Signed: Integer ↗ Binary: 123 456 789 012 286 Convert the Integer Number to a Signed Binary. Converting and Writing the Base Ten Decimal System Signed Integer as Binary Code (Written in Base Two)

Signed integer number 123 456 789 012 286(10)
converted and written as a signed binary (base 2) = ?

1. Divide the number repeatedly by 2:

Keep track of each remainder.

We stop when we get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 123 456 789 012 286 ÷ 2 = 61 728 394 506 143 + 0;
  • 61 728 394 506 143 ÷ 2 = 30 864 197 253 071 + 1;
  • 30 864 197 253 071 ÷ 2 = 15 432 098 626 535 + 1;
  • 15 432 098 626 535 ÷ 2 = 7 716 049 313 267 + 1;
  • 7 716 049 313 267 ÷ 2 = 3 858 024 656 633 + 1;
  • 3 858 024 656 633 ÷ 2 = 1 929 012 328 316 + 1;
  • 1 929 012 328 316 ÷ 2 = 964 506 164 158 + 0;
  • 964 506 164 158 ÷ 2 = 482 253 082 079 + 0;
  • 482 253 082 079 ÷ 2 = 241 126 541 039 + 1;
  • 241 126 541 039 ÷ 2 = 120 563 270 519 + 1;
  • 120 563 270 519 ÷ 2 = 60 281 635 259 + 1;
  • 60 281 635 259 ÷ 2 = 30 140 817 629 + 1;
  • 30 140 817 629 ÷ 2 = 15 070 408 814 + 1;
  • 15 070 408 814 ÷ 2 = 7 535 204 407 + 0;
  • 7 535 204 407 ÷ 2 = 3 767 602 203 + 1;
  • 3 767 602 203 ÷ 2 = 1 883 801 101 + 1;
  • 1 883 801 101 ÷ 2 = 941 900 550 + 1;
  • 941 900 550 ÷ 2 = 470 950 275 + 0;
  • 470 950 275 ÷ 2 = 235 475 137 + 1;
  • 235 475 137 ÷ 2 = 117 737 568 + 1;
  • 117 737 568 ÷ 2 = 58 868 784 + 0;
  • 58 868 784 ÷ 2 = 29 434 392 + 0;
  • 29 434 392 ÷ 2 = 14 717 196 + 0;
  • 14 717 196 ÷ 2 = 7 358 598 + 0;
  • 7 358 598 ÷ 2 = 3 679 299 + 0;
  • 3 679 299 ÷ 2 = 1 839 649 + 1;
  • 1 839 649 ÷ 2 = 919 824 + 1;
  • 919 824 ÷ 2 = 459 912 + 0;
  • 459 912 ÷ 2 = 229 956 + 0;
  • 229 956 ÷ 2 = 114 978 + 0;
  • 114 978 ÷ 2 = 57 489 + 0;
  • 57 489 ÷ 2 = 28 744 + 1;
  • 28 744 ÷ 2 = 14 372 + 0;
  • 14 372 ÷ 2 = 7 186 + 0;
  • 7 186 ÷ 2 = 3 593 + 0;
  • 3 593 ÷ 2 = 1 796 + 1;
  • 1 796 ÷ 2 = 898 + 0;
  • 898 ÷ 2 = 449 + 0;
  • 449 ÷ 2 = 224 + 1;
  • 224 ÷ 2 = 112 + 0;
  • 112 ÷ 2 = 56 + 0;
  • 56 ÷ 2 = 28 + 0;
  • 28 ÷ 2 = 14 + 0;
  • 14 ÷ 2 = 7 + 0;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

2. Construct the base 2 representation of the positive number:

Take all the remainders starting from the bottom of the list constructed above.


123 456 789 012 286(10) = 111 0000 0100 1000 1000 0110 0000 1101 1101 1111 0011 1110(2)


3. Determine the signed binary number bit length:

The base 2 number's actual length, in bits: 47.


A signed binary's bit length must be equal to a power of 2, as of:

21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...


The first bit (the leftmost) is reserved for the sign:

0 = positive integer number, 1 = negative integer number


The least number that is:


1) a power of 2

2) and is larger than the actual length, 47,

3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)


=== is: 64.


4. Get the positive binary computer representation on 64 bits (8 Bytes):

If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:


Number 123 456 789 012 286(10), a signed integer number (with sign),
converted from decimal system (from base 10)
and written as a signed binary (in base 2):

123 456 789 012 286(10) = 0000 0000 0000 0000 0111 0000 0100 1000 1000 0110 0000 1101 1101 1111 0011 1110

Spaces were used to group digits: for binary, by 4, for decimal, by 3.

The latest signed integer numbers (that are written in decimal system, in base ten) converted and written as signed binary numbers

How to convert signed integers from decimal system to binary code system

Follow the steps below to convert a signed base ten integer number to signed binary:

  • 1. In a signed binary, first bit (the leftmost) is reserved for sign: 0 = positive integer number, 1 = positive integer number. If the number to be converted is negative, start with its positive version.
  • 2. Divide repeatedly by 2 the positive integer number keeping track of each remainder. STOP when we get a quotient that is ZERO.
  • 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Binary numbers represented in computer language have a length of 4, 8, 16, 32, 64, ... bits (power of 2) - if needed, fill in extra '0' bits in front of the base 2 number (to the left), up to the right length; this way the first bit (the leftmost one) is always '0', as for a positive representation.
  • 5. To get the negative reprezentation of the number, simply switch the first bit (the leftmost one), from '0' to '1'.

Example: convert the negative number -63 from decimal system (base ten) to signed binary code system:

  • 1. Start with the positive version of the number: |-63| = 63;
  • 2. Divide repeatedly 63 by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder
    • 63 ÷ 2 = 31 + 1
    • 31 ÷ 2 = 15 + 1
    • 15 ÷ 2 = 7 + 1
    • 7 ÷ 2 = 3 + 1
    • 3 ÷ 2 = 1 + 1
    • 1 ÷ 2 = 0 + 1
  • 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above:
    63(10) = 11 1111(2)
  • 4. The actual length of base 2 representation number is 6, so the positive binary computer representation length of the signed binary will take in this case 8 bits (the least power of 2 higher than 6) - add extra '0's in front (to the left), up to the required length; this way the first bit (the leftmost one) is to be '0', as for a positive number:
    63(10) = 0011 1111(2)
  • 5. To get the negative integer number representation simply change the first bit (the leftmost), from '0' to '1':
    -63(10) = 1011 1111
  • Number -63(10), signed integer, converted from decimal system (base 10) to signed binary = 1011 1111