1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 101 100 011 109 995 ÷ 2 = 550 550 005 554 997 + 1;
- 550 550 005 554 997 ÷ 2 = 275 275 002 777 498 + 1;
- 275 275 002 777 498 ÷ 2 = 137 637 501 388 749 + 0;
- 137 637 501 388 749 ÷ 2 = 68 818 750 694 374 + 1;
- 68 818 750 694 374 ÷ 2 = 34 409 375 347 187 + 0;
- 34 409 375 347 187 ÷ 2 = 17 204 687 673 593 + 1;
- 17 204 687 673 593 ÷ 2 = 8 602 343 836 796 + 1;
- 8 602 343 836 796 ÷ 2 = 4 301 171 918 398 + 0;
- 4 301 171 918 398 ÷ 2 = 2 150 585 959 199 + 0;
- 2 150 585 959 199 ÷ 2 = 1 075 292 979 599 + 1;
- 1 075 292 979 599 ÷ 2 = 537 646 489 799 + 1;
- 537 646 489 799 ÷ 2 = 268 823 244 899 + 1;
- 268 823 244 899 ÷ 2 = 134 411 622 449 + 1;
- 134 411 622 449 ÷ 2 = 67 205 811 224 + 1;
- 67 205 811 224 ÷ 2 = 33 602 905 612 + 0;
- 33 602 905 612 ÷ 2 = 16 801 452 806 + 0;
- 16 801 452 806 ÷ 2 = 8 400 726 403 + 0;
- 8 400 726 403 ÷ 2 = 4 200 363 201 + 1;
- 4 200 363 201 ÷ 2 = 2 100 181 600 + 1;
- 2 100 181 600 ÷ 2 = 1 050 090 800 + 0;
- 1 050 090 800 ÷ 2 = 525 045 400 + 0;
- 525 045 400 ÷ 2 = 262 522 700 + 0;
- 262 522 700 ÷ 2 = 131 261 350 + 0;
- 131 261 350 ÷ 2 = 65 630 675 + 0;
- 65 630 675 ÷ 2 = 32 815 337 + 1;
- 32 815 337 ÷ 2 = 16 407 668 + 1;
- 16 407 668 ÷ 2 = 8 203 834 + 0;
- 8 203 834 ÷ 2 = 4 101 917 + 0;
- 4 101 917 ÷ 2 = 2 050 958 + 1;
- 2 050 958 ÷ 2 = 1 025 479 + 0;
- 1 025 479 ÷ 2 = 512 739 + 1;
- 512 739 ÷ 2 = 256 369 + 1;
- 256 369 ÷ 2 = 128 184 + 1;
- 128 184 ÷ 2 = 64 092 + 0;
- 64 092 ÷ 2 = 32 046 + 0;
- 32 046 ÷ 2 = 16 023 + 0;
- 16 023 ÷ 2 = 8 011 + 1;
- 8 011 ÷ 2 = 4 005 + 1;
- 4 005 ÷ 2 = 2 002 + 1;
- 2 002 ÷ 2 = 1 001 + 0;
- 1 001 ÷ 2 = 500 + 1;
- 500 ÷ 2 = 250 + 0;
- 250 ÷ 2 = 125 + 0;
- 125 ÷ 2 = 62 + 1;
- 62 ÷ 2 = 31 + 0;
- 31 ÷ 2 = 15 + 1;
- 15 ÷ 2 = 7 + 1;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 101 100 011 109 995(10) = 11 1110 1001 0111 0001 1101 0011 0000 0110 0011 1110 0110 1011(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 50.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) is reserved for the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 50,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:
Number 1 101 100 011 109 995(10), a signed integer number (with sign),
converted from decimal system (from base 10)
and written as a signed binary (in base 2):
1 101 100 011 109 995(10) = 0000 0000 0000 0011 1110 1001 0111 0001 1101 0011 0000 0110 0011 1110 0110 1011
Spaces were used to group digits: for binary, by 4, for decimal, by 3.