2.718 281 828 459 045 235 360 287 471 352 662 497 757 247 106 3 Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard

Convert decimal 2.718 281 828 459 045 235 360 287 471 352 662 497 757 247 106 3(10) to 64 bit double precision IEEE 754 binary floating point representation standard (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

What are the steps to convert decimal number
2.718 281 828 459 045 235 360 287 471 352 662 497 757 247 106 3(10) to 64 bit double precision IEEE 754 binary floating point representation (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

1. First, convert to binary (in base 2) the integer part: 2.
Divide the number repeatedly by 2.

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 2 ÷ 2 = 1 + 0;
  • 1 ÷ 2 = 0 + 1;

2. Construct the base 2 representation of the integer part of the number.

Take all the remainders starting from the bottom of the list constructed above.

2(10) =

10(2)


3. Convert to binary (base 2) the fractional part: 0.718 281 828 459 045 235 360 287 471 352 662 497 757 247 106 3.

Multiply it repeatedly by 2.

Keep track of each integer part of the results.

Stop when we get a fractional part that is equal to zero.


  • #) multiplying = integer + fractional part;
  • 1) 0.718 281 828 459 045 235 360 287 471 352 662 497 757 247 106 3 × 2 = 1 + 0.436 563 656 918 090 470 720 574 942 705 324 995 514 494 212 6;
  • 2) 0.436 563 656 918 090 470 720 574 942 705 324 995 514 494 212 6 × 2 = 0 + 0.873 127 313 836 180 941 441 149 885 410 649 991 028 988 425 2;
  • 3) 0.873 127 313 836 180 941 441 149 885 410 649 991 028 988 425 2 × 2 = 1 + 0.746 254 627 672 361 882 882 299 770 821 299 982 057 976 850 4;
  • 4) 0.746 254 627 672 361 882 882 299 770 821 299 982 057 976 850 4 × 2 = 1 + 0.492 509 255 344 723 765 764 599 541 642 599 964 115 953 700 8;
  • 5) 0.492 509 255 344 723 765 764 599 541 642 599 964 115 953 700 8 × 2 = 0 + 0.985 018 510 689 447 531 529 199 083 285 199 928 231 907 401 6;
  • 6) 0.985 018 510 689 447 531 529 199 083 285 199 928 231 907 401 6 × 2 = 1 + 0.970 037 021 378 895 063 058 398 166 570 399 856 463 814 803 2;
  • 7) 0.970 037 021 378 895 063 058 398 166 570 399 856 463 814 803 2 × 2 = 1 + 0.940 074 042 757 790 126 116 796 333 140 799 712 927 629 606 4;
  • 8) 0.940 074 042 757 790 126 116 796 333 140 799 712 927 629 606 4 × 2 = 1 + 0.880 148 085 515 580 252 233 592 666 281 599 425 855 259 212 8;
  • 9) 0.880 148 085 515 580 252 233 592 666 281 599 425 855 259 212 8 × 2 = 1 + 0.760 296 171 031 160 504 467 185 332 563 198 851 710 518 425 6;
  • 10) 0.760 296 171 031 160 504 467 185 332 563 198 851 710 518 425 6 × 2 = 1 + 0.520 592 342 062 321 008 934 370 665 126 397 703 421 036 851 2;
  • 11) 0.520 592 342 062 321 008 934 370 665 126 397 703 421 036 851 2 × 2 = 1 + 0.041 184 684 124 642 017 868 741 330 252 795 406 842 073 702 4;
  • 12) 0.041 184 684 124 642 017 868 741 330 252 795 406 842 073 702 4 × 2 = 0 + 0.082 369 368 249 284 035 737 482 660 505 590 813 684 147 404 8;
  • 13) 0.082 369 368 249 284 035 737 482 660 505 590 813 684 147 404 8 × 2 = 0 + 0.164 738 736 498 568 071 474 965 321 011 181 627 368 294 809 6;
  • 14) 0.164 738 736 498 568 071 474 965 321 011 181 627 368 294 809 6 × 2 = 0 + 0.329 477 472 997 136 142 949 930 642 022 363 254 736 589 619 2;
  • 15) 0.329 477 472 997 136 142 949 930 642 022 363 254 736 589 619 2 × 2 = 0 + 0.658 954 945 994 272 285 899 861 284 044 726 509 473 179 238 4;
  • 16) 0.658 954 945 994 272 285 899 861 284 044 726 509 473 179 238 4 × 2 = 1 + 0.317 909 891 988 544 571 799 722 568 089 453 018 946 358 476 8;
  • 17) 0.317 909 891 988 544 571 799 722 568 089 453 018 946 358 476 8 × 2 = 0 + 0.635 819 783 977 089 143 599 445 136 178 906 037 892 716 953 6;
  • 18) 0.635 819 783 977 089 143 599 445 136 178 906 037 892 716 953 6 × 2 = 1 + 0.271 639 567 954 178 287 198 890 272 357 812 075 785 433 907 2;
  • 19) 0.271 639 567 954 178 287 198 890 272 357 812 075 785 433 907 2 × 2 = 0 + 0.543 279 135 908 356 574 397 780 544 715 624 151 570 867 814 4;
  • 20) 0.543 279 135 908 356 574 397 780 544 715 624 151 570 867 814 4 × 2 = 1 + 0.086 558 271 816 713 148 795 561 089 431 248 303 141 735 628 8;
  • 21) 0.086 558 271 816 713 148 795 561 089 431 248 303 141 735 628 8 × 2 = 0 + 0.173 116 543 633 426 297 591 122 178 862 496 606 283 471 257 6;
  • 22) 0.173 116 543 633 426 297 591 122 178 862 496 606 283 471 257 6 × 2 = 0 + 0.346 233 087 266 852 595 182 244 357 724 993 212 566 942 515 2;
  • 23) 0.346 233 087 266 852 595 182 244 357 724 993 212 566 942 515 2 × 2 = 0 + 0.692 466 174 533 705 190 364 488 715 449 986 425 133 885 030 4;
  • 24) 0.692 466 174 533 705 190 364 488 715 449 986 425 133 885 030 4 × 2 = 1 + 0.384 932 349 067 410 380 728 977 430 899 972 850 267 770 060 8;
  • 25) 0.384 932 349 067 410 380 728 977 430 899 972 850 267 770 060 8 × 2 = 0 + 0.769 864 698 134 820 761 457 954 861 799 945 700 535 540 121 6;
  • 26) 0.769 864 698 134 820 761 457 954 861 799 945 700 535 540 121 6 × 2 = 1 + 0.539 729 396 269 641 522 915 909 723 599 891 401 071 080 243 2;
  • 27) 0.539 729 396 269 641 522 915 909 723 599 891 401 071 080 243 2 × 2 = 1 + 0.079 458 792 539 283 045 831 819 447 199 782 802 142 160 486 4;
  • 28) 0.079 458 792 539 283 045 831 819 447 199 782 802 142 160 486 4 × 2 = 0 + 0.158 917 585 078 566 091 663 638 894 399 565 604 284 320 972 8;
  • 29) 0.158 917 585 078 566 091 663 638 894 399 565 604 284 320 972 8 × 2 = 0 + 0.317 835 170 157 132 183 327 277 788 799 131 208 568 641 945 6;
  • 30) 0.317 835 170 157 132 183 327 277 788 799 131 208 568 641 945 6 × 2 = 0 + 0.635 670 340 314 264 366 654 555 577 598 262 417 137 283 891 2;
  • 31) 0.635 670 340 314 264 366 654 555 577 598 262 417 137 283 891 2 × 2 = 1 + 0.271 340 680 628 528 733 309 111 155 196 524 834 274 567 782 4;
  • 32) 0.271 340 680 628 528 733 309 111 155 196 524 834 274 567 782 4 × 2 = 0 + 0.542 681 361 257 057 466 618 222 310 393 049 668 549 135 564 8;
  • 33) 0.542 681 361 257 057 466 618 222 310 393 049 668 549 135 564 8 × 2 = 1 + 0.085 362 722 514 114 933 236 444 620 786 099 337 098 271 129 6;
  • 34) 0.085 362 722 514 114 933 236 444 620 786 099 337 098 271 129 6 × 2 = 0 + 0.170 725 445 028 229 866 472 889 241 572 198 674 196 542 259 2;
  • 35) 0.170 725 445 028 229 866 472 889 241 572 198 674 196 542 259 2 × 2 = 0 + 0.341 450 890 056 459 732 945 778 483 144 397 348 393 084 518 4;
  • 36) 0.341 450 890 056 459 732 945 778 483 144 397 348 393 084 518 4 × 2 = 0 + 0.682 901 780 112 919 465 891 556 966 288 794 696 786 169 036 8;
  • 37) 0.682 901 780 112 919 465 891 556 966 288 794 696 786 169 036 8 × 2 = 1 + 0.365 803 560 225 838 931 783 113 932 577 589 393 572 338 073 6;
  • 38) 0.365 803 560 225 838 931 783 113 932 577 589 393 572 338 073 6 × 2 = 0 + 0.731 607 120 451 677 863 566 227 865 155 178 787 144 676 147 2;
  • 39) 0.731 607 120 451 677 863 566 227 865 155 178 787 144 676 147 2 × 2 = 1 + 0.463 214 240 903 355 727 132 455 730 310 357 574 289 352 294 4;
  • 40) 0.463 214 240 903 355 727 132 455 730 310 357 574 289 352 294 4 × 2 = 0 + 0.926 428 481 806 711 454 264 911 460 620 715 148 578 704 588 8;
  • 41) 0.926 428 481 806 711 454 264 911 460 620 715 148 578 704 588 8 × 2 = 1 + 0.852 856 963 613 422 908 529 822 921 241 430 297 157 409 177 6;
  • 42) 0.852 856 963 613 422 908 529 822 921 241 430 297 157 409 177 6 × 2 = 1 + 0.705 713 927 226 845 817 059 645 842 482 860 594 314 818 355 2;
  • 43) 0.705 713 927 226 845 817 059 645 842 482 860 594 314 818 355 2 × 2 = 1 + 0.411 427 854 453 691 634 119 291 684 965 721 188 629 636 710 4;
  • 44) 0.411 427 854 453 691 634 119 291 684 965 721 188 629 636 710 4 × 2 = 0 + 0.822 855 708 907 383 268 238 583 369 931 442 377 259 273 420 8;
  • 45) 0.822 855 708 907 383 268 238 583 369 931 442 377 259 273 420 8 × 2 = 1 + 0.645 711 417 814 766 536 477 166 739 862 884 754 518 546 841 6;
  • 46) 0.645 711 417 814 766 536 477 166 739 862 884 754 518 546 841 6 × 2 = 1 + 0.291 422 835 629 533 072 954 333 479 725 769 509 037 093 683 2;
  • 47) 0.291 422 835 629 533 072 954 333 479 725 769 509 037 093 683 2 × 2 = 0 + 0.582 845 671 259 066 145 908 666 959 451 539 018 074 187 366 4;
  • 48) 0.582 845 671 259 066 145 908 666 959 451 539 018 074 187 366 4 × 2 = 1 + 0.165 691 342 518 132 291 817 333 918 903 078 036 148 374 732 8;
  • 49) 0.165 691 342 518 132 291 817 333 918 903 078 036 148 374 732 8 × 2 = 0 + 0.331 382 685 036 264 583 634 667 837 806 156 072 296 749 465 6;
  • 50) 0.331 382 685 036 264 583 634 667 837 806 156 072 296 749 465 6 × 2 = 0 + 0.662 765 370 072 529 167 269 335 675 612 312 144 593 498 931 2;
  • 51) 0.662 765 370 072 529 167 269 335 675 612 312 144 593 498 931 2 × 2 = 1 + 0.325 530 740 145 058 334 538 671 351 224 624 289 186 997 862 4;
  • 52) 0.325 530 740 145 058 334 538 671 351 224 624 289 186 997 862 4 × 2 = 0 + 0.651 061 480 290 116 669 077 342 702 449 248 578 373 995 724 8;
  • 53) 0.651 061 480 290 116 669 077 342 702 449 248 578 373 995 724 8 × 2 = 1 + 0.302 122 960 580 233 338 154 685 404 898 497 156 747 991 449 6;

We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit) and at least one integer that was different from zero => FULL STOP (Losing precision - the converted number we get in the end will be just a very good approximation of the initial one).


4. Construct the base 2 representation of the fractional part of the number.

Take all the integer parts of the multiplying operations, starting from the top of the constructed list above:


0.718 281 828 459 045 235 360 287 471 352 662 497 757 247 106 3(10) =

0.1011 0111 1110 0001 0101 0001 0110 0010 1000 1010 1110 1101 0010 1(2)

5. Positive number before normalization:

2.718 281 828 459 045 235 360 287 471 352 662 497 757 247 106 3(10) =

10.1011 0111 1110 0001 0101 0001 0110 0010 1000 1010 1110 1101 0010 1(2)

6. Normalize the binary representation of the number.

Shift the decimal mark 1 positions to the left, so that only one non zero digit remains to the left of it:


2.718 281 828 459 045 235 360 287 471 352 662 497 757 247 106 3(10) =

10.1011 0111 1110 0001 0101 0001 0110 0010 1000 1010 1110 1101 0010 1(2) =

10.1011 0111 1110 0001 0101 0001 0110 0010 1000 1010 1110 1101 0010 1(2) × 20 =

1.0101 1011 1111 0000 1010 1000 1011 0001 0100 0101 0111 0110 1001 01(2) × 21


7. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

Sign 0 (a positive number)

Exponent (unadjusted): 1

Mantissa (not normalized):
1.0101 1011 1111 0000 1010 1000 1011 0001 0100 0101 0111 0110 1001 01


8. Adjust the exponent.

Use the 11 bit excess/bias notation:


Exponent (adjusted) =

Exponent (unadjusted) + 2(11-1) - 1 =

1 + 2(11-1) - 1 =

(1 + 1 023)(10) =

1 024(10)


9. Convert the adjusted exponent from the decimal (base 10) to 11 bit binary.

Use the same technique of repeatedly dividing by 2:


  • division = quotient + remainder;
  • 1 024 ÷ 2 = 512 + 0;
  • 512 ÷ 2 = 256 + 0;
  • 256 ÷ 2 = 128 + 0;
  • 128 ÷ 2 = 64 + 0;
  • 64 ÷ 2 = 32 + 0;
  • 32 ÷ 2 = 16 + 0;
  • 16 ÷ 2 = 8 + 0;
  • 8 ÷ 2 = 4 + 0;
  • 4 ÷ 2 = 2 + 0;
  • 2 ÷ 2 = 1 + 0;
  • 1 ÷ 2 = 0 + 1;

10. Construct the base 2 representation of the adjusted exponent.

Take all the remainders starting from the bottom of the list constructed above.


Exponent (adjusted) =

1024(10) =

100 0000 0000(2)


11. Normalize the mantissa.

a) Remove the leading (the leftmost) bit, since it's allways 1, and the decimal point, if the case.

b) Adjust its length to 52 bits, by removing the excess bits, from the right (if any of the excess bits is set on 1, we are losing precision...).


Mantissa (normalized) =

1. 0101 1011 1111 0000 1010 1000 1011 0001 0100 0101 0111 0110 1001 01 =

0101 1011 1111 0000 1010 1000 1011 0001 0100 0101 0111 0110 1001


12. The three elements that make up the number's 64 bit double precision IEEE 754 binary floating point representation:

Sign (1 bit) =
0 (a positive number)

Exponent (11 bits) =
100 0000 0000

Mantissa (52 bits) =
0101 1011 1111 0000 1010 1000 1011 0001 0100 0101 0111 0110 1001


Decimal number 2.718 281 828 459 045 235 360 287 471 352 662 497 757 247 106 3 converted to 64 bit double precision IEEE 754 binary floating point representation:

0 - 100 0000 0000 - 0101 1011 1111 0000 1010 1000 1011 0001 0100 0101 0111 0110 1001

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How to convert numbers from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point standard

Follow the steps below to convert a base 10 decimal number to 64 bit double precision IEEE 754 binary floating point:

  • 1. If the number to be converted is negative, start with its the positive version.
  • 2. First convert the integer part. Divide repeatedly by 2 the positive representation of the integer number that is to be converted to binary, until we get a quotient that is equal to zero, keeping track of each remainder.
  • 3. Construct the base 2 representation of the positive integer part of the number, by taking all the remainders from the previous operations, starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Then convert the fractional part. Multiply the number repeatedly by 2, until we get a fractional part that is equal to zero, keeping track of each integer part of the results.
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the multiplying operations, starting from the top of the list constructed above (they should appear in the binary representation, from left to right, in the order they have been calculated).
  • 6. Normalize the binary representation of the number, shifting the decimal mark (the decimal point) "n" positions either to the left, or to the right, so that only one non zero digit remains to the left of the decimal mark.
  • 7. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary, by using the same technique of repeatedly dividing by 2, as shown above:
    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1
  • 8. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal mark, if the case) and adjust its length to 52 bits, either by removing the excess bits from the right (losing precision...) or by adding extra bits set on '0' to the right.
  • 9. Sign (it takes 1 bit) is either 1 for a negative or 0 for a positive number.

Example: convert the negative number -31.640 215 from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point:

  • 1. Start with the positive version of the number:

    |-31.640 215| = 31.640 215

  • 2. First convert the integer part, 31. Divide it repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 31 ÷ 2 = 15 + 1;
    • 15 ÷ 2 = 7 + 1;
    • 7 ÷ 2 = 3 + 1;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
    • We have encountered a quotient that is ZERO => FULL STOP
  • 3. Construct the base 2 representation of the integer part of the number by taking all the remainders of the previous dividing operations, starting from the bottom of the list constructed above:

    31(10) = 1 1111(2)

  • 4. Then, convert the fractional part, 0.640 215. Multiply repeatedly by 2, keeping track of each integer part of the results, until we get a fractional part that is equal to zero:
    • #) multiplying = integer + fractional part;
    • 1) 0.640 215 × 2 = 1 + 0.280 43;
    • 2) 0.280 43 × 2 = 0 + 0.560 86;
    • 3) 0.560 86 × 2 = 1 + 0.121 72;
    • 4) 0.121 72 × 2 = 0 + 0.243 44;
    • 5) 0.243 44 × 2 = 0 + 0.486 88;
    • 6) 0.486 88 × 2 = 0 + 0.973 76;
    • 7) 0.973 76 × 2 = 1 + 0.947 52;
    • 8) 0.947 52 × 2 = 1 + 0.895 04;
    • 9) 0.895 04 × 2 = 1 + 0.790 08;
    • 10) 0.790 08 × 2 = 1 + 0.580 16;
    • 11) 0.580 16 × 2 = 1 + 0.160 32;
    • 12) 0.160 32 × 2 = 0 + 0.320 64;
    • 13) 0.320 64 × 2 = 0 + 0.641 28;
    • 14) 0.641 28 × 2 = 1 + 0.282 56;
    • 15) 0.282 56 × 2 = 0 + 0.565 12;
    • 16) 0.565 12 × 2 = 1 + 0.130 24;
    • 17) 0.130 24 × 2 = 0 + 0.260 48;
    • 18) 0.260 48 × 2 = 0 + 0.520 96;
    • 19) 0.520 96 × 2 = 1 + 0.041 92;
    • 20) 0.041 92 × 2 = 0 + 0.083 84;
    • 21) 0.083 84 × 2 = 0 + 0.167 68;
    • 22) 0.167 68 × 2 = 0 + 0.335 36;
    • 23) 0.335 36 × 2 = 0 + 0.670 72;
    • 24) 0.670 72 × 2 = 1 + 0.341 44;
    • 25) 0.341 44 × 2 = 0 + 0.682 88;
    • 26) 0.682 88 × 2 = 1 + 0.365 76;
    • 27) 0.365 76 × 2 = 0 + 0.731 52;
    • 28) 0.731 52 × 2 = 1 + 0.463 04;
    • 29) 0.463 04 × 2 = 0 + 0.926 08;
    • 30) 0.926 08 × 2 = 1 + 0.852 16;
    • 31) 0.852 16 × 2 = 1 + 0.704 32;
    • 32) 0.704 32 × 2 = 1 + 0.408 64;
    • 33) 0.408 64 × 2 = 0 + 0.817 28;
    • 34) 0.817 28 × 2 = 1 + 0.634 56;
    • 35) 0.634 56 × 2 = 1 + 0.269 12;
    • 36) 0.269 12 × 2 = 0 + 0.538 24;
    • 37) 0.538 24 × 2 = 1 + 0.076 48;
    • 38) 0.076 48 × 2 = 0 + 0.152 96;
    • 39) 0.152 96 × 2 = 0 + 0.305 92;
    • 40) 0.305 92 × 2 = 0 + 0.611 84;
    • 41) 0.611 84 × 2 = 1 + 0.223 68;
    • 42) 0.223 68 × 2 = 0 + 0.447 36;
    • 43) 0.447 36 × 2 = 0 + 0.894 72;
    • 44) 0.894 72 × 2 = 1 + 0.789 44;
    • 45) 0.789 44 × 2 = 1 + 0.578 88;
    • 46) 0.578 88 × 2 = 1 + 0.157 76;
    • 47) 0.157 76 × 2 = 0 + 0.315 52;
    • 48) 0.315 52 × 2 = 0 + 0.631 04;
    • 49) 0.631 04 × 2 = 1 + 0.262 08;
    • 50) 0.262 08 × 2 = 0 + 0.524 16;
    • 51) 0.524 16 × 2 = 1 + 0.048 32;
    • 52) 0.048 32 × 2 = 0 + 0.096 64;
    • 53) 0.096 64 × 2 = 0 + 0.193 28;
    • We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit = 52) and at least one integer part that was different from zero => FULL STOP (losing precision...).
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the previous multiplying operations, starting from the top of the constructed list above:

    0.640 215(10) = 0.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 6. Summarizing - the positive number before normalization:

    31.640 215(10) = 1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 7. Normalize the binary representation of the number, shifting the decimal mark 4 positions to the left so that only one non-zero digit stays to the left of the decimal mark:

    31.640 215(10) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 20 =
    1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 24

  • 8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

    Sign: 1 (a negative number)

    Exponent (unadjusted): 4

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

  • 9. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary (base 2), by using the same technique of repeatedly dividing it by 2, as shown above:

    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1 = (4 + 1023)(10) = 1027(10) =
    100 0000 0011(2)

  • 10. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal sign) and adjust its length to 52 bits, by removing the excess bits, from the right (losing precision...):

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

    Mantissa (normalized): 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Conclusion:

    Sign (1 bit) = 1 (a negative number)

    Exponent (8 bits) = 100 0000 0011

    Mantissa (52 bits) = 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Number -31.640 215, converted from decimal system (base 10) to 64 bit double precision IEEE 754 binary floating point =
    1 - 100 0000 0011 - 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100