0.000 020 830 729 321 671 205 134 999 154 507 79 Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard

Convert decimal 0.000 020 830 729 321 671 205 134 999 154 507 79(10) to 64 bit double precision IEEE 754 binary floating point representation standard (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

What are the steps to convert decimal number
0.000 020 830 729 321 671 205 134 999 154 507 79(10) to 64 bit double precision IEEE 754 binary floating point representation (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

1. First, convert to binary (in base 2) the integer part: 0.
Divide the number repeatedly by 2.

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 0 ÷ 2 = 0 + 0;

2. Construct the base 2 representation of the integer part of the number.

Take all the remainders starting from the bottom of the list constructed above.

0(10) =

0(2)


3. Convert to binary (base 2) the fractional part: 0.000 020 830 729 321 671 205 134 999 154 507 79.

Multiply it repeatedly by 2.

Keep track of each integer part of the results.

Stop when we get a fractional part that is equal to zero.


  • #) multiplying = integer + fractional part;
  • 1) 0.000 020 830 729 321 671 205 134 999 154 507 79 × 2 = 0 + 0.000 041 661 458 643 342 410 269 998 309 015 58;
  • 2) 0.000 041 661 458 643 342 410 269 998 309 015 58 × 2 = 0 + 0.000 083 322 917 286 684 820 539 996 618 031 16;
  • 3) 0.000 083 322 917 286 684 820 539 996 618 031 16 × 2 = 0 + 0.000 166 645 834 573 369 641 079 993 236 062 32;
  • 4) 0.000 166 645 834 573 369 641 079 993 236 062 32 × 2 = 0 + 0.000 333 291 669 146 739 282 159 986 472 124 64;
  • 5) 0.000 333 291 669 146 739 282 159 986 472 124 64 × 2 = 0 + 0.000 666 583 338 293 478 564 319 972 944 249 28;
  • 6) 0.000 666 583 338 293 478 564 319 972 944 249 28 × 2 = 0 + 0.001 333 166 676 586 957 128 639 945 888 498 56;
  • 7) 0.001 333 166 676 586 957 128 639 945 888 498 56 × 2 = 0 + 0.002 666 333 353 173 914 257 279 891 776 997 12;
  • 8) 0.002 666 333 353 173 914 257 279 891 776 997 12 × 2 = 0 + 0.005 332 666 706 347 828 514 559 783 553 994 24;
  • 9) 0.005 332 666 706 347 828 514 559 783 553 994 24 × 2 = 0 + 0.010 665 333 412 695 657 029 119 567 107 988 48;
  • 10) 0.010 665 333 412 695 657 029 119 567 107 988 48 × 2 = 0 + 0.021 330 666 825 391 314 058 239 134 215 976 96;
  • 11) 0.021 330 666 825 391 314 058 239 134 215 976 96 × 2 = 0 + 0.042 661 333 650 782 628 116 478 268 431 953 92;
  • 12) 0.042 661 333 650 782 628 116 478 268 431 953 92 × 2 = 0 + 0.085 322 667 301 565 256 232 956 536 863 907 84;
  • 13) 0.085 322 667 301 565 256 232 956 536 863 907 84 × 2 = 0 + 0.170 645 334 603 130 512 465 913 073 727 815 68;
  • 14) 0.170 645 334 603 130 512 465 913 073 727 815 68 × 2 = 0 + 0.341 290 669 206 261 024 931 826 147 455 631 36;
  • 15) 0.341 290 669 206 261 024 931 826 147 455 631 36 × 2 = 0 + 0.682 581 338 412 522 049 863 652 294 911 262 72;
  • 16) 0.682 581 338 412 522 049 863 652 294 911 262 72 × 2 = 1 + 0.365 162 676 825 044 099 727 304 589 822 525 44;
  • 17) 0.365 162 676 825 044 099 727 304 589 822 525 44 × 2 = 0 + 0.730 325 353 650 088 199 454 609 179 645 050 88;
  • 18) 0.730 325 353 650 088 199 454 609 179 645 050 88 × 2 = 1 + 0.460 650 707 300 176 398 909 218 359 290 101 76;
  • 19) 0.460 650 707 300 176 398 909 218 359 290 101 76 × 2 = 0 + 0.921 301 414 600 352 797 818 436 718 580 203 52;
  • 20) 0.921 301 414 600 352 797 818 436 718 580 203 52 × 2 = 1 + 0.842 602 829 200 705 595 636 873 437 160 407 04;
  • 21) 0.842 602 829 200 705 595 636 873 437 160 407 04 × 2 = 1 + 0.685 205 658 401 411 191 273 746 874 320 814 08;
  • 22) 0.685 205 658 401 411 191 273 746 874 320 814 08 × 2 = 1 + 0.370 411 316 802 822 382 547 493 748 641 628 16;
  • 23) 0.370 411 316 802 822 382 547 493 748 641 628 16 × 2 = 0 + 0.740 822 633 605 644 765 094 987 497 283 256 32;
  • 24) 0.740 822 633 605 644 765 094 987 497 283 256 32 × 2 = 1 + 0.481 645 267 211 289 530 189 974 994 566 512 64;
  • 25) 0.481 645 267 211 289 530 189 974 994 566 512 64 × 2 = 0 + 0.963 290 534 422 579 060 379 949 989 133 025 28;
  • 26) 0.963 290 534 422 579 060 379 949 989 133 025 28 × 2 = 1 + 0.926 581 068 845 158 120 759 899 978 266 050 56;
  • 27) 0.926 581 068 845 158 120 759 899 978 266 050 56 × 2 = 1 + 0.853 162 137 690 316 241 519 799 956 532 101 12;
  • 28) 0.853 162 137 690 316 241 519 799 956 532 101 12 × 2 = 1 + 0.706 324 275 380 632 483 039 599 913 064 202 24;
  • 29) 0.706 324 275 380 632 483 039 599 913 064 202 24 × 2 = 1 + 0.412 648 550 761 264 966 079 199 826 128 404 48;
  • 30) 0.412 648 550 761 264 966 079 199 826 128 404 48 × 2 = 0 + 0.825 297 101 522 529 932 158 399 652 256 808 96;
  • 31) 0.825 297 101 522 529 932 158 399 652 256 808 96 × 2 = 1 + 0.650 594 203 045 059 864 316 799 304 513 617 92;
  • 32) 0.650 594 203 045 059 864 316 799 304 513 617 92 × 2 = 1 + 0.301 188 406 090 119 728 633 598 609 027 235 84;
  • 33) 0.301 188 406 090 119 728 633 598 609 027 235 84 × 2 = 0 + 0.602 376 812 180 239 457 267 197 218 054 471 68;
  • 34) 0.602 376 812 180 239 457 267 197 218 054 471 68 × 2 = 1 + 0.204 753 624 360 478 914 534 394 436 108 943 36;
  • 35) 0.204 753 624 360 478 914 534 394 436 108 943 36 × 2 = 0 + 0.409 507 248 720 957 829 068 788 872 217 886 72;
  • 36) 0.409 507 248 720 957 829 068 788 872 217 886 72 × 2 = 0 + 0.819 014 497 441 915 658 137 577 744 435 773 44;
  • 37) 0.819 014 497 441 915 658 137 577 744 435 773 44 × 2 = 1 + 0.638 028 994 883 831 316 275 155 488 871 546 88;
  • 38) 0.638 028 994 883 831 316 275 155 488 871 546 88 × 2 = 1 + 0.276 057 989 767 662 632 550 310 977 743 093 76;
  • 39) 0.276 057 989 767 662 632 550 310 977 743 093 76 × 2 = 0 + 0.552 115 979 535 325 265 100 621 955 486 187 52;
  • 40) 0.552 115 979 535 325 265 100 621 955 486 187 52 × 2 = 1 + 0.104 231 959 070 650 530 201 243 910 972 375 04;
  • 41) 0.104 231 959 070 650 530 201 243 910 972 375 04 × 2 = 0 + 0.208 463 918 141 301 060 402 487 821 944 750 08;
  • 42) 0.208 463 918 141 301 060 402 487 821 944 750 08 × 2 = 0 + 0.416 927 836 282 602 120 804 975 643 889 500 16;
  • 43) 0.416 927 836 282 602 120 804 975 643 889 500 16 × 2 = 0 + 0.833 855 672 565 204 241 609 951 287 779 000 32;
  • 44) 0.833 855 672 565 204 241 609 951 287 779 000 32 × 2 = 1 + 0.667 711 345 130 408 483 219 902 575 558 000 64;
  • 45) 0.667 711 345 130 408 483 219 902 575 558 000 64 × 2 = 1 + 0.335 422 690 260 816 966 439 805 151 116 001 28;
  • 46) 0.335 422 690 260 816 966 439 805 151 116 001 28 × 2 = 0 + 0.670 845 380 521 633 932 879 610 302 232 002 56;
  • 47) 0.670 845 380 521 633 932 879 610 302 232 002 56 × 2 = 1 + 0.341 690 761 043 267 865 759 220 604 464 005 12;
  • 48) 0.341 690 761 043 267 865 759 220 604 464 005 12 × 2 = 0 + 0.683 381 522 086 535 731 518 441 208 928 010 24;
  • 49) 0.683 381 522 086 535 731 518 441 208 928 010 24 × 2 = 1 + 0.366 763 044 173 071 463 036 882 417 856 020 48;
  • 50) 0.366 763 044 173 071 463 036 882 417 856 020 48 × 2 = 0 + 0.733 526 088 346 142 926 073 764 835 712 040 96;
  • 51) 0.733 526 088 346 142 926 073 764 835 712 040 96 × 2 = 1 + 0.467 052 176 692 285 852 147 529 671 424 081 92;
  • 52) 0.467 052 176 692 285 852 147 529 671 424 081 92 × 2 = 0 + 0.934 104 353 384 571 704 295 059 342 848 163 84;
  • 53) 0.934 104 353 384 571 704 295 059 342 848 163 84 × 2 = 1 + 0.868 208 706 769 143 408 590 118 685 696 327 68;
  • 54) 0.868 208 706 769 143 408 590 118 685 696 327 68 × 2 = 1 + 0.736 417 413 538 286 817 180 237 371 392 655 36;
  • 55) 0.736 417 413 538 286 817 180 237 371 392 655 36 × 2 = 1 + 0.472 834 827 076 573 634 360 474 742 785 310 72;
  • 56) 0.472 834 827 076 573 634 360 474 742 785 310 72 × 2 = 0 + 0.945 669 654 153 147 268 720 949 485 570 621 44;
  • 57) 0.945 669 654 153 147 268 720 949 485 570 621 44 × 2 = 1 + 0.891 339 308 306 294 537 441 898 971 141 242 88;
  • 58) 0.891 339 308 306 294 537 441 898 971 141 242 88 × 2 = 1 + 0.782 678 616 612 589 074 883 797 942 282 485 76;
  • 59) 0.782 678 616 612 589 074 883 797 942 282 485 76 × 2 = 1 + 0.565 357 233 225 178 149 767 595 884 564 971 52;
  • 60) 0.565 357 233 225 178 149 767 595 884 564 971 52 × 2 = 1 + 0.130 714 466 450 356 299 535 191 769 129 943 04;
  • 61) 0.130 714 466 450 356 299 535 191 769 129 943 04 × 2 = 0 + 0.261 428 932 900 712 599 070 383 538 259 886 08;
  • 62) 0.261 428 932 900 712 599 070 383 538 259 886 08 × 2 = 0 + 0.522 857 865 801 425 198 140 767 076 519 772 16;
  • 63) 0.522 857 865 801 425 198 140 767 076 519 772 16 × 2 = 1 + 0.045 715 731 602 850 396 281 534 153 039 544 32;
  • 64) 0.045 715 731 602 850 396 281 534 153 039 544 32 × 2 = 0 + 0.091 431 463 205 700 792 563 068 306 079 088 64;
  • 65) 0.091 431 463 205 700 792 563 068 306 079 088 64 × 2 = 0 + 0.182 862 926 411 401 585 126 136 612 158 177 28;
  • 66) 0.182 862 926 411 401 585 126 136 612 158 177 28 × 2 = 0 + 0.365 725 852 822 803 170 252 273 224 316 354 56;
  • 67) 0.365 725 852 822 803 170 252 273 224 316 354 56 × 2 = 0 + 0.731 451 705 645 606 340 504 546 448 632 709 12;
  • 68) 0.731 451 705 645 606 340 504 546 448 632 709 12 × 2 = 1 + 0.462 903 411 291 212 681 009 092 897 265 418 24;

We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit) and at least one integer that was different from zero => FULL STOP (Losing precision - the converted number we get in the end will be just a very good approximation of the initial one).


4. Construct the base 2 representation of the fractional part of the number.

Take all the integer parts of the multiplying operations, starting from the top of the constructed list above:


0.000 020 830 729 321 671 205 134 999 154 507 79(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2)

5. Positive number before normalization:

0.000 020 830 729 321 671 205 134 999 154 507 79(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2)

6. Normalize the binary representation of the number.

Shift the decimal mark 16 positions to the right, so that only one non zero digit remains to the left of it:


0.000 020 830 729 321 671 205 134 999 154 507 79(10) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) =

0.0000 0000 0000 0001 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) × 20 =

1.0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001(2) × 2-16


7. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

Sign 0 (a positive number)

Exponent (unadjusted): -16

Mantissa (not normalized):
1.0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


8. Adjust the exponent.

Use the 11 bit excess/bias notation:


Exponent (adjusted) =

Exponent (unadjusted) + 2(11-1) - 1 =

-16 + 2(11-1) - 1 =

(-16 + 1 023)(10) =

1 007(10)


9. Convert the adjusted exponent from the decimal (base 10) to 11 bit binary.

Use the same technique of repeatedly dividing by 2:


  • division = quotient + remainder;
  • 1 007 ÷ 2 = 503 + 1;
  • 503 ÷ 2 = 251 + 1;
  • 251 ÷ 2 = 125 + 1;
  • 125 ÷ 2 = 62 + 1;
  • 62 ÷ 2 = 31 + 0;
  • 31 ÷ 2 = 15 + 1;
  • 15 ÷ 2 = 7 + 1;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

10. Construct the base 2 representation of the adjusted exponent.

Take all the remainders starting from the bottom of the list constructed above.


Exponent (adjusted) =

1007(10) =

011 1110 1111(2)


11. Normalize the mantissa.

a) Remove the leading (the leftmost) bit, since it's allways 1, and the decimal point, if the case.

b) Adjust its length to 52 bits, only if necessary (not the case here).


Mantissa (normalized) =

1. 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001 =

0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


12. The three elements that make up the number's 64 bit double precision IEEE 754 binary floating point representation:

Sign (1 bit) =
0 (a positive number)

Exponent (11 bits) =
011 1110 1111

Mantissa (52 bits) =
0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001


Decimal number 0.000 020 830 729 321 671 205 134 999 154 507 79 converted to 64 bit double precision IEEE 754 binary floating point representation:

0 - 011 1110 1111 - 0101 1101 0111 1011 0100 1101 0001 1010 1010 1110 1111 0010 0001

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How to convert numbers from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point standard

Follow the steps below to convert a base 10 decimal number to 64 bit double precision IEEE 754 binary floating point:

  • 1. If the number to be converted is negative, start with its the positive version.
  • 2. First convert the integer part. Divide repeatedly by 2 the positive representation of the integer number that is to be converted to binary, until we get a quotient that is equal to zero, keeping track of each remainder.
  • 3. Construct the base 2 representation of the positive integer part of the number, by taking all the remainders from the previous operations, starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Then convert the fractional part. Multiply the number repeatedly by 2, until we get a fractional part that is equal to zero, keeping track of each integer part of the results.
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the multiplying operations, starting from the top of the list constructed above (they should appear in the binary representation, from left to right, in the order they have been calculated).
  • 6. Normalize the binary representation of the number, shifting the decimal mark (the decimal point) "n" positions either to the left, or to the right, so that only one non zero digit remains to the left of the decimal mark.
  • 7. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary, by using the same technique of repeatedly dividing by 2, as shown above:
    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1
  • 8. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal mark, if the case) and adjust its length to 52 bits, either by removing the excess bits from the right (losing precision...) or by adding extra bits set on '0' to the right.
  • 9. Sign (it takes 1 bit) is either 1 for a negative or 0 for a positive number.

Example: convert the negative number -31.640 215 from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point:

  • 1. Start with the positive version of the number:

    |-31.640 215| = 31.640 215

  • 2. First convert the integer part, 31. Divide it repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 31 ÷ 2 = 15 + 1;
    • 15 ÷ 2 = 7 + 1;
    • 7 ÷ 2 = 3 + 1;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
    • We have encountered a quotient that is ZERO => FULL STOP
  • 3. Construct the base 2 representation of the integer part of the number by taking all the remainders of the previous dividing operations, starting from the bottom of the list constructed above:

    31(10) = 1 1111(2)

  • 4. Then, convert the fractional part, 0.640 215. Multiply repeatedly by 2, keeping track of each integer part of the results, until we get a fractional part that is equal to zero:
    • #) multiplying = integer + fractional part;
    • 1) 0.640 215 × 2 = 1 + 0.280 43;
    • 2) 0.280 43 × 2 = 0 + 0.560 86;
    • 3) 0.560 86 × 2 = 1 + 0.121 72;
    • 4) 0.121 72 × 2 = 0 + 0.243 44;
    • 5) 0.243 44 × 2 = 0 + 0.486 88;
    • 6) 0.486 88 × 2 = 0 + 0.973 76;
    • 7) 0.973 76 × 2 = 1 + 0.947 52;
    • 8) 0.947 52 × 2 = 1 + 0.895 04;
    • 9) 0.895 04 × 2 = 1 + 0.790 08;
    • 10) 0.790 08 × 2 = 1 + 0.580 16;
    • 11) 0.580 16 × 2 = 1 + 0.160 32;
    • 12) 0.160 32 × 2 = 0 + 0.320 64;
    • 13) 0.320 64 × 2 = 0 + 0.641 28;
    • 14) 0.641 28 × 2 = 1 + 0.282 56;
    • 15) 0.282 56 × 2 = 0 + 0.565 12;
    • 16) 0.565 12 × 2 = 1 + 0.130 24;
    • 17) 0.130 24 × 2 = 0 + 0.260 48;
    • 18) 0.260 48 × 2 = 0 + 0.520 96;
    • 19) 0.520 96 × 2 = 1 + 0.041 92;
    • 20) 0.041 92 × 2 = 0 + 0.083 84;
    • 21) 0.083 84 × 2 = 0 + 0.167 68;
    • 22) 0.167 68 × 2 = 0 + 0.335 36;
    • 23) 0.335 36 × 2 = 0 + 0.670 72;
    • 24) 0.670 72 × 2 = 1 + 0.341 44;
    • 25) 0.341 44 × 2 = 0 + 0.682 88;
    • 26) 0.682 88 × 2 = 1 + 0.365 76;
    • 27) 0.365 76 × 2 = 0 + 0.731 52;
    • 28) 0.731 52 × 2 = 1 + 0.463 04;
    • 29) 0.463 04 × 2 = 0 + 0.926 08;
    • 30) 0.926 08 × 2 = 1 + 0.852 16;
    • 31) 0.852 16 × 2 = 1 + 0.704 32;
    • 32) 0.704 32 × 2 = 1 + 0.408 64;
    • 33) 0.408 64 × 2 = 0 + 0.817 28;
    • 34) 0.817 28 × 2 = 1 + 0.634 56;
    • 35) 0.634 56 × 2 = 1 + 0.269 12;
    • 36) 0.269 12 × 2 = 0 + 0.538 24;
    • 37) 0.538 24 × 2 = 1 + 0.076 48;
    • 38) 0.076 48 × 2 = 0 + 0.152 96;
    • 39) 0.152 96 × 2 = 0 + 0.305 92;
    • 40) 0.305 92 × 2 = 0 + 0.611 84;
    • 41) 0.611 84 × 2 = 1 + 0.223 68;
    • 42) 0.223 68 × 2 = 0 + 0.447 36;
    • 43) 0.447 36 × 2 = 0 + 0.894 72;
    • 44) 0.894 72 × 2 = 1 + 0.789 44;
    • 45) 0.789 44 × 2 = 1 + 0.578 88;
    • 46) 0.578 88 × 2 = 1 + 0.157 76;
    • 47) 0.157 76 × 2 = 0 + 0.315 52;
    • 48) 0.315 52 × 2 = 0 + 0.631 04;
    • 49) 0.631 04 × 2 = 1 + 0.262 08;
    • 50) 0.262 08 × 2 = 0 + 0.524 16;
    • 51) 0.524 16 × 2 = 1 + 0.048 32;
    • 52) 0.048 32 × 2 = 0 + 0.096 64;
    • 53) 0.096 64 × 2 = 0 + 0.193 28;
    • We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit = 52) and at least one integer part that was different from zero => FULL STOP (losing precision...).
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the previous multiplying operations, starting from the top of the constructed list above:

    0.640 215(10) = 0.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 6. Summarizing - the positive number before normalization:

    31.640 215(10) = 1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 7. Normalize the binary representation of the number, shifting the decimal mark 4 positions to the left so that only one non-zero digit stays to the left of the decimal mark:

    31.640 215(10) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 20 =
    1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 24

  • 8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

    Sign: 1 (a negative number)

    Exponent (unadjusted): 4

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

  • 9. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary (base 2), by using the same technique of repeatedly dividing it by 2, as shown above:

    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1 = (4 + 1023)(10) = 1027(10) =
    100 0000 0011(2)

  • 10. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal sign) and adjust its length to 52 bits, by removing the excess bits, from the right (losing precision...):

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

    Mantissa (normalized): 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Conclusion:

    Sign (1 bit) = 1 (a negative number)

    Exponent (8 bits) = 100 0000 0011

    Mantissa (52 bits) = 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Number -31.640 215, converted from decimal system (base 10) to 64 bit double precision IEEE 754 binary floating point =
    1 - 100 0000 0011 - 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100