What are the required steps to convert base 10 integer
number 11 000 011 100 001 031 to signed binary code (in base 2)?
- A signed integer, written in base ten, or a decimal system number, is a number written using the digits 0 through 9 and the sign, which can be positive (+) or negative (-). If positive, the sign is usually not written. A number written in base two, or binary, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 11 000 011 100 001 031 ÷ 2 = 5 500 005 550 000 515 + 1;
- 5 500 005 550 000 515 ÷ 2 = 2 750 002 775 000 257 + 1;
- 2 750 002 775 000 257 ÷ 2 = 1 375 001 387 500 128 + 1;
- 1 375 001 387 500 128 ÷ 2 = 687 500 693 750 064 + 0;
- 687 500 693 750 064 ÷ 2 = 343 750 346 875 032 + 0;
- 343 750 346 875 032 ÷ 2 = 171 875 173 437 516 + 0;
- 171 875 173 437 516 ÷ 2 = 85 937 586 718 758 + 0;
- 85 937 586 718 758 ÷ 2 = 42 968 793 359 379 + 0;
- 42 968 793 359 379 ÷ 2 = 21 484 396 679 689 + 1;
- 21 484 396 679 689 ÷ 2 = 10 742 198 339 844 + 1;
- 10 742 198 339 844 ÷ 2 = 5 371 099 169 922 + 0;
- 5 371 099 169 922 ÷ 2 = 2 685 549 584 961 + 0;
- 2 685 549 584 961 ÷ 2 = 1 342 774 792 480 + 1;
- 1 342 774 792 480 ÷ 2 = 671 387 396 240 + 0;
- 671 387 396 240 ÷ 2 = 335 693 698 120 + 0;
- 335 693 698 120 ÷ 2 = 167 846 849 060 + 0;
- 167 846 849 060 ÷ 2 = 83 923 424 530 + 0;
- 83 923 424 530 ÷ 2 = 41 961 712 265 + 0;
- 41 961 712 265 ÷ 2 = 20 980 856 132 + 1;
- 20 980 856 132 ÷ 2 = 10 490 428 066 + 0;
- 10 490 428 066 ÷ 2 = 5 245 214 033 + 0;
- 5 245 214 033 ÷ 2 = 2 622 607 016 + 1;
- 2 622 607 016 ÷ 2 = 1 311 303 508 + 0;
- 1 311 303 508 ÷ 2 = 655 651 754 + 0;
- 655 651 754 ÷ 2 = 327 825 877 + 0;
- 327 825 877 ÷ 2 = 163 912 938 + 1;
- 163 912 938 ÷ 2 = 81 956 469 + 0;
- 81 956 469 ÷ 2 = 40 978 234 + 1;
- 40 978 234 ÷ 2 = 20 489 117 + 0;
- 20 489 117 ÷ 2 = 10 244 558 + 1;
- 10 244 558 ÷ 2 = 5 122 279 + 0;
- 5 122 279 ÷ 2 = 2 561 139 + 1;
- 2 561 139 ÷ 2 = 1 280 569 + 1;
- 1 280 569 ÷ 2 = 640 284 + 1;
- 640 284 ÷ 2 = 320 142 + 0;
- 320 142 ÷ 2 = 160 071 + 0;
- 160 071 ÷ 2 = 80 035 + 1;
- 80 035 ÷ 2 = 40 017 + 1;
- 40 017 ÷ 2 = 20 008 + 1;
- 20 008 ÷ 2 = 10 004 + 0;
- 10 004 ÷ 2 = 5 002 + 0;
- 5 002 ÷ 2 = 2 501 + 0;
- 2 501 ÷ 2 = 1 250 + 1;
- 1 250 ÷ 2 = 625 + 0;
- 625 ÷ 2 = 312 + 1;
- 312 ÷ 2 = 156 + 0;
- 156 ÷ 2 = 78 + 0;
- 78 ÷ 2 = 39 + 0;
- 39 ÷ 2 = 19 + 1;
- 19 ÷ 2 = 9 + 1;
- 9 ÷ 2 = 4 + 1;
- 4 ÷ 2 = 2 + 0;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
11 000 011 100 001 031(10) = 10 0111 0001 0100 0111 0011 1010 1010 0010 0100 0001 0011 0000 0111(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 54.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) is reserved for the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 54,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:
11 000 011 100 001 031(10) Base 10 integer number converted and written as a signed binary code (in base 2):
11 000 011 100 001 031(10) = 0000 0000 0010 0111 0001 0100 0111 0011 1010 1010 0010 0100 0001 0011 0000 0111
Spaces were used to group digits: for binary, by 4, for decimal, by 3.