0.000 020 830 729 321 671 205 134 999 154 509 660 617 136 Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard

Convert decimal 0.000 020 830 729 321 671 205 134 999 154 509 660 617 136(10) to 64 bit double precision IEEE 754 binary floating point representation standard (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

What are the steps to convert decimal number
0.000 020 830 729 321 671 205 134 999 154 509 660 617 136(10) to 64 bit double precision IEEE 754 binary floating point representation (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

1. First, convert to binary (in base 2) the integer part: 0.
Divide the number repeatedly by 2.

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 0 ÷ 2 = 0 + 0;

2. Construct the base 2 representation of the integer part of the number.

Take all the remainders starting from the bottom of the list constructed above.

0(10) =

0(2)


3. Convert to binary (base 2) the fractional part: 0.000 020 830 729 321 671 205 134 999 154 509 660 617 136.

Multiply it repeatedly by 2.

Keep track of each integer part of the results.

Stop when we get a fractional part that is equal to zero.


  • #) multiplying = integer + fractional part;
  • 1) 0.000 020 830 729 321 671 205 134 999 154 509 660 617 136 × 2 = 0 + 0.000 041 661 458 643 342 410 269 998 309 019 321 234 272;
  • 2) 0.000 041 661 458 643 342 410 269 998 309 019 321 234 272 × 2 = 0 + 0.000 083 322 917 286 684 820 539 996 618 038 642 468 544;
  • 3) 0.000 083 322 917 286 684 820 539 996 618 038 642 468 544 × 2 = 0 + 0.000 166 645 834 573 369 641 079 993 236 077 284 937 088;
  • 4) 0.000 166 645 834 573 369 641 079 993 236 077 284 937 088 × 2 = 0 + 0.000 333 291 669 146 739 282 159 986 472 154 569 874 176;
  • 5) 0.000 333 291 669 146 739 282 159 986 472 154 569 874 176 × 2 = 0 + 0.000 666 583 338 293 478 564 319 972 944 309 139 748 352;
  • 6) 0.000 666 583 338 293 478 564 319 972 944 309 139 748 352 × 2 = 0 + 0.001 333 166 676 586 957 128 639 945 888 618 279 496 704;
  • 7) 0.001 333 166 676 586 957 128 639 945 888 618 279 496 704 × 2 = 0 + 0.002 666 333 353 173 914 257 279 891 777 236 558 993 408;
  • 8) 0.002 666 333 353 173 914 257 279 891 777 236 558 993 408 × 2 = 0 + 0.005 332 666 706 347 828 514 559 783 554 473 117 986 816;
  • 9) 0.005 332 666 706 347 828 514 559 783 554 473 117 986 816 × 2 = 0 + 0.010 665 333 412 695 657 029 119 567 108 946 235 973 632;
  • 10) 0.010 665 333 412 695 657 029 119 567 108 946 235 973 632 × 2 = 0 + 0.021 330 666 825 391 314 058 239 134 217 892 471 947 264;
  • 11) 0.021 330 666 825 391 314 058 239 134 217 892 471 947 264 × 2 = 0 + 0.042 661 333 650 782 628 116 478 268 435 784 943 894 528;
  • 12) 0.042 661 333 650 782 628 116 478 268 435 784 943 894 528 × 2 = 0 + 0.085 322 667 301 565 256 232 956 536 871 569 887 789 056;
  • 13) 0.085 322 667 301 565 256 232 956 536 871 569 887 789 056 × 2 = 0 + 0.170 645 334 603 130 512 465 913 073 743 139 775 578 112;
  • 14) 0.170 645 334 603 130 512 465 913 073 743 139 775 578 112 × 2 = 0 + 0.341 290 669 206 261 024 931 826 147 486 279 551 156 224;
  • 15) 0.341 290 669 206 261 024 931 826 147 486 279 551 156 224 × 2 = 0 + 0.682 581 338 412 522 049 863 652 294 972 559 102 312 448;
  • 16) 0.682 581 338 412 522 049 863 652 294 972 559 102 312 448 × 2 = 1 + 0.365 162 676 825 044 099 727 304 589 945 118 204 624 896;
  • 17) 0.365 162 676 825 044 099 727 304 589 945 118 204 624 896 × 2 = 0 + 0.730 325 353 650 088 199 454 609 179 890 236 409 249 792;
  • 18) 0.730 325 353 650 088 199 454 609 179 890 236 409 249 792 × 2 = 1 + 0.460 650 707 300 176 398 909 218 359 780 472 818 499 584;
  • 19) 0.460 650 707 300 176 398 909 218 359 780 472 818 499 584 × 2 = 0 + 0.921 301 414 600 352 797 818 436 719 560 945 636 999 168;
  • 20) 0.921 301 414 600 352 797 818 436 719 560 945 636 999 168 × 2 = 1 + 0.842 602 829 200 705 595 636 873 439 121 891 273 998 336;
  • 21) 0.842 602 829 200 705 595 636 873 439 121 891 273 998 336 × 2 = 1 + 0.685 205 658 401 411 191 273 746 878 243 782 547 996 672;
  • 22) 0.685 205 658 401 411 191 273 746 878 243 782 547 996 672 × 2 = 1 + 0.370 411 316 802 822 382 547 493 756 487 565 095 993 344;
  • 23) 0.370 411 316 802 822 382 547 493 756 487 565 095 993 344 × 2 = 0 + 0.740 822 633 605 644 765 094 987 512 975 130 191 986 688;
  • 24) 0.740 822 633 605 644 765 094 987 512 975 130 191 986 688 × 2 = 1 + 0.481 645 267 211 289 530 189 975 025 950 260 383 973 376;
  • 25) 0.481 645 267 211 289 530 189 975 025 950 260 383 973 376 × 2 = 0 + 0.963 290 534 422 579 060 379 950 051 900 520 767 946 752;
  • 26) 0.963 290 534 422 579 060 379 950 051 900 520 767 946 752 × 2 = 1 + 0.926 581 068 845 158 120 759 900 103 801 041 535 893 504;
  • 27) 0.926 581 068 845 158 120 759 900 103 801 041 535 893 504 × 2 = 1 + 0.853 162 137 690 316 241 519 800 207 602 083 071 787 008;
  • 28) 0.853 162 137 690 316 241 519 800 207 602 083 071 787 008 × 2 = 1 + 0.706 324 275 380 632 483 039 600 415 204 166 143 574 016;
  • 29) 0.706 324 275 380 632 483 039 600 415 204 166 143 574 016 × 2 = 1 + 0.412 648 550 761 264 966 079 200 830 408 332 287 148 032;
  • 30) 0.412 648 550 761 264 966 079 200 830 408 332 287 148 032 × 2 = 0 + 0.825 297 101 522 529 932 158 401 660 816 664 574 296 064;
  • 31) 0.825 297 101 522 529 932 158 401 660 816 664 574 296 064 × 2 = 1 + 0.650 594 203 045 059 864 316 803 321 633 329 148 592 128;
  • 32) 0.650 594 203 045 059 864 316 803 321 633 329 148 592 128 × 2 = 1 + 0.301 188 406 090 119 728 633 606 643 266 658 297 184 256;
  • 33) 0.301 188 406 090 119 728 633 606 643 266 658 297 184 256 × 2 = 0 + 0.602 376 812 180 239 457 267 213 286 533 316 594 368 512;
  • 34) 0.602 376 812 180 239 457 267 213 286 533 316 594 368 512 × 2 = 1 + 0.204 753 624 360 478 914 534 426 573 066 633 188 737 024;
  • 35) 0.204 753 624 360 478 914 534 426 573 066 633 188 737 024 × 2 = 0 + 0.409 507 248 720 957 829 068 853 146 133 266 377 474 048;
  • 36) 0.409 507 248 720 957 829 068 853 146 133 266 377 474 048 × 2 = 0 + 0.819 014 497 441 915 658 137 706 292 266 532 754 948 096;
  • 37) 0.819 014 497 441 915 658 137 706 292 266 532 754 948 096 × 2 = 1 + 0.638 028 994 883 831 316 275 412 584 533 065 509 896 192;
  • 38) 0.638 028 994 883 831 316 275 412 584 533 065 509 896 192 × 2 = 1 + 0.276 057 989 767 662 632 550 825 169 066 131 019 792 384;
  • 39) 0.276 057 989 767 662 632 550 825 169 066 131 019 792 384 × 2 = 0 + 0.552 115 979 535 325 265 101 650 338 132 262 039 584 768;
  • 40) 0.552 115 979 535 325 265 101 650 338 132 262 039 584 768 × 2 = 1 + 0.104 231 959 070 650 530 203 300 676 264 524 079 169 536;
  • 41) 0.104 231 959 070 650 530 203 300 676 264 524 079 169 536 × 2 = 0 + 0.208 463 918 141 301 060 406 601 352 529 048 158 339 072;
  • 42) 0.208 463 918 141 301 060 406 601 352 529 048 158 339 072 × 2 = 0 + 0.416 927 836 282 602 120 813 202 705 058 096 316 678 144;
  • 43) 0.416 927 836 282 602 120 813 202 705 058 096 316 678 144 × 2 = 0 + 0.833 855 672 565 204 241 626 405 410 116 192 633 356 288;
  • 44) 0.833 855 672 565 204 241 626 405 410 116 192 633 356 288 × 2 = 1 + 0.667 711 345 130 408 483 252 810 820 232 385 266 712 576;
  • 45) 0.667 711 345 130 408 483 252 810 820 232 385 266 712 576 × 2 = 1 + 0.335 422 690 260 816 966 505 621 640 464 770 533 425 152;
  • 46) 0.335 422 690 260 816 966 505 621 640 464 770 533 425 152 × 2 = 0 + 0.670 845 380 521 633 933 011 243 280 929 541 066 850 304;
  • 47) 0.670 845 380 521 633 933 011 243 280 929 541 066 850 304 × 2 = 1 + 0.341 690 761 043 267 866 022 486 561 859 082 133 700 608;
  • 48) 0.341 690 761 043 267 866 022 486 561 859 082 133 700 608 × 2 = 0 + 0.683 381 522 086 535 732 044 973 123 718 164 267 401 216;
  • 49) 0.683 381 522 086 535 732 044 973 123 718 164 267 401 216 × 2 = 1 + 0.366 763 044 173 071 464 089 946 247 436 328 534 802 432;
  • 50) 0.366 763 044 173 071 464 089 946 247 436 328 534 802 432 × 2 = 0 + 0.733 526 088 346 142 928 179 892 494 872 657 069 604 864;
  • 51) 0.733 526 088 346 142 928 179 892 494 872 657 069 604 864 × 2 = 1 + 0.467 052 176 692 285 856 359 784 989 745 314 139 209 728;
  • 52) 0.467 052 176 692 285 856 359 784 989 745 314 139 209 728 × 2 = 0 + 0.934 104 353 384 571 712 719 569 979 490 628 278 419 456;
  • 53) 0.934 104 353 384 571 712 719 569 979 490 628 278 419 456 × 2 = 1 + 0.868 208 706 769 143 425 439 139 958 981 256 556 838 912;
  • 54) 0.868 208 706 769 143 425 439 139 958 981 256 556 838 912 × 2 = 1 + 0.736 417 413 538 286 850 878 279 917 962 513 113 677 824;
  • 55) 0.736 417 413 538 286 850 878 279 917 962 513 113 677 824 × 2 = 1 + 0.472 834 827 076 573 701 756 559 835 925 026 227 355 648;
  • 56) 0.472 834 827 076 573 701 756 559 835 925 026 227 355 648 × 2 = 0 + 0.945 669 654 153 147 403 513 119 671 850 052 454 711 296;
  • 57) 0.945 669 654 153 147 403 513 119 671 850 052 454 711 296 × 2 = 1 + 0.891 339 308 306 294 807 026 239 343 700 104 909 422 592;
  • 58) 0.891 339 308 306 294 807 026 239 343 700 104 909 422 592 × 2 = 1 + 0.782 678 616 612 589 614 052 478 687 400 209 818 845 184;
  • 59) 0.782 678 616 612 589 614 052 478 687 400 209 818 845 184 × 2 = 1 + 0.565 357 233 225 179 228 104 957 374 800 419 637 690 368;
  • 60) 0.565 357 233 225 179 228 104 957 374 800 419 637 690 368 × 2 = 1 + 0.130 714 466 450 358 456 209 914 749 600 839 275 380 736;
  • 61) 0.130 714 466 450 358 456 209 914 749 600 839 275 380 736 × 2 = 0 + 0.261 428 932 900 716 912 419 829 499 201 678 550 761 472;
  • 62) 0.261 428 932 900 716 912 419 829 499 201 678 550 761 472 × 2 = 0 + 0.522 857 865 801 433 824 839 658 998 403 357 101 522 944;
  • 63) 0.522 857 865 801 433 824 839 658 998 403 357 101 522 944 × 2 = 1 + 0.045 715 731 602 867 649 679 317 996 806 714 203 045 888;
  • 64) 0.045 715 731 602 867 649 679 317 996 806 714 203 045 888 × 2 = 0 + 0.091 431 463 205 735 299 358 635 993 613 428 406 091 776;
  • 65) 0.091 431 463 205 735 299 358 635 993 613 428 406 091 776 × 2 = 0 + 0.182 862 926 411 470 598 717 271 987 226 856 812 183 552;
  • 66) 0.182 862 926 411 470 598 717 271 987 226 856 812 183 552 × 2 = 0 + 0.365 725 852 822 941 197 434 543 974 453 713 624 367 104;
  • 67) 0.365 725 852 822 941 197 434 543 974 453 713 624 367 104 × 2 = 0 + 0.731 451 705 645 882 394 869 087 948 907 427 248 734 208;
  • 68) 0.731 451 705 645 882 394 869 087 948 907 427 248 734 208 × 2 = 1 + 0.462 903 411 291 764 789 738 175 897 814 854 497 468 416;

We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit) and at least one integer that was different from zero => FULL STOP (Losing precision - the converted number we get in the end will be just a very good approximation of the initial one).


4. Construct the base 2 representation of the fractional part of the number.

Take all the integer parts of the multiplying operations, starting from the top of the constructed list above:


0.000 020 830 729 321 671 205 134 999 154 509 660 617 136(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2)

5. Positive number before normalization:

0.000 020 830 729 321 671 205 134 999 154 509 660 617 136(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2)

6. Normalize the binary representation of the number.

Shift the decimal mark 16 positions to the right, so that only one non zero digit remains to the left of it:


0.000 020 830 729 321 671 205 134 999 154 509 660 617 136(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) × 20 =

1.0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) × 2-16


7. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

Sign 0 (a positive number)

Exponent (unadjusted): -16

Mantissa (not normalized):
1.0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


8. Adjust the exponent.

Use the 11 bit excess/bias notation:


Exponent (adjusted) =

Exponent (unadjusted) + 2(11-1) - 1 =

-16 + 2(11-1) - 1 =

(-16 + 1 023)(10) =

1 007(10)


9. Convert the adjusted exponent from the decimal (base 10) to 11 bit binary.

Use the same technique of repeatedly dividing by 2:


  • division = quotient + remainder;
  • 1 007 ÷ 2 = 503 + 1;
  • 503 ÷ 2 = 251 + 1;
  • 251 ÷ 2 = 125 + 1;
  • 125 ÷ 2 = 62 + 1;
  • 62 ÷ 2 = 31 + 0;
  • 31 ÷ 2 = 15 + 1;
  • 15 ÷ 2 = 7 + 1;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

10. Construct the base 2 representation of the adjusted exponent.

Take all the remainders starting from the bottom of the list constructed above.


Exponent (adjusted) =

1007(10) =

011 1110 1111(2)


11. Normalize the mantissa.

a) Remove the leading (the leftmost) bit, since it's allways 1, and the decimal point, if the case.

b) Adjust its length to 52 bits, only if necessary (not the case here).


Mantissa (normalized) =

1. 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001 =

0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


12. The three elements that make up the number's 64 bit double precision IEEE 754 binary floating point representation:

Sign (1 bit) =
0 (a positive number)

Exponent (11 bits) =
011 1110 1111

Mantissa (52 bits) =
0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


Decimal number 0.000 020 830 729 321 671 205 134 999 154 509 660 617 136 converted to 64 bit double precision IEEE 754 binary floating point representation:

0 - 011 1110 1111 - 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001

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How to convert numbers from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point standard

Follow the steps below to convert a base 10 decimal number to 64 bit double precision IEEE 754 binary floating point:

  • 1. If the number to be converted is negative, start with its the positive version.
  • 2. First convert the integer part. Divide repeatedly by 2 the positive representation of the integer number that is to be converted to binary, until we get a quotient that is equal to zero, keeping track of each remainder.
  • 3. Construct the base 2 representation of the positive integer part of the number, by taking all the remainders from the previous operations, starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Then convert the fractional part. Multiply the number repeatedly by 2, until we get a fractional part that is equal to zero, keeping track of each integer part of the results.
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the multiplying operations, starting from the top of the list constructed above (they should appear in the binary representation, from left to right, in the order they have been calculated).
  • 6. Normalize the binary representation of the number, shifting the decimal mark (the decimal point) "n" positions either to the left, or to the right, so that only one non zero digit remains to the left of the decimal mark.
  • 7. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary, by using the same technique of repeatedly dividing by 2, as shown above:
    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1
  • 8. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal mark, if the case) and adjust its length to 52 bits, either by removing the excess bits from the right (losing precision...) or by adding extra bits set on '0' to the right.
  • 9. Sign (it takes 1 bit) is either 1 for a negative or 0 for a positive number.

Example: convert the negative number -31.640 215 from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point:

  • 1. Start with the positive version of the number:

    |-31.640 215| = 31.640 215

  • 2. First convert the integer part, 31. Divide it repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 31 ÷ 2 = 15 + 1;
    • 15 ÷ 2 = 7 + 1;
    • 7 ÷ 2 = 3 + 1;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
    • We have encountered a quotient that is ZERO => FULL STOP
  • 3. Construct the base 2 representation of the integer part of the number by taking all the remainders of the previous dividing operations, starting from the bottom of the list constructed above:

    31(10) = 1 1111(2)

  • 4. Then, convert the fractional part, 0.640 215. Multiply repeatedly by 2, keeping track of each integer part of the results, until we get a fractional part that is equal to zero:
    • #) multiplying = integer + fractional part;
    • 1) 0.640 215 × 2 = 1 + 0.280 43;
    • 2) 0.280 43 × 2 = 0 + 0.560 86;
    • 3) 0.560 86 × 2 = 1 + 0.121 72;
    • 4) 0.121 72 × 2 = 0 + 0.243 44;
    • 5) 0.243 44 × 2 = 0 + 0.486 88;
    • 6) 0.486 88 × 2 = 0 + 0.973 76;
    • 7) 0.973 76 × 2 = 1 + 0.947 52;
    • 8) 0.947 52 × 2 = 1 + 0.895 04;
    • 9) 0.895 04 × 2 = 1 + 0.790 08;
    • 10) 0.790 08 × 2 = 1 + 0.580 16;
    • 11) 0.580 16 × 2 = 1 + 0.160 32;
    • 12) 0.160 32 × 2 = 0 + 0.320 64;
    • 13) 0.320 64 × 2 = 0 + 0.641 28;
    • 14) 0.641 28 × 2 = 1 + 0.282 56;
    • 15) 0.282 56 × 2 = 0 + 0.565 12;
    • 16) 0.565 12 × 2 = 1 + 0.130 24;
    • 17) 0.130 24 × 2 = 0 + 0.260 48;
    • 18) 0.260 48 × 2 = 0 + 0.520 96;
    • 19) 0.520 96 × 2 = 1 + 0.041 92;
    • 20) 0.041 92 × 2 = 0 + 0.083 84;
    • 21) 0.083 84 × 2 = 0 + 0.167 68;
    • 22) 0.167 68 × 2 = 0 + 0.335 36;
    • 23) 0.335 36 × 2 = 0 + 0.670 72;
    • 24) 0.670 72 × 2 = 1 + 0.341 44;
    • 25) 0.341 44 × 2 = 0 + 0.682 88;
    • 26) 0.682 88 × 2 = 1 + 0.365 76;
    • 27) 0.365 76 × 2 = 0 + 0.731 52;
    • 28) 0.731 52 × 2 = 1 + 0.463 04;
    • 29) 0.463 04 × 2 = 0 + 0.926 08;
    • 30) 0.926 08 × 2 = 1 + 0.852 16;
    • 31) 0.852 16 × 2 = 1 + 0.704 32;
    • 32) 0.704 32 × 2 = 1 + 0.408 64;
    • 33) 0.408 64 × 2 = 0 + 0.817 28;
    • 34) 0.817 28 × 2 = 1 + 0.634 56;
    • 35) 0.634 56 × 2 = 1 + 0.269 12;
    • 36) 0.269 12 × 2 = 0 + 0.538 24;
    • 37) 0.538 24 × 2 = 1 + 0.076 48;
    • 38) 0.076 48 × 2 = 0 + 0.152 96;
    • 39) 0.152 96 × 2 = 0 + 0.305 92;
    • 40) 0.305 92 × 2 = 0 + 0.611 84;
    • 41) 0.611 84 × 2 = 1 + 0.223 68;
    • 42) 0.223 68 × 2 = 0 + 0.447 36;
    • 43) 0.447 36 × 2 = 0 + 0.894 72;
    • 44) 0.894 72 × 2 = 1 + 0.789 44;
    • 45) 0.789 44 × 2 = 1 + 0.578 88;
    • 46) 0.578 88 × 2 = 1 + 0.157 76;
    • 47) 0.157 76 × 2 = 0 + 0.315 52;
    • 48) 0.315 52 × 2 = 0 + 0.631 04;
    • 49) 0.631 04 × 2 = 1 + 0.262 08;
    • 50) 0.262 08 × 2 = 0 + 0.524 16;
    • 51) 0.524 16 × 2 = 1 + 0.048 32;
    • 52) 0.048 32 × 2 = 0 + 0.096 64;
    • 53) 0.096 64 × 2 = 0 + 0.193 28;
    • We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit = 52) and at least one integer part that was different from zero => FULL STOP (losing precision...).
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the previous multiplying operations, starting from the top of the constructed list above:

    0.640 215(10) = 0.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 6. Summarizing - the positive number before normalization:

    31.640 215(10) = 1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 7. Normalize the binary representation of the number, shifting the decimal mark 4 positions to the left so that only one non-zero digit stays to the left of the decimal mark:

    31.640 215(10) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 20 =
    1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 24

  • 8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

    Sign: 1 (a negative number)

    Exponent (unadjusted): 4

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

  • 9. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary (base 2), by using the same technique of repeatedly dividing it by 2, as shown above:

    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1 = (4 + 1023)(10) = 1027(10) =
    100 0000 0011(2)

  • 10. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal sign) and adjust its length to 52 bits, by removing the excess bits, from the right (losing precision...):

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

    Mantissa (normalized): 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Conclusion:

    Sign (1 bit) = 1 (a negative number)

    Exponent (8 bits) = 100 0000 0011

    Mantissa (52 bits) = 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Number -31.640 215, converted from decimal system (base 10) to 64 bit double precision IEEE 754 binary floating point =
    1 - 100 0000 0011 - 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100