0.000 020 830 729 321 671 205 134 999 154 509 660 617 204 Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard

Convert decimal 0.000 020 830 729 321 671 205 134 999 154 509 660 617 204(10) to 64 bit double precision IEEE 754 binary floating point representation standard (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

What are the steps to convert decimal number
0.000 020 830 729 321 671 205 134 999 154 509 660 617 204(10) to 64 bit double precision IEEE 754 binary floating point representation (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

1. First, convert to binary (in base 2) the integer part: 0.
Divide the number repeatedly by 2.

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 0 ÷ 2 = 0 + 0;

2. Construct the base 2 representation of the integer part of the number.

Take all the remainders starting from the bottom of the list constructed above.

0(10) =

0(2)


3. Convert to binary (base 2) the fractional part: 0.000 020 830 729 321 671 205 134 999 154 509 660 617 204.

Multiply it repeatedly by 2.

Keep track of each integer part of the results.

Stop when we get a fractional part that is equal to zero.


  • #) multiplying = integer + fractional part;
  • 1) 0.000 020 830 729 321 671 205 134 999 154 509 660 617 204 × 2 = 0 + 0.000 041 661 458 643 342 410 269 998 309 019 321 234 408;
  • 2) 0.000 041 661 458 643 342 410 269 998 309 019 321 234 408 × 2 = 0 + 0.000 083 322 917 286 684 820 539 996 618 038 642 468 816;
  • 3) 0.000 083 322 917 286 684 820 539 996 618 038 642 468 816 × 2 = 0 + 0.000 166 645 834 573 369 641 079 993 236 077 284 937 632;
  • 4) 0.000 166 645 834 573 369 641 079 993 236 077 284 937 632 × 2 = 0 + 0.000 333 291 669 146 739 282 159 986 472 154 569 875 264;
  • 5) 0.000 333 291 669 146 739 282 159 986 472 154 569 875 264 × 2 = 0 + 0.000 666 583 338 293 478 564 319 972 944 309 139 750 528;
  • 6) 0.000 666 583 338 293 478 564 319 972 944 309 139 750 528 × 2 = 0 + 0.001 333 166 676 586 957 128 639 945 888 618 279 501 056;
  • 7) 0.001 333 166 676 586 957 128 639 945 888 618 279 501 056 × 2 = 0 + 0.002 666 333 353 173 914 257 279 891 777 236 559 002 112;
  • 8) 0.002 666 333 353 173 914 257 279 891 777 236 559 002 112 × 2 = 0 + 0.005 332 666 706 347 828 514 559 783 554 473 118 004 224;
  • 9) 0.005 332 666 706 347 828 514 559 783 554 473 118 004 224 × 2 = 0 + 0.010 665 333 412 695 657 029 119 567 108 946 236 008 448;
  • 10) 0.010 665 333 412 695 657 029 119 567 108 946 236 008 448 × 2 = 0 + 0.021 330 666 825 391 314 058 239 134 217 892 472 016 896;
  • 11) 0.021 330 666 825 391 314 058 239 134 217 892 472 016 896 × 2 = 0 + 0.042 661 333 650 782 628 116 478 268 435 784 944 033 792;
  • 12) 0.042 661 333 650 782 628 116 478 268 435 784 944 033 792 × 2 = 0 + 0.085 322 667 301 565 256 232 956 536 871 569 888 067 584;
  • 13) 0.085 322 667 301 565 256 232 956 536 871 569 888 067 584 × 2 = 0 + 0.170 645 334 603 130 512 465 913 073 743 139 776 135 168;
  • 14) 0.170 645 334 603 130 512 465 913 073 743 139 776 135 168 × 2 = 0 + 0.341 290 669 206 261 024 931 826 147 486 279 552 270 336;
  • 15) 0.341 290 669 206 261 024 931 826 147 486 279 552 270 336 × 2 = 0 + 0.682 581 338 412 522 049 863 652 294 972 559 104 540 672;
  • 16) 0.682 581 338 412 522 049 863 652 294 972 559 104 540 672 × 2 = 1 + 0.365 162 676 825 044 099 727 304 589 945 118 209 081 344;
  • 17) 0.365 162 676 825 044 099 727 304 589 945 118 209 081 344 × 2 = 0 + 0.730 325 353 650 088 199 454 609 179 890 236 418 162 688;
  • 18) 0.730 325 353 650 088 199 454 609 179 890 236 418 162 688 × 2 = 1 + 0.460 650 707 300 176 398 909 218 359 780 472 836 325 376;
  • 19) 0.460 650 707 300 176 398 909 218 359 780 472 836 325 376 × 2 = 0 + 0.921 301 414 600 352 797 818 436 719 560 945 672 650 752;
  • 20) 0.921 301 414 600 352 797 818 436 719 560 945 672 650 752 × 2 = 1 + 0.842 602 829 200 705 595 636 873 439 121 891 345 301 504;
  • 21) 0.842 602 829 200 705 595 636 873 439 121 891 345 301 504 × 2 = 1 + 0.685 205 658 401 411 191 273 746 878 243 782 690 603 008;
  • 22) 0.685 205 658 401 411 191 273 746 878 243 782 690 603 008 × 2 = 1 + 0.370 411 316 802 822 382 547 493 756 487 565 381 206 016;
  • 23) 0.370 411 316 802 822 382 547 493 756 487 565 381 206 016 × 2 = 0 + 0.740 822 633 605 644 765 094 987 512 975 130 762 412 032;
  • 24) 0.740 822 633 605 644 765 094 987 512 975 130 762 412 032 × 2 = 1 + 0.481 645 267 211 289 530 189 975 025 950 261 524 824 064;
  • 25) 0.481 645 267 211 289 530 189 975 025 950 261 524 824 064 × 2 = 0 + 0.963 290 534 422 579 060 379 950 051 900 523 049 648 128;
  • 26) 0.963 290 534 422 579 060 379 950 051 900 523 049 648 128 × 2 = 1 + 0.926 581 068 845 158 120 759 900 103 801 046 099 296 256;
  • 27) 0.926 581 068 845 158 120 759 900 103 801 046 099 296 256 × 2 = 1 + 0.853 162 137 690 316 241 519 800 207 602 092 198 592 512;
  • 28) 0.853 162 137 690 316 241 519 800 207 602 092 198 592 512 × 2 = 1 + 0.706 324 275 380 632 483 039 600 415 204 184 397 185 024;
  • 29) 0.706 324 275 380 632 483 039 600 415 204 184 397 185 024 × 2 = 1 + 0.412 648 550 761 264 966 079 200 830 408 368 794 370 048;
  • 30) 0.412 648 550 761 264 966 079 200 830 408 368 794 370 048 × 2 = 0 + 0.825 297 101 522 529 932 158 401 660 816 737 588 740 096;
  • 31) 0.825 297 101 522 529 932 158 401 660 816 737 588 740 096 × 2 = 1 + 0.650 594 203 045 059 864 316 803 321 633 475 177 480 192;
  • 32) 0.650 594 203 045 059 864 316 803 321 633 475 177 480 192 × 2 = 1 + 0.301 188 406 090 119 728 633 606 643 266 950 354 960 384;
  • 33) 0.301 188 406 090 119 728 633 606 643 266 950 354 960 384 × 2 = 0 + 0.602 376 812 180 239 457 267 213 286 533 900 709 920 768;
  • 34) 0.602 376 812 180 239 457 267 213 286 533 900 709 920 768 × 2 = 1 + 0.204 753 624 360 478 914 534 426 573 067 801 419 841 536;
  • 35) 0.204 753 624 360 478 914 534 426 573 067 801 419 841 536 × 2 = 0 + 0.409 507 248 720 957 829 068 853 146 135 602 839 683 072;
  • 36) 0.409 507 248 720 957 829 068 853 146 135 602 839 683 072 × 2 = 0 + 0.819 014 497 441 915 658 137 706 292 271 205 679 366 144;
  • 37) 0.819 014 497 441 915 658 137 706 292 271 205 679 366 144 × 2 = 1 + 0.638 028 994 883 831 316 275 412 584 542 411 358 732 288;
  • 38) 0.638 028 994 883 831 316 275 412 584 542 411 358 732 288 × 2 = 1 + 0.276 057 989 767 662 632 550 825 169 084 822 717 464 576;
  • 39) 0.276 057 989 767 662 632 550 825 169 084 822 717 464 576 × 2 = 0 + 0.552 115 979 535 325 265 101 650 338 169 645 434 929 152;
  • 40) 0.552 115 979 535 325 265 101 650 338 169 645 434 929 152 × 2 = 1 + 0.104 231 959 070 650 530 203 300 676 339 290 869 858 304;
  • 41) 0.104 231 959 070 650 530 203 300 676 339 290 869 858 304 × 2 = 0 + 0.208 463 918 141 301 060 406 601 352 678 581 739 716 608;
  • 42) 0.208 463 918 141 301 060 406 601 352 678 581 739 716 608 × 2 = 0 + 0.416 927 836 282 602 120 813 202 705 357 163 479 433 216;
  • 43) 0.416 927 836 282 602 120 813 202 705 357 163 479 433 216 × 2 = 0 + 0.833 855 672 565 204 241 626 405 410 714 326 958 866 432;
  • 44) 0.833 855 672 565 204 241 626 405 410 714 326 958 866 432 × 2 = 1 + 0.667 711 345 130 408 483 252 810 821 428 653 917 732 864;
  • 45) 0.667 711 345 130 408 483 252 810 821 428 653 917 732 864 × 2 = 1 + 0.335 422 690 260 816 966 505 621 642 857 307 835 465 728;
  • 46) 0.335 422 690 260 816 966 505 621 642 857 307 835 465 728 × 2 = 0 + 0.670 845 380 521 633 933 011 243 285 714 615 670 931 456;
  • 47) 0.670 845 380 521 633 933 011 243 285 714 615 670 931 456 × 2 = 1 + 0.341 690 761 043 267 866 022 486 571 429 231 341 862 912;
  • 48) 0.341 690 761 043 267 866 022 486 571 429 231 341 862 912 × 2 = 0 + 0.683 381 522 086 535 732 044 973 142 858 462 683 725 824;
  • 49) 0.683 381 522 086 535 732 044 973 142 858 462 683 725 824 × 2 = 1 + 0.366 763 044 173 071 464 089 946 285 716 925 367 451 648;
  • 50) 0.366 763 044 173 071 464 089 946 285 716 925 367 451 648 × 2 = 0 + 0.733 526 088 346 142 928 179 892 571 433 850 734 903 296;
  • 51) 0.733 526 088 346 142 928 179 892 571 433 850 734 903 296 × 2 = 1 + 0.467 052 176 692 285 856 359 785 142 867 701 469 806 592;
  • 52) 0.467 052 176 692 285 856 359 785 142 867 701 469 806 592 × 2 = 0 + 0.934 104 353 384 571 712 719 570 285 735 402 939 613 184;
  • 53) 0.934 104 353 384 571 712 719 570 285 735 402 939 613 184 × 2 = 1 + 0.868 208 706 769 143 425 439 140 571 470 805 879 226 368;
  • 54) 0.868 208 706 769 143 425 439 140 571 470 805 879 226 368 × 2 = 1 + 0.736 417 413 538 286 850 878 281 142 941 611 758 452 736;
  • 55) 0.736 417 413 538 286 850 878 281 142 941 611 758 452 736 × 2 = 1 + 0.472 834 827 076 573 701 756 562 285 883 223 516 905 472;
  • 56) 0.472 834 827 076 573 701 756 562 285 883 223 516 905 472 × 2 = 0 + 0.945 669 654 153 147 403 513 124 571 766 447 033 810 944;
  • 57) 0.945 669 654 153 147 403 513 124 571 766 447 033 810 944 × 2 = 1 + 0.891 339 308 306 294 807 026 249 143 532 894 067 621 888;
  • 58) 0.891 339 308 306 294 807 026 249 143 532 894 067 621 888 × 2 = 1 + 0.782 678 616 612 589 614 052 498 287 065 788 135 243 776;
  • 59) 0.782 678 616 612 589 614 052 498 287 065 788 135 243 776 × 2 = 1 + 0.565 357 233 225 179 228 104 996 574 131 576 270 487 552;
  • 60) 0.565 357 233 225 179 228 104 996 574 131 576 270 487 552 × 2 = 1 + 0.130 714 466 450 358 456 209 993 148 263 152 540 975 104;
  • 61) 0.130 714 466 450 358 456 209 993 148 263 152 540 975 104 × 2 = 0 + 0.261 428 932 900 716 912 419 986 296 526 305 081 950 208;
  • 62) 0.261 428 932 900 716 912 419 986 296 526 305 081 950 208 × 2 = 0 + 0.522 857 865 801 433 824 839 972 593 052 610 163 900 416;
  • 63) 0.522 857 865 801 433 824 839 972 593 052 610 163 900 416 × 2 = 1 + 0.045 715 731 602 867 649 679 945 186 105 220 327 800 832;
  • 64) 0.045 715 731 602 867 649 679 945 186 105 220 327 800 832 × 2 = 0 + 0.091 431 463 205 735 299 359 890 372 210 440 655 601 664;
  • 65) 0.091 431 463 205 735 299 359 890 372 210 440 655 601 664 × 2 = 0 + 0.182 862 926 411 470 598 719 780 744 420 881 311 203 328;
  • 66) 0.182 862 926 411 470 598 719 780 744 420 881 311 203 328 × 2 = 0 + 0.365 725 852 822 941 197 439 561 488 841 762 622 406 656;
  • 67) 0.365 725 852 822 941 197 439 561 488 841 762 622 406 656 × 2 = 0 + 0.731 451 705 645 882 394 879 122 977 683 525 244 813 312;
  • 68) 0.731 451 705 645 882 394 879 122 977 683 525 244 813 312 × 2 = 1 + 0.462 903 411 291 764 789 758 245 955 367 050 489 626 624;

We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit) and at least one integer that was different from zero => FULL STOP (Losing precision - the converted number we get in the end will be just a very good approximation of the initial one).


4. Construct the base 2 representation of the fractional part of the number.

Take all the integer parts of the multiplying operations, starting from the top of the constructed list above:


0.000 020 830 729 321 671 205 134 999 154 509 660 617 204(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2)

5. Positive number before normalization:

0.000 020 830 729 321 671 205 134 999 154 509 660 617 204(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2)

6. Normalize the binary representation of the number.

Shift the decimal mark 16 positions to the right, so that only one non zero digit remains to the left of it:


0.000 020 830 729 321 671 205 134 999 154 509 660 617 204(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) × 20 =

1.0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) × 2-16


7. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

Sign 0 (a positive number)

Exponent (unadjusted): -16

Mantissa (not normalized):
1.0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


8. Adjust the exponent.

Use the 11 bit excess/bias notation:


Exponent (adjusted) =

Exponent (unadjusted) + 2(11-1) - 1 =

-16 + 2(11-1) - 1 =

(-16 + 1 023)(10) =

1 007(10)


9. Convert the adjusted exponent from the decimal (base 10) to 11 bit binary.

Use the same technique of repeatedly dividing by 2:


  • division = quotient + remainder;
  • 1 007 ÷ 2 = 503 + 1;
  • 503 ÷ 2 = 251 + 1;
  • 251 ÷ 2 = 125 + 1;
  • 125 ÷ 2 = 62 + 1;
  • 62 ÷ 2 = 31 + 0;
  • 31 ÷ 2 = 15 + 1;
  • 15 ÷ 2 = 7 + 1;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

10. Construct the base 2 representation of the adjusted exponent.

Take all the remainders starting from the bottom of the list constructed above.


Exponent (adjusted) =

1007(10) =

011 1110 1111(2)


11. Normalize the mantissa.

a) Remove the leading (the leftmost) bit, since it's allways 1, and the decimal point, if the case.

b) Adjust its length to 52 bits, only if necessary (not the case here).


Mantissa (normalized) =

1. 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001 =

0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


12. The three elements that make up the number's 64 bit double precision IEEE 754 binary floating point representation:

Sign (1 bit) =
0 (a positive number)

Exponent (11 bits) =
011 1110 1111

Mantissa (52 bits) =
0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


Decimal number 0.000 020 830 729 321 671 205 134 999 154 509 660 617 204 converted to 64 bit double precision IEEE 754 binary floating point representation:

0 - 011 1110 1111 - 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001

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How to convert numbers from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point standard

Follow the steps below to convert a base 10 decimal number to 64 bit double precision IEEE 754 binary floating point:

  • 1. If the number to be converted is negative, start with its the positive version.
  • 2. First convert the integer part. Divide repeatedly by 2 the positive representation of the integer number that is to be converted to binary, until we get a quotient that is equal to zero, keeping track of each remainder.
  • 3. Construct the base 2 representation of the positive integer part of the number, by taking all the remainders from the previous operations, starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Then convert the fractional part. Multiply the number repeatedly by 2, until we get a fractional part that is equal to zero, keeping track of each integer part of the results.
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the multiplying operations, starting from the top of the list constructed above (they should appear in the binary representation, from left to right, in the order they have been calculated).
  • 6. Normalize the binary representation of the number, shifting the decimal mark (the decimal point) "n" positions either to the left, or to the right, so that only one non zero digit remains to the left of the decimal mark.
  • 7. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary, by using the same technique of repeatedly dividing by 2, as shown above:
    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1
  • 8. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal mark, if the case) and adjust its length to 52 bits, either by removing the excess bits from the right (losing precision...) or by adding extra bits set on '0' to the right.
  • 9. Sign (it takes 1 bit) is either 1 for a negative or 0 for a positive number.

Example: convert the negative number -31.640 215 from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point:

  • 1. Start with the positive version of the number:

    |-31.640 215| = 31.640 215

  • 2. First convert the integer part, 31. Divide it repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 31 ÷ 2 = 15 + 1;
    • 15 ÷ 2 = 7 + 1;
    • 7 ÷ 2 = 3 + 1;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
    • We have encountered a quotient that is ZERO => FULL STOP
  • 3. Construct the base 2 representation of the integer part of the number by taking all the remainders of the previous dividing operations, starting from the bottom of the list constructed above:

    31(10) = 1 1111(2)

  • 4. Then, convert the fractional part, 0.640 215. Multiply repeatedly by 2, keeping track of each integer part of the results, until we get a fractional part that is equal to zero:
    • #) multiplying = integer + fractional part;
    • 1) 0.640 215 × 2 = 1 + 0.280 43;
    • 2) 0.280 43 × 2 = 0 + 0.560 86;
    • 3) 0.560 86 × 2 = 1 + 0.121 72;
    • 4) 0.121 72 × 2 = 0 + 0.243 44;
    • 5) 0.243 44 × 2 = 0 + 0.486 88;
    • 6) 0.486 88 × 2 = 0 + 0.973 76;
    • 7) 0.973 76 × 2 = 1 + 0.947 52;
    • 8) 0.947 52 × 2 = 1 + 0.895 04;
    • 9) 0.895 04 × 2 = 1 + 0.790 08;
    • 10) 0.790 08 × 2 = 1 + 0.580 16;
    • 11) 0.580 16 × 2 = 1 + 0.160 32;
    • 12) 0.160 32 × 2 = 0 + 0.320 64;
    • 13) 0.320 64 × 2 = 0 + 0.641 28;
    • 14) 0.641 28 × 2 = 1 + 0.282 56;
    • 15) 0.282 56 × 2 = 0 + 0.565 12;
    • 16) 0.565 12 × 2 = 1 + 0.130 24;
    • 17) 0.130 24 × 2 = 0 + 0.260 48;
    • 18) 0.260 48 × 2 = 0 + 0.520 96;
    • 19) 0.520 96 × 2 = 1 + 0.041 92;
    • 20) 0.041 92 × 2 = 0 + 0.083 84;
    • 21) 0.083 84 × 2 = 0 + 0.167 68;
    • 22) 0.167 68 × 2 = 0 + 0.335 36;
    • 23) 0.335 36 × 2 = 0 + 0.670 72;
    • 24) 0.670 72 × 2 = 1 + 0.341 44;
    • 25) 0.341 44 × 2 = 0 + 0.682 88;
    • 26) 0.682 88 × 2 = 1 + 0.365 76;
    • 27) 0.365 76 × 2 = 0 + 0.731 52;
    • 28) 0.731 52 × 2 = 1 + 0.463 04;
    • 29) 0.463 04 × 2 = 0 + 0.926 08;
    • 30) 0.926 08 × 2 = 1 + 0.852 16;
    • 31) 0.852 16 × 2 = 1 + 0.704 32;
    • 32) 0.704 32 × 2 = 1 + 0.408 64;
    • 33) 0.408 64 × 2 = 0 + 0.817 28;
    • 34) 0.817 28 × 2 = 1 + 0.634 56;
    • 35) 0.634 56 × 2 = 1 + 0.269 12;
    • 36) 0.269 12 × 2 = 0 + 0.538 24;
    • 37) 0.538 24 × 2 = 1 + 0.076 48;
    • 38) 0.076 48 × 2 = 0 + 0.152 96;
    • 39) 0.152 96 × 2 = 0 + 0.305 92;
    • 40) 0.305 92 × 2 = 0 + 0.611 84;
    • 41) 0.611 84 × 2 = 1 + 0.223 68;
    • 42) 0.223 68 × 2 = 0 + 0.447 36;
    • 43) 0.447 36 × 2 = 0 + 0.894 72;
    • 44) 0.894 72 × 2 = 1 + 0.789 44;
    • 45) 0.789 44 × 2 = 1 + 0.578 88;
    • 46) 0.578 88 × 2 = 1 + 0.157 76;
    • 47) 0.157 76 × 2 = 0 + 0.315 52;
    • 48) 0.315 52 × 2 = 0 + 0.631 04;
    • 49) 0.631 04 × 2 = 1 + 0.262 08;
    • 50) 0.262 08 × 2 = 0 + 0.524 16;
    • 51) 0.524 16 × 2 = 1 + 0.048 32;
    • 52) 0.048 32 × 2 = 0 + 0.096 64;
    • 53) 0.096 64 × 2 = 0 + 0.193 28;
    • We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit = 52) and at least one integer part that was different from zero => FULL STOP (losing precision...).
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the previous multiplying operations, starting from the top of the constructed list above:

    0.640 215(10) = 0.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 6. Summarizing - the positive number before normalization:

    31.640 215(10) = 1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 7. Normalize the binary representation of the number, shifting the decimal mark 4 positions to the left so that only one non-zero digit stays to the left of the decimal mark:

    31.640 215(10) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 20 =
    1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 24

  • 8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

    Sign: 1 (a negative number)

    Exponent (unadjusted): 4

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

  • 9. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary (base 2), by using the same technique of repeatedly dividing it by 2, as shown above:

    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1 = (4 + 1023)(10) = 1027(10) =
    100 0000 0011(2)

  • 10. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal sign) and adjust its length to 52 bits, by removing the excess bits, from the right (losing precision...):

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

    Mantissa (normalized): 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Conclusion:

    Sign (1 bit) = 1 (a negative number)

    Exponent (8 bits) = 100 0000 0011

    Mantissa (52 bits) = 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Number -31.640 215, converted from decimal system (base 10) to 64 bit double precision IEEE 754 binary floating point =
    1 - 100 0000 0011 - 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100