-0.000 806 264 623 585 362 514 063 654 156 856 096 9 Converted to 64 Bit Double Precision IEEE 754 Binary Floating Point Representation Standard

Convert decimal -0.000 806 264 623 585 362 514 063 654 156 856 096 9(10) to 64 bit double precision IEEE 754 binary floating point representation standard (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

What are the steps to convert decimal number
-0.000 806 264 623 585 362 514 063 654 156 856 096 9(10) to 64 bit double precision IEEE 754 binary floating point representation (1 bit for sign, 11 bits for exponent, 52 bits for mantissa)

1. Start with the positive version of the number:

|-0.000 806 264 623 585 362 514 063 654 156 856 096 9| = 0.000 806 264 623 585 362 514 063 654 156 856 096 9


2. First, convert to binary (in base 2) the integer part: 0.
Divide the number repeatedly by 2.

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 0 ÷ 2 = 0 + 0;

3. Construct the base 2 representation of the integer part of the number.

Take all the remainders starting from the bottom of the list constructed above.

0(10) =

0(2)


4. Convert to binary (base 2) the fractional part: 0.000 806 264 623 585 362 514 063 654 156 856 096 9.

Multiply it repeatedly by 2.

Keep track of each integer part of the results.

Stop when we get a fractional part that is equal to zero.


  • #) multiplying = integer + fractional part;
  • 1) 0.000 806 264 623 585 362 514 063 654 156 856 096 9 × 2 = 0 + 0.001 612 529 247 170 725 028 127 308 313 712 193 8;
  • 2) 0.001 612 529 247 170 725 028 127 308 313 712 193 8 × 2 = 0 + 0.003 225 058 494 341 450 056 254 616 627 424 387 6;
  • 3) 0.003 225 058 494 341 450 056 254 616 627 424 387 6 × 2 = 0 + 0.006 450 116 988 682 900 112 509 233 254 848 775 2;
  • 4) 0.006 450 116 988 682 900 112 509 233 254 848 775 2 × 2 = 0 + 0.012 900 233 977 365 800 225 018 466 509 697 550 4;
  • 5) 0.012 900 233 977 365 800 225 018 466 509 697 550 4 × 2 = 0 + 0.025 800 467 954 731 600 450 036 933 019 395 100 8;
  • 6) 0.025 800 467 954 731 600 450 036 933 019 395 100 8 × 2 = 0 + 0.051 600 935 909 463 200 900 073 866 038 790 201 6;
  • 7) 0.051 600 935 909 463 200 900 073 866 038 790 201 6 × 2 = 0 + 0.103 201 871 818 926 401 800 147 732 077 580 403 2;
  • 8) 0.103 201 871 818 926 401 800 147 732 077 580 403 2 × 2 = 0 + 0.206 403 743 637 852 803 600 295 464 155 160 806 4;
  • 9) 0.206 403 743 637 852 803 600 295 464 155 160 806 4 × 2 = 0 + 0.412 807 487 275 705 607 200 590 928 310 321 612 8;
  • 10) 0.412 807 487 275 705 607 200 590 928 310 321 612 8 × 2 = 0 + 0.825 614 974 551 411 214 401 181 856 620 643 225 6;
  • 11) 0.825 614 974 551 411 214 401 181 856 620 643 225 6 × 2 = 1 + 0.651 229 949 102 822 428 802 363 713 241 286 451 2;
  • 12) 0.651 229 949 102 822 428 802 363 713 241 286 451 2 × 2 = 1 + 0.302 459 898 205 644 857 604 727 426 482 572 902 4;
  • 13) 0.302 459 898 205 644 857 604 727 426 482 572 902 4 × 2 = 0 + 0.604 919 796 411 289 715 209 454 852 965 145 804 8;
  • 14) 0.604 919 796 411 289 715 209 454 852 965 145 804 8 × 2 = 1 + 0.209 839 592 822 579 430 418 909 705 930 291 609 6;
  • 15) 0.209 839 592 822 579 430 418 909 705 930 291 609 6 × 2 = 0 + 0.419 679 185 645 158 860 837 819 411 860 583 219 2;
  • 16) 0.419 679 185 645 158 860 837 819 411 860 583 219 2 × 2 = 0 + 0.839 358 371 290 317 721 675 638 823 721 166 438 4;
  • 17) 0.839 358 371 290 317 721 675 638 823 721 166 438 4 × 2 = 1 + 0.678 716 742 580 635 443 351 277 647 442 332 876 8;
  • 18) 0.678 716 742 580 635 443 351 277 647 442 332 876 8 × 2 = 1 + 0.357 433 485 161 270 886 702 555 294 884 665 753 6;
  • 19) 0.357 433 485 161 270 886 702 555 294 884 665 753 6 × 2 = 0 + 0.714 866 970 322 541 773 405 110 589 769 331 507 2;
  • 20) 0.714 866 970 322 541 773 405 110 589 769 331 507 2 × 2 = 1 + 0.429 733 940 645 083 546 810 221 179 538 663 014 4;
  • 21) 0.429 733 940 645 083 546 810 221 179 538 663 014 4 × 2 = 0 + 0.859 467 881 290 167 093 620 442 359 077 326 028 8;
  • 22) 0.859 467 881 290 167 093 620 442 359 077 326 028 8 × 2 = 1 + 0.718 935 762 580 334 187 240 884 718 154 652 057 6;
  • 23) 0.718 935 762 580 334 187 240 884 718 154 652 057 6 × 2 = 1 + 0.437 871 525 160 668 374 481 769 436 309 304 115 2;
  • 24) 0.437 871 525 160 668 374 481 769 436 309 304 115 2 × 2 = 0 + 0.875 743 050 321 336 748 963 538 872 618 608 230 4;
  • 25) 0.875 743 050 321 336 748 963 538 872 618 608 230 4 × 2 = 1 + 0.751 486 100 642 673 497 927 077 745 237 216 460 8;
  • 26) 0.751 486 100 642 673 497 927 077 745 237 216 460 8 × 2 = 1 + 0.502 972 201 285 346 995 854 155 490 474 432 921 6;
  • 27) 0.502 972 201 285 346 995 854 155 490 474 432 921 6 × 2 = 1 + 0.005 944 402 570 693 991 708 310 980 948 865 843 2;
  • 28) 0.005 944 402 570 693 991 708 310 980 948 865 843 2 × 2 = 0 + 0.011 888 805 141 387 983 416 621 961 897 731 686 4;
  • 29) 0.011 888 805 141 387 983 416 621 961 897 731 686 4 × 2 = 0 + 0.023 777 610 282 775 966 833 243 923 795 463 372 8;
  • 30) 0.023 777 610 282 775 966 833 243 923 795 463 372 8 × 2 = 0 + 0.047 555 220 565 551 933 666 487 847 590 926 745 6;
  • 31) 0.047 555 220 565 551 933 666 487 847 590 926 745 6 × 2 = 0 + 0.095 110 441 131 103 867 332 975 695 181 853 491 2;
  • 32) 0.095 110 441 131 103 867 332 975 695 181 853 491 2 × 2 = 0 + 0.190 220 882 262 207 734 665 951 390 363 706 982 4;
  • 33) 0.190 220 882 262 207 734 665 951 390 363 706 982 4 × 2 = 0 + 0.380 441 764 524 415 469 331 902 780 727 413 964 8;
  • 34) 0.380 441 764 524 415 469 331 902 780 727 413 964 8 × 2 = 0 + 0.760 883 529 048 830 938 663 805 561 454 827 929 6;
  • 35) 0.760 883 529 048 830 938 663 805 561 454 827 929 6 × 2 = 1 + 0.521 767 058 097 661 877 327 611 122 909 655 859 2;
  • 36) 0.521 767 058 097 661 877 327 611 122 909 655 859 2 × 2 = 1 + 0.043 534 116 195 323 754 655 222 245 819 311 718 4;
  • 37) 0.043 534 116 195 323 754 655 222 245 819 311 718 4 × 2 = 0 + 0.087 068 232 390 647 509 310 444 491 638 623 436 8;
  • 38) 0.087 068 232 390 647 509 310 444 491 638 623 436 8 × 2 = 0 + 0.174 136 464 781 295 018 620 888 983 277 246 873 6;
  • 39) 0.174 136 464 781 295 018 620 888 983 277 246 873 6 × 2 = 0 + 0.348 272 929 562 590 037 241 777 966 554 493 747 2;
  • 40) 0.348 272 929 562 590 037 241 777 966 554 493 747 2 × 2 = 0 + 0.696 545 859 125 180 074 483 555 933 108 987 494 4;
  • 41) 0.696 545 859 125 180 074 483 555 933 108 987 494 4 × 2 = 1 + 0.393 091 718 250 360 148 967 111 866 217 974 988 8;
  • 42) 0.393 091 718 250 360 148 967 111 866 217 974 988 8 × 2 = 0 + 0.786 183 436 500 720 297 934 223 732 435 949 977 6;
  • 43) 0.786 183 436 500 720 297 934 223 732 435 949 977 6 × 2 = 1 + 0.572 366 873 001 440 595 868 447 464 871 899 955 2;
  • 44) 0.572 366 873 001 440 595 868 447 464 871 899 955 2 × 2 = 1 + 0.144 733 746 002 881 191 736 894 929 743 799 910 4;
  • 45) 0.144 733 746 002 881 191 736 894 929 743 799 910 4 × 2 = 0 + 0.289 467 492 005 762 383 473 789 859 487 599 820 8;
  • 46) 0.289 467 492 005 762 383 473 789 859 487 599 820 8 × 2 = 0 + 0.578 934 984 011 524 766 947 579 718 975 199 641 6;
  • 47) 0.578 934 984 011 524 766 947 579 718 975 199 641 6 × 2 = 1 + 0.157 869 968 023 049 533 895 159 437 950 399 283 2;
  • 48) 0.157 869 968 023 049 533 895 159 437 950 399 283 2 × 2 = 0 + 0.315 739 936 046 099 067 790 318 875 900 798 566 4;
  • 49) 0.315 739 936 046 099 067 790 318 875 900 798 566 4 × 2 = 0 + 0.631 479 872 092 198 135 580 637 751 801 597 132 8;
  • 50) 0.631 479 872 092 198 135 580 637 751 801 597 132 8 × 2 = 1 + 0.262 959 744 184 396 271 161 275 503 603 194 265 6;
  • 51) 0.262 959 744 184 396 271 161 275 503 603 194 265 6 × 2 = 0 + 0.525 919 488 368 792 542 322 551 007 206 388 531 2;
  • 52) 0.525 919 488 368 792 542 322 551 007 206 388 531 2 × 2 = 1 + 0.051 838 976 737 585 084 645 102 014 412 777 062 4;
  • 53) 0.051 838 976 737 585 084 645 102 014 412 777 062 4 × 2 = 0 + 0.103 677 953 475 170 169 290 204 028 825 554 124 8;
  • 54) 0.103 677 953 475 170 169 290 204 028 825 554 124 8 × 2 = 0 + 0.207 355 906 950 340 338 580 408 057 651 108 249 6;
  • 55) 0.207 355 906 950 340 338 580 408 057 651 108 249 6 × 2 = 0 + 0.414 711 813 900 680 677 160 816 115 302 216 499 2;
  • 56) 0.414 711 813 900 680 677 160 816 115 302 216 499 2 × 2 = 0 + 0.829 423 627 801 361 354 321 632 230 604 432 998 4;
  • 57) 0.829 423 627 801 361 354 321 632 230 604 432 998 4 × 2 = 1 + 0.658 847 255 602 722 708 643 264 461 208 865 996 8;
  • 58) 0.658 847 255 602 722 708 643 264 461 208 865 996 8 × 2 = 1 + 0.317 694 511 205 445 417 286 528 922 417 731 993 6;
  • 59) 0.317 694 511 205 445 417 286 528 922 417 731 993 6 × 2 = 0 + 0.635 389 022 410 890 834 573 057 844 835 463 987 2;
  • 60) 0.635 389 022 410 890 834 573 057 844 835 463 987 2 × 2 = 1 + 0.270 778 044 821 781 669 146 115 689 670 927 974 4;
  • 61) 0.270 778 044 821 781 669 146 115 689 670 927 974 4 × 2 = 0 + 0.541 556 089 643 563 338 292 231 379 341 855 948 8;
  • 62) 0.541 556 089 643 563 338 292 231 379 341 855 948 8 × 2 = 1 + 0.083 112 179 287 126 676 584 462 758 683 711 897 6;
  • 63) 0.083 112 179 287 126 676 584 462 758 683 711 897 6 × 2 = 0 + 0.166 224 358 574 253 353 168 925 517 367 423 795 2;

We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit) and at least one integer that was different from zero => FULL STOP (Losing precision - the converted number we get in the end will be just a very good approximation of the initial one).


5. Construct the base 2 representation of the fractional part of the number.

Take all the integer parts of the multiplying operations, starting from the top of the constructed list above:


0.000 806 264 623 585 362 514 063 654 156 856 096 9(10) =

0.0000 0000 0011 0100 1101 0110 1110 0000 0011 0000 1011 0010 0101 0000 1101 010(2)

6. Positive number before normalization:

0.000 806 264 623 585 362 514 063 654 156 856 096 9(10) =

0.0000 0000 0011 0100 1101 0110 1110 0000 0011 0000 1011 0010 0101 0000 1101 010(2)

7. Normalize the binary representation of the number.

Shift the decimal mark 11 positions to the right, so that only one non zero digit remains to the left of it:


0.000 806 264 623 585 362 514 063 654 156 856 096 9(10) =

0.0000 0000 0011 0100 1101 0110 1110 0000 0011 0000 1011 0010 0101 0000 1101 010(2) =

0.0000 0000 0011 0100 1101 0110 1110 0000 0011 0000 1011 0010 0101 0000 1101 010(2) × 20 =

1.1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010(2) × 2-11


8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

Sign 1 (a negative number)

Exponent (unadjusted): -11

Mantissa (not normalized):
1.1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010


9. Adjust the exponent.

Use the 11 bit excess/bias notation:


Exponent (adjusted) =

Exponent (unadjusted) + 2(11-1) - 1 =

-11 + 2(11-1) - 1 =

(-11 + 1 023)(10) =

1 012(10)


10. Convert the adjusted exponent from the decimal (base 10) to 11 bit binary.

Use the same technique of repeatedly dividing by 2:


  • division = quotient + remainder;
  • 1 012 ÷ 2 = 506 + 0;
  • 506 ÷ 2 = 253 + 0;
  • 253 ÷ 2 = 126 + 1;
  • 126 ÷ 2 = 63 + 0;
  • 63 ÷ 2 = 31 + 1;
  • 31 ÷ 2 = 15 + 1;
  • 15 ÷ 2 = 7 + 1;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

11. Construct the base 2 representation of the adjusted exponent.

Take all the remainders starting from the bottom of the list constructed above.


Exponent (adjusted) =

1012(10) =

011 1111 0100(2)


12. Normalize the mantissa.

a) Remove the leading (the leftmost) bit, since it's allways 1, and the decimal point, if the case.

b) Adjust its length to 52 bits, only if necessary (not the case here).


Mantissa (normalized) =

1. 1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010 =

1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010


13. The three elements that make up the number's 64 bit double precision IEEE 754 binary floating point representation:

Sign (1 bit) =
1 (a negative number)

Exponent (11 bits) =
011 1111 0100

Mantissa (52 bits) =
1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010


Decimal number -0.000 806 264 623 585 362 514 063 654 156 856 096 9 converted to 64 bit double precision IEEE 754 binary floating point representation:

1 - 011 1111 0100 - 1010 0110 1011 0111 0000 0001 1000 0101 1001 0010 1000 0110 1010

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How to convert numbers from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point standard

Follow the steps below to convert a base 10 decimal number to 64 bit double precision IEEE 754 binary floating point:

  • 1. If the number to be converted is negative, start with its the positive version.
  • 2. First convert the integer part. Divide repeatedly by 2 the positive representation of the integer number that is to be converted to binary, until we get a quotient that is equal to zero, keeping track of each remainder.
  • 3. Construct the base 2 representation of the positive integer part of the number, by taking all the remainders from the previous operations, starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Then convert the fractional part. Multiply the number repeatedly by 2, until we get a fractional part that is equal to zero, keeping track of each integer part of the results.
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the multiplying operations, starting from the top of the list constructed above (they should appear in the binary representation, from left to right, in the order they have been calculated).
  • 6. Normalize the binary representation of the number, shifting the decimal mark (the decimal point) "n" positions either to the left, or to the right, so that only one non zero digit remains to the left of the decimal mark.
  • 7. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary, by using the same technique of repeatedly dividing by 2, as shown above:
    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1
  • 8. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal mark, if the case) and adjust its length to 52 bits, either by removing the excess bits from the right (losing precision...) or by adding extra bits set on '0' to the right.
  • 9. Sign (it takes 1 bit) is either 1 for a negative or 0 for a positive number.

Example: convert the negative number -31.640 215 from the decimal system (base ten) to 64 bit double precision IEEE 754 binary floating point:

  • 1. Start with the positive version of the number:

    |-31.640 215| = 31.640 215

  • 2. First convert the integer part, 31. Divide it repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder;
    • 31 ÷ 2 = 15 + 1;
    • 15 ÷ 2 = 7 + 1;
    • 7 ÷ 2 = 3 + 1;
    • 3 ÷ 2 = 1 + 1;
    • 1 ÷ 2 = 0 + 1;
    • We have encountered a quotient that is ZERO => FULL STOP
  • 3. Construct the base 2 representation of the integer part of the number by taking all the remainders of the previous dividing operations, starting from the bottom of the list constructed above:

    31(10) = 1 1111(2)

  • 4. Then, convert the fractional part, 0.640 215. Multiply repeatedly by 2, keeping track of each integer part of the results, until we get a fractional part that is equal to zero:
    • #) multiplying = integer + fractional part;
    • 1) 0.640 215 × 2 = 1 + 0.280 43;
    • 2) 0.280 43 × 2 = 0 + 0.560 86;
    • 3) 0.560 86 × 2 = 1 + 0.121 72;
    • 4) 0.121 72 × 2 = 0 + 0.243 44;
    • 5) 0.243 44 × 2 = 0 + 0.486 88;
    • 6) 0.486 88 × 2 = 0 + 0.973 76;
    • 7) 0.973 76 × 2 = 1 + 0.947 52;
    • 8) 0.947 52 × 2 = 1 + 0.895 04;
    • 9) 0.895 04 × 2 = 1 + 0.790 08;
    • 10) 0.790 08 × 2 = 1 + 0.580 16;
    • 11) 0.580 16 × 2 = 1 + 0.160 32;
    • 12) 0.160 32 × 2 = 0 + 0.320 64;
    • 13) 0.320 64 × 2 = 0 + 0.641 28;
    • 14) 0.641 28 × 2 = 1 + 0.282 56;
    • 15) 0.282 56 × 2 = 0 + 0.565 12;
    • 16) 0.565 12 × 2 = 1 + 0.130 24;
    • 17) 0.130 24 × 2 = 0 + 0.260 48;
    • 18) 0.260 48 × 2 = 0 + 0.520 96;
    • 19) 0.520 96 × 2 = 1 + 0.041 92;
    • 20) 0.041 92 × 2 = 0 + 0.083 84;
    • 21) 0.083 84 × 2 = 0 + 0.167 68;
    • 22) 0.167 68 × 2 = 0 + 0.335 36;
    • 23) 0.335 36 × 2 = 0 + 0.670 72;
    • 24) 0.670 72 × 2 = 1 + 0.341 44;
    • 25) 0.341 44 × 2 = 0 + 0.682 88;
    • 26) 0.682 88 × 2 = 1 + 0.365 76;
    • 27) 0.365 76 × 2 = 0 + 0.731 52;
    • 28) 0.731 52 × 2 = 1 + 0.463 04;
    • 29) 0.463 04 × 2 = 0 + 0.926 08;
    • 30) 0.926 08 × 2 = 1 + 0.852 16;
    • 31) 0.852 16 × 2 = 1 + 0.704 32;
    • 32) 0.704 32 × 2 = 1 + 0.408 64;
    • 33) 0.408 64 × 2 = 0 + 0.817 28;
    • 34) 0.817 28 × 2 = 1 + 0.634 56;
    • 35) 0.634 56 × 2 = 1 + 0.269 12;
    • 36) 0.269 12 × 2 = 0 + 0.538 24;
    • 37) 0.538 24 × 2 = 1 + 0.076 48;
    • 38) 0.076 48 × 2 = 0 + 0.152 96;
    • 39) 0.152 96 × 2 = 0 + 0.305 92;
    • 40) 0.305 92 × 2 = 0 + 0.611 84;
    • 41) 0.611 84 × 2 = 1 + 0.223 68;
    • 42) 0.223 68 × 2 = 0 + 0.447 36;
    • 43) 0.447 36 × 2 = 0 + 0.894 72;
    • 44) 0.894 72 × 2 = 1 + 0.789 44;
    • 45) 0.789 44 × 2 = 1 + 0.578 88;
    • 46) 0.578 88 × 2 = 1 + 0.157 76;
    • 47) 0.157 76 × 2 = 0 + 0.315 52;
    • 48) 0.315 52 × 2 = 0 + 0.631 04;
    • 49) 0.631 04 × 2 = 1 + 0.262 08;
    • 50) 0.262 08 × 2 = 0 + 0.524 16;
    • 51) 0.524 16 × 2 = 1 + 0.048 32;
    • 52) 0.048 32 × 2 = 0 + 0.096 64;
    • 53) 0.096 64 × 2 = 0 + 0.193 28;
    • We didn't get any fractional part that was equal to zero. But we had enough iterations (over Mantissa limit = 52) and at least one integer part that was different from zero => FULL STOP (losing precision...).
  • 5. Construct the base 2 representation of the fractional part of the number, by taking all the integer parts of the previous multiplying operations, starting from the top of the constructed list above:

    0.640 215(10) = 0.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 6. Summarizing - the positive number before normalization:

    31.640 215(10) = 1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2)

  • 7. Normalize the binary representation of the number, shifting the decimal mark 4 positions to the left so that only one non-zero digit stays to the left of the decimal mark:

    31.640 215(10) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) =
    1 1111.1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 20 =
    1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0(2) × 24

  • 8. Up to this moment, there are the following elements that would feed into the 64 bit double precision IEEE 754 binary floating point representation:

    Sign: 1 (a negative number)

    Exponent (unadjusted): 4

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

  • 9. Adjust the exponent in 11 bit excess/bias notation and then convert it from decimal (base 10) to 11 bit binary (base 2), by using the same technique of repeatedly dividing it by 2, as shown above:

    Exponent (adjusted) = Exponent (unadjusted) + 2(11-1) - 1 = (4 + 1023)(10) = 1027(10) =
    100 0000 0011(2)

  • 10. Normalize mantissa, remove the leading (leftmost) bit, since it's allways '1' (and the decimal sign) and adjust its length to 52 bits, by removing the excess bits, from the right (losing precision...):

    Mantissa (not-normalized): 1.1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100 1010 0

    Mantissa (normalized): 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Conclusion:

    Sign (1 bit) = 1 (a negative number)

    Exponent (8 bits) = 100 0000 0011

    Mantissa (52 bits) = 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100

  • Number -31.640 215, converted from decimal system (base 10) to 64 bit double precision IEEE 754 binary floating point =
    1 - 100 0000 0011 - 1111 1010 0011 1110 0101 0010 0001 0101 0111 0110 1000 1001 1100