0.000 020 830 729 321 671 205 134 999 154 509 660 621 3 Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard

Convert decimal 0.000 020 830 729 321 671 205 134 999 154 509 660 621 3(10) to 64 bit double precision IEEE 754 binary floating point representation standard (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

What are the steps to convert decimal number
0.000 020 830 729 321 671 205 134 999 154 509 660 621 3(10) to 64 bit double precision IEEE 754 binary floating point representation (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

1. First, convert to binary (in base 2) the integer part: 0.
Divide the number repeatedly by 2.

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 0 ÷ 2 = 0 + 0;

2. Construct the base 2 representation of the integer part of the number.

Take all the remainders starting from the bottom of the list constructed above.

0(10) =

0(2)


3. Convert to binary (base 2) the fractional part: 0.000 020 830 729 321 671 205 134 999 154 509 660 621 3.

Multiply it repeatedly by 2.

Keep track of each integer part of the results.

Stop when we get a fractional part that is equal to zero.


  • #) multiplying = integer + fractional part;
  • 1) 0.000 020 830 729 321 671 205 134 999 154 509 660 621 3 × 2 = 0 + 0.000 041 661 458 643 342 410 269 998 309 019 321 242 6;
  • 2) 0.000 041 661 458 643 342 410 269 998 309 019 321 242 6 × 2 = 0 + 0.000 083 322 917 286 684 820 539 996 618 038 642 485 2;
  • 3) 0.000 083 322 917 286 684 820 539 996 618 038 642 485 2 × 2 = 0 + 0.000 166 645 834 573 369 641 079 993 236 077 284 970 4;
  • 4) 0.000 166 645 834 573 369 641 079 993 236 077 284 970 4 × 2 = 0 + 0.000 333 291 669 146 739 282 159 986 472 154 569 940 8;
  • 5) 0.000 333 291 669 146 739 282 159 986 472 154 569 940 8 × 2 = 0 + 0.000 666 583 338 293 478 564 319 972 944 309 139 881 6;
  • 6) 0.000 666 583 338 293 478 564 319 972 944 309 139 881 6 × 2 = 0 + 0.001 333 166 676 586 957 128 639 945 888 618 279 763 2;
  • 7) 0.001 333 166 676 586 957 128 639 945 888 618 279 763 2 × 2 = 0 + 0.002 666 333 353 173 914 257 279 891 777 236 559 526 4;
  • 8) 0.002 666 333 353 173 914 257 279 891 777 236 559 526 4 × 2 = 0 + 0.005 332 666 706 347 828 514 559 783 554 473 119 052 8;
  • 9) 0.005 332 666 706 347 828 514 559 783 554 473 119 052 8 × 2 = 0 + 0.010 665 333 412 695 657 029 119 567 108 946 238 105 6;
  • 10) 0.010 665 333 412 695 657 029 119 567 108 946 238 105 6 × 2 = 0 + 0.021 330 666 825 391 314 058 239 134 217 892 476 211 2;
  • 11) 0.021 330 666 825 391 314 058 239 134 217 892 476 211 2 × 2 = 0 + 0.042 661 333 650 782 628 116 478 268 435 784 952 422 4;
  • 12) 0.042 661 333 650 782 628 116 478 268 435 784 952 422 4 × 2 = 0 + 0.085 322 667 301 565 256 232 956 536 871 569 904 844 8;
  • 13) 0.085 322 667 301 565 256 232 956 536 871 569 904 844 8 × 2 = 0 + 0.170 645 334 603 130 512 465 913 073 743 139 809 689 6;
  • 14) 0.170 645 334 603 130 512 465 913 073 743 139 809 689 6 × 2 = 0 + 0.341 290 669 206 261 024 931 826 147 486 279 619 379 2;
  • 15) 0.341 290 669 206 261 024 931 826 147 486 279 619 379 2 × 2 = 0 + 0.682 581 338 412 522 049 863 652 294 972 559 238 758 4;
  • 16) 0.682 581 338 412 522 049 863 652 294 972 559 238 758 4 × 2 = 1 + 0.365 162 676 825 044 099 727 304 589 945 118 477 516 8;
  • 17) 0.365 162 676 825 044 099 727 304 589 945 118 477 516 8 × 2 = 0 + 0.730 325 353 650 088 199 454 609 179 890 236 955 033 6;
  • 18) 0.730 325 353 650 088 199 454 609 179 890 236 955 033 6 × 2 = 1 + 0.460 650 707 300 176 398 909 218 359 780 473 910 067 2;
  • 19) 0.460 650 707 300 176 398 909 218 359 780 473 910 067 2 × 2 = 0 + 0.921 301 414 600 352 797 818 436 719 560 947 820 134 4;
  • 20) 0.921 301 414 600 352 797 818 436 719 560 947 820 134 4 × 2 = 1 + 0.842 602 829 200 705 595 636 873 439 121 895 640 268 8;
  • 21) 0.842 602 829 200 705 595 636 873 439 121 895 640 268 8 × 2 = 1 + 0.685 205 658 401 411 191 273 746 878 243 791 280 537 6;
  • 22) 0.685 205 658 401 411 191 273 746 878 243 791 280 537 6 × 2 = 1 + 0.370 411 316 802 822 382 547 493 756 487 582 561 075 2;
  • 23) 0.370 411 316 802 822 382 547 493 756 487 582 561 075 2 × 2 = 0 + 0.740 822 633 605 644 765 094 987 512 975 165 122 150 4;
  • 24) 0.740 822 633 605 644 765 094 987 512 975 165 122 150 4 × 2 = 1 + 0.481 645 267 211 289 530 189 975 025 950 330 244 300 8;
  • 25) 0.481 645 267 211 289 530 189 975 025 950 330 244 300 8 × 2 = 0 + 0.963 290 534 422 579 060 379 950 051 900 660 488 601 6;
  • 26) 0.963 290 534 422 579 060 379 950 051 900 660 488 601 6 × 2 = 1 + 0.926 581 068 845 158 120 759 900 103 801 320 977 203 2;
  • 27) 0.926 581 068 845 158 120 759 900 103 801 320 977 203 2 × 2 = 1 + 0.853 162 137 690 316 241 519 800 207 602 641 954 406 4;
  • 28) 0.853 162 137 690 316 241 519 800 207 602 641 954 406 4 × 2 = 1 + 0.706 324 275 380 632 483 039 600 415 205 283 908 812 8;
  • 29) 0.706 324 275 380 632 483 039 600 415 205 283 908 812 8 × 2 = 1 + 0.412 648 550 761 264 966 079 200 830 410 567 817 625 6;
  • 30) 0.412 648 550 761 264 966 079 200 830 410 567 817 625 6 × 2 = 0 + 0.825 297 101 522 529 932 158 401 660 821 135 635 251 2;
  • 31) 0.825 297 101 522 529 932 158 401 660 821 135 635 251 2 × 2 = 1 + 0.650 594 203 045 059 864 316 803 321 642 271 270 502 4;
  • 32) 0.650 594 203 045 059 864 316 803 321 642 271 270 502 4 × 2 = 1 + 0.301 188 406 090 119 728 633 606 643 284 542 541 004 8;
  • 33) 0.301 188 406 090 119 728 633 606 643 284 542 541 004 8 × 2 = 0 + 0.602 376 812 180 239 457 267 213 286 569 085 082 009 6;
  • 34) 0.602 376 812 180 239 457 267 213 286 569 085 082 009 6 × 2 = 1 + 0.204 753 624 360 478 914 534 426 573 138 170 164 019 2;
  • 35) 0.204 753 624 360 478 914 534 426 573 138 170 164 019 2 × 2 = 0 + 0.409 507 248 720 957 829 068 853 146 276 340 328 038 4;
  • 36) 0.409 507 248 720 957 829 068 853 146 276 340 328 038 4 × 2 = 0 + 0.819 014 497 441 915 658 137 706 292 552 680 656 076 8;
  • 37) 0.819 014 497 441 915 658 137 706 292 552 680 656 076 8 × 2 = 1 + 0.638 028 994 883 831 316 275 412 585 105 361 312 153 6;
  • 38) 0.638 028 994 883 831 316 275 412 585 105 361 312 153 6 × 2 = 1 + 0.276 057 989 767 662 632 550 825 170 210 722 624 307 2;
  • 39) 0.276 057 989 767 662 632 550 825 170 210 722 624 307 2 × 2 = 0 + 0.552 115 979 535 325 265 101 650 340 421 445 248 614 4;
  • 40) 0.552 115 979 535 325 265 101 650 340 421 445 248 614 4 × 2 = 1 + 0.104 231 959 070 650 530 203 300 680 842 890 497 228 8;
  • 41) 0.104 231 959 070 650 530 203 300 680 842 890 497 228 8 × 2 = 0 + 0.208 463 918 141 301 060 406 601 361 685 780 994 457 6;
  • 42) 0.208 463 918 141 301 060 406 601 361 685 780 994 457 6 × 2 = 0 + 0.416 927 836 282 602 120 813 202 723 371 561 988 915 2;
  • 43) 0.416 927 836 282 602 120 813 202 723 371 561 988 915 2 × 2 = 0 + 0.833 855 672 565 204 241 626 405 446 743 123 977 830 4;
  • 44) 0.833 855 672 565 204 241 626 405 446 743 123 977 830 4 × 2 = 1 + 0.667 711 345 130 408 483 252 810 893 486 247 955 660 8;
  • 45) 0.667 711 345 130 408 483 252 810 893 486 247 955 660 8 × 2 = 1 + 0.335 422 690 260 816 966 505 621 786 972 495 911 321 6;
  • 46) 0.335 422 690 260 816 966 505 621 786 972 495 911 321 6 × 2 = 0 + 0.670 845 380 521 633 933 011 243 573 944 991 822 643 2;
  • 47) 0.670 845 380 521 633 933 011 243 573 944 991 822 643 2 × 2 = 1 + 0.341 690 761 043 267 866 022 487 147 889 983 645 286 4;
  • 48) 0.341 690 761 043 267 866 022 487 147 889 983 645 286 4 × 2 = 0 + 0.683 381 522 086 535 732 044 974 295 779 967 290 572 8;
  • 49) 0.683 381 522 086 535 732 044 974 295 779 967 290 572 8 × 2 = 1 + 0.366 763 044 173 071 464 089 948 591 559 934 581 145 6;
  • 50) 0.366 763 044 173 071 464 089 948 591 559 934 581 145 6 × 2 = 0 + 0.733 526 088 346 142 928 179 897 183 119 869 162 291 2;
  • 51) 0.733 526 088 346 142 928 179 897 183 119 869 162 291 2 × 2 = 1 + 0.467 052 176 692 285 856 359 794 366 239 738 324 582 4;
  • 52) 0.467 052 176 692 285 856 359 794 366 239 738 324 582 4 × 2 = 0 + 0.934 104 353 384 571 712 719 588 732 479 476 649 164 8;
  • 53) 0.934 104 353 384 571 712 719 588 732 479 476 649 164 8 × 2 = 1 + 0.868 208 706 769 143 425 439 177 464 958 953 298 329 6;
  • 54) 0.868 208 706 769 143 425 439 177 464 958 953 298 329 6 × 2 = 1 + 0.736 417 413 538 286 850 878 354 929 917 906 596 659 2;
  • 55) 0.736 417 413 538 286 850 878 354 929 917 906 596 659 2 × 2 = 1 + 0.472 834 827 076 573 701 756 709 859 835 813 193 318 4;
  • 56) 0.472 834 827 076 573 701 756 709 859 835 813 193 318 4 × 2 = 0 + 0.945 669 654 153 147 403 513 419 719 671 626 386 636 8;
  • 57) 0.945 669 654 153 147 403 513 419 719 671 626 386 636 8 × 2 = 1 + 0.891 339 308 306 294 807 026 839 439 343 252 773 273 6;
  • 58) 0.891 339 308 306 294 807 026 839 439 343 252 773 273 6 × 2 = 1 + 0.782 678 616 612 589 614 053 678 878 686 505 546 547 2;
  • 59) 0.782 678 616 612 589 614 053 678 878 686 505 546 547 2 × 2 = 1 + 0.565 357 233 225 179 228 107 357 757 373 011 093 094 4;
  • 60) 0.565 357 233 225 179 228 107 357 757 373 011 093 094 4 × 2 = 1 + 0.130 714 466 450 358 456 214 715 514 746 022 186 188 8;
  • 61) 0.130 714 466 450 358 456 214 715 514 746 022 186 188 8 × 2 = 0 + 0.261 428 932 900 716 912 429 431 029 492 044 372 377 6;
  • 62) 0.261 428 932 900 716 912 429 431 029 492 044 372 377 6 × 2 = 0 + 0.522 857 865 801 433 824 858 862 058 984 088 744 755 2;
  • 63) 0.522 857 865 801 433 824 858 862 058 984 088 744 755 2 × 2 = 1 + 0.045 715 731 602 867 649 717 724 117 968 177 489 510 4;
  • 64) 0.045 715 731 602 867 649 717 724 117 968 177 489 510 4 × 2 = 0 + 0.091 431 463 205 735 299 435 448 235 936 354 979 020 8;
  • 65) 0.091 431 463 205 735 299 435 448 235 936 354 979 020 8 × 2 = 0 + 0.182 862 926 411 470 598 870 896 471 872 709 958 041 6;
  • 66) 0.182 862 926 411 470 598 870 896 471 872 709 958 041 6 × 2 = 0 + 0.365 725 852 822 941 197 741 792 943 745 419 916 083 2;
  • 67) 0.365 725 852 822 941 197 741 792 943 745 419 916 083 2 × 2 = 0 + 0.731 451 705 645 882 395 483 585 887 490 839 832 166 4;
  • 68) 0.731 451 705 645 882 395 483 585 887 490 839 832 166 4 × 2 = 1 + 0.462 903 411 291 764 790 967 171 774 981 679 664 332 8;

We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit) and at least one integer that was different from zero => FULL STOP (Losing precision - the converted number we get in the end will be just a very good approximation of the initial one).


4. Construct the base 2 representation of the fractional part of the number.

Take all the integer parts of the multiplying operations, starting from the top of the constructed list above:


0.000 020 830 729 321 671 205 134 999 154 509 660 621 3(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2)

5. Positive number before normalization:

0.000 020 830 729 321 671 205 134 999 154 509 660 621 3(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2)

6. Normalize the binary representation of the number.

Shift the decimal mark 16 positions to the right, so that only one non zero digit remains to the left of it:


0.000 020 830 729 321 671 205 134 999 154 509 660 621 3(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) × 20 =

1.0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) × 2-16


7. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

Sign 0 (a positive number)

Exponent (unadjusted): -16

Mantissa (not normalized):
1.0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


8. Adjust the exponent.

Use the 11 bit excess/bias notation:


Exponent (adjusted) =

Exponent (unadjusted) + 2(11-1) - 1 =

-16 + 2(11-1) - 1 =

(-16 + 1 023)(10) =

1 007(10)


9. Convert the adjusted exponent from the decimal (base 10) to 11 bit binary.

Use the same technique of repeatedly dividing by 2:


  • division = quotient + remainder;
  • 1 007 ÷ 2 = 503 + 1;
  • 503 ÷ 2 = 251 + 1;
  • 251 ÷ 2 = 125 + 1;
  • 125 ÷ 2 = 62 + 1;
  • 62 ÷ 2 = 31 + 0;
  • 31 ÷ 2 = 15 + 1;
  • 15 ÷ 2 = 7 + 1;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

10. Construct the base 2 representation of the adjusted exponent.

Take all the remainders starting from the bottom of the list constructed above.


Exponent (adjusted) =

1007(10) =

011 1110 1111(2)


11. Normalize the mantissa.

a) Remove the leading (the leftmost) bit, since it's allways 1, and the decimal point, if the case.

b) Adjust its length to 52 bits, only if necessary (not the case here).


Mantissa (normalized) =

1. 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001 =

0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


12. The three elements that make up the number's 64 bit double precision IEEE 754 binary floating point representation:

Sign (1 bit) =
0 (a positive number)

Exponent (11 bits) =
011 1110 1111

Mantissa (52 bits) =
0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


Decimal number 0.000 020 830 729 321 671 205 134 999 154 509 660 621 3 converted to 64 bit double precision IEEE 754 binary floating point representation:

0 - 011 1110 1111 - 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001

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How to convert numbers from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point standard

Follow the steps below to convert a base 10 decimal number to 64 bit double precision IEEE 754 binary floating point:

  • 1. If the number to be converted is negative, start with its the positive version.
  • 2. First convert the integer part. Divide repeatedly by 2 the positive representation of the integer number that is to be converted to binary, until we get a quotient that is equal to zero, keeping track of each remainder.
  • 3. Construct the base 2 representation of the positive integer part of the number, by taking all the remainders from the previous operations, starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Then convert the fractional part. Multiply the number repeatedly by 2, until we get a fractional part that is equal to zero, keeping track of each integer part of the results.
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the multiplying operations, starting from the top of the list constructed above (they should appear in the binary representation, from left to right, in the order they have been calculated).
  • 6. Normalize the binary representation of the number, shifting the decimal mark (the decimal point) "n" positions either to the left, or to the right, so that only one non zero digit remains to the left of the decimal mark.
  • 7. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary, by using the same technique of repeatedly dividing by 2, as shown above:
    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1
  • 8. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal mark, if the case) and adjust its length to 52 bits, either by removing the excess bits from the right (losing precision...) or by adding extra bits set on '0' to the right.
  • 9. Sign (it takes 1 bit) is either 1 for a negative or 0 for a positive number.

Example: convert the negative number -31.640 215 from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point:

  • 1. Start with the positive version of the number:

    |-31.640 215| = 31.640 215

  • 2. First convert the integer part, 31. Divide it repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 31 ÷ 2 = 15 + 1;
    • 15 ÷ 2 = 7 + 1;
    • 7 ÷ 2 = 3 + 1;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
    • We have encountered a quotient that is ZERO => FULL STOP
  • 3. Construct the base 2 representation of the integer part of the number by taking all the remainders of the previous dividing operations, starting from the bottom of the list constructed above:

    31(10) = 1 1111(2)

  • 4. Then, convert the fractional part, 0.640 215. Multiply repeatedly by 2, keeping track of each integer part of the results, until we get a fractional part that is equal to zero:
    • #) multiplying = integer + fractional part;
    • 1) 0.640 215 × 2 = 1 + 0.280 43;
    • 2) 0.280 43 × 2 = 0 + 0.560 86;
    • 3) 0.560 86 × 2 = 1 + 0.121 72;
    • 4) 0.121 72 × 2 = 0 + 0.243 44;
    • 5) 0.243 44 × 2 = 0 + 0.486 88;
    • 6) 0.486 88 × 2 = 0 + 0.973 76;
    • 7) 0.973 76 × 2 = 1 + 0.947 52;
    • 8) 0.947 52 × 2 = 1 + 0.895 04;
    • 9) 0.895 04 × 2 = 1 + 0.790 08;
    • 10) 0.790 08 × 2 = 1 + 0.580 16;
    • 11) 0.580 16 × 2 = 1 + 0.160 32;
    • 12) 0.160 32 × 2 = 0 + 0.320 64;
    • 13) 0.320 64 × 2 = 0 + 0.641 28;
    • 14) 0.641 28 × 2 = 1 + 0.282 56;
    • 15) 0.282 56 × 2 = 0 + 0.565 12;
    • 16) 0.565 12 × 2 = 1 + 0.130 24;
    • 17) 0.130 24 × 2 = 0 + 0.260 48;
    • 18) 0.260 48 × 2 = 0 + 0.520 96;
    • 19) 0.520 96 × 2 = 1 + 0.041 92;
    • 20) 0.041 92 × 2 = 0 + 0.083 84;
    • 21) 0.083 84 × 2 = 0 + 0.167 68;
    • 22) 0.167 68 × 2 = 0 + 0.335 36;
    • 23) 0.335 36 × 2 = 0 + 0.670 72;
    • 24) 0.670 72 × 2 = 1 + 0.341 44;
    • 25) 0.341 44 × 2 = 0 + 0.682 88;
    • 26) 0.682 88 × 2 = 1 + 0.365 76;
    • 27) 0.365 76 × 2 = 0 + 0.731 52;
    • 28) 0.731 52 × 2 = 1 + 0.463 04;
    • 29) 0.463 04 × 2 = 0 + 0.926 08;
    • 30) 0.926 08 × 2 = 1 + 0.852 16;
    • 31) 0.852 16 × 2 = 1 + 0.704 32;
    • 32) 0.704 32 × 2 = 1 + 0.408 64;
    • 33) 0.408 64 × 2 = 0 + 0.817 28;
    • 34) 0.817 28 × 2 = 1 + 0.634 56;
    • 35) 0.634 56 × 2 = 1 + 0.269 12;
    • 36) 0.269 12 × 2 = 0 + 0.538 24;
    • 37) 0.538 24 × 2 = 1 + 0.076 48;
    • 38) 0.076 48 × 2 = 0 + 0.152 96;
    • 39) 0.152 96 × 2 = 0 + 0.305 92;
    • 40) 0.305 92 × 2 = 0 + 0.611 84;
    • 41) 0.611 84 × 2 = 1 + 0.223 68;
    • 42) 0.223 68 × 2 = 0 + 0.447 36;
    • 43) 0.447 36 × 2 = 0 + 0.894 72;
    • 44) 0.894 72 × 2 = 1 + 0.789 44;
    • 45) 0.789 44 × 2 = 1 + 0.578 88;
    • 46) 0.578 88 × 2 = 1 + 0.157 76;
    • 47) 0.157 76 × 2 = 0 + 0.315 52;
    • 48) 0.315 52 × 2 = 0 + 0.631 04;
    • 49) 0.631 04 × 2 = 1 + 0.262 08;
    • 50) 0.262 08 × 2 = 0 + 0.524 16;
    • 51) 0.524 16 × 2 = 1 + 0.048 32;
    • 52) 0.048 32 × 2 = 0 + 0.096 64;
    • 53) 0.096 64 × 2 = 0 + 0.193 28;
    • We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit = 52) and at least one integer part that was different from zero => FULL STOP (losing precision...).
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the previous multiplying operations, starting from the top of the constructed list above:

    0.640 215(10) = 0.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 6. Summarizing - the positive number before normalization:

    31.640 215(10) = 1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 7. Normalize the binary representation of the number, shifting the decimal mark 4 positions to the left so that only one non-zero digit stays to the left of the decimal mark:

    31.640 215(10) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 20 =
    1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 24

  • 8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

    Sign: 1 (a negative number)

    Exponent (unadjusted): 4

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

  • 9. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary (base 2), by using the same technique of repeatedly dividing it by 2, as shown above:

    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1 = (4 + 1023)(10) = 1027(10) =
    100 0000 0011(2)

  • 10. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal sign) and adjust its length to 52 bits, by removing the excess bits, from the right (losing precision...):

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

    Mantissa (normalized): 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Conclusion:

    Sign (1 bit) = 1 (a negative number)

    Exponent (8 bits) = 100 0000 0011

    Mantissa (52 bits) = 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Number -31.640 215, converted from decimal system (base 10) to 64 bit double precision IEEE 754 binary floating point =
    1 - 100 0000 0011 - 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100