0.000 020 830 729 321 671 205 134 999 154 511 09 Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard

Convert decimal 0.000 020 830 729 321 671 205 134 999 154 511 09(10) to 64 bit double precision IEEE 754 binary floating point representation standard (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

What are the steps to convert decimal number
0.000 020 830 729 321 671 205 134 999 154 511 09(10) to 64 bit double precision IEEE 754 binary floating point representation (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

1. First, convert to binary (in base 2) the integer part: 0.
Divide the number repeatedly by 2.

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 0 ÷ 2 = 0 + 0;

2. Construct the base 2 representation of the integer part of the number.

Take all the remainders starting from the bottom of the list constructed above.

0(10) =

0(2)


3. Convert to binary (base 2) the fractional part: 0.000 020 830 729 321 671 205 134 999 154 511 09.

Multiply it repeatedly by 2.

Keep track of each integer part of the results.

Stop when we get a fractional part that is equal to zero.


  • #) multiplying = integer + fractional part;
  • 1) 0.000 020 830 729 321 671 205 134 999 154 511 09 × 2 = 0 + 0.000 041 661 458 643 342 410 269 998 309 022 18;
  • 2) 0.000 041 661 458 643 342 410 269 998 309 022 18 × 2 = 0 + 0.000 083 322 917 286 684 820 539 996 618 044 36;
  • 3) 0.000 083 322 917 286 684 820 539 996 618 044 36 × 2 = 0 + 0.000 166 645 834 573 369 641 079 993 236 088 72;
  • 4) 0.000 166 645 834 573 369 641 079 993 236 088 72 × 2 = 0 + 0.000 333 291 669 146 739 282 159 986 472 177 44;
  • 5) 0.000 333 291 669 146 739 282 159 986 472 177 44 × 2 = 0 + 0.000 666 583 338 293 478 564 319 972 944 354 88;
  • 6) 0.000 666 583 338 293 478 564 319 972 944 354 88 × 2 = 0 + 0.001 333 166 676 586 957 128 639 945 888 709 76;
  • 7) 0.001 333 166 676 586 957 128 639 945 888 709 76 × 2 = 0 + 0.002 666 333 353 173 914 257 279 891 777 419 52;
  • 8) 0.002 666 333 353 173 914 257 279 891 777 419 52 × 2 = 0 + 0.005 332 666 706 347 828 514 559 783 554 839 04;
  • 9) 0.005 332 666 706 347 828 514 559 783 554 839 04 × 2 = 0 + 0.010 665 333 412 695 657 029 119 567 109 678 08;
  • 10) 0.010 665 333 412 695 657 029 119 567 109 678 08 × 2 = 0 + 0.021 330 666 825 391 314 058 239 134 219 356 16;
  • 11) 0.021 330 666 825 391 314 058 239 134 219 356 16 × 2 = 0 + 0.042 661 333 650 782 628 116 478 268 438 712 32;
  • 12) 0.042 661 333 650 782 628 116 478 268 438 712 32 × 2 = 0 + 0.085 322 667 301 565 256 232 956 536 877 424 64;
  • 13) 0.085 322 667 301 565 256 232 956 536 877 424 64 × 2 = 0 + 0.170 645 334 603 130 512 465 913 073 754 849 28;
  • 14) 0.170 645 334 603 130 512 465 913 073 754 849 28 × 2 = 0 + 0.341 290 669 206 261 024 931 826 147 509 698 56;
  • 15) 0.341 290 669 206 261 024 931 826 147 509 698 56 × 2 = 0 + 0.682 581 338 412 522 049 863 652 295 019 397 12;
  • 16) 0.682 581 338 412 522 049 863 652 295 019 397 12 × 2 = 1 + 0.365 162 676 825 044 099 727 304 590 038 794 24;
  • 17) 0.365 162 676 825 044 099 727 304 590 038 794 24 × 2 = 0 + 0.730 325 353 650 088 199 454 609 180 077 588 48;
  • 18) 0.730 325 353 650 088 199 454 609 180 077 588 48 × 2 = 1 + 0.460 650 707 300 176 398 909 218 360 155 176 96;
  • 19) 0.460 650 707 300 176 398 909 218 360 155 176 96 × 2 = 0 + 0.921 301 414 600 352 797 818 436 720 310 353 92;
  • 20) 0.921 301 414 600 352 797 818 436 720 310 353 92 × 2 = 1 + 0.842 602 829 200 705 595 636 873 440 620 707 84;
  • 21) 0.842 602 829 200 705 595 636 873 440 620 707 84 × 2 = 1 + 0.685 205 658 401 411 191 273 746 881 241 415 68;
  • 22) 0.685 205 658 401 411 191 273 746 881 241 415 68 × 2 = 1 + 0.370 411 316 802 822 382 547 493 762 482 831 36;
  • 23) 0.370 411 316 802 822 382 547 493 762 482 831 36 × 2 = 0 + 0.740 822 633 605 644 765 094 987 524 965 662 72;
  • 24) 0.740 822 633 605 644 765 094 987 524 965 662 72 × 2 = 1 + 0.481 645 267 211 289 530 189 975 049 931 325 44;
  • 25) 0.481 645 267 211 289 530 189 975 049 931 325 44 × 2 = 0 + 0.963 290 534 422 579 060 379 950 099 862 650 88;
  • 26) 0.963 290 534 422 579 060 379 950 099 862 650 88 × 2 = 1 + 0.926 581 068 845 158 120 759 900 199 725 301 76;
  • 27) 0.926 581 068 845 158 120 759 900 199 725 301 76 × 2 = 1 + 0.853 162 137 690 316 241 519 800 399 450 603 52;
  • 28) 0.853 162 137 690 316 241 519 800 399 450 603 52 × 2 = 1 + 0.706 324 275 380 632 483 039 600 798 901 207 04;
  • 29) 0.706 324 275 380 632 483 039 600 798 901 207 04 × 2 = 1 + 0.412 648 550 761 264 966 079 201 597 802 414 08;
  • 30) 0.412 648 550 761 264 966 079 201 597 802 414 08 × 2 = 0 + 0.825 297 101 522 529 932 158 403 195 604 828 16;
  • 31) 0.825 297 101 522 529 932 158 403 195 604 828 16 × 2 = 1 + 0.650 594 203 045 059 864 316 806 391 209 656 32;
  • 32) 0.650 594 203 045 059 864 316 806 391 209 656 32 × 2 = 1 + 0.301 188 406 090 119 728 633 612 782 419 312 64;
  • 33) 0.301 188 406 090 119 728 633 612 782 419 312 64 × 2 = 0 + 0.602 376 812 180 239 457 267 225 564 838 625 28;
  • 34) 0.602 376 812 180 239 457 267 225 564 838 625 28 × 2 = 1 + 0.204 753 624 360 478 914 534 451 129 677 250 56;
  • 35) 0.204 753 624 360 478 914 534 451 129 677 250 56 × 2 = 0 + 0.409 507 248 720 957 829 068 902 259 354 501 12;
  • 36) 0.409 507 248 720 957 829 068 902 259 354 501 12 × 2 = 0 + 0.819 014 497 441 915 658 137 804 518 709 002 24;
  • 37) 0.819 014 497 441 915 658 137 804 518 709 002 24 × 2 = 1 + 0.638 028 994 883 831 316 275 609 037 418 004 48;
  • 38) 0.638 028 994 883 831 316 275 609 037 418 004 48 × 2 = 1 + 0.276 057 989 767 662 632 551 218 074 836 008 96;
  • 39) 0.276 057 989 767 662 632 551 218 074 836 008 96 × 2 = 0 + 0.552 115 979 535 325 265 102 436 149 672 017 92;
  • 40) 0.552 115 979 535 325 265 102 436 149 672 017 92 × 2 = 1 + 0.104 231 959 070 650 530 204 872 299 344 035 84;
  • 41) 0.104 231 959 070 650 530 204 872 299 344 035 84 × 2 = 0 + 0.208 463 918 141 301 060 409 744 598 688 071 68;
  • 42) 0.208 463 918 141 301 060 409 744 598 688 071 68 × 2 = 0 + 0.416 927 836 282 602 120 819 489 197 376 143 36;
  • 43) 0.416 927 836 282 602 120 819 489 197 376 143 36 × 2 = 0 + 0.833 855 672 565 204 241 638 978 394 752 286 72;
  • 44) 0.833 855 672 565 204 241 638 978 394 752 286 72 × 2 = 1 + 0.667 711 345 130 408 483 277 956 789 504 573 44;
  • 45) 0.667 711 345 130 408 483 277 956 789 504 573 44 × 2 = 1 + 0.335 422 690 260 816 966 555 913 579 009 146 88;
  • 46) 0.335 422 690 260 816 966 555 913 579 009 146 88 × 2 = 0 + 0.670 845 380 521 633 933 111 827 158 018 293 76;
  • 47) 0.670 845 380 521 633 933 111 827 158 018 293 76 × 2 = 1 + 0.341 690 761 043 267 866 223 654 316 036 587 52;
  • 48) 0.341 690 761 043 267 866 223 654 316 036 587 52 × 2 = 0 + 0.683 381 522 086 535 732 447 308 632 073 175 04;
  • 49) 0.683 381 522 086 535 732 447 308 632 073 175 04 × 2 = 1 + 0.366 763 044 173 071 464 894 617 264 146 350 08;
  • 50) 0.366 763 044 173 071 464 894 617 264 146 350 08 × 2 = 0 + 0.733 526 088 346 142 929 789 234 528 292 700 16;
  • 51) 0.733 526 088 346 142 929 789 234 528 292 700 16 × 2 = 1 + 0.467 052 176 692 285 859 578 469 056 585 400 32;
  • 52) 0.467 052 176 692 285 859 578 469 056 585 400 32 × 2 = 0 + 0.934 104 353 384 571 719 156 938 113 170 800 64;
  • 53) 0.934 104 353 384 571 719 156 938 113 170 800 64 × 2 = 1 + 0.868 208 706 769 143 438 313 876 226 341 601 28;
  • 54) 0.868 208 706 769 143 438 313 876 226 341 601 28 × 2 = 1 + 0.736 417 413 538 286 876 627 752 452 683 202 56;
  • 55) 0.736 417 413 538 286 876 627 752 452 683 202 56 × 2 = 1 + 0.472 834 827 076 573 753 255 504 905 366 405 12;
  • 56) 0.472 834 827 076 573 753 255 504 905 366 405 12 × 2 = 0 + 0.945 669 654 153 147 506 511 009 810 732 810 24;
  • 57) 0.945 669 654 153 147 506 511 009 810 732 810 24 × 2 = 1 + 0.891 339 308 306 295 013 022 019 621 465 620 48;
  • 58) 0.891 339 308 306 295 013 022 019 621 465 620 48 × 2 = 1 + 0.782 678 616 612 590 026 044 039 242 931 240 96;
  • 59) 0.782 678 616 612 590 026 044 039 242 931 240 96 × 2 = 1 + 0.565 357 233 225 180 052 088 078 485 862 481 92;
  • 60) 0.565 357 233 225 180 052 088 078 485 862 481 92 × 2 = 1 + 0.130 714 466 450 360 104 176 156 971 724 963 84;
  • 61) 0.130 714 466 450 360 104 176 156 971 724 963 84 × 2 = 0 + 0.261 428 932 900 720 208 352 313 943 449 927 68;
  • 62) 0.261 428 932 900 720 208 352 313 943 449 927 68 × 2 = 0 + 0.522 857 865 801 440 416 704 627 886 899 855 36;
  • 63) 0.522 857 865 801 440 416 704 627 886 899 855 36 × 2 = 1 + 0.045 715 731 602 880 833 409 255 773 799 710 72;
  • 64) 0.045 715 731 602 880 833 409 255 773 799 710 72 × 2 = 0 + 0.091 431 463 205 761 666 818 511 547 599 421 44;
  • 65) 0.091 431 463 205 761 666 818 511 547 599 421 44 × 2 = 0 + 0.182 862 926 411 523 333 637 023 095 198 842 88;
  • 66) 0.182 862 926 411 523 333 637 023 095 198 842 88 × 2 = 0 + 0.365 725 852 823 046 667 274 046 190 397 685 76;
  • 67) 0.365 725 852 823 046 667 274 046 190 397 685 76 × 2 = 0 + 0.731 451 705 646 093 334 548 092 380 795 371 52;
  • 68) 0.731 451 705 646 093 334 548 092 380 795 371 52 × 2 = 1 + 0.462 903 411 292 186 669 096 184 761 590 743 04;

We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit) and at least one integer that was different from zero => FULL STOP (Losing precision - the converted number we get in the end will be just a very good approximation of the initial one).


4. Construct the base 2 representation of the fractional part of the number.

Take all the integer parts of the multiplying operations, starting from the top of the constructed list above:


0.000 020 830 729 321 671 205 134 999 154 511 09(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2)

5. Positive number before normalization:

0.000 020 830 729 321 671 205 134 999 154 511 09(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2)

6. Normalize the binary representation of the number.

Shift the decimal mark 16 positions to the right, so that only one non zero digit remains to the left of it:


0.000 020 830 729 321 671 205 134 999 154 511 09(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) × 20 =

1.0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) × 2-16


7. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

Sign 0 (a positive number)

Exponent (unadjusted): -16

Mantissa (not normalized):
1.0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


8. Adjust the exponent.

Use the 11 bit excess/bias notation:


Exponent (adjusted) =

Exponent (unadjusted) + 2(11-1) - 1 =

-16 + 2(11-1) - 1 =

(-16 + 1 023)(10) =

1 007(10)


9. Convert the adjusted exponent from the decimal (base 10) to 11 bit binary.

Use the same technique of repeatedly dividing by 2:


  • division = quotient + remainder;
  • 1 007 ÷ 2 = 503 + 1;
  • 503 ÷ 2 = 251 + 1;
  • 251 ÷ 2 = 125 + 1;
  • 125 ÷ 2 = 62 + 1;
  • 62 ÷ 2 = 31 + 0;
  • 31 ÷ 2 = 15 + 1;
  • 15 ÷ 2 = 7 + 1;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

10. Construct the base 2 representation of the adjusted exponent.

Take all the remainders starting from the bottom of the list constructed above.


Exponent (adjusted) =

1007(10) =

011 1110 1111(2)


11. Normalize the mantissa.

a) Remove the leading (the leftmost) bit, since it's allways 1, and the decimal point, if the case.

b) Adjust its length to 52 bits, only if necessary (not the case here).


Mantissa (normalized) =

1. 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001 =

0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


12. The three elements that make up the number's 64 bit double precision IEEE 754 binary floating point representation:

Sign (1 bit) =
0 (a positive number)

Exponent (11 bits) =
011 1110 1111

Mantissa (52 bits) =
0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


Decimal number 0.000 020 830 729 321 671 205 134 999 154 511 09 converted to 64 bit double precision IEEE 754 binary floating point representation:

0 - 011 1110 1111 - 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001

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How to convert numbers from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point standard

Follow the steps below to convert a base 10 decimal number to 64 bit double precision IEEE 754 binary floating point:

  • 1. If the number to be converted is negative, start with its the positive version.
  • 2. First convert the integer part. Divide repeatedly by 2 the positive representation of the integer number that is to be converted to binary, until we get a quotient that is equal to zero, keeping track of each remainder.
  • 3. Construct the base 2 representation of the positive integer part of the number, by taking all the remainders from the previous operations, starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Then convert the fractional part. Multiply the number repeatedly by 2, until we get a fractional part that is equal to zero, keeping track of each integer part of the results.
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the multiplying operations, starting from the top of the list constructed above (they should appear in the binary representation, from left to right, in the order they have been calculated).
  • 6. Normalize the binary representation of the number, shifting the decimal mark (the decimal point) "n" positions either to the left, or to the right, so that only one non zero digit remains to the left of the decimal mark.
  • 7. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary, by using the same technique of repeatedly dividing by 2, as shown above:
    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1
  • 8. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal mark, if the case) and adjust its length to 52 bits, either by removing the excess bits from the right (losing precision...) or by adding extra bits set on '0' to the right.
  • 9. Sign (it takes 1 bit) is either 1 for a negative or 0 for a positive number.

Example: convert the negative number -31.640 215 from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point:

  • 1. Start with the positive version of the number:

    |-31.640 215| = 31.640 215

  • 2. First convert the integer part, 31. Divide it repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 31 ÷ 2 = 15 + 1;
    • 15 ÷ 2 = 7 + 1;
    • 7 ÷ 2 = 3 + 1;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
    • We have encountered a quotient that is ZERO => FULL STOP
  • 3. Construct the base 2 representation of the integer part of the number by taking all the remainders of the previous dividing operations, starting from the bottom of the list constructed above:

    31(10) = 1 1111(2)

  • 4. Then, convert the fractional part, 0.640 215. Multiply repeatedly by 2, keeping track of each integer part of the results, until we get a fractional part that is equal to zero:
    • #) multiplying = integer + fractional part;
    • 1) 0.640 215 × 2 = 1 + 0.280 43;
    • 2) 0.280 43 × 2 = 0 + 0.560 86;
    • 3) 0.560 86 × 2 = 1 + 0.121 72;
    • 4) 0.121 72 × 2 = 0 + 0.243 44;
    • 5) 0.243 44 × 2 = 0 + 0.486 88;
    • 6) 0.486 88 × 2 = 0 + 0.973 76;
    • 7) 0.973 76 × 2 = 1 + 0.947 52;
    • 8) 0.947 52 × 2 = 1 + 0.895 04;
    • 9) 0.895 04 × 2 = 1 + 0.790 08;
    • 10) 0.790 08 × 2 = 1 + 0.580 16;
    • 11) 0.580 16 × 2 = 1 + 0.160 32;
    • 12) 0.160 32 × 2 = 0 + 0.320 64;
    • 13) 0.320 64 × 2 = 0 + 0.641 28;
    • 14) 0.641 28 × 2 = 1 + 0.282 56;
    • 15) 0.282 56 × 2 = 0 + 0.565 12;
    • 16) 0.565 12 × 2 = 1 + 0.130 24;
    • 17) 0.130 24 × 2 = 0 + 0.260 48;
    • 18) 0.260 48 × 2 = 0 + 0.520 96;
    • 19) 0.520 96 × 2 = 1 + 0.041 92;
    • 20) 0.041 92 × 2 = 0 + 0.083 84;
    • 21) 0.083 84 × 2 = 0 + 0.167 68;
    • 22) 0.167 68 × 2 = 0 + 0.335 36;
    • 23) 0.335 36 × 2 = 0 + 0.670 72;
    • 24) 0.670 72 × 2 = 1 + 0.341 44;
    • 25) 0.341 44 × 2 = 0 + 0.682 88;
    • 26) 0.682 88 × 2 = 1 + 0.365 76;
    • 27) 0.365 76 × 2 = 0 + 0.731 52;
    • 28) 0.731 52 × 2 = 1 + 0.463 04;
    • 29) 0.463 04 × 2 = 0 + 0.926 08;
    • 30) 0.926 08 × 2 = 1 + 0.852 16;
    • 31) 0.852 16 × 2 = 1 + 0.704 32;
    • 32) 0.704 32 × 2 = 1 + 0.408 64;
    • 33) 0.408 64 × 2 = 0 + 0.817 28;
    • 34) 0.817 28 × 2 = 1 + 0.634 56;
    • 35) 0.634 56 × 2 = 1 + 0.269 12;
    • 36) 0.269 12 × 2 = 0 + 0.538 24;
    • 37) 0.538 24 × 2 = 1 + 0.076 48;
    • 38) 0.076 48 × 2 = 0 + 0.152 96;
    • 39) 0.152 96 × 2 = 0 + 0.305 92;
    • 40) 0.305 92 × 2 = 0 + 0.611 84;
    • 41) 0.611 84 × 2 = 1 + 0.223 68;
    • 42) 0.223 68 × 2 = 0 + 0.447 36;
    • 43) 0.447 36 × 2 = 0 + 0.894 72;
    • 44) 0.894 72 × 2 = 1 + 0.789 44;
    • 45) 0.789 44 × 2 = 1 + 0.578 88;
    • 46) 0.578 88 × 2 = 1 + 0.157 76;
    • 47) 0.157 76 × 2 = 0 + 0.315 52;
    • 48) 0.315 52 × 2 = 0 + 0.631 04;
    • 49) 0.631 04 × 2 = 1 + 0.262 08;
    • 50) 0.262 08 × 2 = 0 + 0.524 16;
    • 51) 0.524 16 × 2 = 1 + 0.048 32;
    • 52) 0.048 32 × 2 = 0 + 0.096 64;
    • 53) 0.096 64 × 2 = 0 + 0.193 28;
    • We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit = 52) and at least one integer part that was different from zero => FULL STOP (losing precision...).
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the previous multiplying operations, starting from the top of the constructed list above:

    0.640 215(10) = 0.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 6. Summarizing - the positive number before normalization:

    31.640 215(10) = 1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 7. Normalize the binary representation of the number, shifting the decimal mark 4 positions to the left so that only one non-zero digit stays to the left of the decimal mark:

    31.640 215(10) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 20 =
    1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 24

  • 8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

    Sign: 1 (a negative number)

    Exponent (unadjusted): 4

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

  • 9. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary (base 2), by using the same technique of repeatedly dividing it by 2, as shown above:

    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1 = (4 + 1023)(10) = 1027(10) =
    100 0000 0011(2)

  • 10. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal sign) and adjust its length to 52 bits, by removing the excess bits, from the right (losing precision...):

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

    Mantissa (normalized): 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Conclusion:

    Sign (1 bit) = 1 (a negative number)

    Exponent (8 bits) = 100 0000 0011

    Mantissa (52 bits) = 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Number -31.640 215, converted from decimal system (base 10) to 64 bit double precision IEEE 754 binary floating point =
    1 - 100 0000 0011 - 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100