-0.000 806 264 623 585 362 514 063 654 156 856 191 Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard

Convert decimal -0.000 806 264 623 585 362 514 063 654 156 856 191(10) to 64 bit double precision IEEE 754 binary floating point representation standard (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

What are the steps to convert decimal number
-0.000 806 264 623 585 362 514 063 654 156 856 191(10) to 64 bit double precision IEEE 754 binary floating point representation (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

1. Start with the positive version of the number:

|-0.000 806 264 623 585 362 514 063 654 156 856 191| = 0.000 806 264 623 585 362 514 063 654 156 856 191


2. First, convert to binary (in base 2) the integer part: 0.
Divide the number repeatedly by 2.

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 0 ÷ 2 = 0 + 0;

3. Construct the base 2 representation of the integer part of the number.

Take all the remainders starting from the bottom of the list constructed above.

0(10) =

0(2)


4. Convert to binary (base 2) the fractional part: 0.000 806 264 623 585 362 514 063 654 156 856 191.

Multiply it repeatedly by 2.

Keep track of each integer part of the results.

Stop when we get a fractional part that is equal to zero.


  • #) multiplying = integer + fractional part;
  • 1) 0.000 806 264 623 585 362 514 063 654 156 856 191 × 2 = 0 + 0.001 612 529 247 170 725 028 127 308 313 712 382;
  • 2) 0.001 612 529 247 170 725 028 127 308 313 712 382 × 2 = 0 + 0.003 225 058 494 341 450 056 254 616 627 424 764;
  • 3) 0.003 225 058 494 341 450 056 254 616 627 424 764 × 2 = 0 + 0.006 450 116 988 682 900 112 509 233 254 849 528;
  • 4) 0.006 450 116 988 682 900 112 509 233 254 849 528 × 2 = 0 + 0.012 900 233 977 365 800 225 018 466 509 699 056;
  • 5) 0.012 900 233 977 365 800 225 018 466 509 699 056 × 2 = 0 + 0.025 800 467 954 731 600 450 036 933 019 398 112;
  • 6) 0.025 800 467 954 731 600 450 036 933 019 398 112 × 2 = 0 + 0.051 600 935 909 463 200 900 073 866 038 796 224;
  • 7) 0.051 600 935 909 463 200 900 073 866 038 796 224 × 2 = 0 + 0.103 201 871 818 926 401 800 147 732 077 592 448;
  • 8) 0.103 201 871 818 926 401 800 147 732 077 592 448 × 2 = 0 + 0.206 403 743 637 852 803 600 295 464 155 184 896;
  • 9) 0.206 403 743 637 852 803 600 295 464 155 184 896 × 2 = 0 + 0.412 807 487 275 705 607 200 590 928 310 369 792;
  • 10) 0.412 807 487 275 705 607 200 590 928 310 369 792 × 2 = 0 + 0.825 614 974 551 411 214 401 181 856 620 739 584;
  • 11) 0.825 614 974 551 411 214 401 181 856 620 739 584 × 2 = 1 + 0.651 229 949 102 822 428 802 363 713 241 479 168;
  • 12) 0.651 229 949 102 822 428 802 363 713 241 479 168 × 2 = 1 + 0.302 459 898 205 644 857 604 727 426 482 958 336;
  • 13) 0.302 459 898 205 644 857 604 727 426 482 958 336 × 2 = 0 + 0.604 919 796 411 289 715 209 454 852 965 916 672;
  • 14) 0.604 919 796 411 289 715 209 454 852 965 916 672 × 2 = 1 + 0.209 839 592 822 579 430 418 909 705 931 833 344;
  • 15) 0.209 839 592 822 579 430 418 909 705 931 833 344 × 2 = 0 + 0.419 679 185 645 158 860 837 819 411 863 666 688;
  • 16) 0.419 679 185 645 158 860 837 819 411 863 666 688 × 2 = 0 + 0.839 358 371 290 317 721 675 638 823 727 333 376;
  • 17) 0.839 358 371 290 317 721 675 638 823 727 333 376 × 2 = 1 + 0.678 716 742 580 635 443 351 277 647 454 666 752;
  • 18) 0.678 716 742 580 635 443 351 277 647 454 666 752 × 2 = 1 + 0.357 433 485 161 270 886 702 555 294 909 333 504;
  • 19) 0.357 433 485 161 270 886 702 555 294 909 333 504 × 2 = 0 + 0.714 866 970 322 541 773 405 110 589 818 667 008;
  • 20) 0.714 866 970 322 541 773 405 110 589 818 667 008 × 2 = 1 + 0.429 733 940 645 083 546 810 221 179 637 334 016;
  • 21) 0.429 733 940 645 083 546 810 221 179 637 334 016 × 2 = 0 + 0.859 467 881 290 167 093 620 442 359 274 668 032;
  • 22) 0.859 467 881 290 167 093 620 442 359 274 668 032 × 2 = 1 + 0.718 935 762 580 334 187 240 884 718 549 336 064;
  • 23) 0.718 935 762 580 334 187 240 884 718 549 336 064 × 2 = 1 + 0.437 871 525 160 668 374 481 769 437 098 672 128;
  • 24) 0.437 871 525 160 668 374 481 769 437 098 672 128 × 2 = 0 + 0.875 743 050 321 336 748 963 538 874 197 344 256;
  • 25) 0.875 743 050 321 336 748 963 538 874 197 344 256 × 2 = 1 + 0.751 486 100 642 673 497 927 077 748 394 688 512;
  • 26) 0.751 486 100 642 673 497 927 077 748 394 688 512 × 2 = 1 + 0.502 972 201 285 346 995 854 155 496 789 377 024;
  • 27) 0.502 972 201 285 346 995 854 155 496 789 377 024 × 2 = 1 + 0.005 944 402 570 693 991 708 310 993 578 754 048;
  • 28) 0.005 944 402 570 693 991 708 310 993 578 754 048 × 2 = 0 + 0.011 888 805 141 387 983 416 621 987 157 508 096;
  • 29) 0.011 888 805 141 387 983 416 621 987 157 508 096 × 2 = 0 + 0.023 777 610 282 775 966 833 243 974 315 016 192;
  • 30) 0.023 777 610 282 775 966 833 243 974 315 016 192 × 2 = 0 + 0.047 555 220 565 551 933 666 487 948 630 032 384;
  • 31) 0.047 555 220 565 551 933 666 487 948 630 032 384 × 2 = 0 + 0.095 110 441 131 103 867 332 975 897 260 064 768;
  • 32) 0.095 110 441 131 103 867 332 975 897 260 064 768 × 2 = 0 + 0.190 220 882 262 207 734 665 951 794 520 129 536;
  • 33) 0.190 220 882 262 207 734 665 951 794 520 129 536 × 2 = 0 + 0.380 441 764 524 415 469 331 903 589 040 259 072;
  • 34) 0.380 441 764 524 415 469 331 903 589 040 259 072 × 2 = 0 + 0.760 883 529 048 830 938 663 807 178 080 518 144;
  • 35) 0.760 883 529 048 830 938 663 807 178 080 518 144 × 2 = 1 + 0.521 767 058 097 661 877 327 614 356 161 036 288;
  • 36) 0.521 767 058 097 661 877 327 614 356 161 036 288 × 2 = 1 + 0.043 534 116 195 323 754 655 228 712 322 072 576;
  • 37) 0.043 534 116 195 323 754 655 228 712 322 072 576 × 2 = 0 + 0.087 068 232 390 647 509 310 457 424 644 145 152;
  • 38) 0.087 068 232 390 647 509 310 457 424 644 145 152 × 2 = 0 + 0.174 136 464 781 295 018 620 914 849 288 290 304;
  • 39) 0.174 136 464 781 295 018 620 914 849 288 290 304 × 2 = 0 + 0.348 272 929 562 590 037 241 829 698 576 580 608;
  • 40) 0.348 272 929 562 590 037 241 829 698 576 580 608 × 2 = 0 + 0.696 545 859 125 180 074 483 659 397 153 161 216;
  • 41) 0.696 545 859 125 180 074 483 659 397 153 161 216 × 2 = 1 + 0.393 091 718 250 360 148 967 318 794 306 322 432;
  • 42) 0.393 091 718 250 360 148 967 318 794 306 322 432 × 2 = 0 + 0.786 183 436 500 720 297 934 637 588 612 644 864;
  • 43) 0.786 183 436 500 720 297 934 637 588 612 644 864 × 2 = 1 + 0.572 366 873 001 440 595 869 275 177 225 289 728;
  • 44) 0.572 366 873 001 440 595 869 275 177 225 289 728 × 2 = 1 + 0.144 733 746 002 881 191 738 550 354 450 579 456;
  • 45) 0.144 733 746 002 881 191 738 550 354 450 579 456 × 2 = 0 + 0.289 467 492 005 762 383 477 100 708 901 158 912;
  • 46) 0.289 467 492 005 762 383 477 100 708 901 158 912 × 2 = 0 + 0.578 934 984 011 524 766 954 201 417 802 317 824;
  • 47) 0.578 934 984 011 524 766 954 201 417 802 317 824 × 2 = 1 + 0.157 869 968 023 049 533 908 402 835 604 635 648;
  • 48) 0.157 869 968 023 049 533 908 402 835 604 635 648 × 2 = 0 + 0.315 739 936 046 099 067 816 805 671 209 271 296;
  • 49) 0.315 739 936 046 099 067 816 805 671 209 271 296 × 2 = 0 + 0.631 479 872 092 198 135 633 611 342 418 542 592;
  • 50) 0.631 479 872 092 198 135 633 611 342 418 542 592 × 2 = 1 + 0.262 959 744 184 396 271 267 222 684 837 085 184;
  • 51) 0.262 959 744 184 396 271 267 222 684 837 085 184 × 2 = 0 + 0.525 919 488 368 792 542 534 445 369 674 170 368;
  • 52) 0.525 919 488 368 792 542 534 445 369 674 170 368 × 2 = 1 + 0.051 838 976 737 585 085 068 890 739 348 340 736;
  • 53) 0.051 838 976 737 585 085 068 890 739 348 340 736 × 2 = 0 + 0.103 677 953 475 170 170 137 781 478 696 681 472;
  • 54) 0.103 677 953 475 170 170 137 781 478 696 681 472 × 2 = 0 + 0.207 355 906 950 340 340 275 562 957 393 362 944;
  • 55) 0.207 355 906 950 340 340 275 562 957 393 362 944 × 2 = 0 + 0.414 711 813 900 680 680 551 125 914 786 725 888;
  • 56) 0.414 711 813 900 680 680 551 125 914 786 725 888 × 2 = 0 + 0.829 423 627 801 361 361 102 251 829 573 451 776;
  • 57) 0.829 423 627 801 361 361 102 251 829 573 451 776 × 2 = 1 + 0.658 847 255 602 722 722 204 503 659 146 903 552;
  • 58) 0.658 847 255 602 722 722 204 503 659 146 903 552 × 2 = 1 + 0.317 694 511 205 445 444 409 007 318 293 807 104;
  • 59) 0.317 694 511 205 445 444 409 007 318 293 807 104 × 2 = 0 + 0.635 389 022 410 890 888 818 014 636 587 614 208;
  • 60) 0.635 389 022 410 890 888 818 014 636 587 614 208 × 2 = 1 + 0.270 778 044 821 781 777 636 029 273 175 228 416;
  • 61) 0.270 778 044 821 781 777 636 029 273 175 228 416 × 2 = 0 + 0.541 556 089 643 563 555 272 058 546 350 456 832;
  • 62) 0.541 556 089 643 563 555 272 058 546 350 456 832 × 2 = 1 + 0.083 112 179 287 127 110 544 117 092 700 913 664;
  • 63) 0.083 112 179 287 127 110 544 117 092 700 913 664 × 2 = 0 + 0.166 224 358 574 254 221 088 234 185 401 827 328;

We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit) and at least one integer that was different from zero => FULL STOP (Losing precision - the converted number we get in the end will be just a very good approximation of the initial one).


5. Construct the base 2 representation of the fractional part of the number.

Take all the integer parts of the multiplying operations, starting from the top of the constructed list above:


0.000 806 264 623 585 362 514 063 654 156 856 191(10) =

0.0000 0000 0011 0100 1101 0110 1110 0000 0011 0000 1011 0010 0101 0000 1101 010(2)

6. Positive number before normalization:

0.000 806 264 623 585 362 514 063 654 156 856 191(10) =

0.0000 0000 0011 0100 1101 0110 1110 0000 0011 0000 1011 0010 0101 0000 1101 010(2)

7. Normalize the binary representation of the number.

Shift the decimal mark 11 positions to the right, so that only one non zero digit remains to the left of it:


0.000 806 264 623 585 362 514 063 654 156 856 191(10) =

0.0000 0000 0011 0100 1101 0110 1110 0000 0011 0000 1011 0010 0101 0000 1101 010(2) =

0.0000 0000 0011 0100 1101 0110 1110 0000 0011 0000 1011 0010 0101 0000 1101 010(2) × 20 =

1.1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010(2) × 2-11


8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

Sign 1 (a negative number)

Exponent (unadjusted): -11

Mantissa (not normalized):
1.1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010


9. Adjust the exponent.

Use the 11 bit excess/bias notation:


Exponent (adjusted) =

Exponent (unadjusted) + 2(11-1) - 1 =

-11 + 2(11-1) - 1 =

(-11 + 1 023)(10) =

1 012(10)


10. Convert the adjusted exponent from the decimal (base 10) to 11 bit binary.

Use the same technique of repeatedly dividing by 2:


  • division = quotient + remainder;
  • 1 012 ÷ 2 = 506 + 0;
  • 506 ÷ 2 = 253 + 0;
  • 253 ÷ 2 = 126 + 1;
  • 126 ÷ 2 = 63 + 0;
  • 63 ÷ 2 = 31 + 1;
  • 31 ÷ 2 = 15 + 1;
  • 15 ÷ 2 = 7 + 1;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

11. Construct the base 2 representation of the adjusted exponent.

Take all the remainders starting from the bottom of the list constructed above.


Exponent (adjusted) =

1012(10) =

011 1111 0100(2)


12. Normalize the mantissa.

a) Remove the leading (the leftmost) bit, since it's allways 1, and the decimal point, if the case.

b) Adjust its length to 52 bits, only if necessary (not the case here).


Mantissa (normalized) =

1. 1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010 =

1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010


13. The three elements that make up the number's 64 bit double precision IEEE 754 binary floating point representation:

Sign (1 bit) =
1 (a negative number)

Exponent (11 bits) =
011 1111 0100

Mantissa (52 bits) =
1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010


Decimal number -0.000 806 264 623 585 362 514 063 654 156 856 191 converted to 64 bit double precision IEEE 754 binary floating point representation:

1 - 011 1111 0100 - 1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010

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How to convert numbers from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point standard

Follow the steps below to convert a base 10 decimal number to 64 bit double precision IEEE 754 binary floating point:

  • 1. If the number to be converted is negative, start with its the positive version.
  • 2. First convert the integer part. Divide repeatedly by 2 the positive representation of the integer number that is to be converted to binary, until we get a quotient that is equal to zero, keeping track of each remainder.
  • 3. Construct the base 2 representation of the positive integer part of the number, by taking all the remainders from the previous operations, starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Then convert the fractional part. Multiply the number repeatedly by 2, until we get a fractional part that is equal to zero, keeping track of each integer part of the results.
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the multiplying operations, starting from the top of the list constructed above (they should appear in the binary representation, from left to right, in the order they have been calculated).
  • 6. Normalize the binary representation of the number, shifting the decimal mark (the decimal point) "n" positions either to the left, or to the right, so that only one non zero digit remains to the left of the decimal mark.
  • 7. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary, by using the same technique of repeatedly dividing by 2, as shown above:
    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1
  • 8. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal mark, if the case) and adjust its length to 52 bits, either by removing the excess bits from the right (losing precision...) or by adding extra bits set on '0' to the right.
  • 9. Sign (it takes 1 bit) is either 1 for a negative or 0 for a positive number.

Example: convert the negative number -31.640 215 from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point:

  • 1. Start with the positive version of the number:

    |-31.640 215| = 31.640 215

  • 2. First convert the integer part, 31. Divide it repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 31 ÷ 2 = 15 + 1;
    • 15 ÷ 2 = 7 + 1;
    • 7 ÷ 2 = 3 + 1;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
    • We have encountered a quotient that is ZERO => FULL STOP
  • 3. Construct the base 2 representation of the integer part of the number by taking all the remainders of the previous dividing operations, starting from the bottom of the list constructed above:

    31(10) = 1 1111(2)

  • 4. Then, convert the fractional part, 0.640 215. Multiply repeatedly by 2, keeping track of each integer part of the results, until we get a fractional part that is equal to zero:
    • #) multiplying = integer + fractional part;
    • 1) 0.640 215 × 2 = 1 + 0.280 43;
    • 2) 0.280 43 × 2 = 0 + 0.560 86;
    • 3) 0.560 86 × 2 = 1 + 0.121 72;
    • 4) 0.121 72 × 2 = 0 + 0.243 44;
    • 5) 0.243 44 × 2 = 0 + 0.486 88;
    • 6) 0.486 88 × 2 = 0 + 0.973 76;
    • 7) 0.973 76 × 2 = 1 + 0.947 52;
    • 8) 0.947 52 × 2 = 1 + 0.895 04;
    • 9) 0.895 04 × 2 = 1 + 0.790 08;
    • 10) 0.790 08 × 2 = 1 + 0.580 16;
    • 11) 0.580 16 × 2 = 1 + 0.160 32;
    • 12) 0.160 32 × 2 = 0 + 0.320 64;
    • 13) 0.320 64 × 2 = 0 + 0.641 28;
    • 14) 0.641 28 × 2 = 1 + 0.282 56;
    • 15) 0.282 56 × 2 = 0 + 0.565 12;
    • 16) 0.565 12 × 2 = 1 + 0.130 24;
    • 17) 0.130 24 × 2 = 0 + 0.260 48;
    • 18) 0.260 48 × 2 = 0 + 0.520 96;
    • 19) 0.520 96 × 2 = 1 + 0.041 92;
    • 20) 0.041 92 × 2 = 0 + 0.083 84;
    • 21) 0.083 84 × 2 = 0 + 0.167 68;
    • 22) 0.167 68 × 2 = 0 + 0.335 36;
    • 23) 0.335 36 × 2 = 0 + 0.670 72;
    • 24) 0.670 72 × 2 = 1 + 0.341 44;
    • 25) 0.341 44 × 2 = 0 + 0.682 88;
    • 26) 0.682 88 × 2 = 1 + 0.365 76;
    • 27) 0.365 76 × 2 = 0 + 0.731 52;
    • 28) 0.731 52 × 2 = 1 + 0.463 04;
    • 29) 0.463 04 × 2 = 0 + 0.926 08;
    • 30) 0.926 08 × 2 = 1 + 0.852 16;
    • 31) 0.852 16 × 2 = 1 + 0.704 32;
    • 32) 0.704 32 × 2 = 1 + 0.408 64;
    • 33) 0.408 64 × 2 = 0 + 0.817 28;
    • 34) 0.817 28 × 2 = 1 + 0.634 56;
    • 35) 0.634 56 × 2 = 1 + 0.269 12;
    • 36) 0.269 12 × 2 = 0 + 0.538 24;
    • 37) 0.538 24 × 2 = 1 + 0.076 48;
    • 38) 0.076 48 × 2 = 0 + 0.152 96;
    • 39) 0.152 96 × 2 = 0 + 0.305 92;
    • 40) 0.305 92 × 2 = 0 + 0.611 84;
    • 41) 0.611 84 × 2 = 1 + 0.223 68;
    • 42) 0.223 68 × 2 = 0 + 0.447 36;
    • 43) 0.447 36 × 2 = 0 + 0.894 72;
    • 44) 0.894 72 × 2 = 1 + 0.789 44;
    • 45) 0.789 44 × 2 = 1 + 0.578 88;
    • 46) 0.578 88 × 2 = 1 + 0.157 76;
    • 47) 0.157 76 × 2 = 0 + 0.315 52;
    • 48) 0.315 52 × 2 = 0 + 0.631 04;
    • 49) 0.631 04 × 2 = 1 + 0.262 08;
    • 50) 0.262 08 × 2 = 0 + 0.524 16;
    • 51) 0.524 16 × 2 = 1 + 0.048 32;
    • 52) 0.048 32 × 2 = 0 + 0.096 64;
    • 53) 0.096 64 × 2 = 0 + 0.193 28;
    • We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit = 52) and at least one integer part that was different from zero => FULL STOP (losing precision...).
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the previous multiplying operations, starting from the top of the constructed list above:

    0.640 215(10) = 0.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 6. Summarizing - the positive number before normalization:

    31.640 215(10) = 1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 7. Normalize the binary representation of the number, shifting the decimal mark 4 positions to the left so that only one non-zero digit stays to the left of the decimal mark:

    31.640 215(10) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 20 =
    1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 24

  • 8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

    Sign: 1 (a negative number)

    Exponent (unadjusted): 4

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

  • 9. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary (base 2), by using the same technique of repeatedly dividing it by 2, as shown above:

    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1 = (4 + 1023)(10) = 1027(10) =
    100 0000 0011(2)

  • 10. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal sign) and adjust its length to 52 bits, by removing the excess bits, from the right (losing precision...):

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

    Mantissa (normalized): 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Conclusion:

    Sign (1 bit) = 1 (a negative number)

    Exponent (8 bits) = 100 0000 0011

    Mantissa (52 bits) = 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Number -31.640 215, converted from decimal system (base 10) to 64 bit double precision IEEE 754 binary floating point =
    1 - 100 0000 0011 - 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100