - 0000 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010 1010

How to convert numbers from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point standard

Follow the steps below to convert a base 10 decimal number to 64 bit double precision IEEE 754 binary floating point:

  • 1. If the number to be converted is negative, start with its the positive version.
  • 2. First convert the integer part. Divide repeatedly by 2 the positive representation of the integer number that is to be converted to binary, until we get a quotient that is equal to zero, keeping track of each remainder.
  • 3. Construct the base 2 representation of the positive integer part of the number, by taking all the remainders from the previous operations, starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Then convert the fractional part. Multiply the number repeatedly by 2, until we get a fractional part that is equal to zero, keeping track of each integer part of the results.
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the multiplying operations, starting from the top of the list constructed above (they should appear in the binary representation, from left to right, in the order they have been calculated).
  • 6. Normalize the binary representation of the number, shifting the decimal mark (the decimal point) "n" positions either to the left, or to the right, so that only one non zero digit remains to the left of the decimal mark.
  • 7. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary, by using the same technique of repeatedly dividing by 2, as shown above:
    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1
  • 8. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal mark, if the case) and adjust its length to 52 bits, either by removing the excess bits from the right (losing precision...) or by adding extra bits set on '0' to the right.
  • 9. Sign (it takes 1 bit) is either 1 for a negative or 0 for a positive number.

Example: convert the negative number -31.640 215 from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point:

  • 1. Start with the positive version of the number:

    |-31.640 215| = 31.640 215

  • 2. First convert the integer part, 31. Divide it repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 31 ÷ 2 = 15 + 1;
    • 15 ÷ 2 = 7 + 1;
    • 7 ÷ 2 = 3 + 1;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
    • We have encountered a quotient that is ZERO => FULL STOP
  • 3. Construct the base 2 representation of the integer part of the number by taking all the remainders of the previous dividing operations, starting from the bottom of the list constructed above:

    31(10) = 1 1111(2)

  • 4. Then, convert the fractional part, 0.640 215. Multiply repeatedly by 2, keeping track of each integer part of the results, until we get a fractional part that is equal to zero:
    • #) multiplying = integer + fractional part;
    • 1) 0.640 215 × 2 = 1 + 0.280 43;
    • 2) 0.280 43 × 2 = 0 + 0.560 86;
    • 3) 0.560 86 × 2 = 1 + 0.121 72;
    • 4) 0.121 72 × 2 = 0 + 0.243 44;
    • 5) 0.243 44 × 2 = 0 + 0.486 88;
    • 6) 0.486 88 × 2 = 0 + 0.973 76;
    • 7) 0.973 76 × 2 = 1 + 0.947 52;
    • 8) 0.947 52 × 2 = 1 + 0.895 04;
    • 9) 0.895 04 × 2 = 1 + 0.790 08;
    • 10) 0.790 08 × 2 = 1 + 0.580 16;
    • 11) 0.580 16 × 2 = 1 + 0.160 32;
    • 12) 0.160 32 × 2 = 0 + 0.320 64;
    • 13) 0.320 64 × 2 = 0 + 0.641 28;
    • 14) 0.641 28 × 2 = 1 + 0.282 56;
    • 15) 0.282 56 × 2 = 0 + 0.565 12;
    • 16) 0.565 12 × 2 = 1 + 0.130 24;
    • 17) 0.130 24 × 2 = 0 + 0.260 48;
    • 18) 0.260 48 × 2 = 0 + 0.520 96;
    • 19) 0.520 96 × 2 = 1 + 0.041 92;
    • 20) 0.041 92 × 2 = 0 + 0.083 84;
    • 21) 0.083 84 × 2 = 0 + 0.167 68;
    • 22) 0.167 68 × 2 = 0 + 0.335 36;
    • 23) 0.335 36 × 2 = 0 + 0.670 72;
    • 24) 0.670 72 × 2 = 1 + 0.341 44;
    • 25) 0.341 44 × 2 = 0 + 0.682 88;
    • 26) 0.682 88 × 2 = 1 + 0.365 76;
    • 27) 0.365 76 × 2 = 0 + 0.731 52;
    • 28) 0.731 52 × 2 = 1 + 0.463 04;
    • 29) 0.463 04 × 2 = 0 + 0.926 08;
    • 30) 0.926 08 × 2 = 1 + 0.852 16;
    • 31) 0.852 16 × 2 = 1 + 0.704 32;
    • 32) 0.704 32 × 2 = 1 + 0.408 64;
    • 33) 0.408 64 × 2 = 0 + 0.817 28;
    • 34) 0.817 28 × 2 = 1 + 0.634 56;
    • 35) 0.634 56 × 2 = 1 + 0.269 12;
    • 36) 0.269 12 × 2 = 0 + 0.538 24;
    • 37) 0.538 24 × 2 = 1 + 0.076 48;
    • 38) 0.076 48 × 2 = 0 + 0.152 96;
    • 39) 0.152 96 × 2 = 0 + 0.305 92;
    • 40) 0.305 92 × 2 = 0 + 0.611 84;
    • 41) 0.611 84 × 2 = 1 + 0.223 68;
    • 42) 0.223 68 × 2 = 0 + 0.447 36;
    • 43) 0.447 36 × 2 = 0 + 0.894 72;
    • 44) 0.894 72 × 2 = 1 + 0.789 44;
    • 45) 0.789 44 × 2 = 1 + 0.578 88;
    • 46) 0.578 88 × 2 = 1 + 0.157 76;
    • 47) 0.157 76 × 2 = 0 + 0.315 52;
    • 48) 0.315 52 × 2 = 0 + 0.631 04;
    • 49) 0.631 04 × 2 = 1 + 0.262 08;
    • 50) 0.262 08 × 2 = 0 + 0.524 16;
    • 51) 0.524 16 × 2 = 1 + 0.048 32;
    • 52) 0.048 32 × 2 = 0 + 0.096 64;
    • 53) 0.096 64 × 2 = 0 + 0.193 28;
    • We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit = 52) and at least one integer part that was different from zero => FULL STOP (losing precision...).
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the previous multiplying operations, starting from the top of the constructed list above:

    0.640 215(10) = 0.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 6. Summarizing - the positive number before normalization:

    31.640 215(10) = 1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 7. Normalize the binary representation of the number, shifting the decimal mark 4 positions to the left so that only one non-zero digit stays to the left of the decimal mark:

    31.640 215(10) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 20 =
    1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 24

  • 8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

    Sign: 1 (a negative number)

    Exponent (unadjusted): 4

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

  • 9. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary (base 2), by using the same technique of repeatedly dividing it by 2, as shown above:

    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1 = (4 + 1023)(10) = 1027(10) =
    100 0000 0011(2)

  • 10. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal sign) and adjust its length to 52 bits, by removing the excess bits, from the right (losing precision...):

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

    Mantissa (normalized): 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Conclusion:

    Sign (1 bit) = 1 (a negative number)

    Exponent (8 bits) = 100 0000 0011

    Mantissa (52 bits) = 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Number -31.640 215, converted from decimal system (base 10) to 64 bit double precision IEEE 754 binary floating point =
    1 - 100 0000 0011 - 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100