Convert 4 611 686 018 427 557 to a Signed Binary (Base 2)

How to convert 4 611 686 018 427 557(10), a signed base 10 integer number? How to write it as a signed binary code in base 2

What are the required steps to convert base 10 integer
number 4 611 686 018 427 557 to signed binary code (in base 2)?

  • A signed integer, written in base ten, or a decimal system number, is a number written using the digits 0 through 9 and the sign, which can be positive (+) or negative (-). If positive, the sign is usually not written. A number written in base two, or binary, is a number written using only the digits 0 and 1.

1. Divide the number repeatedly by 2:

Keep track of each remainder.

Stop when you get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 4 611 686 018 427 557 ÷ 2 = 2 305 843 009 213 778 + 1;
  • 2 305 843 009 213 778 ÷ 2 = 1 152 921 504 606 889 + 0;
  • 1 152 921 504 606 889 ÷ 2 = 576 460 752 303 444 + 1;
  • 576 460 752 303 444 ÷ 2 = 288 230 376 151 722 + 0;
  • 288 230 376 151 722 ÷ 2 = 144 115 188 075 861 + 0;
  • 144 115 188 075 861 ÷ 2 = 72 057 594 037 930 + 1;
  • 72 057 594 037 930 ÷ 2 = 36 028 797 018 965 + 0;
  • 36 028 797 018 965 ÷ 2 = 18 014 398 509 482 + 1;
  • 18 014 398 509 482 ÷ 2 = 9 007 199 254 741 + 0;
  • 9 007 199 254 741 ÷ 2 = 4 503 599 627 370 + 1;
  • 4 503 599 627 370 ÷ 2 = 2 251 799 813 685 + 0;
  • 2 251 799 813 685 ÷ 2 = 1 125 899 906 842 + 1;
  • 1 125 899 906 842 ÷ 2 = 562 949 953 421 + 0;
  • 562 949 953 421 ÷ 2 = 281 474 976 710 + 1;
  • 281 474 976 710 ÷ 2 = 140 737 488 355 + 0;
  • 140 737 488 355 ÷ 2 = 70 368 744 177 + 1;
  • 70 368 744 177 ÷ 2 = 35 184 372 088 + 1;
  • 35 184 372 088 ÷ 2 = 17 592 186 044 + 0;
  • 17 592 186 044 ÷ 2 = 8 796 093 022 + 0;
  • 8 796 093 022 ÷ 2 = 4 398 046 511 + 0;
  • 4 398 046 511 ÷ 2 = 2 199 023 255 + 1;
  • 2 199 023 255 ÷ 2 = 1 099 511 627 + 1;
  • 1 099 511 627 ÷ 2 = 549 755 813 + 1;
  • 549 755 813 ÷ 2 = 274 877 906 + 1;
  • 274 877 906 ÷ 2 = 137 438 953 + 0;
  • 137 438 953 ÷ 2 = 68 719 476 + 1;
  • 68 719 476 ÷ 2 = 34 359 738 + 0;
  • 34 359 738 ÷ 2 = 17 179 869 + 0;
  • 17 179 869 ÷ 2 = 8 589 934 + 1;
  • 8 589 934 ÷ 2 = 4 294 967 + 0;
  • 4 294 967 ÷ 2 = 2 147 483 + 1;
  • 2 147 483 ÷ 2 = 1 073 741 + 1;
  • 1 073 741 ÷ 2 = 536 870 + 1;
  • 536 870 ÷ 2 = 268 435 + 0;
  • 268 435 ÷ 2 = 134 217 + 1;
  • 134 217 ÷ 2 = 67 108 + 1;
  • 67 108 ÷ 2 = 33 554 + 0;
  • 33 554 ÷ 2 = 16 777 + 0;
  • 16 777 ÷ 2 = 8 388 + 1;
  • 8 388 ÷ 2 = 4 194 + 0;
  • 4 194 ÷ 2 = 2 097 + 0;
  • 2 097 ÷ 2 = 1 048 + 1;
  • 1 048 ÷ 2 = 524 + 0;
  • 524 ÷ 2 = 262 + 0;
  • 262 ÷ 2 = 131 + 0;
  • 131 ÷ 2 = 65 + 1;
  • 65 ÷ 2 = 32 + 1;
  • 32 ÷ 2 = 16 + 0;
  • 16 ÷ 2 = 8 + 0;
  • 8 ÷ 2 = 4 + 0;
  • 4 ÷ 2 = 2 + 0;
  • 2 ÷ 2 = 1 + 0;
  • 1 ÷ 2 = 0 + 1;

2. Construct the base 2 representation of the positive number:

Take all the remainders starting from the bottom of the list constructed above.

4 611 686 018 427 557(10) = 1 0000 0110 0010 0100 1101 1101 0010 1111 0001 1010 1010 1010 0101(2)


3. Determine the signed binary number bit length:

  • The base 2 number's actual length, in bits: 53.

  • A signed binary's bit length must be equal to a power of 2, as of:
  • 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
  • The first bit (the leftmost) is reserved for the sign:
  • 0 = positive integer number, 1 = negative integer number

The least number that is:


1) a power of 2

2) and is larger than the actual length, 53,

3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)


=== is: 64.


4. Get the positive binary computer representation on 64 bits (8 Bytes):

If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:


4 611 686 018 427 557(10) Base 10 integer number converted and written as a signed binary code (in base 2):

4 611 686 018 427 557(10) = 0000 0000 0001 0000 0110 0010 0100 1101 1101 0010 1111 0001 1010 1010 1010 0101

Spaces were used to group digits: for binary, by 4, for decimal, by 3.


How to convert signed base 10 integers in decimal to binary code system

Follow the steps below to convert a signed base ten integer number to signed binary:

  • 1. In a signed binary, first bit (the leftmost) is reserved for sign: 0 = positive integer number, 1 = positive integer number. If the number to be converted is negative, start with its positive version.
  • 2. Divide repeatedly by 2 the positive integer number keeping track of each remainder. STOP when we get a quotient that is ZERO.
  • 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Binary numbers represented in computer language have a length of 4, 8, 16, 32, 64, ... bits (power of 2) - if needed, fill in extra '0' bits in front of the base 2 number (to the left), up to the right length; this way the first bit (the leftmost one) is always '0', as for a positive representation.
  • 5. To get the negative reprezentation of the number, simply switch the first bit (the leftmost one), from '0' to '1'.

Example: convert the negative number -63 from decimal system (base ten) to signed binary code system:

  • 1. Start with the positive version of the number: |-63| = 63;
  • 2. Divide repeatedly 63 by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder
    • 63 ÷ 2 = 31 + 1
    • 31 ÷ 2 = 15 + 1
    • 15 ÷ 2 = 7 + 1
    • 7 ÷ 2 = 3 + 1
    • 3 ÷ 2 = 1 + 1
    • 1 ÷ 2 = 0 + 1
  • 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above:
    63(10) = 11 1111(2)
  • 4. The actual length of base 2 representation number is 6, so the positive binary computer representation length of the signed binary will take in this case 8 bits (the least power of 2 higher than 6) - add extra '0's in front (to the left), up to the required length; this way the first bit (the leftmost one) is to be '0', as for a positive number:
    63(10) = 0011 1111(2)
  • 5. To get the negative integer number representation simply change the first bit (the leftmost), from '0' to '1':
    -63(10) = 1011 1111
  • Number -63(10), signed integer, converted from decimal system (base 10) to signed binary = 1011 1111