-0.000 806 264 623 585 362 514 063 654 156 856 122 Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard

Convert decimal -0.000 806 264 623 585 362 514 063 654 156 856 122(10) to 64 bit double precision IEEE 754 binary floating point representation standard (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

What are the steps to convert decimal number
-0.000 806 264 623 585 362 514 063 654 156 856 122(10) to 64 bit double precision IEEE 754 binary floating point representation (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

1. Start with the positive version of the number:

|-0.000 806 264 623 585 362 514 063 654 156 856 122| = 0.000 806 264 623 585 362 514 063 654 156 856 122


2. First, convert to binary (in base 2) the integer part: 0.
Divide the number repeatedly by 2.

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 0 ÷ 2 = 0 + 0;

3. Construct the base 2 representation of the integer part of the number.

Take all the remainders starting from the bottom of the list constructed above.

0(10) =

0(2)


4. Convert to binary (base 2) the fractional part: 0.000 806 264 623 585 362 514 063 654 156 856 122.

Multiply it repeatedly by 2.

Keep track of each integer part of the results.

Stop when we get a fractional part that is equal to zero.


  • #) multiplying = integer + fractional part;
  • 1) 0.000 806 264 623 585 362 514 063 654 156 856 122 × 2 = 0 + 0.001 612 529 247 170 725 028 127 308 313 712 244;
  • 2) 0.001 612 529 247 170 725 028 127 308 313 712 244 × 2 = 0 + 0.003 225 058 494 341 450 056 254 616 627 424 488;
  • 3) 0.003 225 058 494 341 450 056 254 616 627 424 488 × 2 = 0 + 0.006 450 116 988 682 900 112 509 233 254 848 976;
  • 4) 0.006 450 116 988 682 900 112 509 233 254 848 976 × 2 = 0 + 0.012 900 233 977 365 800 225 018 466 509 697 952;
  • 5) 0.012 900 233 977 365 800 225 018 466 509 697 952 × 2 = 0 + 0.025 800 467 954 731 600 450 036 933 019 395 904;
  • 6) 0.025 800 467 954 731 600 450 036 933 019 395 904 × 2 = 0 + 0.051 600 935 909 463 200 900 073 866 038 791 808;
  • 7) 0.051 600 935 909 463 200 900 073 866 038 791 808 × 2 = 0 + 0.103 201 871 818 926 401 800 147 732 077 583 616;
  • 8) 0.103 201 871 818 926 401 800 147 732 077 583 616 × 2 = 0 + 0.206 403 743 637 852 803 600 295 464 155 167 232;
  • 9) 0.206 403 743 637 852 803 600 295 464 155 167 232 × 2 = 0 + 0.412 807 487 275 705 607 200 590 928 310 334 464;
  • 10) 0.412 807 487 275 705 607 200 590 928 310 334 464 × 2 = 0 + 0.825 614 974 551 411 214 401 181 856 620 668 928;
  • 11) 0.825 614 974 551 411 214 401 181 856 620 668 928 × 2 = 1 + 0.651 229 949 102 822 428 802 363 713 241 337 856;
  • 12) 0.651 229 949 102 822 428 802 363 713 241 337 856 × 2 = 1 + 0.302 459 898 205 644 857 604 727 426 482 675 712;
  • 13) 0.302 459 898 205 644 857 604 727 426 482 675 712 × 2 = 0 + 0.604 919 796 411 289 715 209 454 852 965 351 424;
  • 14) 0.604 919 796 411 289 715 209 454 852 965 351 424 × 2 = 1 + 0.209 839 592 822 579 430 418 909 705 930 702 848;
  • 15) 0.209 839 592 822 579 430 418 909 705 930 702 848 × 2 = 0 + 0.419 679 185 645 158 860 837 819 411 861 405 696;
  • 16) 0.419 679 185 645 158 860 837 819 411 861 405 696 × 2 = 0 + 0.839 358 371 290 317 721 675 638 823 722 811 392;
  • 17) 0.839 358 371 290 317 721 675 638 823 722 811 392 × 2 = 1 + 0.678 716 742 580 635 443 351 277 647 445 622 784;
  • 18) 0.678 716 742 580 635 443 351 277 647 445 622 784 × 2 = 1 + 0.357 433 485 161 270 886 702 555 294 891 245 568;
  • 19) 0.357 433 485 161 270 886 702 555 294 891 245 568 × 2 = 0 + 0.714 866 970 322 541 773 405 110 589 782 491 136;
  • 20) 0.714 866 970 322 541 773 405 110 589 782 491 136 × 2 = 1 + 0.429 733 940 645 083 546 810 221 179 564 982 272;
  • 21) 0.429 733 940 645 083 546 810 221 179 564 982 272 × 2 = 0 + 0.859 467 881 290 167 093 620 442 359 129 964 544;
  • 22) 0.859 467 881 290 167 093 620 442 359 129 964 544 × 2 = 1 + 0.718 935 762 580 334 187 240 884 718 259 929 088;
  • 23) 0.718 935 762 580 334 187 240 884 718 259 929 088 × 2 = 1 + 0.437 871 525 160 668 374 481 769 436 519 858 176;
  • 24) 0.437 871 525 160 668 374 481 769 436 519 858 176 × 2 = 0 + 0.875 743 050 321 336 748 963 538 873 039 716 352;
  • 25) 0.875 743 050 321 336 748 963 538 873 039 716 352 × 2 = 1 + 0.751 486 100 642 673 497 927 077 746 079 432 704;
  • 26) 0.751 486 100 642 673 497 927 077 746 079 432 704 × 2 = 1 + 0.502 972 201 285 346 995 854 155 492 158 865 408;
  • 27) 0.502 972 201 285 346 995 854 155 492 158 865 408 × 2 = 1 + 0.005 944 402 570 693 991 708 310 984 317 730 816;
  • 28) 0.005 944 402 570 693 991 708 310 984 317 730 816 × 2 = 0 + 0.011 888 805 141 387 983 416 621 968 635 461 632;
  • 29) 0.011 888 805 141 387 983 416 621 968 635 461 632 × 2 = 0 + 0.023 777 610 282 775 966 833 243 937 270 923 264;
  • 30) 0.023 777 610 282 775 966 833 243 937 270 923 264 × 2 = 0 + 0.047 555 220 565 551 933 666 487 874 541 846 528;
  • 31) 0.047 555 220 565 551 933 666 487 874 541 846 528 × 2 = 0 + 0.095 110 441 131 103 867 332 975 749 083 693 056;
  • 32) 0.095 110 441 131 103 867 332 975 749 083 693 056 × 2 = 0 + 0.190 220 882 262 207 734 665 951 498 167 386 112;
  • 33) 0.190 220 882 262 207 734 665 951 498 167 386 112 × 2 = 0 + 0.380 441 764 524 415 469 331 902 996 334 772 224;
  • 34) 0.380 441 764 524 415 469 331 902 996 334 772 224 × 2 = 0 + 0.760 883 529 048 830 938 663 805 992 669 544 448;
  • 35) 0.760 883 529 048 830 938 663 805 992 669 544 448 × 2 = 1 + 0.521 767 058 097 661 877 327 611 985 339 088 896;
  • 36) 0.521 767 058 097 661 877 327 611 985 339 088 896 × 2 = 1 + 0.043 534 116 195 323 754 655 223 970 678 177 792;
  • 37) 0.043 534 116 195 323 754 655 223 970 678 177 792 × 2 = 0 + 0.087 068 232 390 647 509 310 447 941 356 355 584;
  • 38) 0.087 068 232 390 647 509 310 447 941 356 355 584 × 2 = 0 + 0.174 136 464 781 295 018 620 895 882 712 711 168;
  • 39) 0.174 136 464 781 295 018 620 895 882 712 711 168 × 2 = 0 + 0.348 272 929 562 590 037 241 791 765 425 422 336;
  • 40) 0.348 272 929 562 590 037 241 791 765 425 422 336 × 2 = 0 + 0.696 545 859 125 180 074 483 583 530 850 844 672;
  • 41) 0.696 545 859 125 180 074 483 583 530 850 844 672 × 2 = 1 + 0.393 091 718 250 360 148 967 167 061 701 689 344;
  • 42) 0.393 091 718 250 360 148 967 167 061 701 689 344 × 2 = 0 + 0.786 183 436 500 720 297 934 334 123 403 378 688;
  • 43) 0.786 183 436 500 720 297 934 334 123 403 378 688 × 2 = 1 + 0.572 366 873 001 440 595 868 668 246 806 757 376;
  • 44) 0.572 366 873 001 440 595 868 668 246 806 757 376 × 2 = 1 + 0.144 733 746 002 881 191 737 336 493 613 514 752;
  • 45) 0.144 733 746 002 881 191 737 336 493 613 514 752 × 2 = 0 + 0.289 467 492 005 762 383 474 672 987 227 029 504;
  • 46) 0.289 467 492 005 762 383 474 672 987 227 029 504 × 2 = 0 + 0.578 934 984 011 524 766 949 345 974 454 059 008;
  • 47) 0.578 934 984 011 524 766 949 345 974 454 059 008 × 2 = 1 + 0.157 869 968 023 049 533 898 691 948 908 118 016;
  • 48) 0.157 869 968 023 049 533 898 691 948 908 118 016 × 2 = 0 + 0.315 739 936 046 099 067 797 383 897 816 236 032;
  • 49) 0.315 739 936 046 099 067 797 383 897 816 236 032 × 2 = 0 + 0.631 479 872 092 198 135 594 767 795 632 472 064;
  • 50) 0.631 479 872 092 198 135 594 767 795 632 472 064 × 2 = 1 + 0.262 959 744 184 396 271 189 535 591 264 944 128;
  • 51) 0.262 959 744 184 396 271 189 535 591 264 944 128 × 2 = 0 + 0.525 919 488 368 792 542 379 071 182 529 888 256;
  • 52) 0.525 919 488 368 792 542 379 071 182 529 888 256 × 2 = 1 + 0.051 838 976 737 585 084 758 142 365 059 776 512;
  • 53) 0.051 838 976 737 585 084 758 142 365 059 776 512 × 2 = 0 + 0.103 677 953 475 170 169 516 284 730 119 553 024;
  • 54) 0.103 677 953 475 170 169 516 284 730 119 553 024 × 2 = 0 + 0.207 355 906 950 340 339 032 569 460 239 106 048;
  • 55) 0.207 355 906 950 340 339 032 569 460 239 106 048 × 2 = 0 + 0.414 711 813 900 680 678 065 138 920 478 212 096;
  • 56) 0.414 711 813 900 680 678 065 138 920 478 212 096 × 2 = 0 + 0.829 423 627 801 361 356 130 277 840 956 424 192;
  • 57) 0.829 423 627 801 361 356 130 277 840 956 424 192 × 2 = 1 + 0.658 847 255 602 722 712 260 555 681 912 848 384;
  • 58) 0.658 847 255 602 722 712 260 555 681 912 848 384 × 2 = 1 + 0.317 694 511 205 445 424 521 111 363 825 696 768;
  • 59) 0.317 694 511 205 445 424 521 111 363 825 696 768 × 2 = 0 + 0.635 389 022 410 890 849 042 222 727 651 393 536;
  • 60) 0.635 389 022 410 890 849 042 222 727 651 393 536 × 2 = 1 + 0.270 778 044 821 781 698 084 445 455 302 787 072;
  • 61) 0.270 778 044 821 781 698 084 445 455 302 787 072 × 2 = 0 + 0.541 556 089 643 563 396 168 890 910 605 574 144;
  • 62) 0.541 556 089 643 563 396 168 890 910 605 574 144 × 2 = 1 + 0.083 112 179 287 126 792 337 781 821 211 148 288;
  • 63) 0.083 112 179 287 126 792 337 781 821 211 148 288 × 2 = 0 + 0.166 224 358 574 253 584 675 563 642 422 296 576;

We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit) and at least one integer that was different from zero => FULL STOP (Losing precision - the converted number we get in the end will be just a very good approximation of the initial one).


5. Construct the base 2 representation of the fractional part of the number.

Take all the integer parts of the multiplying operations, starting from the top of the constructed list above:


0.000 806 264 623 585 362 514 063 654 156 856 122(10) =

0.0000 0000 0011 0100 1101 0110 1110 0000 0011 0000 1011 0010 0101 0000 1101 010(2)

6. Positive number before normalization:

0.000 806 264 623 585 362 514 063 654 156 856 122(10) =

0.0000 0000 0011 0100 1101 0110 1110 0000 0011 0000 1011 0010 0101 0000 1101 010(2)

7. Normalize the binary representation of the number.

Shift the decimal mark 11 positions to the right, so that only one non zero digit remains to the left of it:


0.000 806 264 623 585 362 514 063 654 156 856 122(10) =

0.0000 0000 0011 0100 1101 0110 1110 0000 0011 0000 1011 0010 0101 0000 1101 010(2) =

0.0000 0000 0011 0100 1101 0110 1110 0000 0011 0000 1011 0010 0101 0000 1101 010(2) × 20 =

1.1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010(2) × 2-11


8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

Sign 1 (a negative number)

Exponent (unadjusted): -11

Mantissa (not normalized):
1.1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010


9. Adjust the exponent.

Use the 11 bit excess/bias notation:


Exponent (adjusted) =

Exponent (unadjusted) + 2(11-1) - 1 =

-11 + 2(11-1) - 1 =

(-11 + 1 023)(10) =

1 012(10)


10. Convert the adjusted exponent from the decimal (base 10) to 11 bit binary.

Use the same technique of repeatedly dividing by 2:


  • division = quotient + remainder;
  • 1 012 ÷ 2 = 506 + 0;
  • 506 ÷ 2 = 253 + 0;
  • 253 ÷ 2 = 126 + 1;
  • 126 ÷ 2 = 63 + 0;
  • 63 ÷ 2 = 31 + 1;
  • 31 ÷ 2 = 15 + 1;
  • 15 ÷ 2 = 7 + 1;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

11. Construct the base 2 representation of the adjusted exponent.

Take all the remainders starting from the bottom of the list constructed above.


Exponent (adjusted) =

1012(10) =

011 1111 0100(2)


12. Normalize the mantissa.

a) Remove the leading (the leftmost) bit, since it's allways 1, and the decimal point, if the case.

b) Adjust its length to 52 bits, only if necessary (not the case here).


Mantissa (normalized) =

1. 1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010 =

1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010


13. The three elements that make up the number's 64 bit double precision IEEE 754 binary floating point representation:

Sign (1 bit) =
1 (a negative number)

Exponent (11 bits) =
011 1111 0100

Mantissa (52 bits) =
1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010


Decimal number -0.000 806 264 623 585 362 514 063 654 156 856 122 converted to 64 bit double precision IEEE 754 binary floating point representation:

1 - 011 1111 0100 - 1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010

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How to convert numbers from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point standard

Follow the steps below to convert a base 10 decimal number to 64 bit double precision IEEE 754 binary floating point:

  • 1. If the number to be converted is negative, start with its the positive version.
  • 2. First convert the integer part. Divide repeatedly by 2 the positive representation of the integer number that is to be converted to binary, until we get a quotient that is equal to zero, keeping track of each remainder.
  • 3. Construct the base 2 representation of the positive integer part of the number, by taking all the remainders from the previous operations, starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Then convert the fractional part. Multiply the number repeatedly by 2, until we get a fractional part that is equal to zero, keeping track of each integer part of the results.
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the multiplying operations, starting from the top of the list constructed above (they should appear in the binary representation, from left to right, in the order they have been calculated).
  • 6. Normalize the binary representation of the number, shifting the decimal mark (the decimal point) "n" positions either to the left, or to the right, so that only one non zero digit remains to the left of the decimal mark.
  • 7. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary, by using the same technique of repeatedly dividing by 2, as shown above:
    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1
  • 8. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal mark, if the case) and adjust its length to 52 bits, either by removing the excess bits from the right (losing precision...) or by adding extra bits set on '0' to the right.
  • 9. Sign (it takes 1 bit) is either 1 for a negative or 0 for a positive number.

Example: convert the negative number -31.640 215 from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point:

  • 1. Start with the positive version of the number:

    |-31.640 215| = 31.640 215

  • 2. First convert the integer part, 31. Divide it repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 31 ÷ 2 = 15 + 1;
    • 15 ÷ 2 = 7 + 1;
    • 7 ÷ 2 = 3 + 1;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
    • We have encountered a quotient that is ZERO => FULL STOP
  • 3. Construct the base 2 representation of the integer part of the number by taking all the remainders of the previous dividing operations, starting from the bottom of the list constructed above:

    31(10) = 1 1111(2)

  • 4. Then, convert the fractional part, 0.640 215. Multiply repeatedly by 2, keeping track of each integer part of the results, until we get a fractional part that is equal to zero:
    • #) multiplying = integer + fractional part;
    • 1) 0.640 215 × 2 = 1 + 0.280 43;
    • 2) 0.280 43 × 2 = 0 + 0.560 86;
    • 3) 0.560 86 × 2 = 1 + 0.121 72;
    • 4) 0.121 72 × 2 = 0 + 0.243 44;
    • 5) 0.243 44 × 2 = 0 + 0.486 88;
    • 6) 0.486 88 × 2 = 0 + 0.973 76;
    • 7) 0.973 76 × 2 = 1 + 0.947 52;
    • 8) 0.947 52 × 2 = 1 + 0.895 04;
    • 9) 0.895 04 × 2 = 1 + 0.790 08;
    • 10) 0.790 08 × 2 = 1 + 0.580 16;
    • 11) 0.580 16 × 2 = 1 + 0.160 32;
    • 12) 0.160 32 × 2 = 0 + 0.320 64;
    • 13) 0.320 64 × 2 = 0 + 0.641 28;
    • 14) 0.641 28 × 2 = 1 + 0.282 56;
    • 15) 0.282 56 × 2 = 0 + 0.565 12;
    • 16) 0.565 12 × 2 = 1 + 0.130 24;
    • 17) 0.130 24 × 2 = 0 + 0.260 48;
    • 18) 0.260 48 × 2 = 0 + 0.520 96;
    • 19) 0.520 96 × 2 = 1 + 0.041 92;
    • 20) 0.041 92 × 2 = 0 + 0.083 84;
    • 21) 0.083 84 × 2 = 0 + 0.167 68;
    • 22) 0.167 68 × 2 = 0 + 0.335 36;
    • 23) 0.335 36 × 2 = 0 + 0.670 72;
    • 24) 0.670 72 × 2 = 1 + 0.341 44;
    • 25) 0.341 44 × 2 = 0 + 0.682 88;
    • 26) 0.682 88 × 2 = 1 + 0.365 76;
    • 27) 0.365 76 × 2 = 0 + 0.731 52;
    • 28) 0.731 52 × 2 = 1 + 0.463 04;
    • 29) 0.463 04 × 2 = 0 + 0.926 08;
    • 30) 0.926 08 × 2 = 1 + 0.852 16;
    • 31) 0.852 16 × 2 = 1 + 0.704 32;
    • 32) 0.704 32 × 2 = 1 + 0.408 64;
    • 33) 0.408 64 × 2 = 0 + 0.817 28;
    • 34) 0.817 28 × 2 = 1 + 0.634 56;
    • 35) 0.634 56 × 2 = 1 + 0.269 12;
    • 36) 0.269 12 × 2 = 0 + 0.538 24;
    • 37) 0.538 24 × 2 = 1 + 0.076 48;
    • 38) 0.076 48 × 2 = 0 + 0.152 96;
    • 39) 0.152 96 × 2 = 0 + 0.305 92;
    • 40) 0.305 92 × 2 = 0 + 0.611 84;
    • 41) 0.611 84 × 2 = 1 + 0.223 68;
    • 42) 0.223 68 × 2 = 0 + 0.447 36;
    • 43) 0.447 36 × 2 = 0 + 0.894 72;
    • 44) 0.894 72 × 2 = 1 + 0.789 44;
    • 45) 0.789 44 × 2 = 1 + 0.578 88;
    • 46) 0.578 88 × 2 = 1 + 0.157 76;
    • 47) 0.157 76 × 2 = 0 + 0.315 52;
    • 48) 0.315 52 × 2 = 0 + 0.631 04;
    • 49) 0.631 04 × 2 = 1 + 0.262 08;
    • 50) 0.262 08 × 2 = 0 + 0.524 16;
    • 51) 0.524 16 × 2 = 1 + 0.048 32;
    • 52) 0.048 32 × 2 = 0 + 0.096 64;
    • 53) 0.096 64 × 2 = 0 + 0.193 28;
    • We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit = 52) and at least one integer part that was different from zero => FULL STOP (losing precision...).
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the previous multiplying operations, starting from the top of the constructed list above:

    0.640 215(10) = 0.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 6. Summarizing - the positive number before normalization:

    31.640 215(10) = 1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 7. Normalize the binary representation of the number, shifting the decimal mark 4 positions to the left so that only one non-zero digit stays to the left of the decimal mark:

    31.640 215(10) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 20 =
    1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 24

  • 8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

    Sign: 1 (a negative number)

    Exponent (unadjusted): 4

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

  • 9. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary (base 2), by using the same technique of repeatedly dividing it by 2, as shown above:

    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1 = (4 + 1023)(10) = 1027(10) =
    100 0000 0011(2)

  • 10. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal sign) and adjust its length to 52 bits, by removing the excess bits, from the right (losing precision...):

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

    Mantissa (normalized): 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Conclusion:

    Sign (1 bit) = 1 (a negative number)

    Exponent (8 bits) = 100 0000 0011

    Mantissa (52 bits) = 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Number -31.640 215, converted from decimal system (base 10) to 64 bit double precision IEEE 754 binary floating point =
    1 - 100 0000 0011 - 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100