Convert 83 255 020 456 253 to a Signed Binary (Base 2)

How to convert 83 255 020 456 253(10), a signed base 10 integer number? How to write it as a signed binary code in base 2

What are the required steps to convert base 10 integer
number 83 255 020 456 253 to signed binary code (in base 2)?

  • A signed integer, written in base ten, or a decimal system number, is a number written using the digits 0 through 9 and the sign, which can be positive (+) or negative (-). If positive, the sign is usually not written. A number written in base two, or binary, is a number written using only the digits 0 and 1.

1. Divide the number repeatedly by 2:

Keep track of each remainder.

Stop when you get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 83 255 020 456 253 ÷ 2 = 41 627 510 228 126 + 1;
  • 41 627 510 228 126 ÷ 2 = 20 813 755 114 063 + 0;
  • 20 813 755 114 063 ÷ 2 = 10 406 877 557 031 + 1;
  • 10 406 877 557 031 ÷ 2 = 5 203 438 778 515 + 1;
  • 5 203 438 778 515 ÷ 2 = 2 601 719 389 257 + 1;
  • 2 601 719 389 257 ÷ 2 = 1 300 859 694 628 + 1;
  • 1 300 859 694 628 ÷ 2 = 650 429 847 314 + 0;
  • 650 429 847 314 ÷ 2 = 325 214 923 657 + 0;
  • 325 214 923 657 ÷ 2 = 162 607 461 828 + 1;
  • 162 607 461 828 ÷ 2 = 81 303 730 914 + 0;
  • 81 303 730 914 ÷ 2 = 40 651 865 457 + 0;
  • 40 651 865 457 ÷ 2 = 20 325 932 728 + 1;
  • 20 325 932 728 ÷ 2 = 10 162 966 364 + 0;
  • 10 162 966 364 ÷ 2 = 5 081 483 182 + 0;
  • 5 081 483 182 ÷ 2 = 2 540 741 591 + 0;
  • 2 540 741 591 ÷ 2 = 1 270 370 795 + 1;
  • 1 270 370 795 ÷ 2 = 635 185 397 + 1;
  • 635 185 397 ÷ 2 = 317 592 698 + 1;
  • 317 592 698 ÷ 2 = 158 796 349 + 0;
  • 158 796 349 ÷ 2 = 79 398 174 + 1;
  • 79 398 174 ÷ 2 = 39 699 087 + 0;
  • 39 699 087 ÷ 2 = 19 849 543 + 1;
  • 19 849 543 ÷ 2 = 9 924 771 + 1;
  • 9 924 771 ÷ 2 = 4 962 385 + 1;
  • 4 962 385 ÷ 2 = 2 481 192 + 1;
  • 2 481 192 ÷ 2 = 1 240 596 + 0;
  • 1 240 596 ÷ 2 = 620 298 + 0;
  • 620 298 ÷ 2 = 310 149 + 0;
  • 310 149 ÷ 2 = 155 074 + 1;
  • 155 074 ÷ 2 = 77 537 + 0;
  • 77 537 ÷ 2 = 38 768 + 1;
  • 38 768 ÷ 2 = 19 384 + 0;
  • 19 384 ÷ 2 = 9 692 + 0;
  • 9 692 ÷ 2 = 4 846 + 0;
  • 4 846 ÷ 2 = 2 423 + 0;
  • 2 423 ÷ 2 = 1 211 + 1;
  • 1 211 ÷ 2 = 605 + 1;
  • 605 ÷ 2 = 302 + 1;
  • 302 ÷ 2 = 151 + 0;
  • 151 ÷ 2 = 75 + 1;
  • 75 ÷ 2 = 37 + 1;
  • 37 ÷ 2 = 18 + 1;
  • 18 ÷ 2 = 9 + 0;
  • 9 ÷ 2 = 4 + 1;
  • 4 ÷ 2 = 2 + 0;
  • 2 ÷ 2 = 1 + 0;
  • 1 ÷ 2 = 0 + 1;

2. Construct the base 2 representation of the positive number:

Take all the remainders starting from the bottom of the list constructed above.

83 255 020 456 253(10) = 100 1011 1011 1000 0101 0001 1110 1011 1000 1001 0011 1101(2)


3. Determine the signed binary number bit length:

  • The base 2 number's actual length, in bits: 47.

  • A signed binary's bit length must be equal to a power of 2, as of:
  • 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
  • The first bit (the leftmost) is reserved for the sign:
  • 0 = positive integer number, 1 = negative integer number

The least number that is:


1) a power of 2

2) and is larger than the actual length, 47,

3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)


=== is: 64.


4. Get the positive binary computer representation on 64 bits (8 Bytes):

If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:


83 255 020 456 253(10) Base 10 integer number converted and written as a signed binary code (in base 2):

83 255 020 456 253(10) = 0000 0000 0000 0000 0100 1011 1011 1000 0101 0001 1110 1011 1000 1001 0011 1101

Spaces were used to group digits: for binary, by 4, for decimal, by 3.

How to convert signed base 10 integers in decimal to binary code system

Follow the steps below to convert a signed base ten integer number to signed binary:

  • 1. In a signed binary, first bit (the leftmost) is reserved for sign: 0 = positive integer number, 1 = positive integer number. If the number to be converted is negative, start with its positive version.
  • 2. Divide repeatedly by 2 the positive integer number keeping track of each remainder. STOP when we get a quotient that is ZERO.
  • 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Binary numbers represented in computer language have a length of 4, 8, 16, 32, 64, ... bits (power of 2) - if needed, fill in extra '0' bits in front of the base 2 number (to the left), up to the right length; this way the first bit (the leftmost one) is always '0', as for a positive representation.
  • 5. To get the negative reprezentation of the number, simply switch the first bit (the leftmost one), from '0' to '1'.

Example: convert the negative number -63 from decimal system (base ten) to signed binary code system:

  • 1. Start with the positive version of the number: |-63| = 63;
  • 2. Divide repeatedly 63 by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder
    • 63 ÷ 2 = 31 + 1
    • 31 ÷ 2 = 15 + 1
    • 15 ÷ 2 = 7 + 1
    • 7 ÷ 2 = 3 + 1
    • 3 ÷ 2 = 1 + 1
    • 1 ÷ 2 = 0 + 1
  • 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above:
    63(10) = 11 1111(2)
  • 4. The actual length of base 2 representation number is 6, so the positive binary computer representation length of the signed binary will take in this case 8 bits (the least power of 2 higher than 6) - add extra '0's in front (to the left), up to the required length; this way the first bit (the leftmost one) is to be '0', as for a positive number:
    63(10) = 0011 1111(2)
  • 5. To get the negative integer number representation simply change the first bit (the leftmost), from '0' to '1':
    -63(10) = 1011 1111
  • Number -63(10), signed integer, converted from decimal system (base 10) to signed binary = 1011 1111