0.031 415 926 535 897 932 384 626 433 832 795 028 841 971 693 993 799 Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard

Convert decimal 0.031 415 926 535 897 932 384 626 433 832 795 028 841 971 693 993 799(10) to 64 bit double precision IEEE 754 binary floating point representation standard (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

What are the steps to convert decimal number
0.031 415 926 535 897 932 384 626 433 832 795 028 841 971 693 993 799(10) to 64 bit double precision IEEE 754 binary floating point representation (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

1. First, convert to binary (in base 2) the integer part: 0.
Divide the number repeatedly by 2.

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 0 ÷ 2 = 0 + 0;

2. Construct the base 2 representation of the integer part of the number.

Take all the remainders starting from the bottom of the list constructed above.

0(10) =

0(2)


3. Convert to binary (base 2) the fractional part: 0.031 415 926 535 897 932 384 626 433 832 795 028 841 971 693 993 799.

Multiply it repeatedly by 2.

Keep track of each integer part of the results.

Stop when we get a fractional part that is equal to zero.


  • #) multiplying = integer + fractional part;
  • 1) 0.031 415 926 535 897 932 384 626 433 832 795 028 841 971 693 993 799 × 2 = 0 + 0.062 831 853 071 795 864 769 252 867 665 590 057 683 943 387 987 598;
  • 2) 0.062 831 853 071 795 864 769 252 867 665 590 057 683 943 387 987 598 × 2 = 0 + 0.125 663 706 143 591 729 538 505 735 331 180 115 367 886 775 975 196;
  • 3) 0.125 663 706 143 591 729 538 505 735 331 180 115 367 886 775 975 196 × 2 = 0 + 0.251 327 412 287 183 459 077 011 470 662 360 230 735 773 551 950 392;
  • 4) 0.251 327 412 287 183 459 077 011 470 662 360 230 735 773 551 950 392 × 2 = 0 + 0.502 654 824 574 366 918 154 022 941 324 720 461 471 547 103 900 784;
  • 5) 0.502 654 824 574 366 918 154 022 941 324 720 461 471 547 103 900 784 × 2 = 1 + 0.005 309 649 148 733 836 308 045 882 649 440 922 943 094 207 801 568;
  • 6) 0.005 309 649 148 733 836 308 045 882 649 440 922 943 094 207 801 568 × 2 = 0 + 0.010 619 298 297 467 672 616 091 765 298 881 845 886 188 415 603 136;
  • 7) 0.010 619 298 297 467 672 616 091 765 298 881 845 886 188 415 603 136 × 2 = 0 + 0.021 238 596 594 935 345 232 183 530 597 763 691 772 376 831 206 272;
  • 8) 0.021 238 596 594 935 345 232 183 530 597 763 691 772 376 831 206 272 × 2 = 0 + 0.042 477 193 189 870 690 464 367 061 195 527 383 544 753 662 412 544;
  • 9) 0.042 477 193 189 870 690 464 367 061 195 527 383 544 753 662 412 544 × 2 = 0 + 0.084 954 386 379 741 380 928 734 122 391 054 767 089 507 324 825 088;
  • 10) 0.084 954 386 379 741 380 928 734 122 391 054 767 089 507 324 825 088 × 2 = 0 + 0.169 908 772 759 482 761 857 468 244 782 109 534 179 014 649 650 176;
  • 11) 0.169 908 772 759 482 761 857 468 244 782 109 534 179 014 649 650 176 × 2 = 0 + 0.339 817 545 518 965 523 714 936 489 564 219 068 358 029 299 300 352;
  • 12) 0.339 817 545 518 965 523 714 936 489 564 219 068 358 029 299 300 352 × 2 = 0 + 0.679 635 091 037 931 047 429 872 979 128 438 136 716 058 598 600 704;
  • 13) 0.679 635 091 037 931 047 429 872 979 128 438 136 716 058 598 600 704 × 2 = 1 + 0.359 270 182 075 862 094 859 745 958 256 876 273 432 117 197 201 408;
  • 14) 0.359 270 182 075 862 094 859 745 958 256 876 273 432 117 197 201 408 × 2 = 0 + 0.718 540 364 151 724 189 719 491 916 513 752 546 864 234 394 402 816;
  • 15) 0.718 540 364 151 724 189 719 491 916 513 752 546 864 234 394 402 816 × 2 = 1 + 0.437 080 728 303 448 379 438 983 833 027 505 093 728 468 788 805 632;
  • 16) 0.437 080 728 303 448 379 438 983 833 027 505 093 728 468 788 805 632 × 2 = 0 + 0.874 161 456 606 896 758 877 967 666 055 010 187 456 937 577 611 264;
  • 17) 0.874 161 456 606 896 758 877 967 666 055 010 187 456 937 577 611 264 × 2 = 1 + 0.748 322 913 213 793 517 755 935 332 110 020 374 913 875 155 222 528;
  • 18) 0.748 322 913 213 793 517 755 935 332 110 020 374 913 875 155 222 528 × 2 = 1 + 0.496 645 826 427 587 035 511 870 664 220 040 749 827 750 310 445 056;
  • 19) 0.496 645 826 427 587 035 511 870 664 220 040 749 827 750 310 445 056 × 2 = 0 + 0.993 291 652 855 174 071 023 741 328 440 081 499 655 500 620 890 112;
  • 20) 0.993 291 652 855 174 071 023 741 328 440 081 499 655 500 620 890 112 × 2 = 1 + 0.986 583 305 710 348 142 047 482 656 880 162 999 311 001 241 780 224;
  • 21) 0.986 583 305 710 348 142 047 482 656 880 162 999 311 001 241 780 224 × 2 = 1 + 0.973 166 611 420 696 284 094 965 313 760 325 998 622 002 483 560 448;
  • 22) 0.973 166 611 420 696 284 094 965 313 760 325 998 622 002 483 560 448 × 2 = 1 + 0.946 333 222 841 392 568 189 930 627 520 651 997 244 004 967 120 896;
  • 23) 0.946 333 222 841 392 568 189 930 627 520 651 997 244 004 967 120 896 × 2 = 1 + 0.892 666 445 682 785 136 379 861 255 041 303 994 488 009 934 241 792;
  • 24) 0.892 666 445 682 785 136 379 861 255 041 303 994 488 009 934 241 792 × 2 = 1 + 0.785 332 891 365 570 272 759 722 510 082 607 988 976 019 868 483 584;
  • 25) 0.785 332 891 365 570 272 759 722 510 082 607 988 976 019 868 483 584 × 2 = 1 + 0.570 665 782 731 140 545 519 445 020 165 215 977 952 039 736 967 168;
  • 26) 0.570 665 782 731 140 545 519 445 020 165 215 977 952 039 736 967 168 × 2 = 1 + 0.141 331 565 462 281 091 038 890 040 330 431 955 904 079 473 934 336;
  • 27) 0.141 331 565 462 281 091 038 890 040 330 431 955 904 079 473 934 336 × 2 = 0 + 0.282 663 130 924 562 182 077 780 080 660 863 911 808 158 947 868 672;
  • 28) 0.282 663 130 924 562 182 077 780 080 660 863 911 808 158 947 868 672 × 2 = 0 + 0.565 326 261 849 124 364 155 560 161 321 727 823 616 317 895 737 344;
  • 29) 0.565 326 261 849 124 364 155 560 161 321 727 823 616 317 895 737 344 × 2 = 1 + 0.130 652 523 698 248 728 311 120 322 643 455 647 232 635 791 474 688;
  • 30) 0.130 652 523 698 248 728 311 120 322 643 455 647 232 635 791 474 688 × 2 = 0 + 0.261 305 047 396 497 456 622 240 645 286 911 294 465 271 582 949 376;
  • 31) 0.261 305 047 396 497 456 622 240 645 286 911 294 465 271 582 949 376 × 2 = 0 + 0.522 610 094 792 994 913 244 481 290 573 822 588 930 543 165 898 752;
  • 32) 0.522 610 094 792 994 913 244 481 290 573 822 588 930 543 165 898 752 × 2 = 1 + 0.045 220 189 585 989 826 488 962 581 147 645 177 861 086 331 797 504;
  • 33) 0.045 220 189 585 989 826 488 962 581 147 645 177 861 086 331 797 504 × 2 = 0 + 0.090 440 379 171 979 652 977 925 162 295 290 355 722 172 663 595 008;
  • 34) 0.090 440 379 171 979 652 977 925 162 295 290 355 722 172 663 595 008 × 2 = 0 + 0.180 880 758 343 959 305 955 850 324 590 580 711 444 345 327 190 016;
  • 35) 0.180 880 758 343 959 305 955 850 324 590 580 711 444 345 327 190 016 × 2 = 0 + 0.361 761 516 687 918 611 911 700 649 181 161 422 888 690 654 380 032;
  • 36) 0.361 761 516 687 918 611 911 700 649 181 161 422 888 690 654 380 032 × 2 = 0 + 0.723 523 033 375 837 223 823 401 298 362 322 845 777 381 308 760 064;
  • 37) 0.723 523 033 375 837 223 823 401 298 362 322 845 777 381 308 760 064 × 2 = 1 + 0.447 046 066 751 674 447 646 802 596 724 645 691 554 762 617 520 128;
  • 38) 0.447 046 066 751 674 447 646 802 596 724 645 691 554 762 617 520 128 × 2 = 0 + 0.894 092 133 503 348 895 293 605 193 449 291 383 109 525 235 040 256;
  • 39) 0.894 092 133 503 348 895 293 605 193 449 291 383 109 525 235 040 256 × 2 = 1 + 0.788 184 267 006 697 790 587 210 386 898 582 766 219 050 470 080 512;
  • 40) 0.788 184 267 006 697 790 587 210 386 898 582 766 219 050 470 080 512 × 2 = 1 + 0.576 368 534 013 395 581 174 420 773 797 165 532 438 100 940 161 024;
  • 41) 0.576 368 534 013 395 581 174 420 773 797 165 532 438 100 940 161 024 × 2 = 1 + 0.152 737 068 026 791 162 348 841 547 594 331 064 876 201 880 322 048;
  • 42) 0.152 737 068 026 791 162 348 841 547 594 331 064 876 201 880 322 048 × 2 = 0 + 0.305 474 136 053 582 324 697 683 095 188 662 129 752 403 760 644 096;
  • 43) 0.305 474 136 053 582 324 697 683 095 188 662 129 752 403 760 644 096 × 2 = 0 + 0.610 948 272 107 164 649 395 366 190 377 324 259 504 807 521 288 192;
  • 44) 0.610 948 272 107 164 649 395 366 190 377 324 259 504 807 521 288 192 × 2 = 1 + 0.221 896 544 214 329 298 790 732 380 754 648 519 009 615 042 576 384;
  • 45) 0.221 896 544 214 329 298 790 732 380 754 648 519 009 615 042 576 384 × 2 = 0 + 0.443 793 088 428 658 597 581 464 761 509 297 038 019 230 085 152 768;
  • 46) 0.443 793 088 428 658 597 581 464 761 509 297 038 019 230 085 152 768 × 2 = 0 + 0.887 586 176 857 317 195 162 929 523 018 594 076 038 460 170 305 536;
  • 47) 0.887 586 176 857 317 195 162 929 523 018 594 076 038 460 170 305 536 × 2 = 1 + 0.775 172 353 714 634 390 325 859 046 037 188 152 076 920 340 611 072;
  • 48) 0.775 172 353 714 634 390 325 859 046 037 188 152 076 920 340 611 072 × 2 = 1 + 0.550 344 707 429 268 780 651 718 092 074 376 304 153 840 681 222 144;
  • 49) 0.550 344 707 429 268 780 651 718 092 074 376 304 153 840 681 222 144 × 2 = 1 + 0.100 689 414 858 537 561 303 436 184 148 752 608 307 681 362 444 288;
  • 50) 0.100 689 414 858 537 561 303 436 184 148 752 608 307 681 362 444 288 × 2 = 0 + 0.201 378 829 717 075 122 606 872 368 297 505 216 615 362 724 888 576;
  • 51) 0.201 378 829 717 075 122 606 872 368 297 505 216 615 362 724 888 576 × 2 = 0 + 0.402 757 659 434 150 245 213 744 736 595 010 433 230 725 449 777 152;
  • 52) 0.402 757 659 434 150 245 213 744 736 595 010 433 230 725 449 777 152 × 2 = 0 + 0.805 515 318 868 300 490 427 489 473 190 020 866 461 450 899 554 304;
  • 53) 0.805 515 318 868 300 490 427 489 473 190 020 866 461 450 899 554 304 × 2 = 1 + 0.611 030 637 736 600 980 854 978 946 380 041 732 922 901 799 108 608;
  • 54) 0.611 030 637 736 600 980 854 978 946 380 041 732 922 901 799 108 608 × 2 = 1 + 0.222 061 275 473 201 961 709 957 892 760 083 465 845 803 598 217 216;
  • 55) 0.222 061 275 473 201 961 709 957 892 760 083 465 845 803 598 217 216 × 2 = 0 + 0.444 122 550 946 403 923 419 915 785 520 166 931 691 607 196 434 432;
  • 56) 0.444 122 550 946 403 923 419 915 785 520 166 931 691 607 196 434 432 × 2 = 0 + 0.888 245 101 892 807 846 839 831 571 040 333 863 383 214 392 868 864;
  • 57) 0.888 245 101 892 807 846 839 831 571 040 333 863 383 214 392 868 864 × 2 = 1 + 0.776 490 203 785 615 693 679 663 142 080 667 726 766 428 785 737 728;

We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit) and at least one integer that was different from zero => FULL STOP (Losing precision - the converted number we get in the end will be just a very good approximation of the initial one).


4. Construct the base 2 representation of the fractional part of the number.

Take all the integer parts of the multiplying operations, starting from the top of the constructed list above:


0.031 415 926 535 897 932 384 626 433 832 795 028 841 971 693 993 799(10) =

0.0000 1000 0000 1010 1101 1111 1100 1001 0000 1011 1001 0011 1000 1100 1(2)

5. Positive number before normalization:

0.031 415 926 535 897 932 384 626 433 832 795 028 841 971 693 993 799(10) =

0.0000 1000 0000 1010 1101 1111 1100 1001 0000 1011 1001 0011 1000 1100 1(2)

6. Normalize the binary representation of the number.

Shift the decimal mark 5 positions to the right, so that only one non zero digit remains to the left of it:


0.031 415 926 535 897 932 384 626 433 832 795 028 841 971 693 993 799(10) =

0.0000 1000 0000 1010 1101 1111 1100 1001 0000 1011 1001 0011 1000 1100 1(2) =

0.0000 1000 0000 1010 1101 1111 1100 1001 0000 1011 1001 0011 1000 1100 1(2) × 20 =

1.0000 0001 0101 1011 1111 1001 0010 0001 0111 0010 0111 0001 1001(2) × 2-5


7. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

Sign 0 (a positive number)

Exponent (unadjusted): -5

Mantissa (not normalized):
1.0000 0001 0101 1011 1111 1001 0010 0001 0111 0010 0111 0001 1001


8. Adjust the exponent.

Use the 11 bit excess/bias notation:


Exponent (adjusted) =

Exponent (unadjusted) + 2(11-1) - 1 =

-5 + 2(11-1) - 1 =

(-5 + 1 023)(10) =

1 018(10)


9. Convert the adjusted exponent from the decimal (base 10) to 11 bit binary.

Use the same technique of repeatedly dividing by 2:


  • division = quotient + remainder;
  • 1 018 ÷ 2 = 509 + 0;
  • 509 ÷ 2 = 254 + 1;
  • 254 ÷ 2 = 127 + 0;
  • 127 ÷ 2 = 63 + 1;
  • 63 ÷ 2 = 31 + 1;
  • 31 ÷ 2 = 15 + 1;
  • 15 ÷ 2 = 7 + 1;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

10. Construct the base 2 representation of the adjusted exponent.

Take all the remainders starting from the bottom of the list constructed above.


Exponent (adjusted) =

1018(10) =

011 1111 1010(2)


11. Normalize the mantissa.

a) Remove the leading (the leftmost) bit, since it's allways 1, and the decimal point, if the case.

b) Adjust its length to 52 bits, only if necessary (not the case here).


Mantissa (normalized) =

1. 0000 0001 0101 1011 1111 1001 0010 0001 0111 0010 0111 0001 1001 =

0000 0001 0101 1011 1111 1001 0010 0001 0111 0010 0111 0001 1001


12. The three elements that make up the number's 64 bit double precision IEEE 754 binary floating point representation:

Sign (1 bit) =
0 (a positive number)

Exponent (11 bits) =
011 1111 1010

Mantissa (52 bits) =
0000 0001 0101 1011 1111 1001 0010 0001 0111 0010 0111 0001 1001


Decimal number 0.031 415 926 535 897 932 384 626 433 832 795 028 841 971 693 993 799 converted to 64 bit double precision IEEE 754 binary floating point representation:

0 - 011 1111 1010 - 0000 0001 0101 1011 1111 1001 0010 0001 0111 0010 0111 0001 1001

Share

» Convert decimal 0.031 415 926 535 897 932 384 626 433 832 795 028 841 971 693 993 814 to 64 bit double precision IEEE 754 binary floating point representation standard

» Calculations Performed by Our Visitors: Decimal Numbers Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard. Data organized on a Monthly Basis

» Month 05, 2026 [May]: Decimal Numbers Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard. Calculations performed during the month of: May - by our visitors

» Improve your social skills: Your greatest rival, your most powerful ally. NotebookLM YouTube Video of 7.54 minutes

How to convert numbers from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point standard

Follow the steps below to convert a base 10 decimal number to 64 bit double precision IEEE 754 binary floating point:

  • 1. If the number to be converted is negative, start with its the positive version.
  • 2. First convert the integer part. Divide repeatedly by 2 the positive representation of the integer number that is to be converted to binary, until we get a quotient that is equal to zero, keeping track of each remainder.
  • 3. Construct the base 2 representation of the positive integer part of the number, by taking all the remainders from the previous operations, starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Then convert the fractional part. Multiply the number repeatedly by 2, until we get a fractional part that is equal to zero, keeping track of each integer part of the results.
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the multiplying operations, starting from the top of the list constructed above (they should appear in the binary representation, from left to right, in the order they have been calculated).
  • 6. Normalize the binary representation of the number, shifting the decimal mark (the decimal point) "n" positions either to the left, or to the right, so that only one non zero digit remains to the left of the decimal mark.
  • 7. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary, by using the same technique of repeatedly dividing by 2, as shown above:
    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1
  • 8. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal mark, if the case) and adjust its length to 52 bits, either by removing the excess bits from the right (losing precision...) or by adding extra bits set on '0' to the right.
  • 9. Sign (it takes 1 bit) is either 1 for a negative or 0 for a positive number.

Example: convert the negative number -31.640 215 from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point:

  • 1. Start with the positive version of the number:

    |-31.640 215| = 31.640 215

  • 2. First convert the integer part, 31. Divide it repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 31 ÷ 2 = 15 + 1;
    • 15 ÷ 2 = 7 + 1;
    • 7 ÷ 2 = 3 + 1;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
    • We have encountered a quotient that is ZERO => FULL STOP
  • 3. Construct the base 2 representation of the integer part of the number by taking all the remainders of the previous dividing operations, starting from the bottom of the list constructed above:

    31(10) = 1 1111(2)

  • 4. Then, convert the fractional part, 0.640 215. Multiply repeatedly by 2, keeping track of each integer part of the results, until we get a fractional part that is equal to zero:
    • #) multiplying = integer + fractional part;
    • 1) 0.640 215 × 2 = 1 + 0.280 43;
    • 2) 0.280 43 × 2 = 0 + 0.560 86;
    • 3) 0.560 86 × 2 = 1 + 0.121 72;
    • 4) 0.121 72 × 2 = 0 + 0.243 44;
    • 5) 0.243 44 × 2 = 0 + 0.486 88;
    • 6) 0.486 88 × 2 = 0 + 0.973 76;
    • 7) 0.973 76 × 2 = 1 + 0.947 52;
    • 8) 0.947 52 × 2 = 1 + 0.895 04;
    • 9) 0.895 04 × 2 = 1 + 0.790 08;
    • 10) 0.790 08 × 2 = 1 + 0.580 16;
    • 11) 0.580 16 × 2 = 1 + 0.160 32;
    • 12) 0.160 32 × 2 = 0 + 0.320 64;
    • 13) 0.320 64 × 2 = 0 + 0.641 28;
    • 14) 0.641 28 × 2 = 1 + 0.282 56;
    • 15) 0.282 56 × 2 = 0 + 0.565 12;
    • 16) 0.565 12 × 2 = 1 + 0.130 24;
    • 17) 0.130 24 × 2 = 0 + 0.260 48;
    • 18) 0.260 48 × 2 = 0 + 0.520 96;
    • 19) 0.520 96 × 2 = 1 + 0.041 92;
    • 20) 0.041 92 × 2 = 0 + 0.083 84;
    • 21) 0.083 84 × 2 = 0 + 0.167 68;
    • 22) 0.167 68 × 2 = 0 + 0.335 36;
    • 23) 0.335 36 × 2 = 0 + 0.670 72;
    • 24) 0.670 72 × 2 = 1 + 0.341 44;
    • 25) 0.341 44 × 2 = 0 + 0.682 88;
    • 26) 0.682 88 × 2 = 1 + 0.365 76;
    • 27) 0.365 76 × 2 = 0 + 0.731 52;
    • 28) 0.731 52 × 2 = 1 + 0.463 04;
    • 29) 0.463 04 × 2 = 0 + 0.926 08;
    • 30) 0.926 08 × 2 = 1 + 0.852 16;
    • 31) 0.852 16 × 2 = 1 + 0.704 32;
    • 32) 0.704 32 × 2 = 1 + 0.408 64;
    • 33) 0.408 64 × 2 = 0 + 0.817 28;
    • 34) 0.817 28 × 2 = 1 + 0.634 56;
    • 35) 0.634 56 × 2 = 1 + 0.269 12;
    • 36) 0.269 12 × 2 = 0 + 0.538 24;
    • 37) 0.538 24 × 2 = 1 + 0.076 48;
    • 38) 0.076 48 × 2 = 0 + 0.152 96;
    • 39) 0.152 96 × 2 = 0 + 0.305 92;
    • 40) 0.305 92 × 2 = 0 + 0.611 84;
    • 41) 0.611 84 × 2 = 1 + 0.223 68;
    • 42) 0.223 68 × 2 = 0 + 0.447 36;
    • 43) 0.447 36 × 2 = 0 + 0.894 72;
    • 44) 0.894 72 × 2 = 1 + 0.789 44;
    • 45) 0.789 44 × 2 = 1 + 0.578 88;
    • 46) 0.578 88 × 2 = 1 + 0.157 76;
    • 47) 0.157 76 × 2 = 0 + 0.315 52;
    • 48) 0.315 52 × 2 = 0 + 0.631 04;
    • 49) 0.631 04 × 2 = 1 + 0.262 08;
    • 50) 0.262 08 × 2 = 0 + 0.524 16;
    • 51) 0.524 16 × 2 = 1 + 0.048 32;
    • 52) 0.048 32 × 2 = 0 + 0.096 64;
    • 53) 0.096 64 × 2 = 0 + 0.193 28;
    • We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit = 52) and at least one integer part that was different from zero => FULL STOP (losing precision...).
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the previous multiplying operations, starting from the top of the constructed list above:

    0.640 215(10) = 0.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 6. Summarizing - the positive number before normalization:

    31.640 215(10) = 1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 7. Normalize the binary representation of the number, shifting the decimal mark 4 positions to the left so that only one non-zero digit stays to the left of the decimal mark:

    31.640 215(10) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 20 =
    1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 24

  • 8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

    Sign: 1 (a negative number)

    Exponent (unadjusted): 4

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

  • 9. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary (base 2), by using the same technique of repeatedly dividing it by 2, as shown above:

    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1 = (4 + 1023)(10) = 1027(10) =
    100 0000 0011(2)

  • 10. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal sign) and adjust its length to 52 bits, by removing the excess bits, from the right (losing precision...):

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

    Mantissa (normalized): 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Conclusion:

    Sign (1 bit) = 1 (a negative number)

    Exponent (8 bits) = 100 0000 0011

    Mantissa (52 bits) = 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Number -31.640 215, converted from decimal system (base 10) to 64 bit double precision IEEE 754 binary floating point =
    1 - 100 0000 0011 - 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100