-0.000 806 264 623 585 362 514 063 654 156 866 1 Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard

Convert decimal -0.000 806 264 623 585 362 514 063 654 156 866 1(10) to 64 bit double precision IEEE 754 binary floating point representation standard (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

What are the steps to convert decimal number
-0.000 806 264 623 585 362 514 063 654 156 866 1(10) to 64 bit double precision IEEE 754 binary floating point representation (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

1. Start with the positive version of the number:

|-0.000 806 264 623 585 362 514 063 654 156 866 1| = 0.000 806 264 623 585 362 514 063 654 156 866 1


2. First, convert to binary (in base 2) the integer part: 0.
Divide the number repeatedly by 2.

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 0 ÷ 2 = 0 + 0;

3. Construct the base 2 representation of the integer part of the number.

Take all the remainders starting from the bottom of the list constructed above.

0(10) =

0(2)


4. Convert to binary (base 2) the fractional part: 0.000 806 264 623 585 362 514 063 654 156 866 1.

Multiply it repeatedly by 2.

Keep track of each integer part of the results.

Stop when we get a fractional part that is equal to zero.


  • #) multiplying = integer + fractional part;
  • 1) 0.000 806 264 623 585 362 514 063 654 156 866 1 × 2 = 0 + 0.001 612 529 247 170 725 028 127 308 313 732 2;
  • 2) 0.001 612 529 247 170 725 028 127 308 313 732 2 × 2 = 0 + 0.003 225 058 494 341 450 056 254 616 627 464 4;
  • 3) 0.003 225 058 494 341 450 056 254 616 627 464 4 × 2 = 0 + 0.006 450 116 988 682 900 112 509 233 254 928 8;
  • 4) 0.006 450 116 988 682 900 112 509 233 254 928 8 × 2 = 0 + 0.012 900 233 977 365 800 225 018 466 509 857 6;
  • 5) 0.012 900 233 977 365 800 225 018 466 509 857 6 × 2 = 0 + 0.025 800 467 954 731 600 450 036 933 019 715 2;
  • 6) 0.025 800 467 954 731 600 450 036 933 019 715 2 × 2 = 0 + 0.051 600 935 909 463 200 900 073 866 039 430 4;
  • 7) 0.051 600 935 909 463 200 900 073 866 039 430 4 × 2 = 0 + 0.103 201 871 818 926 401 800 147 732 078 860 8;
  • 8) 0.103 201 871 818 926 401 800 147 732 078 860 8 × 2 = 0 + 0.206 403 743 637 852 803 600 295 464 157 721 6;
  • 9) 0.206 403 743 637 852 803 600 295 464 157 721 6 × 2 = 0 + 0.412 807 487 275 705 607 200 590 928 315 443 2;
  • 10) 0.412 807 487 275 705 607 200 590 928 315 443 2 × 2 = 0 + 0.825 614 974 551 411 214 401 181 856 630 886 4;
  • 11) 0.825 614 974 551 411 214 401 181 856 630 886 4 × 2 = 1 + 0.651 229 949 102 822 428 802 363 713 261 772 8;
  • 12) 0.651 229 949 102 822 428 802 363 713 261 772 8 × 2 = 1 + 0.302 459 898 205 644 857 604 727 426 523 545 6;
  • 13) 0.302 459 898 205 644 857 604 727 426 523 545 6 × 2 = 0 + 0.604 919 796 411 289 715 209 454 853 047 091 2;
  • 14) 0.604 919 796 411 289 715 209 454 853 047 091 2 × 2 = 1 + 0.209 839 592 822 579 430 418 909 706 094 182 4;
  • 15) 0.209 839 592 822 579 430 418 909 706 094 182 4 × 2 = 0 + 0.419 679 185 645 158 860 837 819 412 188 364 8;
  • 16) 0.419 679 185 645 158 860 837 819 412 188 364 8 × 2 = 0 + 0.839 358 371 290 317 721 675 638 824 376 729 6;
  • 17) 0.839 358 371 290 317 721 675 638 824 376 729 6 × 2 = 1 + 0.678 716 742 580 635 443 351 277 648 753 459 2;
  • 18) 0.678 716 742 580 635 443 351 277 648 753 459 2 × 2 = 1 + 0.357 433 485 161 270 886 702 555 297 506 918 4;
  • 19) 0.357 433 485 161 270 886 702 555 297 506 918 4 × 2 = 0 + 0.714 866 970 322 541 773 405 110 595 013 836 8;
  • 20) 0.714 866 970 322 541 773 405 110 595 013 836 8 × 2 = 1 + 0.429 733 940 645 083 546 810 221 190 027 673 6;
  • 21) 0.429 733 940 645 083 546 810 221 190 027 673 6 × 2 = 0 + 0.859 467 881 290 167 093 620 442 380 055 347 2;
  • 22) 0.859 467 881 290 167 093 620 442 380 055 347 2 × 2 = 1 + 0.718 935 762 580 334 187 240 884 760 110 694 4;
  • 23) 0.718 935 762 580 334 187 240 884 760 110 694 4 × 2 = 1 + 0.437 871 525 160 668 374 481 769 520 221 388 8;
  • 24) 0.437 871 525 160 668 374 481 769 520 221 388 8 × 2 = 0 + 0.875 743 050 321 336 748 963 539 040 442 777 6;
  • 25) 0.875 743 050 321 336 748 963 539 040 442 777 6 × 2 = 1 + 0.751 486 100 642 673 497 927 078 080 885 555 2;
  • 26) 0.751 486 100 642 673 497 927 078 080 885 555 2 × 2 = 1 + 0.502 972 201 285 346 995 854 156 161 771 110 4;
  • 27) 0.502 972 201 285 346 995 854 156 161 771 110 4 × 2 = 1 + 0.005 944 402 570 693 991 708 312 323 542 220 8;
  • 28) 0.005 944 402 570 693 991 708 312 323 542 220 8 × 2 = 0 + 0.011 888 805 141 387 983 416 624 647 084 441 6;
  • 29) 0.011 888 805 141 387 983 416 624 647 084 441 6 × 2 = 0 + 0.023 777 610 282 775 966 833 249 294 168 883 2;
  • 30) 0.023 777 610 282 775 966 833 249 294 168 883 2 × 2 = 0 + 0.047 555 220 565 551 933 666 498 588 337 766 4;
  • 31) 0.047 555 220 565 551 933 666 498 588 337 766 4 × 2 = 0 + 0.095 110 441 131 103 867 332 997 176 675 532 8;
  • 32) 0.095 110 441 131 103 867 332 997 176 675 532 8 × 2 = 0 + 0.190 220 882 262 207 734 665 994 353 351 065 6;
  • 33) 0.190 220 882 262 207 734 665 994 353 351 065 6 × 2 = 0 + 0.380 441 764 524 415 469 331 988 706 702 131 2;
  • 34) 0.380 441 764 524 415 469 331 988 706 702 131 2 × 2 = 0 + 0.760 883 529 048 830 938 663 977 413 404 262 4;
  • 35) 0.760 883 529 048 830 938 663 977 413 404 262 4 × 2 = 1 + 0.521 767 058 097 661 877 327 954 826 808 524 8;
  • 36) 0.521 767 058 097 661 877 327 954 826 808 524 8 × 2 = 1 + 0.043 534 116 195 323 754 655 909 653 617 049 6;
  • 37) 0.043 534 116 195 323 754 655 909 653 617 049 6 × 2 = 0 + 0.087 068 232 390 647 509 311 819 307 234 099 2;
  • 38) 0.087 068 232 390 647 509 311 819 307 234 099 2 × 2 = 0 + 0.174 136 464 781 295 018 623 638 614 468 198 4;
  • 39) 0.174 136 464 781 295 018 623 638 614 468 198 4 × 2 = 0 + 0.348 272 929 562 590 037 247 277 228 936 396 8;
  • 40) 0.348 272 929 562 590 037 247 277 228 936 396 8 × 2 = 0 + 0.696 545 859 125 180 074 494 554 457 872 793 6;
  • 41) 0.696 545 859 125 180 074 494 554 457 872 793 6 × 2 = 1 + 0.393 091 718 250 360 148 989 108 915 745 587 2;
  • 42) 0.393 091 718 250 360 148 989 108 915 745 587 2 × 2 = 0 + 0.786 183 436 500 720 297 978 217 831 491 174 4;
  • 43) 0.786 183 436 500 720 297 978 217 831 491 174 4 × 2 = 1 + 0.572 366 873 001 440 595 956 435 662 982 348 8;
  • 44) 0.572 366 873 001 440 595 956 435 662 982 348 8 × 2 = 1 + 0.144 733 746 002 881 191 912 871 325 964 697 6;
  • 45) 0.144 733 746 002 881 191 912 871 325 964 697 6 × 2 = 0 + 0.289 467 492 005 762 383 825 742 651 929 395 2;
  • 46) 0.289 467 492 005 762 383 825 742 651 929 395 2 × 2 = 0 + 0.578 934 984 011 524 767 651 485 303 858 790 4;
  • 47) 0.578 934 984 011 524 767 651 485 303 858 790 4 × 2 = 1 + 0.157 869 968 023 049 535 302 970 607 717 580 8;
  • 48) 0.157 869 968 023 049 535 302 970 607 717 580 8 × 2 = 0 + 0.315 739 936 046 099 070 605 941 215 435 161 6;
  • 49) 0.315 739 936 046 099 070 605 941 215 435 161 6 × 2 = 0 + 0.631 479 872 092 198 141 211 882 430 870 323 2;
  • 50) 0.631 479 872 092 198 141 211 882 430 870 323 2 × 2 = 1 + 0.262 959 744 184 396 282 423 764 861 740 646 4;
  • 51) 0.262 959 744 184 396 282 423 764 861 740 646 4 × 2 = 0 + 0.525 919 488 368 792 564 847 529 723 481 292 8;
  • 52) 0.525 919 488 368 792 564 847 529 723 481 292 8 × 2 = 1 + 0.051 838 976 737 585 129 695 059 446 962 585 6;
  • 53) 0.051 838 976 737 585 129 695 059 446 962 585 6 × 2 = 0 + 0.103 677 953 475 170 259 390 118 893 925 171 2;
  • 54) 0.103 677 953 475 170 259 390 118 893 925 171 2 × 2 = 0 + 0.207 355 906 950 340 518 780 237 787 850 342 4;
  • 55) 0.207 355 906 950 340 518 780 237 787 850 342 4 × 2 = 0 + 0.414 711 813 900 681 037 560 475 575 700 684 8;
  • 56) 0.414 711 813 900 681 037 560 475 575 700 684 8 × 2 = 0 + 0.829 423 627 801 362 075 120 951 151 401 369 6;
  • 57) 0.829 423 627 801 362 075 120 951 151 401 369 6 × 2 = 1 + 0.658 847 255 602 724 150 241 902 302 802 739 2;
  • 58) 0.658 847 255 602 724 150 241 902 302 802 739 2 × 2 = 1 + 0.317 694 511 205 448 300 483 804 605 605 478 4;
  • 59) 0.317 694 511 205 448 300 483 804 605 605 478 4 × 2 = 0 + 0.635 389 022 410 896 600 967 609 211 210 956 8;
  • 60) 0.635 389 022 410 896 600 967 609 211 210 956 8 × 2 = 1 + 0.270 778 044 821 793 201 935 218 422 421 913 6;
  • 61) 0.270 778 044 821 793 201 935 218 422 421 913 6 × 2 = 0 + 0.541 556 089 643 586 403 870 436 844 843 827 2;
  • 62) 0.541 556 089 643 586 403 870 436 844 843 827 2 × 2 = 1 + 0.083 112 179 287 172 807 740 873 689 687 654 4;
  • 63) 0.083 112 179 287 172 807 740 873 689 687 654 4 × 2 = 0 + 0.166 224 358 574 345 615 481 747 379 375 308 8;

We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit) and at least one integer that was different from zero => FULL STOP (Losing precision - the converted number we get in the end will be just a very good approximation of the initial one).


5. Construct the base 2 representation of the fractional part of the number.

Take all the integer parts of the multiplying operations, starting from the top of the constructed list above:


0.000 806 264 623 585 362 514 063 654 156 866 1(10) =

0.0000 0000 0011 0100 1101 0110 1110 0000 0011 0000 1011 0010 0101 0000 1101 010(2)

6. Positive number before normalization:

0.000 806 264 623 585 362 514 063 654 156 866 1(10) =

0.0000 0000 0011 0100 1101 0110 1110 0000 0011 0000 1011 0010 0101 0000 1101 010(2)

7. Normalize the binary representation of the number.

Shift the decimal mark 11 positions to the right, so that only one non zero digit remains to the left of it:


0.000 806 264 623 585 362 514 063 654 156 866 1(10) =

0.0000 0000 0011 0100 1101 0110 1110 0000 0011 0000 1011 0010 0101 0000 1101 010(2) =

0.0000 0000 0011 0100 1101 0110 1110 0000 0011 0000 1011 0010 0101 0000 1101 010(2) × 20 =

1.1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010(2) × 2-11


8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

Sign 1 (a negative number)

Exponent (unadjusted): -11

Mantissa (not normalized):
1.1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010


9. Adjust the exponent.

Use the 11 bit excess/bias notation:


Exponent (adjusted) =

Exponent (unadjusted) + 2(11-1) - 1 =

-11 + 2(11-1) - 1 =

(-11 + 1 023)(10) =

1 012(10)


10. Convert the adjusted exponent from the decimal (base 10) to 11 bit binary.

Use the same technique of repeatedly dividing by 2:


  • division = quotient + remainder;
  • 1 012 ÷ 2 = 506 + 0;
  • 506 ÷ 2 = 253 + 0;
  • 253 ÷ 2 = 126 + 1;
  • 126 ÷ 2 = 63 + 0;
  • 63 ÷ 2 = 31 + 1;
  • 31 ÷ 2 = 15 + 1;
  • 15 ÷ 2 = 7 + 1;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

11. Construct the base 2 representation of the adjusted exponent.

Take all the remainders starting from the bottom of the list constructed above.


Exponent (adjusted) =

1012(10) =

011 1111 0100(2)


12. Normalize the mantissa.

a) Remove the leading (the leftmost) bit, since it's allways 1, and the decimal point, if the case.

b) Adjust its length to 52 bits, only if necessary (not the case here).


Mantissa (normalized) =

1. 1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010 =

1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010


13. The three elements that make up the number's 64 bit double precision IEEE 754 binary floating point representation:

Sign (1 bit) =
1 (a negative number)

Exponent (11 bits) =
011 1111 0100

Mantissa (52 bits) =
1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010


Decimal number -0.000 806 264 623 585 362 514 063 654 156 866 1 converted to 64 bit double precision IEEE 754 binary floating point representation:

1 - 011 1111 0100 - 1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010

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How to convert numbers from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point standard

Follow the steps below to convert a base 10 decimal number to 64 bit double precision IEEE 754 binary floating point:

  • 1. If the number to be converted is negative, start with its the positive version.
  • 2. First convert the integer part. Divide repeatedly by 2 the positive representation of the integer number that is to be converted to binary, until we get a quotient that is equal to zero, keeping track of each remainder.
  • 3. Construct the base 2 representation of the positive integer part of the number, by taking all the remainders from the previous operations, starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Then convert the fractional part. Multiply the number repeatedly by 2, until we get a fractional part that is equal to zero, keeping track of each integer part of the results.
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the multiplying operations, starting from the top of the list constructed above (they should appear in the binary representation, from left to right, in the order they have been calculated).
  • 6. Normalize the binary representation of the number, shifting the decimal mark (the decimal point) "n" positions either to the left, or to the right, so that only one non zero digit remains to the left of the decimal mark.
  • 7. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary, by using the same technique of repeatedly dividing by 2, as shown above:
    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1
  • 8. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal mark, if the case) and adjust its length to 52 bits, either by removing the excess bits from the right (losing precision...) or by adding extra bits set on '0' to the right.
  • 9. Sign (it takes 1 bit) is either 1 for a negative or 0 for a positive number.

Example: convert the negative number -31.640 215 from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point:

  • 1. Start with the positive version of the number:

    |-31.640 215| = 31.640 215

  • 2. First convert the integer part, 31. Divide it repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 31 ÷ 2 = 15 + 1;
    • 15 ÷ 2 = 7 + 1;
    • 7 ÷ 2 = 3 + 1;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
    • We have encountered a quotient that is ZERO => FULL STOP
  • 3. Construct the base 2 representation of the integer part of the number by taking all the remainders of the previous dividing operations, starting from the bottom of the list constructed above:

    31(10) = 1 1111(2)

  • 4. Then, convert the fractional part, 0.640 215. Multiply repeatedly by 2, keeping track of each integer part of the results, until we get a fractional part that is equal to zero:
    • #) multiplying = integer + fractional part;
    • 1) 0.640 215 × 2 = 1 + 0.280 43;
    • 2) 0.280 43 × 2 = 0 + 0.560 86;
    • 3) 0.560 86 × 2 = 1 + 0.121 72;
    • 4) 0.121 72 × 2 = 0 + 0.243 44;
    • 5) 0.243 44 × 2 = 0 + 0.486 88;
    • 6) 0.486 88 × 2 = 0 + 0.973 76;
    • 7) 0.973 76 × 2 = 1 + 0.947 52;
    • 8) 0.947 52 × 2 = 1 + 0.895 04;
    • 9) 0.895 04 × 2 = 1 + 0.790 08;
    • 10) 0.790 08 × 2 = 1 + 0.580 16;
    • 11) 0.580 16 × 2 = 1 + 0.160 32;
    • 12) 0.160 32 × 2 = 0 + 0.320 64;
    • 13) 0.320 64 × 2 = 0 + 0.641 28;
    • 14) 0.641 28 × 2 = 1 + 0.282 56;
    • 15) 0.282 56 × 2 = 0 + 0.565 12;
    • 16) 0.565 12 × 2 = 1 + 0.130 24;
    • 17) 0.130 24 × 2 = 0 + 0.260 48;
    • 18) 0.260 48 × 2 = 0 + 0.520 96;
    • 19) 0.520 96 × 2 = 1 + 0.041 92;
    • 20) 0.041 92 × 2 = 0 + 0.083 84;
    • 21) 0.083 84 × 2 = 0 + 0.167 68;
    • 22) 0.167 68 × 2 = 0 + 0.335 36;
    • 23) 0.335 36 × 2 = 0 + 0.670 72;
    • 24) 0.670 72 × 2 = 1 + 0.341 44;
    • 25) 0.341 44 × 2 = 0 + 0.682 88;
    • 26) 0.682 88 × 2 = 1 + 0.365 76;
    • 27) 0.365 76 × 2 = 0 + 0.731 52;
    • 28) 0.731 52 × 2 = 1 + 0.463 04;
    • 29) 0.463 04 × 2 = 0 + 0.926 08;
    • 30) 0.926 08 × 2 = 1 + 0.852 16;
    • 31) 0.852 16 × 2 = 1 + 0.704 32;
    • 32) 0.704 32 × 2 = 1 + 0.408 64;
    • 33) 0.408 64 × 2 = 0 + 0.817 28;
    • 34) 0.817 28 × 2 = 1 + 0.634 56;
    • 35) 0.634 56 × 2 = 1 + 0.269 12;
    • 36) 0.269 12 × 2 = 0 + 0.538 24;
    • 37) 0.538 24 × 2 = 1 + 0.076 48;
    • 38) 0.076 48 × 2 = 0 + 0.152 96;
    • 39) 0.152 96 × 2 = 0 + 0.305 92;
    • 40) 0.305 92 × 2 = 0 + 0.611 84;
    • 41) 0.611 84 × 2 = 1 + 0.223 68;
    • 42) 0.223 68 × 2 = 0 + 0.447 36;
    • 43) 0.447 36 × 2 = 0 + 0.894 72;
    • 44) 0.894 72 × 2 = 1 + 0.789 44;
    • 45) 0.789 44 × 2 = 1 + 0.578 88;
    • 46) 0.578 88 × 2 = 1 + 0.157 76;
    • 47) 0.157 76 × 2 = 0 + 0.315 52;
    • 48) 0.315 52 × 2 = 0 + 0.631 04;
    • 49) 0.631 04 × 2 = 1 + 0.262 08;
    • 50) 0.262 08 × 2 = 0 + 0.524 16;
    • 51) 0.524 16 × 2 = 1 + 0.048 32;
    • 52) 0.048 32 × 2 = 0 + 0.096 64;
    • 53) 0.096 64 × 2 = 0 + 0.193 28;
    • We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit = 52) and at least one integer part that was different from zero => FULL STOP (losing precision...).
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the previous multiplying operations, starting from the top of the constructed list above:

    0.640 215(10) = 0.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 6. Summarizing - the positive number before normalization:

    31.640 215(10) = 1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 7. Normalize the binary representation of the number, shifting the decimal mark 4 positions to the left so that only one non-zero digit stays to the left of the decimal mark:

    31.640 215(10) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 20 =
    1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 24

  • 8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

    Sign: 1 (a negative number)

    Exponent (unadjusted): 4

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

  • 9. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary (base 2), by using the same technique of repeatedly dividing it by 2, as shown above:

    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1 = (4 + 1023)(10) = 1027(10) =
    100 0000 0011(2)

  • 10. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal sign) and adjust its length to 52 bits, by removing the excess bits, from the right (losing precision...):

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

    Mantissa (normalized): 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Conclusion:

    Sign (1 bit) = 1 (a negative number)

    Exponent (8 bits) = 100 0000 0011

    Mantissa (52 bits) = 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Number -31.640 215, converted from decimal system (base 10) to 64 bit double precision IEEE 754 binary floating point =
    1 - 100 0000 0011 - 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100