-0.000 806 264 623 585 362 514 063 654 156 856 383 Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard

Convert decimal -0.000 806 264 623 585 362 514 063 654 156 856 383(10) to 64 bit double precision IEEE 754 binary floating point representation standard (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

What are the steps to convert decimal number
-0.000 806 264 623 585 362 514 063 654 156 856 383(10) to 64 bit double precision IEEE 754 binary floating point representation (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

1. Start with the positive version of the number:

|-0.000 806 264 623 585 362 514 063 654 156 856 383| = 0.000 806 264 623 585 362 514 063 654 156 856 383


2. First, convert to binary (in base 2) the integer part: 0.
Divide the number repeatedly by 2.

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 0 ÷ 2 = 0 + 0;

3. Construct the base 2 representation of the integer part of the number.

Take all the remainders starting from the bottom of the list constructed above.

0(10) =

0(2)


4. Convert to binary (base 2) the fractional part: 0.000 806 264 623 585 362 514 063 654 156 856 383.

Multiply it repeatedly by 2.

Keep track of each integer part of the results.

Stop when we get a fractional part that is equal to zero.


  • #) multiplying = integer + fractional part;
  • 1) 0.000 806 264 623 585 362 514 063 654 156 856 383 × 2 = 0 + 0.001 612 529 247 170 725 028 127 308 313 712 766;
  • 2) 0.001 612 529 247 170 725 028 127 308 313 712 766 × 2 = 0 + 0.003 225 058 494 341 450 056 254 616 627 425 532;
  • 3) 0.003 225 058 494 341 450 056 254 616 627 425 532 × 2 = 0 + 0.006 450 116 988 682 900 112 509 233 254 851 064;
  • 4) 0.006 450 116 988 682 900 112 509 233 254 851 064 × 2 = 0 + 0.012 900 233 977 365 800 225 018 466 509 702 128;
  • 5) 0.012 900 233 977 365 800 225 018 466 509 702 128 × 2 = 0 + 0.025 800 467 954 731 600 450 036 933 019 404 256;
  • 6) 0.025 800 467 954 731 600 450 036 933 019 404 256 × 2 = 0 + 0.051 600 935 909 463 200 900 073 866 038 808 512;
  • 7) 0.051 600 935 909 463 200 900 073 866 038 808 512 × 2 = 0 + 0.103 201 871 818 926 401 800 147 732 077 617 024;
  • 8) 0.103 201 871 818 926 401 800 147 732 077 617 024 × 2 = 0 + 0.206 403 743 637 852 803 600 295 464 155 234 048;
  • 9) 0.206 403 743 637 852 803 600 295 464 155 234 048 × 2 = 0 + 0.412 807 487 275 705 607 200 590 928 310 468 096;
  • 10) 0.412 807 487 275 705 607 200 590 928 310 468 096 × 2 = 0 + 0.825 614 974 551 411 214 401 181 856 620 936 192;
  • 11) 0.825 614 974 551 411 214 401 181 856 620 936 192 × 2 = 1 + 0.651 229 949 102 822 428 802 363 713 241 872 384;
  • 12) 0.651 229 949 102 822 428 802 363 713 241 872 384 × 2 = 1 + 0.302 459 898 205 644 857 604 727 426 483 744 768;
  • 13) 0.302 459 898 205 644 857 604 727 426 483 744 768 × 2 = 0 + 0.604 919 796 411 289 715 209 454 852 967 489 536;
  • 14) 0.604 919 796 411 289 715 209 454 852 967 489 536 × 2 = 1 + 0.209 839 592 822 579 430 418 909 705 934 979 072;
  • 15) 0.209 839 592 822 579 430 418 909 705 934 979 072 × 2 = 0 + 0.419 679 185 645 158 860 837 819 411 869 958 144;
  • 16) 0.419 679 185 645 158 860 837 819 411 869 958 144 × 2 = 0 + 0.839 358 371 290 317 721 675 638 823 739 916 288;
  • 17) 0.839 358 371 290 317 721 675 638 823 739 916 288 × 2 = 1 + 0.678 716 742 580 635 443 351 277 647 479 832 576;
  • 18) 0.678 716 742 580 635 443 351 277 647 479 832 576 × 2 = 1 + 0.357 433 485 161 270 886 702 555 294 959 665 152;
  • 19) 0.357 433 485 161 270 886 702 555 294 959 665 152 × 2 = 0 + 0.714 866 970 322 541 773 405 110 589 919 330 304;
  • 20) 0.714 866 970 322 541 773 405 110 589 919 330 304 × 2 = 1 + 0.429 733 940 645 083 546 810 221 179 838 660 608;
  • 21) 0.429 733 940 645 083 546 810 221 179 838 660 608 × 2 = 0 + 0.859 467 881 290 167 093 620 442 359 677 321 216;
  • 22) 0.859 467 881 290 167 093 620 442 359 677 321 216 × 2 = 1 + 0.718 935 762 580 334 187 240 884 719 354 642 432;
  • 23) 0.718 935 762 580 334 187 240 884 719 354 642 432 × 2 = 1 + 0.437 871 525 160 668 374 481 769 438 709 284 864;
  • 24) 0.437 871 525 160 668 374 481 769 438 709 284 864 × 2 = 0 + 0.875 743 050 321 336 748 963 538 877 418 569 728;
  • 25) 0.875 743 050 321 336 748 963 538 877 418 569 728 × 2 = 1 + 0.751 486 100 642 673 497 927 077 754 837 139 456;
  • 26) 0.751 486 100 642 673 497 927 077 754 837 139 456 × 2 = 1 + 0.502 972 201 285 346 995 854 155 509 674 278 912;
  • 27) 0.502 972 201 285 346 995 854 155 509 674 278 912 × 2 = 1 + 0.005 944 402 570 693 991 708 311 019 348 557 824;
  • 28) 0.005 944 402 570 693 991 708 311 019 348 557 824 × 2 = 0 + 0.011 888 805 141 387 983 416 622 038 697 115 648;
  • 29) 0.011 888 805 141 387 983 416 622 038 697 115 648 × 2 = 0 + 0.023 777 610 282 775 966 833 244 077 394 231 296;
  • 30) 0.023 777 610 282 775 966 833 244 077 394 231 296 × 2 = 0 + 0.047 555 220 565 551 933 666 488 154 788 462 592;
  • 31) 0.047 555 220 565 551 933 666 488 154 788 462 592 × 2 = 0 + 0.095 110 441 131 103 867 332 976 309 576 925 184;
  • 32) 0.095 110 441 131 103 867 332 976 309 576 925 184 × 2 = 0 + 0.190 220 882 262 207 734 665 952 619 153 850 368;
  • 33) 0.190 220 882 262 207 734 665 952 619 153 850 368 × 2 = 0 + 0.380 441 764 524 415 469 331 905 238 307 700 736;
  • 34) 0.380 441 764 524 415 469 331 905 238 307 700 736 × 2 = 0 + 0.760 883 529 048 830 938 663 810 476 615 401 472;
  • 35) 0.760 883 529 048 830 938 663 810 476 615 401 472 × 2 = 1 + 0.521 767 058 097 661 877 327 620 953 230 802 944;
  • 36) 0.521 767 058 097 661 877 327 620 953 230 802 944 × 2 = 1 + 0.043 534 116 195 323 754 655 241 906 461 605 888;
  • 37) 0.043 534 116 195 323 754 655 241 906 461 605 888 × 2 = 0 + 0.087 068 232 390 647 509 310 483 812 923 211 776;
  • 38) 0.087 068 232 390 647 509 310 483 812 923 211 776 × 2 = 0 + 0.174 136 464 781 295 018 620 967 625 846 423 552;
  • 39) 0.174 136 464 781 295 018 620 967 625 846 423 552 × 2 = 0 + 0.348 272 929 562 590 037 241 935 251 692 847 104;
  • 40) 0.348 272 929 562 590 037 241 935 251 692 847 104 × 2 = 0 + 0.696 545 859 125 180 074 483 870 503 385 694 208;
  • 41) 0.696 545 859 125 180 074 483 870 503 385 694 208 × 2 = 1 + 0.393 091 718 250 360 148 967 741 006 771 388 416;
  • 42) 0.393 091 718 250 360 148 967 741 006 771 388 416 × 2 = 0 + 0.786 183 436 500 720 297 935 482 013 542 776 832;
  • 43) 0.786 183 436 500 720 297 935 482 013 542 776 832 × 2 = 1 + 0.572 366 873 001 440 595 870 964 027 085 553 664;
  • 44) 0.572 366 873 001 440 595 870 964 027 085 553 664 × 2 = 1 + 0.144 733 746 002 881 191 741 928 054 171 107 328;
  • 45) 0.144 733 746 002 881 191 741 928 054 171 107 328 × 2 = 0 + 0.289 467 492 005 762 383 483 856 108 342 214 656;
  • 46) 0.289 467 492 005 762 383 483 856 108 342 214 656 × 2 = 0 + 0.578 934 984 011 524 766 967 712 216 684 429 312;
  • 47) 0.578 934 984 011 524 766 967 712 216 684 429 312 × 2 = 1 + 0.157 869 968 023 049 533 935 424 433 368 858 624;
  • 48) 0.157 869 968 023 049 533 935 424 433 368 858 624 × 2 = 0 + 0.315 739 936 046 099 067 870 848 866 737 717 248;
  • 49) 0.315 739 936 046 099 067 870 848 866 737 717 248 × 2 = 0 + 0.631 479 872 092 198 135 741 697 733 475 434 496;
  • 50) 0.631 479 872 092 198 135 741 697 733 475 434 496 × 2 = 1 + 0.262 959 744 184 396 271 483 395 466 950 868 992;
  • 51) 0.262 959 744 184 396 271 483 395 466 950 868 992 × 2 = 0 + 0.525 919 488 368 792 542 966 790 933 901 737 984;
  • 52) 0.525 919 488 368 792 542 966 790 933 901 737 984 × 2 = 1 + 0.051 838 976 737 585 085 933 581 867 803 475 968;
  • 53) 0.051 838 976 737 585 085 933 581 867 803 475 968 × 2 = 0 + 0.103 677 953 475 170 171 867 163 735 606 951 936;
  • 54) 0.103 677 953 475 170 171 867 163 735 606 951 936 × 2 = 0 + 0.207 355 906 950 340 343 734 327 471 213 903 872;
  • 55) 0.207 355 906 950 340 343 734 327 471 213 903 872 × 2 = 0 + 0.414 711 813 900 680 687 468 654 942 427 807 744;
  • 56) 0.414 711 813 900 680 687 468 654 942 427 807 744 × 2 = 0 + 0.829 423 627 801 361 374 937 309 884 855 615 488;
  • 57) 0.829 423 627 801 361 374 937 309 884 855 615 488 × 2 = 1 + 0.658 847 255 602 722 749 874 619 769 711 230 976;
  • 58) 0.658 847 255 602 722 749 874 619 769 711 230 976 × 2 = 1 + 0.317 694 511 205 445 499 749 239 539 422 461 952;
  • 59) 0.317 694 511 205 445 499 749 239 539 422 461 952 × 2 = 0 + 0.635 389 022 410 890 999 498 479 078 844 923 904;
  • 60) 0.635 389 022 410 890 999 498 479 078 844 923 904 × 2 = 1 + 0.270 778 044 821 781 998 996 958 157 689 847 808;
  • 61) 0.270 778 044 821 781 998 996 958 157 689 847 808 × 2 = 0 + 0.541 556 089 643 563 997 993 916 315 379 695 616;
  • 62) 0.541 556 089 643 563 997 993 916 315 379 695 616 × 2 = 1 + 0.083 112 179 287 127 995 987 832 630 759 391 232;
  • 63) 0.083 112 179 287 127 995 987 832 630 759 391 232 × 2 = 0 + 0.166 224 358 574 255 991 975 665 261 518 782 464;

We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit) and at least one integer that was different from zero => FULL STOP (Losing precision - the converted number we get in the end will be just a very good approximation of the initial one).


5. Construct the base 2 representation of the fractional part of the number.

Take all the integer parts of the multiplying operations, starting from the top of the constructed list above:


0.000 806 264 623 585 362 514 063 654 156 856 383(10) =

0.0000 0000 0011 0100 1101 0110 1110 0000 0011 0000 1011 0010 0101 0000 1101 010(2)

6. Positive number before normalization:

0.000 806 264 623 585 362 514 063 654 156 856 383(10) =

0.0000 0000 0011 0100 1101 0110 1110 0000 0011 0000 1011 0010 0101 0000 1101 010(2)

7. Normalize the binary representation of the number.

Shift the decimal mark 11 positions to the right, so that only one non zero digit remains to the left of it:


0.000 806 264 623 585 362 514 063 654 156 856 383(10) =

0.0000 0000 0011 0100 1101 0110 1110 0000 0011 0000 1011 0010 0101 0000 1101 010(2) =

0.0000 0000 0011 0100 1101 0110 1110 0000 0011 0000 1011 0010 0101 0000 1101 010(2) × 20 =

1.1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010(2) × 2-11


8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

Sign 1 (a negative number)

Exponent (unadjusted): -11

Mantissa (not normalized):
1.1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010


9. Adjust the exponent.

Use the 11 bit excess/bias notation:


Exponent (adjusted) =

Exponent (unadjusted) + 2(11-1) - 1 =

-11 + 2(11-1) - 1 =

(-11 + 1 023)(10) =

1 012(10)


10. Convert the adjusted exponent from the decimal (base 10) to 11 bit binary.

Use the same technique of repeatedly dividing by 2:


  • division = quotient + remainder;
  • 1 012 ÷ 2 = 506 + 0;
  • 506 ÷ 2 = 253 + 0;
  • 253 ÷ 2 = 126 + 1;
  • 126 ÷ 2 = 63 + 0;
  • 63 ÷ 2 = 31 + 1;
  • 31 ÷ 2 = 15 + 1;
  • 15 ÷ 2 = 7 + 1;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

11. Construct the base 2 representation of the adjusted exponent.

Take all the remainders starting from the bottom of the list constructed above.


Exponent (adjusted) =

1012(10) =

011 1111 0100(2)


12. Normalize the mantissa.

a) Remove the leading (the leftmost) bit, since it's allways 1, and the decimal point, if the case.

b) Adjust its length to 52 bits, only if necessary (not the case here).


Mantissa (normalized) =

1. 1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010 =

1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010


13. The three elements that make up the number's 64 bit double precision IEEE 754 binary floating point representation:

Sign (1 bit) =
1 (a negative number)

Exponent (11 bits) =
011 1111 0100

Mantissa (52 bits) =
1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010


Decimal number -0.000 806 264 623 585 362 514 063 654 156 856 383 converted to 64 bit double precision IEEE 754 binary floating point representation:

1 - 011 1111 0100 - 1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010

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How to convert numbers from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point standard

Follow the steps below to convert a base 10 decimal number to 64 bit double precision IEEE 754 binary floating point:

  • 1. If the number to be converted is negative, start with its the positive version.
  • 2. First convert the integer part. Divide repeatedly by 2 the positive representation of the integer number that is to be converted to binary, until we get a quotient that is equal to zero, keeping track of each remainder.
  • 3. Construct the base 2 representation of the positive integer part of the number, by taking all the remainders from the previous operations, starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Then convert the fractional part. Multiply the number repeatedly by 2, until we get a fractional part that is equal to zero, keeping track of each integer part of the results.
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the multiplying operations, starting from the top of the list constructed above (they should appear in the binary representation, from left to right, in the order they have been calculated).
  • 6. Normalize the binary representation of the number, shifting the decimal mark (the decimal point) "n" positions either to the left, or to the right, so that only one non zero digit remains to the left of the decimal mark.
  • 7. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary, by using the same technique of repeatedly dividing by 2, as shown above:
    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1
  • 8. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal mark, if the case) and adjust its length to 52 bits, either by removing the excess bits from the right (losing precision...) or by adding extra bits set on '0' to the right.
  • 9. Sign (it takes 1 bit) is either 1 for a negative or 0 for a positive number.

Example: convert the negative number -31.640 215 from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point:

  • 1. Start with the positive version of the number:

    |-31.640 215| = 31.640 215

  • 2. First convert the integer part, 31. Divide it repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 31 ÷ 2 = 15 + 1;
    • 15 ÷ 2 = 7 + 1;
    • 7 ÷ 2 = 3 + 1;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
    • We have encountered a quotient that is ZERO => FULL STOP
  • 3. Construct the base 2 representation of the integer part of the number by taking all the remainders of the previous dividing operations, starting from the bottom of the list constructed above:

    31(10) = 1 1111(2)

  • 4. Then, convert the fractional part, 0.640 215. Multiply repeatedly by 2, keeping track of each integer part of the results, until we get a fractional part that is equal to zero:
    • #) multiplying = integer + fractional part;
    • 1) 0.640 215 × 2 = 1 + 0.280 43;
    • 2) 0.280 43 × 2 = 0 + 0.560 86;
    • 3) 0.560 86 × 2 = 1 + 0.121 72;
    • 4) 0.121 72 × 2 = 0 + 0.243 44;
    • 5) 0.243 44 × 2 = 0 + 0.486 88;
    • 6) 0.486 88 × 2 = 0 + 0.973 76;
    • 7) 0.973 76 × 2 = 1 + 0.947 52;
    • 8) 0.947 52 × 2 = 1 + 0.895 04;
    • 9) 0.895 04 × 2 = 1 + 0.790 08;
    • 10) 0.790 08 × 2 = 1 + 0.580 16;
    • 11) 0.580 16 × 2 = 1 + 0.160 32;
    • 12) 0.160 32 × 2 = 0 + 0.320 64;
    • 13) 0.320 64 × 2 = 0 + 0.641 28;
    • 14) 0.641 28 × 2 = 1 + 0.282 56;
    • 15) 0.282 56 × 2 = 0 + 0.565 12;
    • 16) 0.565 12 × 2 = 1 + 0.130 24;
    • 17) 0.130 24 × 2 = 0 + 0.260 48;
    • 18) 0.260 48 × 2 = 0 + 0.520 96;
    • 19) 0.520 96 × 2 = 1 + 0.041 92;
    • 20) 0.041 92 × 2 = 0 + 0.083 84;
    • 21) 0.083 84 × 2 = 0 + 0.167 68;
    • 22) 0.167 68 × 2 = 0 + 0.335 36;
    • 23) 0.335 36 × 2 = 0 + 0.670 72;
    • 24) 0.670 72 × 2 = 1 + 0.341 44;
    • 25) 0.341 44 × 2 = 0 + 0.682 88;
    • 26) 0.682 88 × 2 = 1 + 0.365 76;
    • 27) 0.365 76 × 2 = 0 + 0.731 52;
    • 28) 0.731 52 × 2 = 1 + 0.463 04;
    • 29) 0.463 04 × 2 = 0 + 0.926 08;
    • 30) 0.926 08 × 2 = 1 + 0.852 16;
    • 31) 0.852 16 × 2 = 1 + 0.704 32;
    • 32) 0.704 32 × 2 = 1 + 0.408 64;
    • 33) 0.408 64 × 2 = 0 + 0.817 28;
    • 34) 0.817 28 × 2 = 1 + 0.634 56;
    • 35) 0.634 56 × 2 = 1 + 0.269 12;
    • 36) 0.269 12 × 2 = 0 + 0.538 24;
    • 37) 0.538 24 × 2 = 1 + 0.076 48;
    • 38) 0.076 48 × 2 = 0 + 0.152 96;
    • 39) 0.152 96 × 2 = 0 + 0.305 92;
    • 40) 0.305 92 × 2 = 0 + 0.611 84;
    • 41) 0.611 84 × 2 = 1 + 0.223 68;
    • 42) 0.223 68 × 2 = 0 + 0.447 36;
    • 43) 0.447 36 × 2 = 0 + 0.894 72;
    • 44) 0.894 72 × 2 = 1 + 0.789 44;
    • 45) 0.789 44 × 2 = 1 + 0.578 88;
    • 46) 0.578 88 × 2 = 1 + 0.157 76;
    • 47) 0.157 76 × 2 = 0 + 0.315 52;
    • 48) 0.315 52 × 2 = 0 + 0.631 04;
    • 49) 0.631 04 × 2 = 1 + 0.262 08;
    • 50) 0.262 08 × 2 = 0 + 0.524 16;
    • 51) 0.524 16 × 2 = 1 + 0.048 32;
    • 52) 0.048 32 × 2 = 0 + 0.096 64;
    • 53) 0.096 64 × 2 = 0 + 0.193 28;
    • We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit = 52) and at least one integer part that was different from zero => FULL STOP (losing precision...).
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the previous multiplying operations, starting from the top of the constructed list above:

    0.640 215(10) = 0.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 6. Summarizing - the positive number before normalization:

    31.640 215(10) = 1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 7. Normalize the binary representation of the number, shifting the decimal mark 4 positions to the left so that only one non-zero digit stays to the left of the decimal mark:

    31.640 215(10) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 20 =
    1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 24

  • 8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

    Sign: 1 (a negative number)

    Exponent (unadjusted): 4

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

  • 9. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary (base 2), by using the same technique of repeatedly dividing it by 2, as shown above:

    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1 = (4 + 1023)(10) = 1027(10) =
    100 0000 0011(2)

  • 10. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal sign) and adjust its length to 52 bits, by removing the excess bits, from the right (losing precision...):

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

    Mantissa (normalized): 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Conclusion:

    Sign (1 bit) = 1 (a negative number)

    Exponent (8 bits) = 100 0000 0011

    Mantissa (52 bits) = 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Number -31.640 215, converted from decimal system (base 10) to 64 bit double precision IEEE 754 binary floating point =
    1 - 100 0000 0011 - 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100