0.000 020 830 729 321 671 205 134 999 154 509 660 617 527 Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard

Convert decimal 0.000 020 830 729 321 671 205 134 999 154 509 660 617 527(10) to 64 bit double precision IEEE 754 binary floating point representation standard (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

What are the steps to convert decimal number
0.000 020 830 729 321 671 205 134 999 154 509 660 617 527(10) to 64 bit double precision IEEE 754 binary floating point representation (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

1. First, convert to binary (in base 2) the integer part: 0.
Divide the number repeatedly by 2.

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 0 ÷ 2 = 0 + 0;

2. Construct the base 2 representation of the integer part of the number.

Take all the remainders starting from the bottom of the list constructed above.

0(10) =

0(2)


3. Convert to binary (base 2) the fractional part: 0.000 020 830 729 321 671 205 134 999 154 509 660 617 527.

Multiply it repeatedly by 2.

Keep track of each integer part of the results.

Stop when we get a fractional part that is equal to zero.


  • #) multiplying = integer + fractional part;
  • 1) 0.000 020 830 729 321 671 205 134 999 154 509 660 617 527 × 2 = 0 + 0.000 041 661 458 643 342 410 269 998 309 019 321 235 054;
  • 2) 0.000 041 661 458 643 342 410 269 998 309 019 321 235 054 × 2 = 0 + 0.000 083 322 917 286 684 820 539 996 618 038 642 470 108;
  • 3) 0.000 083 322 917 286 684 820 539 996 618 038 642 470 108 × 2 = 0 + 0.000 166 645 834 573 369 641 079 993 236 077 284 940 216;
  • 4) 0.000 166 645 834 573 369 641 079 993 236 077 284 940 216 × 2 = 0 + 0.000 333 291 669 146 739 282 159 986 472 154 569 880 432;
  • 5) 0.000 333 291 669 146 739 282 159 986 472 154 569 880 432 × 2 = 0 + 0.000 666 583 338 293 478 564 319 972 944 309 139 760 864;
  • 6) 0.000 666 583 338 293 478 564 319 972 944 309 139 760 864 × 2 = 0 + 0.001 333 166 676 586 957 128 639 945 888 618 279 521 728;
  • 7) 0.001 333 166 676 586 957 128 639 945 888 618 279 521 728 × 2 = 0 + 0.002 666 333 353 173 914 257 279 891 777 236 559 043 456;
  • 8) 0.002 666 333 353 173 914 257 279 891 777 236 559 043 456 × 2 = 0 + 0.005 332 666 706 347 828 514 559 783 554 473 118 086 912;
  • 9) 0.005 332 666 706 347 828 514 559 783 554 473 118 086 912 × 2 = 0 + 0.010 665 333 412 695 657 029 119 567 108 946 236 173 824;
  • 10) 0.010 665 333 412 695 657 029 119 567 108 946 236 173 824 × 2 = 0 + 0.021 330 666 825 391 314 058 239 134 217 892 472 347 648;
  • 11) 0.021 330 666 825 391 314 058 239 134 217 892 472 347 648 × 2 = 0 + 0.042 661 333 650 782 628 116 478 268 435 784 944 695 296;
  • 12) 0.042 661 333 650 782 628 116 478 268 435 784 944 695 296 × 2 = 0 + 0.085 322 667 301 565 256 232 956 536 871 569 889 390 592;
  • 13) 0.085 322 667 301 565 256 232 956 536 871 569 889 390 592 × 2 = 0 + 0.170 645 334 603 130 512 465 913 073 743 139 778 781 184;
  • 14) 0.170 645 334 603 130 512 465 913 073 743 139 778 781 184 × 2 = 0 + 0.341 290 669 206 261 024 931 826 147 486 279 557 562 368;
  • 15) 0.341 290 669 206 261 024 931 826 147 486 279 557 562 368 × 2 = 0 + 0.682 581 338 412 522 049 863 652 294 972 559 115 124 736;
  • 16) 0.682 581 338 412 522 049 863 652 294 972 559 115 124 736 × 2 = 1 + 0.365 162 676 825 044 099 727 304 589 945 118 230 249 472;
  • 17) 0.365 162 676 825 044 099 727 304 589 945 118 230 249 472 × 2 = 0 + 0.730 325 353 650 088 199 454 609 179 890 236 460 498 944;
  • 18) 0.730 325 353 650 088 199 454 609 179 890 236 460 498 944 × 2 = 1 + 0.460 650 707 300 176 398 909 218 359 780 472 920 997 888;
  • 19) 0.460 650 707 300 176 398 909 218 359 780 472 920 997 888 × 2 = 0 + 0.921 301 414 600 352 797 818 436 719 560 945 841 995 776;
  • 20) 0.921 301 414 600 352 797 818 436 719 560 945 841 995 776 × 2 = 1 + 0.842 602 829 200 705 595 636 873 439 121 891 683 991 552;
  • 21) 0.842 602 829 200 705 595 636 873 439 121 891 683 991 552 × 2 = 1 + 0.685 205 658 401 411 191 273 746 878 243 783 367 983 104;
  • 22) 0.685 205 658 401 411 191 273 746 878 243 783 367 983 104 × 2 = 1 + 0.370 411 316 802 822 382 547 493 756 487 566 735 966 208;
  • 23) 0.370 411 316 802 822 382 547 493 756 487 566 735 966 208 × 2 = 0 + 0.740 822 633 605 644 765 094 987 512 975 133 471 932 416;
  • 24) 0.740 822 633 605 644 765 094 987 512 975 133 471 932 416 × 2 = 1 + 0.481 645 267 211 289 530 189 975 025 950 266 943 864 832;
  • 25) 0.481 645 267 211 289 530 189 975 025 950 266 943 864 832 × 2 = 0 + 0.963 290 534 422 579 060 379 950 051 900 533 887 729 664;
  • 26) 0.963 290 534 422 579 060 379 950 051 900 533 887 729 664 × 2 = 1 + 0.926 581 068 845 158 120 759 900 103 801 067 775 459 328;
  • 27) 0.926 581 068 845 158 120 759 900 103 801 067 775 459 328 × 2 = 1 + 0.853 162 137 690 316 241 519 800 207 602 135 550 918 656;
  • 28) 0.853 162 137 690 316 241 519 800 207 602 135 550 918 656 × 2 = 1 + 0.706 324 275 380 632 483 039 600 415 204 271 101 837 312;
  • 29) 0.706 324 275 380 632 483 039 600 415 204 271 101 837 312 × 2 = 1 + 0.412 648 550 761 264 966 079 200 830 408 542 203 674 624;
  • 30) 0.412 648 550 761 264 966 079 200 830 408 542 203 674 624 × 2 = 0 + 0.825 297 101 522 529 932 158 401 660 817 084 407 349 248;
  • 31) 0.825 297 101 522 529 932 158 401 660 817 084 407 349 248 × 2 = 1 + 0.650 594 203 045 059 864 316 803 321 634 168 814 698 496;
  • 32) 0.650 594 203 045 059 864 316 803 321 634 168 814 698 496 × 2 = 1 + 0.301 188 406 090 119 728 633 606 643 268 337 629 396 992;
  • 33) 0.301 188 406 090 119 728 633 606 643 268 337 629 396 992 × 2 = 0 + 0.602 376 812 180 239 457 267 213 286 536 675 258 793 984;
  • 34) 0.602 376 812 180 239 457 267 213 286 536 675 258 793 984 × 2 = 1 + 0.204 753 624 360 478 914 534 426 573 073 350 517 587 968;
  • 35) 0.204 753 624 360 478 914 534 426 573 073 350 517 587 968 × 2 = 0 + 0.409 507 248 720 957 829 068 853 146 146 701 035 175 936;
  • 36) 0.409 507 248 720 957 829 068 853 146 146 701 035 175 936 × 2 = 0 + 0.819 014 497 441 915 658 137 706 292 293 402 070 351 872;
  • 37) 0.819 014 497 441 915 658 137 706 292 293 402 070 351 872 × 2 = 1 + 0.638 028 994 883 831 316 275 412 584 586 804 140 703 744;
  • 38) 0.638 028 994 883 831 316 275 412 584 586 804 140 703 744 × 2 = 1 + 0.276 057 989 767 662 632 550 825 169 173 608 281 407 488;
  • 39) 0.276 057 989 767 662 632 550 825 169 173 608 281 407 488 × 2 = 0 + 0.552 115 979 535 325 265 101 650 338 347 216 562 814 976;
  • 40) 0.552 115 979 535 325 265 101 650 338 347 216 562 814 976 × 2 = 1 + 0.104 231 959 070 650 530 203 300 676 694 433 125 629 952;
  • 41) 0.104 231 959 070 650 530 203 300 676 694 433 125 629 952 × 2 = 0 + 0.208 463 918 141 301 060 406 601 353 388 866 251 259 904;
  • 42) 0.208 463 918 141 301 060 406 601 353 388 866 251 259 904 × 2 = 0 + 0.416 927 836 282 602 120 813 202 706 777 732 502 519 808;
  • 43) 0.416 927 836 282 602 120 813 202 706 777 732 502 519 808 × 2 = 0 + 0.833 855 672 565 204 241 626 405 413 555 465 005 039 616;
  • 44) 0.833 855 672 565 204 241 626 405 413 555 465 005 039 616 × 2 = 1 + 0.667 711 345 130 408 483 252 810 827 110 930 010 079 232;
  • 45) 0.667 711 345 130 408 483 252 810 827 110 930 010 079 232 × 2 = 1 + 0.335 422 690 260 816 966 505 621 654 221 860 020 158 464;
  • 46) 0.335 422 690 260 816 966 505 621 654 221 860 020 158 464 × 2 = 0 + 0.670 845 380 521 633 933 011 243 308 443 720 040 316 928;
  • 47) 0.670 845 380 521 633 933 011 243 308 443 720 040 316 928 × 2 = 1 + 0.341 690 761 043 267 866 022 486 616 887 440 080 633 856;
  • 48) 0.341 690 761 043 267 866 022 486 616 887 440 080 633 856 × 2 = 0 + 0.683 381 522 086 535 732 044 973 233 774 880 161 267 712;
  • 49) 0.683 381 522 086 535 732 044 973 233 774 880 161 267 712 × 2 = 1 + 0.366 763 044 173 071 464 089 946 467 549 760 322 535 424;
  • 50) 0.366 763 044 173 071 464 089 946 467 549 760 322 535 424 × 2 = 0 + 0.733 526 088 346 142 928 179 892 935 099 520 645 070 848;
  • 51) 0.733 526 088 346 142 928 179 892 935 099 520 645 070 848 × 2 = 1 + 0.467 052 176 692 285 856 359 785 870 199 041 290 141 696;
  • 52) 0.467 052 176 692 285 856 359 785 870 199 041 290 141 696 × 2 = 0 + 0.934 104 353 384 571 712 719 571 740 398 082 580 283 392;
  • 53) 0.934 104 353 384 571 712 719 571 740 398 082 580 283 392 × 2 = 1 + 0.868 208 706 769 143 425 439 143 480 796 165 160 566 784;
  • 54) 0.868 208 706 769 143 425 439 143 480 796 165 160 566 784 × 2 = 1 + 0.736 417 413 538 286 850 878 286 961 592 330 321 133 568;
  • 55) 0.736 417 413 538 286 850 878 286 961 592 330 321 133 568 × 2 = 1 + 0.472 834 827 076 573 701 756 573 923 184 660 642 267 136;
  • 56) 0.472 834 827 076 573 701 756 573 923 184 660 642 267 136 × 2 = 0 + 0.945 669 654 153 147 403 513 147 846 369 321 284 534 272;
  • 57) 0.945 669 654 153 147 403 513 147 846 369 321 284 534 272 × 2 = 1 + 0.891 339 308 306 294 807 026 295 692 738 642 569 068 544;
  • 58) 0.891 339 308 306 294 807 026 295 692 738 642 569 068 544 × 2 = 1 + 0.782 678 616 612 589 614 052 591 385 477 285 138 137 088;
  • 59) 0.782 678 616 612 589 614 052 591 385 477 285 138 137 088 × 2 = 1 + 0.565 357 233 225 179 228 105 182 770 954 570 276 274 176;
  • 60) 0.565 357 233 225 179 228 105 182 770 954 570 276 274 176 × 2 = 1 + 0.130 714 466 450 358 456 210 365 541 909 140 552 548 352;
  • 61) 0.130 714 466 450 358 456 210 365 541 909 140 552 548 352 × 2 = 0 + 0.261 428 932 900 716 912 420 731 083 818 281 105 096 704;
  • 62) 0.261 428 932 900 716 912 420 731 083 818 281 105 096 704 × 2 = 0 + 0.522 857 865 801 433 824 841 462 167 636 562 210 193 408;
  • 63) 0.522 857 865 801 433 824 841 462 167 636 562 210 193 408 × 2 = 1 + 0.045 715 731 602 867 649 682 924 335 273 124 420 386 816;
  • 64) 0.045 715 731 602 867 649 682 924 335 273 124 420 386 816 × 2 = 0 + 0.091 431 463 205 735 299 365 848 670 546 248 840 773 632;
  • 65) 0.091 431 463 205 735 299 365 848 670 546 248 840 773 632 × 2 = 0 + 0.182 862 926 411 470 598 731 697 341 092 497 681 547 264;
  • 66) 0.182 862 926 411 470 598 731 697 341 092 497 681 547 264 × 2 = 0 + 0.365 725 852 822 941 197 463 394 682 184 995 363 094 528;
  • 67) 0.365 725 852 822 941 197 463 394 682 184 995 363 094 528 × 2 = 0 + 0.731 451 705 645 882 394 926 789 364 369 990 726 189 056;
  • 68) 0.731 451 705 645 882 394 926 789 364 369 990 726 189 056 × 2 = 1 + 0.462 903 411 291 764 789 853 578 728 739 981 452 378 112;

We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit) and at least one integer that was different from zero => FULL STOP (Losing precision - the converted number we get in the end will be just a very good approximation of the initial one).


4. Construct the base 2 representation of the fractional part of the number.

Take all the integer parts of the multiplying operations, starting from the top of the constructed list above:


0.000 020 830 729 321 671 205 134 999 154 509 660 617 527(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2)

5. Positive number before normalization:

0.000 020 830 729 321 671 205 134 999 154 509 660 617 527(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2)

6. Normalize the binary representation of the number.

Shift the decimal mark 16 positions to the right, so that only one non zero digit remains to the left of it:


0.000 020 830 729 321 671 205 134 999 154 509 660 617 527(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) × 20 =

1.0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) × 2-16


7. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

Sign 0 (a positive number)

Exponent (unadjusted): -16

Mantissa (not normalized):
1.0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


8. Adjust the exponent.

Use the 11 bit excess/bias notation:


Exponent (adjusted) =

Exponent (unadjusted) + 2(11-1) - 1 =

-16 + 2(11-1) - 1 =

(-16 + 1 023)(10) =

1 007(10)


9. Convert the adjusted exponent from the decimal (base 10) to 11 bit binary.

Use the same technique of repeatedly dividing by 2:


  • division = quotient + remainder;
  • 1 007 ÷ 2 = 503 + 1;
  • 503 ÷ 2 = 251 + 1;
  • 251 ÷ 2 = 125 + 1;
  • 125 ÷ 2 = 62 + 1;
  • 62 ÷ 2 = 31 + 0;
  • 31 ÷ 2 = 15 + 1;
  • 15 ÷ 2 = 7 + 1;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

10. Construct the base 2 representation of the adjusted exponent.

Take all the remainders starting from the bottom of the list constructed above.


Exponent (adjusted) =

1007(10) =

011 1110 1111(2)


11. Normalize the mantissa.

a) Remove the leading (the leftmost) bit, since it's allways 1, and the decimal point, if the case.

b) Adjust its length to 52 bits, only if necessary (not the case here).


Mantissa (normalized) =

1. 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001 =

0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


12. The three elements that make up the number's 64 bit double precision IEEE 754 binary floating point representation:

Sign (1 bit) =
0 (a positive number)

Exponent (11 bits) =
011 1110 1111

Mantissa (52 bits) =
0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


Decimal number 0.000 020 830 729 321 671 205 134 999 154 509 660 617 527 converted to 64 bit double precision IEEE 754 binary floating point representation:

0 - 011 1110 1111 - 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001

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How to convert numbers from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point standard

Follow the steps below to convert a base 10 decimal number to 64 bit double precision IEEE 754 binary floating point:

  • 1. If the number to be converted is negative, start with its the positive version.
  • 2. First convert the integer part. Divide repeatedly by 2 the positive representation of the integer number that is to be converted to binary, until we get a quotient that is equal to zero, keeping track of each remainder.
  • 3. Construct the base 2 representation of the positive integer part of the number, by taking all the remainders from the previous operations, starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Then convert the fractional part. Multiply the number repeatedly by 2, until we get a fractional part that is equal to zero, keeping track of each integer part of the results.
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the multiplying operations, starting from the top of the list constructed above (they should appear in the binary representation, from left to right, in the order they have been calculated).
  • 6. Normalize the binary representation of the number, shifting the decimal mark (the decimal point) "n" positions either to the left, or to the right, so that only one non zero digit remains to the left of the decimal mark.
  • 7. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary, by using the same technique of repeatedly dividing by 2, as shown above:
    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1
  • 8. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal mark, if the case) and adjust its length to 52 bits, either by removing the excess bits from the right (losing precision...) or by adding extra bits set on '0' to the right.
  • 9. Sign (it takes 1 bit) is either 1 for a negative or 0 for a positive number.

Example: convert the negative number -31.640 215 from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point:

  • 1. Start with the positive version of the number:

    |-31.640 215| = 31.640 215

  • 2. First convert the integer part, 31. Divide it repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 31 ÷ 2 = 15 + 1;
    • 15 ÷ 2 = 7 + 1;
    • 7 ÷ 2 = 3 + 1;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
    • We have encountered a quotient that is ZERO => FULL STOP
  • 3. Construct the base 2 representation of the integer part of the number by taking all the remainders of the previous dividing operations, starting from the bottom of the list constructed above:

    31(10) = 1 1111(2)

  • 4. Then, convert the fractional part, 0.640 215. Multiply repeatedly by 2, keeping track of each integer part of the results, until we get a fractional part that is equal to zero:
    • #) multiplying = integer + fractional part;
    • 1) 0.640 215 × 2 = 1 + 0.280 43;
    • 2) 0.280 43 × 2 = 0 + 0.560 86;
    • 3) 0.560 86 × 2 = 1 + 0.121 72;
    • 4) 0.121 72 × 2 = 0 + 0.243 44;
    • 5) 0.243 44 × 2 = 0 + 0.486 88;
    • 6) 0.486 88 × 2 = 0 + 0.973 76;
    • 7) 0.973 76 × 2 = 1 + 0.947 52;
    • 8) 0.947 52 × 2 = 1 + 0.895 04;
    • 9) 0.895 04 × 2 = 1 + 0.790 08;
    • 10) 0.790 08 × 2 = 1 + 0.580 16;
    • 11) 0.580 16 × 2 = 1 + 0.160 32;
    • 12) 0.160 32 × 2 = 0 + 0.320 64;
    • 13) 0.320 64 × 2 = 0 + 0.641 28;
    • 14) 0.641 28 × 2 = 1 + 0.282 56;
    • 15) 0.282 56 × 2 = 0 + 0.565 12;
    • 16) 0.565 12 × 2 = 1 + 0.130 24;
    • 17) 0.130 24 × 2 = 0 + 0.260 48;
    • 18) 0.260 48 × 2 = 0 + 0.520 96;
    • 19) 0.520 96 × 2 = 1 + 0.041 92;
    • 20) 0.041 92 × 2 = 0 + 0.083 84;
    • 21) 0.083 84 × 2 = 0 + 0.167 68;
    • 22) 0.167 68 × 2 = 0 + 0.335 36;
    • 23) 0.335 36 × 2 = 0 + 0.670 72;
    • 24) 0.670 72 × 2 = 1 + 0.341 44;
    • 25) 0.341 44 × 2 = 0 + 0.682 88;
    • 26) 0.682 88 × 2 = 1 + 0.365 76;
    • 27) 0.365 76 × 2 = 0 + 0.731 52;
    • 28) 0.731 52 × 2 = 1 + 0.463 04;
    • 29) 0.463 04 × 2 = 0 + 0.926 08;
    • 30) 0.926 08 × 2 = 1 + 0.852 16;
    • 31) 0.852 16 × 2 = 1 + 0.704 32;
    • 32) 0.704 32 × 2 = 1 + 0.408 64;
    • 33) 0.408 64 × 2 = 0 + 0.817 28;
    • 34) 0.817 28 × 2 = 1 + 0.634 56;
    • 35) 0.634 56 × 2 = 1 + 0.269 12;
    • 36) 0.269 12 × 2 = 0 + 0.538 24;
    • 37) 0.538 24 × 2 = 1 + 0.076 48;
    • 38) 0.076 48 × 2 = 0 + 0.152 96;
    • 39) 0.152 96 × 2 = 0 + 0.305 92;
    • 40) 0.305 92 × 2 = 0 + 0.611 84;
    • 41) 0.611 84 × 2 = 1 + 0.223 68;
    • 42) 0.223 68 × 2 = 0 + 0.447 36;
    • 43) 0.447 36 × 2 = 0 + 0.894 72;
    • 44) 0.894 72 × 2 = 1 + 0.789 44;
    • 45) 0.789 44 × 2 = 1 + 0.578 88;
    • 46) 0.578 88 × 2 = 1 + 0.157 76;
    • 47) 0.157 76 × 2 = 0 + 0.315 52;
    • 48) 0.315 52 × 2 = 0 + 0.631 04;
    • 49) 0.631 04 × 2 = 1 + 0.262 08;
    • 50) 0.262 08 × 2 = 0 + 0.524 16;
    • 51) 0.524 16 × 2 = 1 + 0.048 32;
    • 52) 0.048 32 × 2 = 0 + 0.096 64;
    • 53) 0.096 64 × 2 = 0 + 0.193 28;
    • We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit = 52) and at least one integer part that was different from zero => FULL STOP (losing precision...).
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the previous multiplying operations, starting from the top of the constructed list above:

    0.640 215(10) = 0.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 6. Summarizing - the positive number before normalization:

    31.640 215(10) = 1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 7. Normalize the binary representation of the number, shifting the decimal mark 4 positions to the left so that only one non-zero digit stays to the left of the decimal mark:

    31.640 215(10) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 20 =
    1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 24

  • 8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

    Sign: 1 (a negative number)

    Exponent (unadjusted): 4

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

  • 9. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary (base 2), by using the same technique of repeatedly dividing it by 2, as shown above:

    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1 = (4 + 1023)(10) = 1027(10) =
    100 0000 0011(2)

  • 10. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal sign) and adjust its length to 52 bits, by removing the excess bits, from the right (losing precision...):

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

    Mantissa (normalized): 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Conclusion:

    Sign (1 bit) = 1 (a negative number)

    Exponent (8 bits) = 100 0000 0011

    Mantissa (52 bits) = 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Number -31.640 215, converted from decimal system (base 10) to 64 bit double precision IEEE 754 binary floating point =
    1 - 100 0000 0011 - 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100