What are the required steps to convert base 10 integer
number 11 000 101 011 101 519 to signed binary code (in base 2)?
- A signed integer, written in base ten, or a decimal system number, is a number written using the digits 0 through 9 and the sign, which can be positive (+) or negative (-). If positive, the sign is usually not written. A number written in base two, or binary, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 11 000 101 011 101 519 ÷ 2 = 5 500 050 505 550 759 + 1;
- 5 500 050 505 550 759 ÷ 2 = 2 750 025 252 775 379 + 1;
- 2 750 025 252 775 379 ÷ 2 = 1 375 012 626 387 689 + 1;
- 1 375 012 626 387 689 ÷ 2 = 687 506 313 193 844 + 1;
- 687 506 313 193 844 ÷ 2 = 343 753 156 596 922 + 0;
- 343 753 156 596 922 ÷ 2 = 171 876 578 298 461 + 0;
- 171 876 578 298 461 ÷ 2 = 85 938 289 149 230 + 1;
- 85 938 289 149 230 ÷ 2 = 42 969 144 574 615 + 0;
- 42 969 144 574 615 ÷ 2 = 21 484 572 287 307 + 1;
- 21 484 572 287 307 ÷ 2 = 10 742 286 143 653 + 1;
- 10 742 286 143 653 ÷ 2 = 5 371 143 071 826 + 1;
- 5 371 143 071 826 ÷ 2 = 2 685 571 535 913 + 0;
- 2 685 571 535 913 ÷ 2 = 1 342 785 767 956 + 1;
- 1 342 785 767 956 ÷ 2 = 671 392 883 978 + 0;
- 671 392 883 978 ÷ 2 = 335 696 441 989 + 0;
- 335 696 441 989 ÷ 2 = 167 848 220 994 + 1;
- 167 848 220 994 ÷ 2 = 83 924 110 497 + 0;
- 83 924 110 497 ÷ 2 = 41 962 055 248 + 1;
- 41 962 055 248 ÷ 2 = 20 981 027 624 + 0;
- 20 981 027 624 ÷ 2 = 10 490 513 812 + 0;
- 10 490 513 812 ÷ 2 = 5 245 256 906 + 0;
- 5 245 256 906 ÷ 2 = 2 622 628 453 + 0;
- 2 622 628 453 ÷ 2 = 1 311 314 226 + 1;
- 1 311 314 226 ÷ 2 = 655 657 113 + 0;
- 655 657 113 ÷ 2 = 327 828 556 + 1;
- 327 828 556 ÷ 2 = 163 914 278 + 0;
- 163 914 278 ÷ 2 = 81 957 139 + 0;
- 81 957 139 ÷ 2 = 40 978 569 + 1;
- 40 978 569 ÷ 2 = 20 489 284 + 1;
- 20 489 284 ÷ 2 = 10 244 642 + 0;
- 10 244 642 ÷ 2 = 5 122 321 + 0;
- 5 122 321 ÷ 2 = 2 561 160 + 1;
- 2 561 160 ÷ 2 = 1 280 580 + 0;
- 1 280 580 ÷ 2 = 640 290 + 0;
- 640 290 ÷ 2 = 320 145 + 0;
- 320 145 ÷ 2 = 160 072 + 1;
- 160 072 ÷ 2 = 80 036 + 0;
- 80 036 ÷ 2 = 40 018 + 0;
- 40 018 ÷ 2 = 20 009 + 0;
- 20 009 ÷ 2 = 10 004 + 1;
- 10 004 ÷ 2 = 5 002 + 0;
- 5 002 ÷ 2 = 2 501 + 0;
- 2 501 ÷ 2 = 1 250 + 1;
- 1 250 ÷ 2 = 625 + 0;
- 625 ÷ 2 = 312 + 1;
- 312 ÷ 2 = 156 + 0;
- 156 ÷ 2 = 78 + 0;
- 78 ÷ 2 = 39 + 0;
- 39 ÷ 2 = 19 + 1;
- 19 ÷ 2 = 9 + 1;
- 9 ÷ 2 = 4 + 1;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
11 000 101 011 101 519(10) = 10 0111 0001 0100 1000 1000 1001 1001 0100 0010 1001 0111 0100 1111(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 54.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) is reserved for the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 54,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:
11 000 101 011 101 519(10) Base 10 integer number converted and written as a signed binary code (in base 2):
11 000 101 011 101 519(10) = 0000 0000 0010 0111 0001 0100 1000 1000 1001 1001 0100 0010 1001 0111 0100 1111
Spaces were used to group digits: for binary, by 4, for decimal, by 3.