0.000 020 830 729 321 671 205 134 999 154 509 660 628 5 Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard

Convert decimal 0.000 020 830 729 321 671 205 134 999 154 509 660 628 5(10) to 64 bit double precision IEEE 754 binary floating point representation standard (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

What are the steps to convert decimal number
0.000 020 830 729 321 671 205 134 999 154 509 660 628 5(10) to 64 bit double precision IEEE 754 binary floating point representation (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

1. First, convert to binary (in base 2) the integer part: 0.
Divide the number repeatedly by 2.

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 0 ÷ 2 = 0 + 0;

2. Construct the base 2 representation of the integer part of the number.

Take all the remainders starting from the bottom of the list constructed above.

0(10) =

0(2)


3. Convert to binary (base 2) the fractional part: 0.000 020 830 729 321 671 205 134 999 154 509 660 628 5.

Multiply it repeatedly by 2.

Keep track of each integer part of the results.

Stop when we get a fractional part that is equal to zero.


  • #) multiplying = integer + fractional part;
  • 1) 0.000 020 830 729 321 671 205 134 999 154 509 660 628 5 × 2 = 0 + 0.000 041 661 458 643 342 410 269 998 309 019 321 257;
  • 2) 0.000 041 661 458 643 342 410 269 998 309 019 321 257 × 2 = 0 + 0.000 083 322 917 286 684 820 539 996 618 038 642 514;
  • 3) 0.000 083 322 917 286 684 820 539 996 618 038 642 514 × 2 = 0 + 0.000 166 645 834 573 369 641 079 993 236 077 285 028;
  • 4) 0.000 166 645 834 573 369 641 079 993 236 077 285 028 × 2 = 0 + 0.000 333 291 669 146 739 282 159 986 472 154 570 056;
  • 5) 0.000 333 291 669 146 739 282 159 986 472 154 570 056 × 2 = 0 + 0.000 666 583 338 293 478 564 319 972 944 309 140 112;
  • 6) 0.000 666 583 338 293 478 564 319 972 944 309 140 112 × 2 = 0 + 0.001 333 166 676 586 957 128 639 945 888 618 280 224;
  • 7) 0.001 333 166 676 586 957 128 639 945 888 618 280 224 × 2 = 0 + 0.002 666 333 353 173 914 257 279 891 777 236 560 448;
  • 8) 0.002 666 333 353 173 914 257 279 891 777 236 560 448 × 2 = 0 + 0.005 332 666 706 347 828 514 559 783 554 473 120 896;
  • 9) 0.005 332 666 706 347 828 514 559 783 554 473 120 896 × 2 = 0 + 0.010 665 333 412 695 657 029 119 567 108 946 241 792;
  • 10) 0.010 665 333 412 695 657 029 119 567 108 946 241 792 × 2 = 0 + 0.021 330 666 825 391 314 058 239 134 217 892 483 584;
  • 11) 0.021 330 666 825 391 314 058 239 134 217 892 483 584 × 2 = 0 + 0.042 661 333 650 782 628 116 478 268 435 784 967 168;
  • 12) 0.042 661 333 650 782 628 116 478 268 435 784 967 168 × 2 = 0 + 0.085 322 667 301 565 256 232 956 536 871 569 934 336;
  • 13) 0.085 322 667 301 565 256 232 956 536 871 569 934 336 × 2 = 0 + 0.170 645 334 603 130 512 465 913 073 743 139 868 672;
  • 14) 0.170 645 334 603 130 512 465 913 073 743 139 868 672 × 2 = 0 + 0.341 290 669 206 261 024 931 826 147 486 279 737 344;
  • 15) 0.341 290 669 206 261 024 931 826 147 486 279 737 344 × 2 = 0 + 0.682 581 338 412 522 049 863 652 294 972 559 474 688;
  • 16) 0.682 581 338 412 522 049 863 652 294 972 559 474 688 × 2 = 1 + 0.365 162 676 825 044 099 727 304 589 945 118 949 376;
  • 17) 0.365 162 676 825 044 099 727 304 589 945 118 949 376 × 2 = 0 + 0.730 325 353 650 088 199 454 609 179 890 237 898 752;
  • 18) 0.730 325 353 650 088 199 454 609 179 890 237 898 752 × 2 = 1 + 0.460 650 707 300 176 398 909 218 359 780 475 797 504;
  • 19) 0.460 650 707 300 176 398 909 218 359 780 475 797 504 × 2 = 0 + 0.921 301 414 600 352 797 818 436 719 560 951 595 008;
  • 20) 0.921 301 414 600 352 797 818 436 719 560 951 595 008 × 2 = 1 + 0.842 602 829 200 705 595 636 873 439 121 903 190 016;
  • 21) 0.842 602 829 200 705 595 636 873 439 121 903 190 016 × 2 = 1 + 0.685 205 658 401 411 191 273 746 878 243 806 380 032;
  • 22) 0.685 205 658 401 411 191 273 746 878 243 806 380 032 × 2 = 1 + 0.370 411 316 802 822 382 547 493 756 487 612 760 064;
  • 23) 0.370 411 316 802 822 382 547 493 756 487 612 760 064 × 2 = 0 + 0.740 822 633 605 644 765 094 987 512 975 225 520 128;
  • 24) 0.740 822 633 605 644 765 094 987 512 975 225 520 128 × 2 = 1 + 0.481 645 267 211 289 530 189 975 025 950 451 040 256;
  • 25) 0.481 645 267 211 289 530 189 975 025 950 451 040 256 × 2 = 0 + 0.963 290 534 422 579 060 379 950 051 900 902 080 512;
  • 26) 0.963 290 534 422 579 060 379 950 051 900 902 080 512 × 2 = 1 + 0.926 581 068 845 158 120 759 900 103 801 804 161 024;
  • 27) 0.926 581 068 845 158 120 759 900 103 801 804 161 024 × 2 = 1 + 0.853 162 137 690 316 241 519 800 207 603 608 322 048;
  • 28) 0.853 162 137 690 316 241 519 800 207 603 608 322 048 × 2 = 1 + 0.706 324 275 380 632 483 039 600 415 207 216 644 096;
  • 29) 0.706 324 275 380 632 483 039 600 415 207 216 644 096 × 2 = 1 + 0.412 648 550 761 264 966 079 200 830 414 433 288 192;
  • 30) 0.412 648 550 761 264 966 079 200 830 414 433 288 192 × 2 = 0 + 0.825 297 101 522 529 932 158 401 660 828 866 576 384;
  • 31) 0.825 297 101 522 529 932 158 401 660 828 866 576 384 × 2 = 1 + 0.650 594 203 045 059 864 316 803 321 657 733 152 768;
  • 32) 0.650 594 203 045 059 864 316 803 321 657 733 152 768 × 2 = 1 + 0.301 188 406 090 119 728 633 606 643 315 466 305 536;
  • 33) 0.301 188 406 090 119 728 633 606 643 315 466 305 536 × 2 = 0 + 0.602 376 812 180 239 457 267 213 286 630 932 611 072;
  • 34) 0.602 376 812 180 239 457 267 213 286 630 932 611 072 × 2 = 1 + 0.204 753 624 360 478 914 534 426 573 261 865 222 144;
  • 35) 0.204 753 624 360 478 914 534 426 573 261 865 222 144 × 2 = 0 + 0.409 507 248 720 957 829 068 853 146 523 730 444 288;
  • 36) 0.409 507 248 720 957 829 068 853 146 523 730 444 288 × 2 = 0 + 0.819 014 497 441 915 658 137 706 293 047 460 888 576;
  • 37) 0.819 014 497 441 915 658 137 706 293 047 460 888 576 × 2 = 1 + 0.638 028 994 883 831 316 275 412 586 094 921 777 152;
  • 38) 0.638 028 994 883 831 316 275 412 586 094 921 777 152 × 2 = 1 + 0.276 057 989 767 662 632 550 825 172 189 843 554 304;
  • 39) 0.276 057 989 767 662 632 550 825 172 189 843 554 304 × 2 = 0 + 0.552 115 979 535 325 265 101 650 344 379 687 108 608;
  • 40) 0.552 115 979 535 325 265 101 650 344 379 687 108 608 × 2 = 1 + 0.104 231 959 070 650 530 203 300 688 759 374 217 216;
  • 41) 0.104 231 959 070 650 530 203 300 688 759 374 217 216 × 2 = 0 + 0.208 463 918 141 301 060 406 601 377 518 748 434 432;
  • 42) 0.208 463 918 141 301 060 406 601 377 518 748 434 432 × 2 = 0 + 0.416 927 836 282 602 120 813 202 755 037 496 868 864;
  • 43) 0.416 927 836 282 602 120 813 202 755 037 496 868 864 × 2 = 0 + 0.833 855 672 565 204 241 626 405 510 074 993 737 728;
  • 44) 0.833 855 672 565 204 241 626 405 510 074 993 737 728 × 2 = 1 + 0.667 711 345 130 408 483 252 811 020 149 987 475 456;
  • 45) 0.667 711 345 130 408 483 252 811 020 149 987 475 456 × 2 = 1 + 0.335 422 690 260 816 966 505 622 040 299 974 950 912;
  • 46) 0.335 422 690 260 816 966 505 622 040 299 974 950 912 × 2 = 0 + 0.670 845 380 521 633 933 011 244 080 599 949 901 824;
  • 47) 0.670 845 380 521 633 933 011 244 080 599 949 901 824 × 2 = 1 + 0.341 690 761 043 267 866 022 488 161 199 899 803 648;
  • 48) 0.341 690 761 043 267 866 022 488 161 199 899 803 648 × 2 = 0 + 0.683 381 522 086 535 732 044 976 322 399 799 607 296;
  • 49) 0.683 381 522 086 535 732 044 976 322 399 799 607 296 × 2 = 1 + 0.366 763 044 173 071 464 089 952 644 799 599 214 592;
  • 50) 0.366 763 044 173 071 464 089 952 644 799 599 214 592 × 2 = 0 + 0.733 526 088 346 142 928 179 905 289 599 198 429 184;
  • 51) 0.733 526 088 346 142 928 179 905 289 599 198 429 184 × 2 = 1 + 0.467 052 176 692 285 856 359 810 579 198 396 858 368;
  • 52) 0.467 052 176 692 285 856 359 810 579 198 396 858 368 × 2 = 0 + 0.934 104 353 384 571 712 719 621 158 396 793 716 736;
  • 53) 0.934 104 353 384 571 712 719 621 158 396 793 716 736 × 2 = 1 + 0.868 208 706 769 143 425 439 242 316 793 587 433 472;
  • 54) 0.868 208 706 769 143 425 439 242 316 793 587 433 472 × 2 = 1 + 0.736 417 413 538 286 850 878 484 633 587 174 866 944;
  • 55) 0.736 417 413 538 286 850 878 484 633 587 174 866 944 × 2 = 1 + 0.472 834 827 076 573 701 756 969 267 174 349 733 888;
  • 56) 0.472 834 827 076 573 701 756 969 267 174 349 733 888 × 2 = 0 + 0.945 669 654 153 147 403 513 938 534 348 699 467 776;
  • 57) 0.945 669 654 153 147 403 513 938 534 348 699 467 776 × 2 = 1 + 0.891 339 308 306 294 807 027 877 068 697 398 935 552;
  • 58) 0.891 339 308 306 294 807 027 877 068 697 398 935 552 × 2 = 1 + 0.782 678 616 612 589 614 055 754 137 394 797 871 104;
  • 59) 0.782 678 616 612 589 614 055 754 137 394 797 871 104 × 2 = 1 + 0.565 357 233 225 179 228 111 508 274 789 595 742 208;
  • 60) 0.565 357 233 225 179 228 111 508 274 789 595 742 208 × 2 = 1 + 0.130 714 466 450 358 456 223 016 549 579 191 484 416;
  • 61) 0.130 714 466 450 358 456 223 016 549 579 191 484 416 × 2 = 0 + 0.261 428 932 900 716 912 446 033 099 158 382 968 832;
  • 62) 0.261 428 932 900 716 912 446 033 099 158 382 968 832 × 2 = 0 + 0.522 857 865 801 433 824 892 066 198 316 765 937 664;
  • 63) 0.522 857 865 801 433 824 892 066 198 316 765 937 664 × 2 = 1 + 0.045 715 731 602 867 649 784 132 396 633 531 875 328;
  • 64) 0.045 715 731 602 867 649 784 132 396 633 531 875 328 × 2 = 0 + 0.091 431 463 205 735 299 568 264 793 267 063 750 656;
  • 65) 0.091 431 463 205 735 299 568 264 793 267 063 750 656 × 2 = 0 + 0.182 862 926 411 470 599 136 529 586 534 127 501 312;
  • 66) 0.182 862 926 411 470 599 136 529 586 534 127 501 312 × 2 = 0 + 0.365 725 852 822 941 198 273 059 173 068 255 002 624;
  • 67) 0.365 725 852 822 941 198 273 059 173 068 255 002 624 × 2 = 0 + 0.731 451 705 645 882 396 546 118 346 136 510 005 248;
  • 68) 0.731 451 705 645 882 396 546 118 346 136 510 005 248 × 2 = 1 + 0.462 903 411 291 764 793 092 236 692 273 020 010 496;

We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit) and at least one integer that was different from zero => FULL STOP (Losing precision - the converted number we get in the end will be just a very good approximation of the initial one).


4. Construct the base 2 representation of the fractional part of the number.

Take all the integer parts of the multiplying operations, starting from the top of the constructed list above:


0.000 020 830 729 321 671 205 134 999 154 509 660 628 5(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2)

5. Positive number before normalization:

0.000 020 830 729 321 671 205 134 999 154 509 660 628 5(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2)

6. Normalize the binary representation of the number.

Shift the decimal mark 16 positions to the right, so that only one non zero digit remains to the left of it:


0.000 020 830 729 321 671 205 134 999 154 509 660 628 5(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) × 20 =

1.0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) × 2-16


7. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

Sign 0 (a positive number)

Exponent (unadjusted): -16

Mantissa (not normalized):
1.0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


8. Adjust the exponent.

Use the 11 bit excess/bias notation:


Exponent (adjusted) =

Exponent (unadjusted) + 2(11-1) - 1 =

-16 + 2(11-1) - 1 =

(-16 + 1 023)(10) =

1 007(10)


9. Convert the adjusted exponent from the decimal (base 10) to 11 bit binary.

Use the same technique of repeatedly dividing by 2:


  • division = quotient + remainder;
  • 1 007 ÷ 2 = 503 + 1;
  • 503 ÷ 2 = 251 + 1;
  • 251 ÷ 2 = 125 + 1;
  • 125 ÷ 2 = 62 + 1;
  • 62 ÷ 2 = 31 + 0;
  • 31 ÷ 2 = 15 + 1;
  • 15 ÷ 2 = 7 + 1;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

10. Construct the base 2 representation of the adjusted exponent.

Take all the remainders starting from the bottom of the list constructed above.


Exponent (adjusted) =

1007(10) =

011 1110 1111(2)


11. Normalize the mantissa.

a) Remove the leading (the leftmost) bit, since it's allways 1, and the decimal point, if the case.

b) Adjust its length to 52 bits, only if necessary (not the case here).


Mantissa (normalized) =

1. 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001 =

0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


12. The three elements that make up the number's 64 bit double precision IEEE 754 binary floating point representation:

Sign (1 bit) =
0 (a positive number)

Exponent (11 bits) =
011 1110 1111

Mantissa (52 bits) =
0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


Decimal number 0.000 020 830 729 321 671 205 134 999 154 509 660 628 5 converted to 64 bit double precision IEEE 754 binary floating point representation:

0 - 011 1110 1111 - 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001

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How to convert numbers from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point standard

Follow the steps below to convert a base 10 decimal number to 64 bit double precision IEEE 754 binary floating point:

  • 1. If the number to be converted is negative, start with its the positive version.
  • 2. First convert the integer part. Divide repeatedly by 2 the positive representation of the integer number that is to be converted to binary, until we get a quotient that is equal to zero, keeping track of each remainder.
  • 3. Construct the base 2 representation of the positive integer part of the number, by taking all the remainders from the previous operations, starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Then convert the fractional part. Multiply the number repeatedly by 2, until we get a fractional part that is equal to zero, keeping track of each integer part of the results.
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the multiplying operations, starting from the top of the list constructed above (they should appear in the binary representation, from left to right, in the order they have been calculated).
  • 6. Normalize the binary representation of the number, shifting the decimal mark (the decimal point) "n" positions either to the left, or to the right, so that only one non zero digit remains to the left of the decimal mark.
  • 7. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary, by using the same technique of repeatedly dividing by 2, as shown above:
    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1
  • 8. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal mark, if the case) and adjust its length to 52 bits, either by removing the excess bits from the right (losing precision...) or by adding extra bits set on '0' to the right.
  • 9. Sign (it takes 1 bit) is either 1 for a negative or 0 for a positive number.

Example: convert the negative number -31.640 215 from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point:

  • 1. Start with the positive version of the number:

    |-31.640 215| = 31.640 215

  • 2. First convert the integer part, 31. Divide it repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 31 ÷ 2 = 15 + 1;
    • 15 ÷ 2 = 7 + 1;
    • 7 ÷ 2 = 3 + 1;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
    • We have encountered a quotient that is ZERO => FULL STOP
  • 3. Construct the base 2 representation of the integer part of the number by taking all the remainders of the previous dividing operations, starting from the bottom of the list constructed above:

    31(10) = 1 1111(2)

  • 4. Then, convert the fractional part, 0.640 215. Multiply repeatedly by 2, keeping track of each integer part of the results, until we get a fractional part that is equal to zero:
    • #) multiplying = integer + fractional part;
    • 1) 0.640 215 × 2 = 1 + 0.280 43;
    • 2) 0.280 43 × 2 = 0 + 0.560 86;
    • 3) 0.560 86 × 2 = 1 + 0.121 72;
    • 4) 0.121 72 × 2 = 0 + 0.243 44;
    • 5) 0.243 44 × 2 = 0 + 0.486 88;
    • 6) 0.486 88 × 2 = 0 + 0.973 76;
    • 7) 0.973 76 × 2 = 1 + 0.947 52;
    • 8) 0.947 52 × 2 = 1 + 0.895 04;
    • 9) 0.895 04 × 2 = 1 + 0.790 08;
    • 10) 0.790 08 × 2 = 1 + 0.580 16;
    • 11) 0.580 16 × 2 = 1 + 0.160 32;
    • 12) 0.160 32 × 2 = 0 + 0.320 64;
    • 13) 0.320 64 × 2 = 0 + 0.641 28;
    • 14) 0.641 28 × 2 = 1 + 0.282 56;
    • 15) 0.282 56 × 2 = 0 + 0.565 12;
    • 16) 0.565 12 × 2 = 1 + 0.130 24;
    • 17) 0.130 24 × 2 = 0 + 0.260 48;
    • 18) 0.260 48 × 2 = 0 + 0.520 96;
    • 19) 0.520 96 × 2 = 1 + 0.041 92;
    • 20) 0.041 92 × 2 = 0 + 0.083 84;
    • 21) 0.083 84 × 2 = 0 + 0.167 68;
    • 22) 0.167 68 × 2 = 0 + 0.335 36;
    • 23) 0.335 36 × 2 = 0 + 0.670 72;
    • 24) 0.670 72 × 2 = 1 + 0.341 44;
    • 25) 0.341 44 × 2 = 0 + 0.682 88;
    • 26) 0.682 88 × 2 = 1 + 0.365 76;
    • 27) 0.365 76 × 2 = 0 + 0.731 52;
    • 28) 0.731 52 × 2 = 1 + 0.463 04;
    • 29) 0.463 04 × 2 = 0 + 0.926 08;
    • 30) 0.926 08 × 2 = 1 + 0.852 16;
    • 31) 0.852 16 × 2 = 1 + 0.704 32;
    • 32) 0.704 32 × 2 = 1 + 0.408 64;
    • 33) 0.408 64 × 2 = 0 + 0.817 28;
    • 34) 0.817 28 × 2 = 1 + 0.634 56;
    • 35) 0.634 56 × 2 = 1 + 0.269 12;
    • 36) 0.269 12 × 2 = 0 + 0.538 24;
    • 37) 0.538 24 × 2 = 1 + 0.076 48;
    • 38) 0.076 48 × 2 = 0 + 0.152 96;
    • 39) 0.152 96 × 2 = 0 + 0.305 92;
    • 40) 0.305 92 × 2 = 0 + 0.611 84;
    • 41) 0.611 84 × 2 = 1 + 0.223 68;
    • 42) 0.223 68 × 2 = 0 + 0.447 36;
    • 43) 0.447 36 × 2 = 0 + 0.894 72;
    • 44) 0.894 72 × 2 = 1 + 0.789 44;
    • 45) 0.789 44 × 2 = 1 + 0.578 88;
    • 46) 0.578 88 × 2 = 1 + 0.157 76;
    • 47) 0.157 76 × 2 = 0 + 0.315 52;
    • 48) 0.315 52 × 2 = 0 + 0.631 04;
    • 49) 0.631 04 × 2 = 1 + 0.262 08;
    • 50) 0.262 08 × 2 = 0 + 0.524 16;
    • 51) 0.524 16 × 2 = 1 + 0.048 32;
    • 52) 0.048 32 × 2 = 0 + 0.096 64;
    • 53) 0.096 64 × 2 = 0 + 0.193 28;
    • We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit = 52) and at least one integer part that was different from zero => FULL STOP (losing precision...).
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the previous multiplying operations, starting from the top of the constructed list above:

    0.640 215(10) = 0.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 6. Summarizing - the positive number before normalization:

    31.640 215(10) = 1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 7. Normalize the binary representation of the number, shifting the decimal mark 4 positions to the left so that only one non-zero digit stays to the left of the decimal mark:

    31.640 215(10) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 20 =
    1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 24

  • 8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

    Sign: 1 (a negative number)

    Exponent (unadjusted): 4

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

  • 9. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary (base 2), by using the same technique of repeatedly dividing it by 2, as shown above:

    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1 = (4 + 1023)(10) = 1027(10) =
    100 0000 0011(2)

  • 10. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal sign) and adjust its length to 52 bits, by removing the excess bits, from the right (losing precision...):

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

    Mantissa (normalized): 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Conclusion:

    Sign (1 bit) = 1 (a negative number)

    Exponent (8 bits) = 100 0000 0011

    Mantissa (52 bits) = 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Number -31.640 215, converted from decimal system (base 10) to 64 bit double precision IEEE 754 binary floating point =
    1 - 100 0000 0011 - 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100