0.000 020 830 729 321 671 205 134 999 154 508 84 Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard

Convert decimal 0.000 020 830 729 321 671 205 134 999 154 508 84(10) to 64 bit double precision IEEE 754 binary floating point representation standard (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

What are the steps to convert decimal number
0.000 020 830 729 321 671 205 134 999 154 508 84(10) to 64 bit double precision IEEE 754 binary floating point representation (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

1. First, convert to binary (in base 2) the integer part: 0.
Divide the number repeatedly by 2.

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 0 ÷ 2 = 0 + 0;

2. Construct the base 2 representation of the integer part of the number.

Take all the remainders starting from the bottom of the list constructed above.

0(10) =

0(2)


3. Convert to binary (base 2) the fractional part: 0.000 020 830 729 321 671 205 134 999 154 508 84.

Multiply it repeatedly by 2.

Keep track of each integer part of the results.

Stop when we get a fractional part that is equal to zero.


  • #) multiplying = integer + fractional part;
  • 1) 0.000 020 830 729 321 671 205 134 999 154 508 84 × 2 = 0 + 0.000 041 661 458 643 342 410 269 998 309 017 68;
  • 2) 0.000 041 661 458 643 342 410 269 998 309 017 68 × 2 = 0 + 0.000 083 322 917 286 684 820 539 996 618 035 36;
  • 3) 0.000 083 322 917 286 684 820 539 996 618 035 36 × 2 = 0 + 0.000 166 645 834 573 369 641 079 993 236 070 72;
  • 4) 0.000 166 645 834 573 369 641 079 993 236 070 72 × 2 = 0 + 0.000 333 291 669 146 739 282 159 986 472 141 44;
  • 5) 0.000 333 291 669 146 739 282 159 986 472 141 44 × 2 = 0 + 0.000 666 583 338 293 478 564 319 972 944 282 88;
  • 6) 0.000 666 583 338 293 478 564 319 972 944 282 88 × 2 = 0 + 0.001 333 166 676 586 957 128 639 945 888 565 76;
  • 7) 0.001 333 166 676 586 957 128 639 945 888 565 76 × 2 = 0 + 0.002 666 333 353 173 914 257 279 891 777 131 52;
  • 8) 0.002 666 333 353 173 914 257 279 891 777 131 52 × 2 = 0 + 0.005 332 666 706 347 828 514 559 783 554 263 04;
  • 9) 0.005 332 666 706 347 828 514 559 783 554 263 04 × 2 = 0 + 0.010 665 333 412 695 657 029 119 567 108 526 08;
  • 10) 0.010 665 333 412 695 657 029 119 567 108 526 08 × 2 = 0 + 0.021 330 666 825 391 314 058 239 134 217 052 16;
  • 11) 0.021 330 666 825 391 314 058 239 134 217 052 16 × 2 = 0 + 0.042 661 333 650 782 628 116 478 268 434 104 32;
  • 12) 0.042 661 333 650 782 628 116 478 268 434 104 32 × 2 = 0 + 0.085 322 667 301 565 256 232 956 536 868 208 64;
  • 13) 0.085 322 667 301 565 256 232 956 536 868 208 64 × 2 = 0 + 0.170 645 334 603 130 512 465 913 073 736 417 28;
  • 14) 0.170 645 334 603 130 512 465 913 073 736 417 28 × 2 = 0 + 0.341 290 669 206 261 024 931 826 147 472 834 56;
  • 15) 0.341 290 669 206 261 024 931 826 147 472 834 56 × 2 = 0 + 0.682 581 338 412 522 049 863 652 294 945 669 12;
  • 16) 0.682 581 338 412 522 049 863 652 294 945 669 12 × 2 = 1 + 0.365 162 676 825 044 099 727 304 589 891 338 24;
  • 17) 0.365 162 676 825 044 099 727 304 589 891 338 24 × 2 = 0 + 0.730 325 353 650 088 199 454 609 179 782 676 48;
  • 18) 0.730 325 353 650 088 199 454 609 179 782 676 48 × 2 = 1 + 0.460 650 707 300 176 398 909 218 359 565 352 96;
  • 19) 0.460 650 707 300 176 398 909 218 359 565 352 96 × 2 = 0 + 0.921 301 414 600 352 797 818 436 719 130 705 92;
  • 20) 0.921 301 414 600 352 797 818 436 719 130 705 92 × 2 = 1 + 0.842 602 829 200 705 595 636 873 438 261 411 84;
  • 21) 0.842 602 829 200 705 595 636 873 438 261 411 84 × 2 = 1 + 0.685 205 658 401 411 191 273 746 876 522 823 68;
  • 22) 0.685 205 658 401 411 191 273 746 876 522 823 68 × 2 = 1 + 0.370 411 316 802 822 382 547 493 753 045 647 36;
  • 23) 0.370 411 316 802 822 382 547 493 753 045 647 36 × 2 = 0 + 0.740 822 633 605 644 765 094 987 506 091 294 72;
  • 24) 0.740 822 633 605 644 765 094 987 506 091 294 72 × 2 = 1 + 0.481 645 267 211 289 530 189 975 012 182 589 44;
  • 25) 0.481 645 267 211 289 530 189 975 012 182 589 44 × 2 = 0 + 0.963 290 534 422 579 060 379 950 024 365 178 88;
  • 26) 0.963 290 534 422 579 060 379 950 024 365 178 88 × 2 = 1 + 0.926 581 068 845 158 120 759 900 048 730 357 76;
  • 27) 0.926 581 068 845 158 120 759 900 048 730 357 76 × 2 = 1 + 0.853 162 137 690 316 241 519 800 097 460 715 52;
  • 28) 0.853 162 137 690 316 241 519 800 097 460 715 52 × 2 = 1 + 0.706 324 275 380 632 483 039 600 194 921 431 04;
  • 29) 0.706 324 275 380 632 483 039 600 194 921 431 04 × 2 = 1 + 0.412 648 550 761 264 966 079 200 389 842 862 08;
  • 30) 0.412 648 550 761 264 966 079 200 389 842 862 08 × 2 = 0 + 0.825 297 101 522 529 932 158 400 779 685 724 16;
  • 31) 0.825 297 101 522 529 932 158 400 779 685 724 16 × 2 = 1 + 0.650 594 203 045 059 864 316 801 559 371 448 32;
  • 32) 0.650 594 203 045 059 864 316 801 559 371 448 32 × 2 = 1 + 0.301 188 406 090 119 728 633 603 118 742 896 64;
  • 33) 0.301 188 406 090 119 728 633 603 118 742 896 64 × 2 = 0 + 0.602 376 812 180 239 457 267 206 237 485 793 28;
  • 34) 0.602 376 812 180 239 457 267 206 237 485 793 28 × 2 = 1 + 0.204 753 624 360 478 914 534 412 474 971 586 56;
  • 35) 0.204 753 624 360 478 914 534 412 474 971 586 56 × 2 = 0 + 0.409 507 248 720 957 829 068 824 949 943 173 12;
  • 36) 0.409 507 248 720 957 829 068 824 949 943 173 12 × 2 = 0 + 0.819 014 497 441 915 658 137 649 899 886 346 24;
  • 37) 0.819 014 497 441 915 658 137 649 899 886 346 24 × 2 = 1 + 0.638 028 994 883 831 316 275 299 799 772 692 48;
  • 38) 0.638 028 994 883 831 316 275 299 799 772 692 48 × 2 = 1 + 0.276 057 989 767 662 632 550 599 599 545 384 96;
  • 39) 0.276 057 989 767 662 632 550 599 599 545 384 96 × 2 = 0 + 0.552 115 979 535 325 265 101 199 199 090 769 92;
  • 40) 0.552 115 979 535 325 265 101 199 199 090 769 92 × 2 = 1 + 0.104 231 959 070 650 530 202 398 398 181 539 84;
  • 41) 0.104 231 959 070 650 530 202 398 398 181 539 84 × 2 = 0 + 0.208 463 918 141 301 060 404 796 796 363 079 68;
  • 42) 0.208 463 918 141 301 060 404 796 796 363 079 68 × 2 = 0 + 0.416 927 836 282 602 120 809 593 592 726 159 36;
  • 43) 0.416 927 836 282 602 120 809 593 592 726 159 36 × 2 = 0 + 0.833 855 672 565 204 241 619 187 185 452 318 72;
  • 44) 0.833 855 672 565 204 241 619 187 185 452 318 72 × 2 = 1 + 0.667 711 345 130 408 483 238 374 370 904 637 44;
  • 45) 0.667 711 345 130 408 483 238 374 370 904 637 44 × 2 = 1 + 0.335 422 690 260 816 966 476 748 741 809 274 88;
  • 46) 0.335 422 690 260 816 966 476 748 741 809 274 88 × 2 = 0 + 0.670 845 380 521 633 932 953 497 483 618 549 76;
  • 47) 0.670 845 380 521 633 932 953 497 483 618 549 76 × 2 = 1 + 0.341 690 761 043 267 865 906 994 967 237 099 52;
  • 48) 0.341 690 761 043 267 865 906 994 967 237 099 52 × 2 = 0 + 0.683 381 522 086 535 731 813 989 934 474 199 04;
  • 49) 0.683 381 522 086 535 731 813 989 934 474 199 04 × 2 = 1 + 0.366 763 044 173 071 463 627 979 868 948 398 08;
  • 50) 0.366 763 044 173 071 463 627 979 868 948 398 08 × 2 = 0 + 0.733 526 088 346 142 927 255 959 737 896 796 16;
  • 51) 0.733 526 088 346 142 927 255 959 737 896 796 16 × 2 = 1 + 0.467 052 176 692 285 854 511 919 475 793 592 32;
  • 52) 0.467 052 176 692 285 854 511 919 475 793 592 32 × 2 = 0 + 0.934 104 353 384 571 709 023 838 951 587 184 64;
  • 53) 0.934 104 353 384 571 709 023 838 951 587 184 64 × 2 = 1 + 0.868 208 706 769 143 418 047 677 903 174 369 28;
  • 54) 0.868 208 706 769 143 418 047 677 903 174 369 28 × 2 = 1 + 0.736 417 413 538 286 836 095 355 806 348 738 56;
  • 55) 0.736 417 413 538 286 836 095 355 806 348 738 56 × 2 = 1 + 0.472 834 827 076 573 672 190 711 612 697 477 12;
  • 56) 0.472 834 827 076 573 672 190 711 612 697 477 12 × 2 = 0 + 0.945 669 654 153 147 344 381 423 225 394 954 24;
  • 57) 0.945 669 654 153 147 344 381 423 225 394 954 24 × 2 = 1 + 0.891 339 308 306 294 688 762 846 450 789 908 48;
  • 58) 0.891 339 308 306 294 688 762 846 450 789 908 48 × 2 = 1 + 0.782 678 616 612 589 377 525 692 901 579 816 96;
  • 59) 0.782 678 616 612 589 377 525 692 901 579 816 96 × 2 = 1 + 0.565 357 233 225 178 755 051 385 803 159 633 92;
  • 60) 0.565 357 233 225 178 755 051 385 803 159 633 92 × 2 = 1 + 0.130 714 466 450 357 510 102 771 606 319 267 84;
  • 61) 0.130 714 466 450 357 510 102 771 606 319 267 84 × 2 = 0 + 0.261 428 932 900 715 020 205 543 212 638 535 68;
  • 62) 0.261 428 932 900 715 020 205 543 212 638 535 68 × 2 = 0 + 0.522 857 865 801 430 040 411 086 425 277 071 36;
  • 63) 0.522 857 865 801 430 040 411 086 425 277 071 36 × 2 = 1 + 0.045 715 731 602 860 080 822 172 850 554 142 72;
  • 64) 0.045 715 731 602 860 080 822 172 850 554 142 72 × 2 = 0 + 0.091 431 463 205 720 161 644 345 701 108 285 44;
  • 65) 0.091 431 463 205 720 161 644 345 701 108 285 44 × 2 = 0 + 0.182 862 926 411 440 323 288 691 402 216 570 88;
  • 66) 0.182 862 926 411 440 323 288 691 402 216 570 88 × 2 = 0 + 0.365 725 852 822 880 646 577 382 804 433 141 76;
  • 67) 0.365 725 852 822 880 646 577 382 804 433 141 76 × 2 = 0 + 0.731 451 705 645 761 293 154 765 608 866 283 52;
  • 68) 0.731 451 705 645 761 293 154 765 608 866 283 52 × 2 = 1 + 0.462 903 411 291 522 586 309 531 217 732 567 04;

We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit) and at least one integer that was different from zero => FULL STOP (Losing precision - the converted number we get in the end will be just a very good approximation of the initial one).


4. Construct the base 2 representation of the fractional part of the number.

Take all the integer parts of the multiplying operations, starting from the top of the constructed list above:


0.000 020 830 729 321 671 205 134 999 154 508 84(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2)

5. Positive number before normalization:

0.000 020 830 729 321 671 205 134 999 154 508 84(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2)

6. Normalize the binary representation of the number.

Shift the decimal mark 16 positions to the right, so that only one non zero digit remains to the left of it:


0.000 020 830 729 321 671 205 134 999 154 508 84(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) × 20 =

1.0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) × 2-16


7. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

Sign 0 (a positive number)

Exponent (unadjusted): -16

Mantissa (not normalized):
1.0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


8. Adjust the exponent.

Use the 11 bit excess/bias notation:


Exponent (adjusted) =

Exponent (unadjusted) + 2(11-1) - 1 =

-16 + 2(11-1) - 1 =

(-16 + 1 023)(10) =

1 007(10)


9. Convert the adjusted exponent from the decimal (base 10) to 11 bit binary.

Use the same technique of repeatedly dividing by 2:


  • division = quotient + remainder;
  • 1 007 ÷ 2 = 503 + 1;
  • 503 ÷ 2 = 251 + 1;
  • 251 ÷ 2 = 125 + 1;
  • 125 ÷ 2 = 62 + 1;
  • 62 ÷ 2 = 31 + 0;
  • 31 ÷ 2 = 15 + 1;
  • 15 ÷ 2 = 7 + 1;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

10. Construct the base 2 representation of the adjusted exponent.

Take all the remainders starting from the bottom of the list constructed above.


Exponent (adjusted) =

1007(10) =

011 1110 1111(2)


11. Normalize the mantissa.

a) Remove the leading (the leftmost) bit, since it's allways 1, and the decimal point, if the case.

b) Adjust its length to 52 bits, only if necessary (not the case here).


Mantissa (normalized) =

1. 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001 =

0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


12. The three elements that make up the number's 64 bit double precision IEEE 754 binary floating point representation:

Sign (1 bit) =
0 (a positive number)

Exponent (11 bits) =
011 1110 1111

Mantissa (52 bits) =
0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


Decimal number 0.000 020 830 729 321 671 205 134 999 154 508 84 converted to 64 bit double precision IEEE 754 binary floating point representation:

0 - 011 1110 1111 - 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001

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How to convert numbers from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point standard

Follow the steps below to convert a base 10 decimal number to 64 bit double precision IEEE 754 binary floating point:

  • 1. If the number to be converted is negative, start with its the positive version.
  • 2. First convert the integer part. Divide repeatedly by 2 the positive representation of the integer number that is to be converted to binary, until we get a quotient that is equal to zero, keeping track of each remainder.
  • 3. Construct the base 2 representation of the positive integer part of the number, by taking all the remainders from the previous operations, starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Then convert the fractional part. Multiply the number repeatedly by 2, until we get a fractional part that is equal to zero, keeping track of each integer part of the results.
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the multiplying operations, starting from the top of the list constructed above (they should appear in the binary representation, from left to right, in the order they have been calculated).
  • 6. Normalize the binary representation of the number, shifting the decimal mark (the decimal point) "n" positions either to the left, or to the right, so that only one non zero digit remains to the left of the decimal mark.
  • 7. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary, by using the same technique of repeatedly dividing by 2, as shown above:
    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1
  • 8. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal mark, if the case) and adjust its length to 52 bits, either by removing the excess bits from the right (losing precision...) or by adding extra bits set on '0' to the right.
  • 9. Sign (it takes 1 bit) is either 1 for a negative or 0 for a positive number.

Example: convert the negative number -31.640 215 from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point:

  • 1. Start with the positive version of the number:

    |-31.640 215| = 31.640 215

  • 2. First convert the integer part, 31. Divide it repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 31 ÷ 2 = 15 + 1;
    • 15 ÷ 2 = 7 + 1;
    • 7 ÷ 2 = 3 + 1;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
    • We have encountered a quotient that is ZERO => FULL STOP
  • 3. Construct the base 2 representation of the integer part of the number by taking all the remainders of the previous dividing operations, starting from the bottom of the list constructed above:

    31(10) = 1 1111(2)

  • 4. Then, convert the fractional part, 0.640 215. Multiply repeatedly by 2, keeping track of each integer part of the results, until we get a fractional part that is equal to zero:
    • #) multiplying = integer + fractional part;
    • 1) 0.640 215 × 2 = 1 + 0.280 43;
    • 2) 0.280 43 × 2 = 0 + 0.560 86;
    • 3) 0.560 86 × 2 = 1 + 0.121 72;
    • 4) 0.121 72 × 2 = 0 + 0.243 44;
    • 5) 0.243 44 × 2 = 0 + 0.486 88;
    • 6) 0.486 88 × 2 = 0 + 0.973 76;
    • 7) 0.973 76 × 2 = 1 + 0.947 52;
    • 8) 0.947 52 × 2 = 1 + 0.895 04;
    • 9) 0.895 04 × 2 = 1 + 0.790 08;
    • 10) 0.790 08 × 2 = 1 + 0.580 16;
    • 11) 0.580 16 × 2 = 1 + 0.160 32;
    • 12) 0.160 32 × 2 = 0 + 0.320 64;
    • 13) 0.320 64 × 2 = 0 + 0.641 28;
    • 14) 0.641 28 × 2 = 1 + 0.282 56;
    • 15) 0.282 56 × 2 = 0 + 0.565 12;
    • 16) 0.565 12 × 2 = 1 + 0.130 24;
    • 17) 0.130 24 × 2 = 0 + 0.260 48;
    • 18) 0.260 48 × 2 = 0 + 0.520 96;
    • 19) 0.520 96 × 2 = 1 + 0.041 92;
    • 20) 0.041 92 × 2 = 0 + 0.083 84;
    • 21) 0.083 84 × 2 = 0 + 0.167 68;
    • 22) 0.167 68 × 2 = 0 + 0.335 36;
    • 23) 0.335 36 × 2 = 0 + 0.670 72;
    • 24) 0.670 72 × 2 = 1 + 0.341 44;
    • 25) 0.341 44 × 2 = 0 + 0.682 88;
    • 26) 0.682 88 × 2 = 1 + 0.365 76;
    • 27) 0.365 76 × 2 = 0 + 0.731 52;
    • 28) 0.731 52 × 2 = 1 + 0.463 04;
    • 29) 0.463 04 × 2 = 0 + 0.926 08;
    • 30) 0.926 08 × 2 = 1 + 0.852 16;
    • 31) 0.852 16 × 2 = 1 + 0.704 32;
    • 32) 0.704 32 × 2 = 1 + 0.408 64;
    • 33) 0.408 64 × 2 = 0 + 0.817 28;
    • 34) 0.817 28 × 2 = 1 + 0.634 56;
    • 35) 0.634 56 × 2 = 1 + 0.269 12;
    • 36) 0.269 12 × 2 = 0 + 0.538 24;
    • 37) 0.538 24 × 2 = 1 + 0.076 48;
    • 38) 0.076 48 × 2 = 0 + 0.152 96;
    • 39) 0.152 96 × 2 = 0 + 0.305 92;
    • 40) 0.305 92 × 2 = 0 + 0.611 84;
    • 41) 0.611 84 × 2 = 1 + 0.223 68;
    • 42) 0.223 68 × 2 = 0 + 0.447 36;
    • 43) 0.447 36 × 2 = 0 + 0.894 72;
    • 44) 0.894 72 × 2 = 1 + 0.789 44;
    • 45) 0.789 44 × 2 = 1 + 0.578 88;
    • 46) 0.578 88 × 2 = 1 + 0.157 76;
    • 47) 0.157 76 × 2 = 0 + 0.315 52;
    • 48) 0.315 52 × 2 = 0 + 0.631 04;
    • 49) 0.631 04 × 2 = 1 + 0.262 08;
    • 50) 0.262 08 × 2 = 0 + 0.524 16;
    • 51) 0.524 16 × 2 = 1 + 0.048 32;
    • 52) 0.048 32 × 2 = 0 + 0.096 64;
    • 53) 0.096 64 × 2 = 0 + 0.193 28;
    • We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit = 52) and at least one integer part that was different from zero => FULL STOP (losing precision...).
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the previous multiplying operations, starting from the top of the constructed list above:

    0.640 215(10) = 0.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 6. Summarizing - the positive number before normalization:

    31.640 215(10) = 1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 7. Normalize the binary representation of the number, shifting the decimal mark 4 positions to the left so that only one non-zero digit stays to the left of the decimal mark:

    31.640 215(10) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 20 =
    1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 24

  • 8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

    Sign: 1 (a negative number)

    Exponent (unadjusted): 4

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

  • 9. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary (base 2), by using the same technique of repeatedly dividing it by 2, as shown above:

    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1 = (4 + 1023)(10) = 1027(10) =
    100 0000 0011(2)

  • 10. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal sign) and adjust its length to 52 bits, by removing the excess bits, from the right (losing precision...):

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

    Mantissa (normalized): 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Conclusion:

    Sign (1 bit) = 1 (a negative number)

    Exponent (8 bits) = 100 0000 0011

    Mantissa (52 bits) = 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Number -31.640 215, converted from decimal system (base 10) to 64 bit double precision IEEE 754 binary floating point =
    1 - 100 0000 0011 - 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100