What are the required steps to convert base 10 integer
number 439 397 866 167 861 110 to signed binary code (in base 2)?
- A signed integer, written in base ten, or a decimal system number, is a number written using the digits 0 through 9 and the sign, which can be positive (+) or negative (-). If positive, the sign is usually not written. A number written in base two, or binary, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 439 397 866 167 861 110 ÷ 2 = 219 698 933 083 930 555 + 0;
- 219 698 933 083 930 555 ÷ 2 = 109 849 466 541 965 277 + 1;
- 109 849 466 541 965 277 ÷ 2 = 54 924 733 270 982 638 + 1;
- 54 924 733 270 982 638 ÷ 2 = 27 462 366 635 491 319 + 0;
- 27 462 366 635 491 319 ÷ 2 = 13 731 183 317 745 659 + 1;
- 13 731 183 317 745 659 ÷ 2 = 6 865 591 658 872 829 + 1;
- 6 865 591 658 872 829 ÷ 2 = 3 432 795 829 436 414 + 1;
- 3 432 795 829 436 414 ÷ 2 = 1 716 397 914 718 207 + 0;
- 1 716 397 914 718 207 ÷ 2 = 858 198 957 359 103 + 1;
- 858 198 957 359 103 ÷ 2 = 429 099 478 679 551 + 1;
- 429 099 478 679 551 ÷ 2 = 214 549 739 339 775 + 1;
- 214 549 739 339 775 ÷ 2 = 107 274 869 669 887 + 1;
- 107 274 869 669 887 ÷ 2 = 53 637 434 834 943 + 1;
- 53 637 434 834 943 ÷ 2 = 26 818 717 417 471 + 1;
- 26 818 717 417 471 ÷ 2 = 13 409 358 708 735 + 1;
- 13 409 358 708 735 ÷ 2 = 6 704 679 354 367 + 1;
- 6 704 679 354 367 ÷ 2 = 3 352 339 677 183 + 1;
- 3 352 339 677 183 ÷ 2 = 1 676 169 838 591 + 1;
- 1 676 169 838 591 ÷ 2 = 838 084 919 295 + 1;
- 838 084 919 295 ÷ 2 = 419 042 459 647 + 1;
- 419 042 459 647 ÷ 2 = 209 521 229 823 + 1;
- 209 521 229 823 ÷ 2 = 104 760 614 911 + 1;
- 104 760 614 911 ÷ 2 = 52 380 307 455 + 1;
- 52 380 307 455 ÷ 2 = 26 190 153 727 + 1;
- 26 190 153 727 ÷ 2 = 13 095 076 863 + 1;
- 13 095 076 863 ÷ 2 = 6 547 538 431 + 1;
- 6 547 538 431 ÷ 2 = 3 273 769 215 + 1;
- 3 273 769 215 ÷ 2 = 1 636 884 607 + 1;
- 1 636 884 607 ÷ 2 = 818 442 303 + 1;
- 818 442 303 ÷ 2 = 409 221 151 + 1;
- 409 221 151 ÷ 2 = 204 610 575 + 1;
- 204 610 575 ÷ 2 = 102 305 287 + 1;
- 102 305 287 ÷ 2 = 51 152 643 + 1;
- 51 152 643 ÷ 2 = 25 576 321 + 1;
- 25 576 321 ÷ 2 = 12 788 160 + 1;
- 12 788 160 ÷ 2 = 6 394 080 + 0;
- 6 394 080 ÷ 2 = 3 197 040 + 0;
- 3 197 040 ÷ 2 = 1 598 520 + 0;
- 1 598 520 ÷ 2 = 799 260 + 0;
- 799 260 ÷ 2 = 399 630 + 0;
- 399 630 ÷ 2 = 199 815 + 0;
- 199 815 ÷ 2 = 99 907 + 1;
- 99 907 ÷ 2 = 49 953 + 1;
- 49 953 ÷ 2 = 24 976 + 1;
- 24 976 ÷ 2 = 12 488 + 0;
- 12 488 ÷ 2 = 6 244 + 0;
- 6 244 ÷ 2 = 3 122 + 0;
- 3 122 ÷ 2 = 1 561 + 0;
- 1 561 ÷ 2 = 780 + 1;
- 780 ÷ 2 = 390 + 0;
- 390 ÷ 2 = 195 + 0;
- 195 ÷ 2 = 97 + 1;
- 97 ÷ 2 = 48 + 1;
- 48 ÷ 2 = 24 + 0;
- 24 ÷ 2 = 12 + 0;
- 12 ÷ 2 = 6 + 0;
- 6 ÷ 2 = 3 + 0;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
439 397 866 167 861 110(10) = 110 0001 1001 0000 1110 0000 0111 1111 1111 1111 1111 1111 1111 0111 0110(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 59.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) is reserved for the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 59,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:
439 397 866 167 861 110(10) Base 10 integer number converted and written as a signed binary code (in base 2):
439 397 866 167 861 110(10) = 0000 0110 0001 1001 0000 1110 0000 0111 1111 1111 1111 1111 1111 1111 0111 0110
Spaces were used to group digits: for binary, by 4, for decimal, by 3.