0.000 020 830 729 321 671 205 134 999 154 509 53 Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard

Convert decimal 0.000 020 830 729 321 671 205 134 999 154 509 53(10) to 64 bit double precision IEEE 754 binary floating point representation standard (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

What are the steps to convert decimal number
0.000 020 830 729 321 671 205 134 999 154 509 53(10) to 64 bit double precision IEEE 754 binary floating point representation (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

1. First, convert to binary (in base 2) the integer part: 0.
Divide the number repeatedly by 2.

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 0 ÷ 2 = 0 + 0;

2. Construct the base 2 representation of the integer part of the number.

Take all the remainders starting from the bottom of the list constructed above.

0(10) =

0(2)


3. Convert to binary (base 2) the fractional part: 0.000 020 830 729 321 671 205 134 999 154 509 53.

Multiply it repeatedly by 2.

Keep track of each integer part of the results.

Stop when we get a fractional part that is equal to zero.


  • #) multiplying = integer + fractional part;
  • 1) 0.000 020 830 729 321 671 205 134 999 154 509 53 × 2 = 0 + 0.000 041 661 458 643 342 410 269 998 309 019 06;
  • 2) 0.000 041 661 458 643 342 410 269 998 309 019 06 × 2 = 0 + 0.000 083 322 917 286 684 820 539 996 618 038 12;
  • 3) 0.000 083 322 917 286 684 820 539 996 618 038 12 × 2 = 0 + 0.000 166 645 834 573 369 641 079 993 236 076 24;
  • 4) 0.000 166 645 834 573 369 641 079 993 236 076 24 × 2 = 0 + 0.000 333 291 669 146 739 282 159 986 472 152 48;
  • 5) 0.000 333 291 669 146 739 282 159 986 472 152 48 × 2 = 0 + 0.000 666 583 338 293 478 564 319 972 944 304 96;
  • 6) 0.000 666 583 338 293 478 564 319 972 944 304 96 × 2 = 0 + 0.001 333 166 676 586 957 128 639 945 888 609 92;
  • 7) 0.001 333 166 676 586 957 128 639 945 888 609 92 × 2 = 0 + 0.002 666 333 353 173 914 257 279 891 777 219 84;
  • 8) 0.002 666 333 353 173 914 257 279 891 777 219 84 × 2 = 0 + 0.005 332 666 706 347 828 514 559 783 554 439 68;
  • 9) 0.005 332 666 706 347 828 514 559 783 554 439 68 × 2 = 0 + 0.010 665 333 412 695 657 029 119 567 108 879 36;
  • 10) 0.010 665 333 412 695 657 029 119 567 108 879 36 × 2 = 0 + 0.021 330 666 825 391 314 058 239 134 217 758 72;
  • 11) 0.021 330 666 825 391 314 058 239 134 217 758 72 × 2 = 0 + 0.042 661 333 650 782 628 116 478 268 435 517 44;
  • 12) 0.042 661 333 650 782 628 116 478 268 435 517 44 × 2 = 0 + 0.085 322 667 301 565 256 232 956 536 871 034 88;
  • 13) 0.085 322 667 301 565 256 232 956 536 871 034 88 × 2 = 0 + 0.170 645 334 603 130 512 465 913 073 742 069 76;
  • 14) 0.170 645 334 603 130 512 465 913 073 742 069 76 × 2 = 0 + 0.341 290 669 206 261 024 931 826 147 484 139 52;
  • 15) 0.341 290 669 206 261 024 931 826 147 484 139 52 × 2 = 0 + 0.682 581 338 412 522 049 863 652 294 968 279 04;
  • 16) 0.682 581 338 412 522 049 863 652 294 968 279 04 × 2 = 1 + 0.365 162 676 825 044 099 727 304 589 936 558 08;
  • 17) 0.365 162 676 825 044 099 727 304 589 936 558 08 × 2 = 0 + 0.730 325 353 650 088 199 454 609 179 873 116 16;
  • 18) 0.730 325 353 650 088 199 454 609 179 873 116 16 × 2 = 1 + 0.460 650 707 300 176 398 909 218 359 746 232 32;
  • 19) 0.460 650 707 300 176 398 909 218 359 746 232 32 × 2 = 0 + 0.921 301 414 600 352 797 818 436 719 492 464 64;
  • 20) 0.921 301 414 600 352 797 818 436 719 492 464 64 × 2 = 1 + 0.842 602 829 200 705 595 636 873 438 984 929 28;
  • 21) 0.842 602 829 200 705 595 636 873 438 984 929 28 × 2 = 1 + 0.685 205 658 401 411 191 273 746 877 969 858 56;
  • 22) 0.685 205 658 401 411 191 273 746 877 969 858 56 × 2 = 1 + 0.370 411 316 802 822 382 547 493 755 939 717 12;
  • 23) 0.370 411 316 802 822 382 547 493 755 939 717 12 × 2 = 0 + 0.740 822 633 605 644 765 094 987 511 879 434 24;
  • 24) 0.740 822 633 605 644 765 094 987 511 879 434 24 × 2 = 1 + 0.481 645 267 211 289 530 189 975 023 758 868 48;
  • 25) 0.481 645 267 211 289 530 189 975 023 758 868 48 × 2 = 0 + 0.963 290 534 422 579 060 379 950 047 517 736 96;
  • 26) 0.963 290 534 422 579 060 379 950 047 517 736 96 × 2 = 1 + 0.926 581 068 845 158 120 759 900 095 035 473 92;
  • 27) 0.926 581 068 845 158 120 759 900 095 035 473 92 × 2 = 1 + 0.853 162 137 690 316 241 519 800 190 070 947 84;
  • 28) 0.853 162 137 690 316 241 519 800 190 070 947 84 × 2 = 1 + 0.706 324 275 380 632 483 039 600 380 141 895 68;
  • 29) 0.706 324 275 380 632 483 039 600 380 141 895 68 × 2 = 1 + 0.412 648 550 761 264 966 079 200 760 283 791 36;
  • 30) 0.412 648 550 761 264 966 079 200 760 283 791 36 × 2 = 0 + 0.825 297 101 522 529 932 158 401 520 567 582 72;
  • 31) 0.825 297 101 522 529 932 158 401 520 567 582 72 × 2 = 1 + 0.650 594 203 045 059 864 316 803 041 135 165 44;
  • 32) 0.650 594 203 045 059 864 316 803 041 135 165 44 × 2 = 1 + 0.301 188 406 090 119 728 633 606 082 270 330 88;
  • 33) 0.301 188 406 090 119 728 633 606 082 270 330 88 × 2 = 0 + 0.602 376 812 180 239 457 267 212 164 540 661 76;
  • 34) 0.602 376 812 180 239 457 267 212 164 540 661 76 × 2 = 1 + 0.204 753 624 360 478 914 534 424 329 081 323 52;
  • 35) 0.204 753 624 360 478 914 534 424 329 081 323 52 × 2 = 0 + 0.409 507 248 720 957 829 068 848 658 162 647 04;
  • 36) 0.409 507 248 720 957 829 068 848 658 162 647 04 × 2 = 0 + 0.819 014 497 441 915 658 137 697 316 325 294 08;
  • 37) 0.819 014 497 441 915 658 137 697 316 325 294 08 × 2 = 1 + 0.638 028 994 883 831 316 275 394 632 650 588 16;
  • 38) 0.638 028 994 883 831 316 275 394 632 650 588 16 × 2 = 1 + 0.276 057 989 767 662 632 550 789 265 301 176 32;
  • 39) 0.276 057 989 767 662 632 550 789 265 301 176 32 × 2 = 0 + 0.552 115 979 535 325 265 101 578 530 602 352 64;
  • 40) 0.552 115 979 535 325 265 101 578 530 602 352 64 × 2 = 1 + 0.104 231 959 070 650 530 203 157 061 204 705 28;
  • 41) 0.104 231 959 070 650 530 203 157 061 204 705 28 × 2 = 0 + 0.208 463 918 141 301 060 406 314 122 409 410 56;
  • 42) 0.208 463 918 141 301 060 406 314 122 409 410 56 × 2 = 0 + 0.416 927 836 282 602 120 812 628 244 818 821 12;
  • 43) 0.416 927 836 282 602 120 812 628 244 818 821 12 × 2 = 0 + 0.833 855 672 565 204 241 625 256 489 637 642 24;
  • 44) 0.833 855 672 565 204 241 625 256 489 637 642 24 × 2 = 1 + 0.667 711 345 130 408 483 250 512 979 275 284 48;
  • 45) 0.667 711 345 130 408 483 250 512 979 275 284 48 × 2 = 1 + 0.335 422 690 260 816 966 501 025 958 550 568 96;
  • 46) 0.335 422 690 260 816 966 501 025 958 550 568 96 × 2 = 0 + 0.670 845 380 521 633 933 002 051 917 101 137 92;
  • 47) 0.670 845 380 521 633 933 002 051 917 101 137 92 × 2 = 1 + 0.341 690 761 043 267 866 004 103 834 202 275 84;
  • 48) 0.341 690 761 043 267 866 004 103 834 202 275 84 × 2 = 0 + 0.683 381 522 086 535 732 008 207 668 404 551 68;
  • 49) 0.683 381 522 086 535 732 008 207 668 404 551 68 × 2 = 1 + 0.366 763 044 173 071 464 016 415 336 809 103 36;
  • 50) 0.366 763 044 173 071 464 016 415 336 809 103 36 × 2 = 0 + 0.733 526 088 346 142 928 032 830 673 618 206 72;
  • 51) 0.733 526 088 346 142 928 032 830 673 618 206 72 × 2 = 1 + 0.467 052 176 692 285 856 065 661 347 236 413 44;
  • 52) 0.467 052 176 692 285 856 065 661 347 236 413 44 × 2 = 0 + 0.934 104 353 384 571 712 131 322 694 472 826 88;
  • 53) 0.934 104 353 384 571 712 131 322 694 472 826 88 × 2 = 1 + 0.868 208 706 769 143 424 262 645 388 945 653 76;
  • 54) 0.868 208 706 769 143 424 262 645 388 945 653 76 × 2 = 1 + 0.736 417 413 538 286 848 525 290 777 891 307 52;
  • 55) 0.736 417 413 538 286 848 525 290 777 891 307 52 × 2 = 1 + 0.472 834 827 076 573 697 050 581 555 782 615 04;
  • 56) 0.472 834 827 076 573 697 050 581 555 782 615 04 × 2 = 0 + 0.945 669 654 153 147 394 101 163 111 565 230 08;
  • 57) 0.945 669 654 153 147 394 101 163 111 565 230 08 × 2 = 1 + 0.891 339 308 306 294 788 202 326 223 130 460 16;
  • 58) 0.891 339 308 306 294 788 202 326 223 130 460 16 × 2 = 1 + 0.782 678 616 612 589 576 404 652 446 260 920 32;
  • 59) 0.782 678 616 612 589 576 404 652 446 260 920 32 × 2 = 1 + 0.565 357 233 225 179 152 809 304 892 521 840 64;
  • 60) 0.565 357 233 225 179 152 809 304 892 521 840 64 × 2 = 1 + 0.130 714 466 450 358 305 618 609 785 043 681 28;
  • 61) 0.130 714 466 450 358 305 618 609 785 043 681 28 × 2 = 0 + 0.261 428 932 900 716 611 237 219 570 087 362 56;
  • 62) 0.261 428 932 900 716 611 237 219 570 087 362 56 × 2 = 0 + 0.522 857 865 801 433 222 474 439 140 174 725 12;
  • 63) 0.522 857 865 801 433 222 474 439 140 174 725 12 × 2 = 1 + 0.045 715 731 602 866 444 948 878 280 349 450 24;
  • 64) 0.045 715 731 602 866 444 948 878 280 349 450 24 × 2 = 0 + 0.091 431 463 205 732 889 897 756 560 698 900 48;
  • 65) 0.091 431 463 205 732 889 897 756 560 698 900 48 × 2 = 0 + 0.182 862 926 411 465 779 795 513 121 397 800 96;
  • 66) 0.182 862 926 411 465 779 795 513 121 397 800 96 × 2 = 0 + 0.365 725 852 822 931 559 591 026 242 795 601 92;
  • 67) 0.365 725 852 822 931 559 591 026 242 795 601 92 × 2 = 0 + 0.731 451 705 645 863 119 182 052 485 591 203 84;
  • 68) 0.731 451 705 645 863 119 182 052 485 591 203 84 × 2 = 1 + 0.462 903 411 291 726 238 364 104 971 182 407 68;

We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit) and at least one integer that was different from zero => FULL STOP (Losing precision - the converted number we get in the end will be just a very good approximation of the initial one).


4. Construct the base 2 representation of the fractional part of the number.

Take all the integer parts of the multiplying operations, starting from the top of the constructed list above:


0.000 020 830 729 321 671 205 134 999 154 509 53(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2)

5. Positive number before normalization:

0.000 020 830 729 321 671 205 134 999 154 509 53(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2)

6. Normalize the binary representation of the number.

Shift the decimal mark 16 positions to the right, so that only one non zero digit remains to the left of it:


0.000 020 830 729 321 671 205 134 999 154 509 53(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) × 20 =

1.0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) × 2-16


7. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

Sign 0 (a positive number)

Exponent (unadjusted): -16

Mantissa (not normalized):
1.0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


8. Adjust the exponent.

Use the 11 bit excess/bias notation:


Exponent (adjusted) =

Exponent (unadjusted) + 2(11-1) - 1 =

-16 + 2(11-1) - 1 =

(-16 + 1 023)(10) =

1 007(10)


9. Convert the adjusted exponent from the decimal (base 10) to 11 bit binary.

Use the same technique of repeatedly dividing by 2:


  • division = quotient + remainder;
  • 1 007 ÷ 2 = 503 + 1;
  • 503 ÷ 2 = 251 + 1;
  • 251 ÷ 2 = 125 + 1;
  • 125 ÷ 2 = 62 + 1;
  • 62 ÷ 2 = 31 + 0;
  • 31 ÷ 2 = 15 + 1;
  • 15 ÷ 2 = 7 + 1;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

10. Construct the base 2 representation of the adjusted exponent.

Take all the remainders starting from the bottom of the list constructed above.


Exponent (adjusted) =

1007(10) =

011 1110 1111(2)


11. Normalize the mantissa.

a) Remove the leading (the leftmost) bit, since it's allways 1, and the decimal point, if the case.

b) Adjust its length to 52 bits, only if necessary (not the case here).


Mantissa (normalized) =

1. 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001 =

0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


12. The three elements that make up the number's 64 bit double precision IEEE 754 binary floating point representation:

Sign (1 bit) =
0 (a positive number)

Exponent (11 bits) =
011 1110 1111

Mantissa (52 bits) =
0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


Decimal number 0.000 020 830 729 321 671 205 134 999 154 509 53 converted to 64 bit double precision IEEE 754 binary floating point representation:

0 - 011 1110 1111 - 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001

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How to convert numbers from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point standard

Follow the steps below to convert a base 10 decimal number to 64 bit double precision IEEE 754 binary floating point:

  • 1. If the number to be converted is negative, start with its the positive version.
  • 2. First convert the integer part. Divide repeatedly by 2 the positive representation of the integer number that is to be converted to binary, until we get a quotient that is equal to zero, keeping track of each remainder.
  • 3. Construct the base 2 representation of the positive integer part of the number, by taking all the remainders from the previous operations, starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Then convert the fractional part. Multiply the number repeatedly by 2, until we get a fractional part that is equal to zero, keeping track of each integer part of the results.
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the multiplying operations, starting from the top of the list constructed above (they should appear in the binary representation, from left to right, in the order they have been calculated).
  • 6. Normalize the binary representation of the number, shifting the decimal mark (the decimal point) "n" positions either to the left, or to the right, so that only one non zero digit remains to the left of the decimal mark.
  • 7. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary, by using the same technique of repeatedly dividing by 2, as shown above:
    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1
  • 8. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal mark, if the case) and adjust its length to 52 bits, either by removing the excess bits from the right (losing precision...) or by adding extra bits set on '0' to the right.
  • 9. Sign (it takes 1 bit) is either 1 for a negative or 0 for a positive number.

Example: convert the negative number -31.640 215 from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point:

  • 1. Start with the positive version of the number:

    |-31.640 215| = 31.640 215

  • 2. First convert the integer part, 31. Divide it repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 31 ÷ 2 = 15 + 1;
    • 15 ÷ 2 = 7 + 1;
    • 7 ÷ 2 = 3 + 1;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
    • We have encountered a quotient that is ZERO => FULL STOP
  • 3. Construct the base 2 representation of the integer part of the number by taking all the remainders of the previous dividing operations, starting from the bottom of the list constructed above:

    31(10) = 1 1111(2)

  • 4. Then, convert the fractional part, 0.640 215. Multiply repeatedly by 2, keeping track of each integer part of the results, until we get a fractional part that is equal to zero:
    • #) multiplying = integer + fractional part;
    • 1) 0.640 215 × 2 = 1 + 0.280 43;
    • 2) 0.280 43 × 2 = 0 + 0.560 86;
    • 3) 0.560 86 × 2 = 1 + 0.121 72;
    • 4) 0.121 72 × 2 = 0 + 0.243 44;
    • 5) 0.243 44 × 2 = 0 + 0.486 88;
    • 6) 0.486 88 × 2 = 0 + 0.973 76;
    • 7) 0.973 76 × 2 = 1 + 0.947 52;
    • 8) 0.947 52 × 2 = 1 + 0.895 04;
    • 9) 0.895 04 × 2 = 1 + 0.790 08;
    • 10) 0.790 08 × 2 = 1 + 0.580 16;
    • 11) 0.580 16 × 2 = 1 + 0.160 32;
    • 12) 0.160 32 × 2 = 0 + 0.320 64;
    • 13) 0.320 64 × 2 = 0 + 0.641 28;
    • 14) 0.641 28 × 2 = 1 + 0.282 56;
    • 15) 0.282 56 × 2 = 0 + 0.565 12;
    • 16) 0.565 12 × 2 = 1 + 0.130 24;
    • 17) 0.130 24 × 2 = 0 + 0.260 48;
    • 18) 0.260 48 × 2 = 0 + 0.520 96;
    • 19) 0.520 96 × 2 = 1 + 0.041 92;
    • 20) 0.041 92 × 2 = 0 + 0.083 84;
    • 21) 0.083 84 × 2 = 0 + 0.167 68;
    • 22) 0.167 68 × 2 = 0 + 0.335 36;
    • 23) 0.335 36 × 2 = 0 + 0.670 72;
    • 24) 0.670 72 × 2 = 1 + 0.341 44;
    • 25) 0.341 44 × 2 = 0 + 0.682 88;
    • 26) 0.682 88 × 2 = 1 + 0.365 76;
    • 27) 0.365 76 × 2 = 0 + 0.731 52;
    • 28) 0.731 52 × 2 = 1 + 0.463 04;
    • 29) 0.463 04 × 2 = 0 + 0.926 08;
    • 30) 0.926 08 × 2 = 1 + 0.852 16;
    • 31) 0.852 16 × 2 = 1 + 0.704 32;
    • 32) 0.704 32 × 2 = 1 + 0.408 64;
    • 33) 0.408 64 × 2 = 0 + 0.817 28;
    • 34) 0.817 28 × 2 = 1 + 0.634 56;
    • 35) 0.634 56 × 2 = 1 + 0.269 12;
    • 36) 0.269 12 × 2 = 0 + 0.538 24;
    • 37) 0.538 24 × 2 = 1 + 0.076 48;
    • 38) 0.076 48 × 2 = 0 + 0.152 96;
    • 39) 0.152 96 × 2 = 0 + 0.305 92;
    • 40) 0.305 92 × 2 = 0 + 0.611 84;
    • 41) 0.611 84 × 2 = 1 + 0.223 68;
    • 42) 0.223 68 × 2 = 0 + 0.447 36;
    • 43) 0.447 36 × 2 = 0 + 0.894 72;
    • 44) 0.894 72 × 2 = 1 + 0.789 44;
    • 45) 0.789 44 × 2 = 1 + 0.578 88;
    • 46) 0.578 88 × 2 = 1 + 0.157 76;
    • 47) 0.157 76 × 2 = 0 + 0.315 52;
    • 48) 0.315 52 × 2 = 0 + 0.631 04;
    • 49) 0.631 04 × 2 = 1 + 0.262 08;
    • 50) 0.262 08 × 2 = 0 + 0.524 16;
    • 51) 0.524 16 × 2 = 1 + 0.048 32;
    • 52) 0.048 32 × 2 = 0 + 0.096 64;
    • 53) 0.096 64 × 2 = 0 + 0.193 28;
    • We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit = 52) and at least one integer part that was different from zero => FULL STOP (losing precision...).
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the previous multiplying operations, starting from the top of the constructed list above:

    0.640 215(10) = 0.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 6. Summarizing - the positive number before normalization:

    31.640 215(10) = 1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 7. Normalize the binary representation of the number, shifting the decimal mark 4 positions to the left so that only one non-zero digit stays to the left of the decimal mark:

    31.640 215(10) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 20 =
    1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 24

  • 8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

    Sign: 1 (a negative number)

    Exponent (unadjusted): 4

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

  • 9. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary (base 2), by using the same technique of repeatedly dividing it by 2, as shown above:

    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1 = (4 + 1023)(10) = 1027(10) =
    100 0000 0011(2)

  • 10. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal sign) and adjust its length to 52 bits, by removing the excess bits, from the right (losing precision...):

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

    Mantissa (normalized): 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Conclusion:

    Sign (1 bit) = 1 (a negative number)

    Exponent (8 bits) = 100 0000 0011

    Mantissa (52 bits) = 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Number -31.640 215, converted from decimal system (base 10) to 64 bit double precision IEEE 754 binary floating point =
    1 - 100 0000 0011 - 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100