Convert 180 420 031 709 542 833 to a Signed Binary (Base 2)

How to convert 180 420 031 709 542 833(10), a signed base 10 integer number? How to write it as a signed binary code in base 2

What are the required steps to convert base 10 integer
number 180 420 031 709 542 833 to signed binary code (in base 2)?

  • A signed integer, written in base ten, or a decimal system number, is a number written using the digits 0 through 9 and the sign, which can be positive (+) or negative (-). If positive, the sign is usually not written. A number written in base two, or binary, is a number written using only the digits 0 and 1.

1. Divide the number repeatedly by 2:

Keep track of each remainder.

Stop when you get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 180 420 031 709 542 833 ÷ 2 = 90 210 015 854 771 416 + 1;
  • 90 210 015 854 771 416 ÷ 2 = 45 105 007 927 385 708 + 0;
  • 45 105 007 927 385 708 ÷ 2 = 22 552 503 963 692 854 + 0;
  • 22 552 503 963 692 854 ÷ 2 = 11 276 251 981 846 427 + 0;
  • 11 276 251 981 846 427 ÷ 2 = 5 638 125 990 923 213 + 1;
  • 5 638 125 990 923 213 ÷ 2 = 2 819 062 995 461 606 + 1;
  • 2 819 062 995 461 606 ÷ 2 = 1 409 531 497 730 803 + 0;
  • 1 409 531 497 730 803 ÷ 2 = 704 765 748 865 401 + 1;
  • 704 765 748 865 401 ÷ 2 = 352 382 874 432 700 + 1;
  • 352 382 874 432 700 ÷ 2 = 176 191 437 216 350 + 0;
  • 176 191 437 216 350 ÷ 2 = 88 095 718 608 175 + 0;
  • 88 095 718 608 175 ÷ 2 = 44 047 859 304 087 + 1;
  • 44 047 859 304 087 ÷ 2 = 22 023 929 652 043 + 1;
  • 22 023 929 652 043 ÷ 2 = 11 011 964 826 021 + 1;
  • 11 011 964 826 021 ÷ 2 = 5 505 982 413 010 + 1;
  • 5 505 982 413 010 ÷ 2 = 2 752 991 206 505 + 0;
  • 2 752 991 206 505 ÷ 2 = 1 376 495 603 252 + 1;
  • 1 376 495 603 252 ÷ 2 = 688 247 801 626 + 0;
  • 688 247 801 626 ÷ 2 = 344 123 900 813 + 0;
  • 344 123 900 813 ÷ 2 = 172 061 950 406 + 1;
  • 172 061 950 406 ÷ 2 = 86 030 975 203 + 0;
  • 86 030 975 203 ÷ 2 = 43 015 487 601 + 1;
  • 43 015 487 601 ÷ 2 = 21 507 743 800 + 1;
  • 21 507 743 800 ÷ 2 = 10 753 871 900 + 0;
  • 10 753 871 900 ÷ 2 = 5 376 935 950 + 0;
  • 5 376 935 950 ÷ 2 = 2 688 467 975 + 0;
  • 2 688 467 975 ÷ 2 = 1 344 233 987 + 1;
  • 1 344 233 987 ÷ 2 = 672 116 993 + 1;
  • 672 116 993 ÷ 2 = 336 058 496 + 1;
  • 336 058 496 ÷ 2 = 168 029 248 + 0;
  • 168 029 248 ÷ 2 = 84 014 624 + 0;
  • 84 014 624 ÷ 2 = 42 007 312 + 0;
  • 42 007 312 ÷ 2 = 21 003 656 + 0;
  • 21 003 656 ÷ 2 = 10 501 828 + 0;
  • 10 501 828 ÷ 2 = 5 250 914 + 0;
  • 5 250 914 ÷ 2 = 2 625 457 + 0;
  • 2 625 457 ÷ 2 = 1 312 728 + 1;
  • 1 312 728 ÷ 2 = 656 364 + 0;
  • 656 364 ÷ 2 = 328 182 + 0;
  • 328 182 ÷ 2 = 164 091 + 0;
  • 164 091 ÷ 2 = 82 045 + 1;
  • 82 045 ÷ 2 = 41 022 + 1;
  • 41 022 ÷ 2 = 20 511 + 0;
  • 20 511 ÷ 2 = 10 255 + 1;
  • 10 255 ÷ 2 = 5 127 + 1;
  • 5 127 ÷ 2 = 2 563 + 1;
  • 2 563 ÷ 2 = 1 281 + 1;
  • 1 281 ÷ 2 = 640 + 1;
  • 640 ÷ 2 = 320 + 0;
  • 320 ÷ 2 = 160 + 0;
  • 160 ÷ 2 = 80 + 0;
  • 80 ÷ 2 = 40 + 0;
  • 40 ÷ 2 = 20 + 0;
  • 20 ÷ 2 = 10 + 0;
  • 10 ÷ 2 = 5 + 0;
  • 5 ÷ 2 = 2 + 1;
  • 2 ÷ 2 = 1 + 0;
  • 1 ÷ 2 = 0 + 1;

2. Construct the base 2 representation of the positive number:

Take all the remainders starting from the bottom of the list constructed above.

180 420 031 709 542 833(10) = 10 1000 0000 1111 1011 0001 0000 0001 1100 0110 1001 0111 1001 1011 0001(2)


3. Determine the signed binary number bit length:

  • The base 2 number's actual length, in bits: 58.

  • A signed binary's bit length must be equal to a power of 2, as of:
  • 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
  • The first bit (the leftmost) is reserved for the sign:
  • 0 = positive integer number, 1 = negative integer number

The least number that is:


1) a power of 2

2) and is larger than the actual length, 58,

3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)


=== is: 64.


4. Get the positive binary computer representation on 64 bits (8 Bytes):

If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:


180 420 031 709 542 833(10) Base 10 integer number converted and written as a signed binary code (in base 2):

180 420 031 709 542 833(10) = 0000 0010 1000 0000 1111 1011 0001 0000 0001 1100 0110 1001 0111 1001 1011 0001

Spaces were used to group digits: for binary, by 4, for decimal, by 3.


How to convert signed base 10 integers in decimal to binary code system

Follow the steps below to convert a signed base ten integer number to signed binary:

  • 1. In a signed binary, first bit (the leftmost) is reserved for sign: 0 = positive integer number, 1 = positive integer number. If the number to be converted is negative, start with its positive version.
  • 2. Divide repeatedly by 2 the positive integer number keeping track of each remainder. STOP when we get a quotient that is ZERO.
  • 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Binary numbers represented in computer language have a length of 4, 8, 16, 32, 64, ... bits (power of 2) - if needed, fill in extra '0' bits in front of the base 2 number (to the left), up to the right length; this way the first bit (the leftmost one) is always '0', as for a positive representation.
  • 5. To get the negative reprezentation of the number, simply switch the first bit (the leftmost one), from '0' to '1'.

Example: convert the negative number -63 from decimal system (base ten) to signed binary code system:

  • 1. Start with the positive version of the number: |-63| = 63;
  • 2. Divide repeatedly 63 by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder
    • 63 ÷ 2 = 31 + 1
    • 31 ÷ 2 = 15 + 1
    • 15 ÷ 2 = 7 + 1
    • 7 ÷ 2 = 3 + 1
    • 3 ÷ 2 = 1 + 1
    • 1 ÷ 2 = 0 + 1
  • 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above:
    63(10) = 11 1111(2)
  • 4. The actual length of base 2 representation number is 6, so the positive binary computer representation length of the signed binary will take in this case 8 bits (the least power of 2 higher than 6) - add extra '0's in front (to the left), up to the required length; this way the first bit (the leftmost one) is to be '0', as for a positive number:
    63(10) = 0011 1111(2)
  • 5. To get the negative integer number representation simply change the first bit (the leftmost), from '0' to '1':
    -63(10) = 1011 1111
  • Number -63(10), signed integer, converted from decimal system (base 10) to signed binary = 1011 1111