Convert 9 122 999 999 999 999 374 to a Signed Binary (Base 2)

How to convert 9 122 999 999 999 999 374(10), a signed base 10 integer number? How to write it as a signed binary code in base 2

What are the required steps to convert base 10 integer
number 9 122 999 999 999 999 374 to signed binary code (in base 2)?

  • A signed integer, written in base ten, or a decimal system number, is a number written using the digits 0 through 9 and the sign, which can be positive (+) or negative (-). If positive, the sign is usually not written. A number written in base two, or binary, is a number written using only the digits 0 and 1.

1. Divide the number repeatedly by 2:

Keep track of each remainder.

Stop when you get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 9 122 999 999 999 999 374 ÷ 2 = 4 561 499 999 999 999 687 + 0;
  • 4 561 499 999 999 999 687 ÷ 2 = 2 280 749 999 999 999 843 + 1;
  • 2 280 749 999 999 999 843 ÷ 2 = 1 140 374 999 999 999 921 + 1;
  • 1 140 374 999 999 999 921 ÷ 2 = 570 187 499 999 999 960 + 1;
  • 570 187 499 999 999 960 ÷ 2 = 285 093 749 999 999 980 + 0;
  • 285 093 749 999 999 980 ÷ 2 = 142 546 874 999 999 990 + 0;
  • 142 546 874 999 999 990 ÷ 2 = 71 273 437 499 999 995 + 0;
  • 71 273 437 499 999 995 ÷ 2 = 35 636 718 749 999 997 + 1;
  • 35 636 718 749 999 997 ÷ 2 = 17 818 359 374 999 998 + 1;
  • 17 818 359 374 999 998 ÷ 2 = 8 909 179 687 499 999 + 0;
  • 8 909 179 687 499 999 ÷ 2 = 4 454 589 843 749 999 + 1;
  • 4 454 589 843 749 999 ÷ 2 = 2 227 294 921 874 999 + 1;
  • 2 227 294 921 874 999 ÷ 2 = 1 113 647 460 937 499 + 1;
  • 1 113 647 460 937 499 ÷ 2 = 556 823 730 468 749 + 1;
  • 556 823 730 468 749 ÷ 2 = 278 411 865 234 374 + 1;
  • 278 411 865 234 374 ÷ 2 = 139 205 932 617 187 + 0;
  • 139 205 932 617 187 ÷ 2 = 69 602 966 308 593 + 1;
  • 69 602 966 308 593 ÷ 2 = 34 801 483 154 296 + 1;
  • 34 801 483 154 296 ÷ 2 = 17 400 741 577 148 + 0;
  • 17 400 741 577 148 ÷ 2 = 8 700 370 788 574 + 0;
  • 8 700 370 788 574 ÷ 2 = 4 350 185 394 287 + 0;
  • 4 350 185 394 287 ÷ 2 = 2 175 092 697 143 + 1;
  • 2 175 092 697 143 ÷ 2 = 1 087 546 348 571 + 1;
  • 1 087 546 348 571 ÷ 2 = 543 773 174 285 + 1;
  • 543 773 174 285 ÷ 2 = 271 886 587 142 + 1;
  • 271 886 587 142 ÷ 2 = 135 943 293 571 + 0;
  • 135 943 293 571 ÷ 2 = 67 971 646 785 + 1;
  • 67 971 646 785 ÷ 2 = 33 985 823 392 + 1;
  • 33 985 823 392 ÷ 2 = 16 992 911 696 + 0;
  • 16 992 911 696 ÷ 2 = 8 496 455 848 + 0;
  • 8 496 455 848 ÷ 2 = 4 248 227 924 + 0;
  • 4 248 227 924 ÷ 2 = 2 124 113 962 + 0;
  • 2 124 113 962 ÷ 2 = 1 062 056 981 + 0;
  • 1 062 056 981 ÷ 2 = 531 028 490 + 1;
  • 531 028 490 ÷ 2 = 265 514 245 + 0;
  • 265 514 245 ÷ 2 = 132 757 122 + 1;
  • 132 757 122 ÷ 2 = 66 378 561 + 0;
  • 66 378 561 ÷ 2 = 33 189 280 + 1;
  • 33 189 280 ÷ 2 = 16 594 640 + 0;
  • 16 594 640 ÷ 2 = 8 297 320 + 0;
  • 8 297 320 ÷ 2 = 4 148 660 + 0;
  • 4 148 660 ÷ 2 = 2 074 330 + 0;
  • 2 074 330 ÷ 2 = 1 037 165 + 0;
  • 1 037 165 ÷ 2 = 518 582 + 1;
  • 518 582 ÷ 2 = 259 291 + 0;
  • 259 291 ÷ 2 = 129 645 + 1;
  • 129 645 ÷ 2 = 64 822 + 1;
  • 64 822 ÷ 2 = 32 411 + 0;
  • 32 411 ÷ 2 = 16 205 + 1;
  • 16 205 ÷ 2 = 8 102 + 1;
  • 8 102 ÷ 2 = 4 051 + 0;
  • 4 051 ÷ 2 = 2 025 + 1;
  • 2 025 ÷ 2 = 1 012 + 1;
  • 1 012 ÷ 2 = 506 + 0;
  • 506 ÷ 2 = 253 + 0;
  • 253 ÷ 2 = 126 + 1;
  • 126 ÷ 2 = 63 + 0;
  • 63 ÷ 2 = 31 + 1;
  • 31 ÷ 2 = 15 + 1;
  • 15 ÷ 2 = 7 + 1;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

2. Construct the base 2 representation of the positive number:

Take all the remainders starting from the bottom of the list constructed above.

9 122 999 999 999 999 374(10) = 111 1110 1001 1011 0110 1000 0010 1010 0000 1101 1110 0011 0111 1101 1000 1110(2)


3. Determine the signed binary number bit length:

  • The base 2 number's actual length, in bits: 63.

  • A signed binary's bit length must be equal to a power of 2, as of:
  • 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
  • The first bit (the leftmost) is reserved for the sign:
  • 0 = positive integer number, 1 = negative integer number

The least number that is:


1) a power of 2

2) and is larger than the actual length, 63,

3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)


=== is: 64.


4. Get the positive binary computer representation on 64 bits (8 Bytes):

If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:


9 122 999 999 999 999 374(10) Base 10 integer number converted and written as a signed binary code (in base 2):

9 122 999 999 999 999 374(10) = 0111 1110 1001 1011 0110 1000 0010 1010 0000 1101 1110 0011 0111 1101 1000 1110

Spaces were used to group digits: for binary, by 4, for decimal, by 3.


How to convert signed base 10 integers in decimal to binary code system

Follow the steps below to convert a signed base ten integer number to signed binary:

  • 1. In a signed binary, first bit (the leftmost) is reserved for sign: 0 = positive integer number, 1 = positive integer number. If the number to be converted is negative, start with its positive version.
  • 2. Divide repeatedly by 2 the positive integer number keeping track of each remainder. STOP when we get a quotient that is ZERO.
  • 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Binary numbers represented in computer language have a length of 4, 8, 16, 32, 64, ... bits (power of 2) - if needed, fill in extra '0' bits in front of the base 2 number (to the left), up to the right length; this way the first bit (the leftmost one) is always '0', as for a positive representation.
  • 5. To get the negative reprezentation of the number, simply switch the first bit (the leftmost one), from '0' to '1'.

Example: convert the negative number -63 from decimal system (base ten) to signed binary code system:

  • 1. Start with the positive version of the number: |-63| = 63;
  • 2. Divide repeatedly 63 by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder
    • 63 ÷ 2 = 31 + 1
    • 31 ÷ 2 = 15 + 1
    • 15 ÷ 2 = 7 + 1
    • 7 ÷ 2 = 3 + 1
    • 3 ÷ 2 = 1 + 1
    • 1 ÷ 2 = 0 + 1
  • 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above:
    63(10) = 11 1111(2)
  • 4. The actual length of base 2 representation number is 6, so the positive binary computer representation length of the signed binary will take in this case 8 bits (the least power of 2 higher than 6) - add extra '0's in front (to the left), up to the required length; this way the first bit (the leftmost one) is to be '0', as for a positive number:
    63(10) = 0011 1111(2)
  • 5. To get the negative integer number representation simply change the first bit (the leftmost), from '0' to '1':
    -63(10) = 1011 1111
  • Number -63(10), signed integer, converted from decimal system (base 10) to signed binary = 1011 1111