1.161 834 032 785 773 095 167 300 531 840 609 646 036 411 516 475 022 8 Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard

Convert decimal 1.161 834 032 785 773 095 167 300 531 840 609 646 036 411 516 475 022 8(10) to 64 bit double precision IEEE 754 binary floating point representation standard (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

What are the steps to convert decimal number
1.161 834 032 785 773 095 167 300 531 840 609 646 036 411 516 475 022 8(10) to 64 bit double precision IEEE 754 binary floating point representation (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

1. First, convert to binary (in base 2) the integer part: 1.
Divide the number repeatedly by 2.

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 1 ÷ 2 = 0 + 1;

2. Construct the base 2 representation of the integer part of the number.

Take all the remainders starting from the bottom of the list constructed above.

1(10) =

1(2)


3. Convert to binary (base 2) the fractional part: 0.161 834 032 785 773 095 167 300 531 840 609 646 036 411 516 475 022 8.

Multiply it repeatedly by 2.

Keep track of each integer part of the results.

Stop when we get a fractional part that is equal to zero.


  • #) multiplying = integer + fractional part;
  • 1) 0.161 834 032 785 773 095 167 300 531 840 609 646 036 411 516 475 022 8 × 2 = 0 + 0.323 668 065 571 546 190 334 601 063 681 219 292 072 823 032 950 045 6;
  • 2) 0.323 668 065 571 546 190 334 601 063 681 219 292 072 823 032 950 045 6 × 2 = 0 + 0.647 336 131 143 092 380 669 202 127 362 438 584 145 646 065 900 091 2;
  • 3) 0.647 336 131 143 092 380 669 202 127 362 438 584 145 646 065 900 091 2 × 2 = 1 + 0.294 672 262 286 184 761 338 404 254 724 877 168 291 292 131 800 182 4;
  • 4) 0.294 672 262 286 184 761 338 404 254 724 877 168 291 292 131 800 182 4 × 2 = 0 + 0.589 344 524 572 369 522 676 808 509 449 754 336 582 584 263 600 364 8;
  • 5) 0.589 344 524 572 369 522 676 808 509 449 754 336 582 584 263 600 364 8 × 2 = 1 + 0.178 689 049 144 739 045 353 617 018 899 508 673 165 168 527 200 729 6;
  • 6) 0.178 689 049 144 739 045 353 617 018 899 508 673 165 168 527 200 729 6 × 2 = 0 + 0.357 378 098 289 478 090 707 234 037 799 017 346 330 337 054 401 459 2;
  • 7) 0.357 378 098 289 478 090 707 234 037 799 017 346 330 337 054 401 459 2 × 2 = 0 + 0.714 756 196 578 956 181 414 468 075 598 034 692 660 674 108 802 918 4;
  • 8) 0.714 756 196 578 956 181 414 468 075 598 034 692 660 674 108 802 918 4 × 2 = 1 + 0.429 512 393 157 912 362 828 936 151 196 069 385 321 348 217 605 836 8;
  • 9) 0.429 512 393 157 912 362 828 936 151 196 069 385 321 348 217 605 836 8 × 2 = 0 + 0.859 024 786 315 824 725 657 872 302 392 138 770 642 696 435 211 673 6;
  • 10) 0.859 024 786 315 824 725 657 872 302 392 138 770 642 696 435 211 673 6 × 2 = 1 + 0.718 049 572 631 649 451 315 744 604 784 277 541 285 392 870 423 347 2;
  • 11) 0.718 049 572 631 649 451 315 744 604 784 277 541 285 392 870 423 347 2 × 2 = 1 + 0.436 099 145 263 298 902 631 489 209 568 555 082 570 785 740 846 694 4;
  • 12) 0.436 099 145 263 298 902 631 489 209 568 555 082 570 785 740 846 694 4 × 2 = 0 + 0.872 198 290 526 597 805 262 978 419 137 110 165 141 571 481 693 388 8;
  • 13) 0.872 198 290 526 597 805 262 978 419 137 110 165 141 571 481 693 388 8 × 2 = 1 + 0.744 396 581 053 195 610 525 956 838 274 220 330 283 142 963 386 777 6;
  • 14) 0.744 396 581 053 195 610 525 956 838 274 220 330 283 142 963 386 777 6 × 2 = 1 + 0.488 793 162 106 391 221 051 913 676 548 440 660 566 285 926 773 555 2;
  • 15) 0.488 793 162 106 391 221 051 913 676 548 440 660 566 285 926 773 555 2 × 2 = 0 + 0.977 586 324 212 782 442 103 827 353 096 881 321 132 571 853 547 110 4;
  • 16) 0.977 586 324 212 782 442 103 827 353 096 881 321 132 571 853 547 110 4 × 2 = 1 + 0.955 172 648 425 564 884 207 654 706 193 762 642 265 143 707 094 220 8;
  • 17) 0.955 172 648 425 564 884 207 654 706 193 762 642 265 143 707 094 220 8 × 2 = 1 + 0.910 345 296 851 129 768 415 309 412 387 525 284 530 287 414 188 441 6;
  • 18) 0.910 345 296 851 129 768 415 309 412 387 525 284 530 287 414 188 441 6 × 2 = 1 + 0.820 690 593 702 259 536 830 618 824 775 050 569 060 574 828 376 883 2;
  • 19) 0.820 690 593 702 259 536 830 618 824 775 050 569 060 574 828 376 883 2 × 2 = 1 + 0.641 381 187 404 519 073 661 237 649 550 101 138 121 149 656 753 766 4;
  • 20) 0.641 381 187 404 519 073 661 237 649 550 101 138 121 149 656 753 766 4 × 2 = 1 + 0.282 762 374 809 038 147 322 475 299 100 202 276 242 299 313 507 532 8;
  • 21) 0.282 762 374 809 038 147 322 475 299 100 202 276 242 299 313 507 532 8 × 2 = 0 + 0.565 524 749 618 076 294 644 950 598 200 404 552 484 598 627 015 065 6;
  • 22) 0.565 524 749 618 076 294 644 950 598 200 404 552 484 598 627 015 065 6 × 2 = 1 + 0.131 049 499 236 152 589 289 901 196 400 809 104 969 197 254 030 131 2;
  • 23) 0.131 049 499 236 152 589 289 901 196 400 809 104 969 197 254 030 131 2 × 2 = 0 + 0.262 098 998 472 305 178 579 802 392 801 618 209 938 394 508 060 262 4;
  • 24) 0.262 098 998 472 305 178 579 802 392 801 618 209 938 394 508 060 262 4 × 2 = 0 + 0.524 197 996 944 610 357 159 604 785 603 236 419 876 789 016 120 524 8;
  • 25) 0.524 197 996 944 610 357 159 604 785 603 236 419 876 789 016 120 524 8 × 2 = 1 + 0.048 395 993 889 220 714 319 209 571 206 472 839 753 578 032 241 049 6;
  • 26) 0.048 395 993 889 220 714 319 209 571 206 472 839 753 578 032 241 049 6 × 2 = 0 + 0.096 791 987 778 441 428 638 419 142 412 945 679 507 156 064 482 099 2;
  • 27) 0.096 791 987 778 441 428 638 419 142 412 945 679 507 156 064 482 099 2 × 2 = 0 + 0.193 583 975 556 882 857 276 838 284 825 891 359 014 312 128 964 198 4;
  • 28) 0.193 583 975 556 882 857 276 838 284 825 891 359 014 312 128 964 198 4 × 2 = 0 + 0.387 167 951 113 765 714 553 676 569 651 782 718 028 624 257 928 396 8;
  • 29) 0.387 167 951 113 765 714 553 676 569 651 782 718 028 624 257 928 396 8 × 2 = 0 + 0.774 335 902 227 531 429 107 353 139 303 565 436 057 248 515 856 793 6;
  • 30) 0.774 335 902 227 531 429 107 353 139 303 565 436 057 248 515 856 793 6 × 2 = 1 + 0.548 671 804 455 062 858 214 706 278 607 130 872 114 497 031 713 587 2;
  • 31) 0.548 671 804 455 062 858 214 706 278 607 130 872 114 497 031 713 587 2 × 2 = 1 + 0.097 343 608 910 125 716 429 412 557 214 261 744 228 994 063 427 174 4;
  • 32) 0.097 343 608 910 125 716 429 412 557 214 261 744 228 994 063 427 174 4 × 2 = 0 + 0.194 687 217 820 251 432 858 825 114 428 523 488 457 988 126 854 348 8;
  • 33) 0.194 687 217 820 251 432 858 825 114 428 523 488 457 988 126 854 348 8 × 2 = 0 + 0.389 374 435 640 502 865 717 650 228 857 046 976 915 976 253 708 697 6;
  • 34) 0.389 374 435 640 502 865 717 650 228 857 046 976 915 976 253 708 697 6 × 2 = 0 + 0.778 748 871 281 005 731 435 300 457 714 093 953 831 952 507 417 395 2;
  • 35) 0.778 748 871 281 005 731 435 300 457 714 093 953 831 952 507 417 395 2 × 2 = 1 + 0.557 497 742 562 011 462 870 600 915 428 187 907 663 905 014 834 790 4;
  • 36) 0.557 497 742 562 011 462 870 600 915 428 187 907 663 905 014 834 790 4 × 2 = 1 + 0.114 995 485 124 022 925 741 201 830 856 375 815 327 810 029 669 580 8;
  • 37) 0.114 995 485 124 022 925 741 201 830 856 375 815 327 810 029 669 580 8 × 2 = 0 + 0.229 990 970 248 045 851 482 403 661 712 751 630 655 620 059 339 161 6;
  • 38) 0.229 990 970 248 045 851 482 403 661 712 751 630 655 620 059 339 161 6 × 2 = 0 + 0.459 981 940 496 091 702 964 807 323 425 503 261 311 240 118 678 323 2;
  • 39) 0.459 981 940 496 091 702 964 807 323 425 503 261 311 240 118 678 323 2 × 2 = 0 + 0.919 963 880 992 183 405 929 614 646 851 006 522 622 480 237 356 646 4;
  • 40) 0.919 963 880 992 183 405 929 614 646 851 006 522 622 480 237 356 646 4 × 2 = 1 + 0.839 927 761 984 366 811 859 229 293 702 013 045 244 960 474 713 292 8;
  • 41) 0.839 927 761 984 366 811 859 229 293 702 013 045 244 960 474 713 292 8 × 2 = 1 + 0.679 855 523 968 733 623 718 458 587 404 026 090 489 920 949 426 585 6;
  • 42) 0.679 855 523 968 733 623 718 458 587 404 026 090 489 920 949 426 585 6 × 2 = 1 + 0.359 711 047 937 467 247 436 917 174 808 052 180 979 841 898 853 171 2;
  • 43) 0.359 711 047 937 467 247 436 917 174 808 052 180 979 841 898 853 171 2 × 2 = 0 + 0.719 422 095 874 934 494 873 834 349 616 104 361 959 683 797 706 342 4;
  • 44) 0.719 422 095 874 934 494 873 834 349 616 104 361 959 683 797 706 342 4 × 2 = 1 + 0.438 844 191 749 868 989 747 668 699 232 208 723 919 367 595 412 684 8;
  • 45) 0.438 844 191 749 868 989 747 668 699 232 208 723 919 367 595 412 684 8 × 2 = 0 + 0.877 688 383 499 737 979 495 337 398 464 417 447 838 735 190 825 369 6;
  • 46) 0.877 688 383 499 737 979 495 337 398 464 417 447 838 735 190 825 369 6 × 2 = 1 + 0.755 376 766 999 475 958 990 674 796 928 834 895 677 470 381 650 739 2;
  • 47) 0.755 376 766 999 475 958 990 674 796 928 834 895 677 470 381 650 739 2 × 2 = 1 + 0.510 753 533 998 951 917 981 349 593 857 669 791 354 940 763 301 478 4;
  • 48) 0.510 753 533 998 951 917 981 349 593 857 669 791 354 940 763 301 478 4 × 2 = 1 + 0.021 507 067 997 903 835 962 699 187 715 339 582 709 881 526 602 956 8;
  • 49) 0.021 507 067 997 903 835 962 699 187 715 339 582 709 881 526 602 956 8 × 2 = 0 + 0.043 014 135 995 807 671 925 398 375 430 679 165 419 763 053 205 913 6;
  • 50) 0.043 014 135 995 807 671 925 398 375 430 679 165 419 763 053 205 913 6 × 2 = 0 + 0.086 028 271 991 615 343 850 796 750 861 358 330 839 526 106 411 827 2;
  • 51) 0.086 028 271 991 615 343 850 796 750 861 358 330 839 526 106 411 827 2 × 2 = 0 + 0.172 056 543 983 230 687 701 593 501 722 716 661 679 052 212 823 654 4;
  • 52) 0.172 056 543 983 230 687 701 593 501 722 716 661 679 052 212 823 654 4 × 2 = 0 + 0.344 113 087 966 461 375 403 187 003 445 433 323 358 104 425 647 308 8;
  • 53) 0.344 113 087 966 461 375 403 187 003 445 433 323 358 104 425 647 308 8 × 2 = 0 + 0.688 226 175 932 922 750 806 374 006 890 866 646 716 208 851 294 617 6;

We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit) and at least one integer that was different from zero => FULL STOP (Losing precision - the converted number we get in the end will be just a very good approximation of the initial one).


4. Construct the base 2 representation of the fractional part of the number.

Take all the integer parts of the multiplying operations, starting from the top of the constructed list above:


0.161 834 032 785 773 095 167 300 531 840 609 646 036 411 516 475 022 8(10) =

0.0010 1001 0110 1101 1111 0100 1000 0110 0011 0001 1101 0111 0000 0(2)

5. Positive number before normalization:

1.161 834 032 785 773 095 167 300 531 840 609 646 036 411 516 475 022 8(10) =

1.0010 1001 0110 1101 1111 0100 1000 0110 0011 0001 1101 0111 0000 0(2)

6. Normalize the binary representation of the number.

Shift the decimal mark 0 positions to the left, so that only one non zero digit remains to the left of it:


1.161 834 032 785 773 095 167 300 531 840 609 646 036 411 516 475 022 8(10) =

1.0010 1001 0110 1101 1111 0100 1000 0110 0011 0001 1101 0111 0000 0(2) =

1.0010 1001 0110 1101 1111 0100 1000 0110 0011 0001 1101 0111 0000 0(2) × 20


7. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

Sign 0 (a positive number)

Exponent (unadjusted): 0

Mantissa (not normalized):
1.0010 1001 0110 1101 1111 0100 1000 0110 0011 0001 1101 0111 0000 0


8. Adjust the exponent.

Use the 11 bit excess/bias notation:


Exponent (adjusted) =

Exponent (unadjusted) + 2(11-1) - 1 =

0 + 2(11-1) - 1 =

(0 + 1 023)(10) =

1 023(10)


9. Convert the adjusted exponent from the decimal (base 10) to 11 bit binary.

Use the same technique of repeatedly dividing by 2:


  • division = quotient + remainder;
  • 1 023 ÷ 2 = 511 + 1;
  • 511 ÷ 2 = 255 + 1;
  • 255 ÷ 2 = 127 + 1;
  • 127 ÷ 2 = 63 + 1;
  • 63 ÷ 2 = 31 + 1;
  • 31 ÷ 2 = 15 + 1;
  • 15 ÷ 2 = 7 + 1;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

10. Construct the base 2 representation of the adjusted exponent.

Take all the remainders starting from the bottom of the list constructed above.


Exponent (adjusted) =

1023(10) =

011 1111 1111(2)


11. Normalize the mantissa.

a) Remove the leading (the leftmost) bit, since it's allways 1, and the decimal point, if the case.

b) Adjust its length to 52 bits, by removing the excess bits, from the right (if any of the excess bits is set on 1, we are losing precision...).


Mantissa (normalized) =

1. 0010 1001 0110 1101 1111 0100 1000 0110 0011 0001 1101 0111 0000 0 =

0010 1001 0110 1101 1111 0100 1000 0110 0011 0001 1101 0111 0000


12. The three elements that make up the number's 64 bit double precision IEEE 754 binary floating point representation:

Sign (1 bit) =
0 (a positive number)

Exponent (11 bits) =
011 1111 1111

Mantissa (52 bits) =
0010 1001 0110 1101 1111 0100 1000 0110 0011 0001 1101 0111 0000


Decimal number 1.161 834 032 785 773 095 167 300 531 840 609 646 036 411 516 475 022 8 converted to 64 bit double precision IEEE 754 binary floating point representation:

0 - 011 1111 1111 - 0010 1001 0110 1101 1111 0100 1000 0110 0011 0001 1101 0111 0000

Share

» Convert decimal 1.161 834 032 785 773 095 167 300 531 840 609 646 036 411 516 475 031 9 to 64 bit double precision IEEE 754 binary floating point representation standard

» Calculations Performed by Our Visitors: Decimal Numbers Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard. Data organized on a Monthly Basis

» Month 07, 2026 [July]: Decimal Numbers Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard. Calculations performed during the month of: July - by our visitors

» Improve your social skills: The Attention Economy - The Battlefield For Your Focus. NotebookLM YouTube Video of 7.50 minutes

How to convert numbers from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point standard

Follow the steps below to convert a base 10 decimal number to 64 bit double precision IEEE 754 binary floating point:

  • 1. If the number to be converted is negative, start with its the positive version.
  • 2. First convert the integer part. Divide repeatedly by 2 the positive representation of the integer number that is to be converted to binary, until we get a quotient that is equal to zero, keeping track of each remainder.
  • 3. Construct the base 2 representation of the positive integer part of the number, by taking all the remainders from the previous operations, starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Then convert the fractional part. Multiply the number repeatedly by 2, until we get a fractional part that is equal to zero, keeping track of each integer part of the results.
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the multiplying operations, starting from the top of the list constructed above (they should appear in the binary representation, from left to right, in the order they have been calculated).
  • 6. Normalize the binary representation of the number, shifting the decimal mark (the decimal point) "n" positions either to the left, or to the right, so that only one non zero digit remains to the left of the decimal mark.
  • 7. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary, by using the same technique of repeatedly dividing by 2, as shown above:
    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1
  • 8. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal mark, if the case) and adjust its length to 52 bits, either by removing the excess bits from the right (losing precision...) or by adding extra bits set on '0' to the right.
  • 9. Sign (it takes 1 bit) is either 1 for a negative or 0 for a positive number.

Example: convert the negative number -31.640 215 from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point:

  • 1. Start with the positive version of the number:

    |-31.640 215| = 31.640 215

  • 2. First convert the integer part, 31. Divide it repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 31 ÷ 2 = 15 + 1;
    • 15 ÷ 2 = 7 + 1;
    • 7 ÷ 2 = 3 + 1;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
    • We have encountered a quotient that is ZERO => FULL STOP
  • 3. Construct the base 2 representation of the integer part of the number by taking all the remainders of the previous dividing operations, starting from the bottom of the list constructed above:

    31(10) = 1 1111(2)

  • 4. Then, convert the fractional part, 0.640 215. Multiply repeatedly by 2, keeping track of each integer part of the results, until we get a fractional part that is equal to zero:
    • #) multiplying = integer + fractional part;
    • 1) 0.640 215 × 2 = 1 + 0.280 43;
    • 2) 0.280 43 × 2 = 0 + 0.560 86;
    • 3) 0.560 86 × 2 = 1 + 0.121 72;
    • 4) 0.121 72 × 2 = 0 + 0.243 44;
    • 5) 0.243 44 × 2 = 0 + 0.486 88;
    • 6) 0.486 88 × 2 = 0 + 0.973 76;
    • 7) 0.973 76 × 2 = 1 + 0.947 52;
    • 8) 0.947 52 × 2 = 1 + 0.895 04;
    • 9) 0.895 04 × 2 = 1 + 0.790 08;
    • 10) 0.790 08 × 2 = 1 + 0.580 16;
    • 11) 0.580 16 × 2 = 1 + 0.160 32;
    • 12) 0.160 32 × 2 = 0 + 0.320 64;
    • 13) 0.320 64 × 2 = 0 + 0.641 28;
    • 14) 0.641 28 × 2 = 1 + 0.282 56;
    • 15) 0.282 56 × 2 = 0 + 0.565 12;
    • 16) 0.565 12 × 2 = 1 + 0.130 24;
    • 17) 0.130 24 × 2 = 0 + 0.260 48;
    • 18) 0.260 48 × 2 = 0 + 0.520 96;
    • 19) 0.520 96 × 2 = 1 + 0.041 92;
    • 20) 0.041 92 × 2 = 0 + 0.083 84;
    • 21) 0.083 84 × 2 = 0 + 0.167 68;
    • 22) 0.167 68 × 2 = 0 + 0.335 36;
    • 23) 0.335 36 × 2 = 0 + 0.670 72;
    • 24) 0.670 72 × 2 = 1 + 0.341 44;
    • 25) 0.341 44 × 2 = 0 + 0.682 88;
    • 26) 0.682 88 × 2 = 1 + 0.365 76;
    • 27) 0.365 76 × 2 = 0 + 0.731 52;
    • 28) 0.731 52 × 2 = 1 + 0.463 04;
    • 29) 0.463 04 × 2 = 0 + 0.926 08;
    • 30) 0.926 08 × 2 = 1 + 0.852 16;
    • 31) 0.852 16 × 2 = 1 + 0.704 32;
    • 32) 0.704 32 × 2 = 1 + 0.408 64;
    • 33) 0.408 64 × 2 = 0 + 0.817 28;
    • 34) 0.817 28 × 2 = 1 + 0.634 56;
    • 35) 0.634 56 × 2 = 1 + 0.269 12;
    • 36) 0.269 12 × 2 = 0 + 0.538 24;
    • 37) 0.538 24 × 2 = 1 + 0.076 48;
    • 38) 0.076 48 × 2 = 0 + 0.152 96;
    • 39) 0.152 96 × 2 = 0 + 0.305 92;
    • 40) 0.305 92 × 2 = 0 + 0.611 84;
    • 41) 0.611 84 × 2 = 1 + 0.223 68;
    • 42) 0.223 68 × 2 = 0 + 0.447 36;
    • 43) 0.447 36 × 2 = 0 + 0.894 72;
    • 44) 0.894 72 × 2 = 1 + 0.789 44;
    • 45) 0.789 44 × 2 = 1 + 0.578 88;
    • 46) 0.578 88 × 2 = 1 + 0.157 76;
    • 47) 0.157 76 × 2 = 0 + 0.315 52;
    • 48) 0.315 52 × 2 = 0 + 0.631 04;
    • 49) 0.631 04 × 2 = 1 + 0.262 08;
    • 50) 0.262 08 × 2 = 0 + 0.524 16;
    • 51) 0.524 16 × 2 = 1 + 0.048 32;
    • 52) 0.048 32 × 2 = 0 + 0.096 64;
    • 53) 0.096 64 × 2 = 0 + 0.193 28;
    • We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit = 52) and at least one integer part that was different from zero => FULL STOP (losing precision...).
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the previous multiplying operations, starting from the top of the constructed list above:

    0.640 215(10) = 0.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 6. Summarizing - the positive number before normalization:

    31.640 215(10) = 1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 7. Normalize the binary representation of the number, shifting the decimal mark 4 positions to the left so that only one non-zero digit stays to the left of the decimal mark:

    31.640 215(10) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 20 =
    1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 24

  • 8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

    Sign: 1 (a negative number)

    Exponent (unadjusted): 4

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

  • 9. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary (base 2), by using the same technique of repeatedly dividing it by 2, as shown above:

    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1 = (4 + 1023)(10) = 1027(10) =
    100 0000 0011(2)

  • 10. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal sign) and adjust its length to 52 bits, by removing the excess bits, from the right (losing precision...):

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

    Mantissa (normalized): 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Conclusion:

    Sign (1 bit) = 1 (a negative number)

    Exponent (8 bits) = 100 0000 0011

    Mantissa (52 bits) = 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Number -31.640 215, converted from decimal system (base 10) to 64 bit double precision IEEE 754 binary floating point =
    1 - 100 0000 0011 - 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100