0.000 020 830 729 321 671 205 134 999 155 54 Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard

Convert decimal 0.000 020 830 729 321 671 205 134 999 155 54(10) to 64 bit double precision IEEE 754 binary floating point representation standard (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

What are the steps to convert decimal number
0.000 020 830 729 321 671 205 134 999 155 54(10) to 64 bit double precision IEEE 754 binary floating point representation (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

1. First, convert to binary (in base 2) the integer part: 0.
Divide the number repeatedly by 2.

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 0 ÷ 2 = 0 + 0;

2. Construct the base 2 representation of the integer part of the number.

Take all the remainders starting from the bottom of the list constructed above.

0(10) =

0(2)


3. Convert to binary (base 2) the fractional part: 0.000 020 830 729 321 671 205 134 999 155 54.

Multiply it repeatedly by 2.

Keep track of each integer part of the results.

Stop when we get a fractional part that is equal to zero.


  • #) multiplying = integer + fractional part;
  • 1) 0.000 020 830 729 321 671 205 134 999 155 54 × 2 = 0 + 0.000 041 661 458 643 342 410 269 998 311 08;
  • 2) 0.000 041 661 458 643 342 410 269 998 311 08 × 2 = 0 + 0.000 083 322 917 286 684 820 539 996 622 16;
  • 3) 0.000 083 322 917 286 684 820 539 996 622 16 × 2 = 0 + 0.000 166 645 834 573 369 641 079 993 244 32;
  • 4) 0.000 166 645 834 573 369 641 079 993 244 32 × 2 = 0 + 0.000 333 291 669 146 739 282 159 986 488 64;
  • 5) 0.000 333 291 669 146 739 282 159 986 488 64 × 2 = 0 + 0.000 666 583 338 293 478 564 319 972 977 28;
  • 6) 0.000 666 583 338 293 478 564 319 972 977 28 × 2 = 0 + 0.001 333 166 676 586 957 128 639 945 954 56;
  • 7) 0.001 333 166 676 586 957 128 639 945 954 56 × 2 = 0 + 0.002 666 333 353 173 914 257 279 891 909 12;
  • 8) 0.002 666 333 353 173 914 257 279 891 909 12 × 2 = 0 + 0.005 332 666 706 347 828 514 559 783 818 24;
  • 9) 0.005 332 666 706 347 828 514 559 783 818 24 × 2 = 0 + 0.010 665 333 412 695 657 029 119 567 636 48;
  • 10) 0.010 665 333 412 695 657 029 119 567 636 48 × 2 = 0 + 0.021 330 666 825 391 314 058 239 135 272 96;
  • 11) 0.021 330 666 825 391 314 058 239 135 272 96 × 2 = 0 + 0.042 661 333 650 782 628 116 478 270 545 92;
  • 12) 0.042 661 333 650 782 628 116 478 270 545 92 × 2 = 0 + 0.085 322 667 301 565 256 232 956 541 091 84;
  • 13) 0.085 322 667 301 565 256 232 956 541 091 84 × 2 = 0 + 0.170 645 334 603 130 512 465 913 082 183 68;
  • 14) 0.170 645 334 603 130 512 465 913 082 183 68 × 2 = 0 + 0.341 290 669 206 261 024 931 826 164 367 36;
  • 15) 0.341 290 669 206 261 024 931 826 164 367 36 × 2 = 0 + 0.682 581 338 412 522 049 863 652 328 734 72;
  • 16) 0.682 581 338 412 522 049 863 652 328 734 72 × 2 = 1 + 0.365 162 676 825 044 099 727 304 657 469 44;
  • 17) 0.365 162 676 825 044 099 727 304 657 469 44 × 2 = 0 + 0.730 325 353 650 088 199 454 609 314 938 88;
  • 18) 0.730 325 353 650 088 199 454 609 314 938 88 × 2 = 1 + 0.460 650 707 300 176 398 909 218 629 877 76;
  • 19) 0.460 650 707 300 176 398 909 218 629 877 76 × 2 = 0 + 0.921 301 414 600 352 797 818 437 259 755 52;
  • 20) 0.921 301 414 600 352 797 818 437 259 755 52 × 2 = 1 + 0.842 602 829 200 705 595 636 874 519 511 04;
  • 21) 0.842 602 829 200 705 595 636 874 519 511 04 × 2 = 1 + 0.685 205 658 401 411 191 273 749 039 022 08;
  • 22) 0.685 205 658 401 411 191 273 749 039 022 08 × 2 = 1 + 0.370 411 316 802 822 382 547 498 078 044 16;
  • 23) 0.370 411 316 802 822 382 547 498 078 044 16 × 2 = 0 + 0.740 822 633 605 644 765 094 996 156 088 32;
  • 24) 0.740 822 633 605 644 765 094 996 156 088 32 × 2 = 1 + 0.481 645 267 211 289 530 189 992 312 176 64;
  • 25) 0.481 645 267 211 289 530 189 992 312 176 64 × 2 = 0 + 0.963 290 534 422 579 060 379 984 624 353 28;
  • 26) 0.963 290 534 422 579 060 379 984 624 353 28 × 2 = 1 + 0.926 581 068 845 158 120 759 969 248 706 56;
  • 27) 0.926 581 068 845 158 120 759 969 248 706 56 × 2 = 1 + 0.853 162 137 690 316 241 519 938 497 413 12;
  • 28) 0.853 162 137 690 316 241 519 938 497 413 12 × 2 = 1 + 0.706 324 275 380 632 483 039 876 994 826 24;
  • 29) 0.706 324 275 380 632 483 039 876 994 826 24 × 2 = 1 + 0.412 648 550 761 264 966 079 753 989 652 48;
  • 30) 0.412 648 550 761 264 966 079 753 989 652 48 × 2 = 0 + 0.825 297 101 522 529 932 159 507 979 304 96;
  • 31) 0.825 297 101 522 529 932 159 507 979 304 96 × 2 = 1 + 0.650 594 203 045 059 864 319 015 958 609 92;
  • 32) 0.650 594 203 045 059 864 319 015 958 609 92 × 2 = 1 + 0.301 188 406 090 119 728 638 031 917 219 84;
  • 33) 0.301 188 406 090 119 728 638 031 917 219 84 × 2 = 0 + 0.602 376 812 180 239 457 276 063 834 439 68;
  • 34) 0.602 376 812 180 239 457 276 063 834 439 68 × 2 = 1 + 0.204 753 624 360 478 914 552 127 668 879 36;
  • 35) 0.204 753 624 360 478 914 552 127 668 879 36 × 2 = 0 + 0.409 507 248 720 957 829 104 255 337 758 72;
  • 36) 0.409 507 248 720 957 829 104 255 337 758 72 × 2 = 0 + 0.819 014 497 441 915 658 208 510 675 517 44;
  • 37) 0.819 014 497 441 915 658 208 510 675 517 44 × 2 = 1 + 0.638 028 994 883 831 316 417 021 351 034 88;
  • 38) 0.638 028 994 883 831 316 417 021 351 034 88 × 2 = 1 + 0.276 057 989 767 662 632 834 042 702 069 76;
  • 39) 0.276 057 989 767 662 632 834 042 702 069 76 × 2 = 0 + 0.552 115 979 535 325 265 668 085 404 139 52;
  • 40) 0.552 115 979 535 325 265 668 085 404 139 52 × 2 = 1 + 0.104 231 959 070 650 531 336 170 808 279 04;
  • 41) 0.104 231 959 070 650 531 336 170 808 279 04 × 2 = 0 + 0.208 463 918 141 301 062 672 341 616 558 08;
  • 42) 0.208 463 918 141 301 062 672 341 616 558 08 × 2 = 0 + 0.416 927 836 282 602 125 344 683 233 116 16;
  • 43) 0.416 927 836 282 602 125 344 683 233 116 16 × 2 = 0 + 0.833 855 672 565 204 250 689 366 466 232 32;
  • 44) 0.833 855 672 565 204 250 689 366 466 232 32 × 2 = 1 + 0.667 711 345 130 408 501 378 732 932 464 64;
  • 45) 0.667 711 345 130 408 501 378 732 932 464 64 × 2 = 1 + 0.335 422 690 260 817 002 757 465 864 929 28;
  • 46) 0.335 422 690 260 817 002 757 465 864 929 28 × 2 = 0 + 0.670 845 380 521 634 005 514 931 729 858 56;
  • 47) 0.670 845 380 521 634 005 514 931 729 858 56 × 2 = 1 + 0.341 690 761 043 268 011 029 863 459 717 12;
  • 48) 0.341 690 761 043 268 011 029 863 459 717 12 × 2 = 0 + 0.683 381 522 086 536 022 059 726 919 434 24;
  • 49) 0.683 381 522 086 536 022 059 726 919 434 24 × 2 = 1 + 0.366 763 044 173 072 044 119 453 838 868 48;
  • 50) 0.366 763 044 173 072 044 119 453 838 868 48 × 2 = 0 + 0.733 526 088 346 144 088 238 907 677 736 96;
  • 51) 0.733 526 088 346 144 088 238 907 677 736 96 × 2 = 1 + 0.467 052 176 692 288 176 477 815 355 473 92;
  • 52) 0.467 052 176 692 288 176 477 815 355 473 92 × 2 = 0 + 0.934 104 353 384 576 352 955 630 710 947 84;
  • 53) 0.934 104 353 384 576 352 955 630 710 947 84 × 2 = 1 + 0.868 208 706 769 152 705 911 261 421 895 68;
  • 54) 0.868 208 706 769 152 705 911 261 421 895 68 × 2 = 1 + 0.736 417 413 538 305 411 822 522 843 791 36;
  • 55) 0.736 417 413 538 305 411 822 522 843 791 36 × 2 = 1 + 0.472 834 827 076 610 823 645 045 687 582 72;
  • 56) 0.472 834 827 076 610 823 645 045 687 582 72 × 2 = 0 + 0.945 669 654 153 221 647 290 091 375 165 44;
  • 57) 0.945 669 654 153 221 647 290 091 375 165 44 × 2 = 1 + 0.891 339 308 306 443 294 580 182 750 330 88;
  • 58) 0.891 339 308 306 443 294 580 182 750 330 88 × 2 = 1 + 0.782 678 616 612 886 589 160 365 500 661 76;
  • 59) 0.782 678 616 612 886 589 160 365 500 661 76 × 2 = 1 + 0.565 357 233 225 773 178 320 731 001 323 52;
  • 60) 0.565 357 233 225 773 178 320 731 001 323 52 × 2 = 1 + 0.130 714 466 451 546 356 641 462 002 647 04;
  • 61) 0.130 714 466 451 546 356 641 462 002 647 04 × 2 = 0 + 0.261 428 932 903 092 713 282 924 005 294 08;
  • 62) 0.261 428 932 903 092 713 282 924 005 294 08 × 2 = 0 + 0.522 857 865 806 185 426 565 848 010 588 16;
  • 63) 0.522 857 865 806 185 426 565 848 010 588 16 × 2 = 1 + 0.045 715 731 612 370 853 131 696 021 176 32;
  • 64) 0.045 715 731 612 370 853 131 696 021 176 32 × 2 = 0 + 0.091 431 463 224 741 706 263 392 042 352 64;
  • 65) 0.091 431 463 224 741 706 263 392 042 352 64 × 2 = 0 + 0.182 862 926 449 483 412 526 784 084 705 28;
  • 66) 0.182 862 926 449 483 412 526 784 084 705 28 × 2 = 0 + 0.365 725 852 898 966 825 053 568 169 410 56;
  • 67) 0.365 725 852 898 966 825 053 568 169 410 56 × 2 = 0 + 0.731 451 705 797 933 650 107 136 338 821 12;
  • 68) 0.731 451 705 797 933 650 107 136 338 821 12 × 2 = 1 + 0.462 903 411 595 867 300 214 272 677 642 24;

We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit) and at least one integer that was different from zero => FULL STOP (Losing precision - the converted number we get in the end will be just a very good approximation of the initial one).


4. Construct the base 2 representation of the fractional part of the number.

Take all the integer parts of the multiplying operations, starting from the top of the constructed list above:


0.000 020 830 729 321 671 205 134 999 155 54(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2)

5. Positive number before normalization:

0.000 020 830 729 321 671 205 134 999 155 54(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2)

6. Normalize the binary representation of the number.

Shift the decimal mark 16 positions to the right, so that only one non zero digit remains to the left of it:


0.000 020 830 729 321 671 205 134 999 155 54(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) × 20 =

1.0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) × 2-16


7. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

Sign 0 (a positive number)

Exponent (unadjusted): -16

Mantissa (not normalized):
1.0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


8. Adjust the exponent.

Use the 11 bit excess/bias notation:


Exponent (adjusted) =

Exponent (unadjusted) + 2(11-1) - 1 =

-16 + 2(11-1) - 1 =

(-16 + 1 023)(10) =

1 007(10)


9. Convert the adjusted exponent from the decimal (base 10) to 11 bit binary.

Use the same technique of repeatedly dividing by 2:


  • division = quotient + remainder;
  • 1 007 ÷ 2 = 503 + 1;
  • 503 ÷ 2 = 251 + 1;
  • 251 ÷ 2 = 125 + 1;
  • 125 ÷ 2 = 62 + 1;
  • 62 ÷ 2 = 31 + 0;
  • 31 ÷ 2 = 15 + 1;
  • 15 ÷ 2 = 7 + 1;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

10. Construct the base 2 representation of the adjusted exponent.

Take all the remainders starting from the bottom of the list constructed above.


Exponent (adjusted) =

1007(10) =

011 1110 1111(2)


11. Normalize the mantissa.

a) Remove the leading (the leftmost) bit, since it's allways 1, and the decimal point, if the case.

b) Adjust its length to 52 bits, only if necessary (not the case here).


Mantissa (normalized) =

1. 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001 =

0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


12. The three elements that make up the number's 64 bit double precision IEEE 754 binary floating point representation:

Sign (1 bit) =
0 (a positive number)

Exponent (11 bits) =
011 1110 1111

Mantissa (52 bits) =
0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


Decimal number 0.000 020 830 729 321 671 205 134 999 155 54 converted to 64 bit double precision IEEE 754 binary floating point representation:

0 - 011 1110 1111 - 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001

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How to convert numbers from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point standard

Follow the steps below to convert a base 10 decimal number to 64 bit double precision IEEE 754 binary floating point:

  • 1. If the number to be converted is negative, start with its the positive version.
  • 2. First convert the integer part. Divide repeatedly by 2 the positive representation of the integer number that is to be converted to binary, until we get a quotient that is equal to zero, keeping track of each remainder.
  • 3. Construct the base 2 representation of the positive integer part of the number, by taking all the remainders from the previous operations, starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Then convert the fractional part. Multiply the number repeatedly by 2, until we get a fractional part that is equal to zero, keeping track of each integer part of the results.
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the multiplying operations, starting from the top of the list constructed above (they should appear in the binary representation, from left to right, in the order they have been calculated).
  • 6. Normalize the binary representation of the number, shifting the decimal mark (the decimal point) "n" positions either to the left, or to the right, so that only one non zero digit remains to the left of the decimal mark.
  • 7. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary, by using the same technique of repeatedly dividing by 2, as shown above:
    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1
  • 8. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal mark, if the case) and adjust its length to 52 bits, either by removing the excess bits from the right (losing precision...) or by adding extra bits set on '0' to the right.
  • 9. Sign (it takes 1 bit) is either 1 for a negative or 0 for a positive number.

Example: convert the negative number -31.640 215 from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point:

  • 1. Start with the positive version of the number:

    |-31.640 215| = 31.640 215

  • 2. First convert the integer part, 31. Divide it repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 31 ÷ 2 = 15 + 1;
    • 15 ÷ 2 = 7 + 1;
    • 7 ÷ 2 = 3 + 1;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
    • We have encountered a quotient that is ZERO => FULL STOP
  • 3. Construct the base 2 representation of the integer part of the number by taking all the remainders of the previous dividing operations, starting from the bottom of the list constructed above:

    31(10) = 1 1111(2)

  • 4. Then, convert the fractional part, 0.640 215. Multiply repeatedly by 2, keeping track of each integer part of the results, until we get a fractional part that is equal to zero:
    • #) multiplying = integer + fractional part;
    • 1) 0.640 215 × 2 = 1 + 0.280 43;
    • 2) 0.280 43 × 2 = 0 + 0.560 86;
    • 3) 0.560 86 × 2 = 1 + 0.121 72;
    • 4) 0.121 72 × 2 = 0 + 0.243 44;
    • 5) 0.243 44 × 2 = 0 + 0.486 88;
    • 6) 0.486 88 × 2 = 0 + 0.973 76;
    • 7) 0.973 76 × 2 = 1 + 0.947 52;
    • 8) 0.947 52 × 2 = 1 + 0.895 04;
    • 9) 0.895 04 × 2 = 1 + 0.790 08;
    • 10) 0.790 08 × 2 = 1 + 0.580 16;
    • 11) 0.580 16 × 2 = 1 + 0.160 32;
    • 12) 0.160 32 × 2 = 0 + 0.320 64;
    • 13) 0.320 64 × 2 = 0 + 0.641 28;
    • 14) 0.641 28 × 2 = 1 + 0.282 56;
    • 15) 0.282 56 × 2 = 0 + 0.565 12;
    • 16) 0.565 12 × 2 = 1 + 0.130 24;
    • 17) 0.130 24 × 2 = 0 + 0.260 48;
    • 18) 0.260 48 × 2 = 0 + 0.520 96;
    • 19) 0.520 96 × 2 = 1 + 0.041 92;
    • 20) 0.041 92 × 2 = 0 + 0.083 84;
    • 21) 0.083 84 × 2 = 0 + 0.167 68;
    • 22) 0.167 68 × 2 = 0 + 0.335 36;
    • 23) 0.335 36 × 2 = 0 + 0.670 72;
    • 24) 0.670 72 × 2 = 1 + 0.341 44;
    • 25) 0.341 44 × 2 = 0 + 0.682 88;
    • 26) 0.682 88 × 2 = 1 + 0.365 76;
    • 27) 0.365 76 × 2 = 0 + 0.731 52;
    • 28) 0.731 52 × 2 = 1 + 0.463 04;
    • 29) 0.463 04 × 2 = 0 + 0.926 08;
    • 30) 0.926 08 × 2 = 1 + 0.852 16;
    • 31) 0.852 16 × 2 = 1 + 0.704 32;
    • 32) 0.704 32 × 2 = 1 + 0.408 64;
    • 33) 0.408 64 × 2 = 0 + 0.817 28;
    • 34) 0.817 28 × 2 = 1 + 0.634 56;
    • 35) 0.634 56 × 2 = 1 + 0.269 12;
    • 36) 0.269 12 × 2 = 0 + 0.538 24;
    • 37) 0.538 24 × 2 = 1 + 0.076 48;
    • 38) 0.076 48 × 2 = 0 + 0.152 96;
    • 39) 0.152 96 × 2 = 0 + 0.305 92;
    • 40) 0.305 92 × 2 = 0 + 0.611 84;
    • 41) 0.611 84 × 2 = 1 + 0.223 68;
    • 42) 0.223 68 × 2 = 0 + 0.447 36;
    • 43) 0.447 36 × 2 = 0 + 0.894 72;
    • 44) 0.894 72 × 2 = 1 + 0.789 44;
    • 45) 0.789 44 × 2 = 1 + 0.578 88;
    • 46) 0.578 88 × 2 = 1 + 0.157 76;
    • 47) 0.157 76 × 2 = 0 + 0.315 52;
    • 48) 0.315 52 × 2 = 0 + 0.631 04;
    • 49) 0.631 04 × 2 = 1 + 0.262 08;
    • 50) 0.262 08 × 2 = 0 + 0.524 16;
    • 51) 0.524 16 × 2 = 1 + 0.048 32;
    • 52) 0.048 32 × 2 = 0 + 0.096 64;
    • 53) 0.096 64 × 2 = 0 + 0.193 28;
    • We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit = 52) and at least one integer part that was different from zero => FULL STOP (losing precision...).
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the previous multiplying operations, starting from the top of the constructed list above:

    0.640 215(10) = 0.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 6. Summarizing - the positive number before normalization:

    31.640 215(10) = 1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 7. Normalize the binary representation of the number, shifting the decimal mark 4 positions to the left so that only one non-zero digit stays to the left of the decimal mark:

    31.640 215(10) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 20 =
    1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 24

  • 8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

    Sign: 1 (a negative number)

    Exponent (unadjusted): 4

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

  • 9. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary (base 2), by using the same technique of repeatedly dividing it by 2, as shown above:

    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1 = (4 + 1023)(10) = 1027(10) =
    100 0000 0011(2)

  • 10. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal sign) and adjust its length to 52 bits, by removing the excess bits, from the right (losing precision...):

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

    Mantissa (normalized): 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Conclusion:

    Sign (1 bit) = 1 (a negative number)

    Exponent (8 bits) = 100 0000 0011

    Mantissa (52 bits) = 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Number -31.640 215, converted from decimal system (base 10) to 64 bit double precision IEEE 754 binary floating point =
    1 - 100 0000 0011 - 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100