Convert 10 654 388 378 748 to a Signed Binary (Base 2)

How to convert 10 654 388 378 748(10), a signed base 10 integer number? How to write it as a signed binary code in base 2

What are the required steps to convert base 10 integer
number 10 654 388 378 748 to signed binary code (in base 2)?

  • A signed integer, written in base ten, or a decimal system number, is a number written using the digits 0 through 9 and the sign, which can be positive (+) or negative (-). If positive, the sign is usually not written. A number written in base two, or binary, is a number written using only the digits 0 and 1.

1. Divide the number repeatedly by 2:

Keep track of each remainder.

Stop when you get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 10 654 388 378 748 ÷ 2 = 5 327 194 189 374 + 0;
  • 5 327 194 189 374 ÷ 2 = 2 663 597 094 687 + 0;
  • 2 663 597 094 687 ÷ 2 = 1 331 798 547 343 + 1;
  • 1 331 798 547 343 ÷ 2 = 665 899 273 671 + 1;
  • 665 899 273 671 ÷ 2 = 332 949 636 835 + 1;
  • 332 949 636 835 ÷ 2 = 166 474 818 417 + 1;
  • 166 474 818 417 ÷ 2 = 83 237 409 208 + 1;
  • 83 237 409 208 ÷ 2 = 41 618 704 604 + 0;
  • 41 618 704 604 ÷ 2 = 20 809 352 302 + 0;
  • 20 809 352 302 ÷ 2 = 10 404 676 151 + 0;
  • 10 404 676 151 ÷ 2 = 5 202 338 075 + 1;
  • 5 202 338 075 ÷ 2 = 2 601 169 037 + 1;
  • 2 601 169 037 ÷ 2 = 1 300 584 518 + 1;
  • 1 300 584 518 ÷ 2 = 650 292 259 + 0;
  • 650 292 259 ÷ 2 = 325 146 129 + 1;
  • 325 146 129 ÷ 2 = 162 573 064 + 1;
  • 162 573 064 ÷ 2 = 81 286 532 + 0;
  • 81 286 532 ÷ 2 = 40 643 266 + 0;
  • 40 643 266 ÷ 2 = 20 321 633 + 0;
  • 20 321 633 ÷ 2 = 10 160 816 + 1;
  • 10 160 816 ÷ 2 = 5 080 408 + 0;
  • 5 080 408 ÷ 2 = 2 540 204 + 0;
  • 2 540 204 ÷ 2 = 1 270 102 + 0;
  • 1 270 102 ÷ 2 = 635 051 + 0;
  • 635 051 ÷ 2 = 317 525 + 1;
  • 317 525 ÷ 2 = 158 762 + 1;
  • 158 762 ÷ 2 = 79 381 + 0;
  • 79 381 ÷ 2 = 39 690 + 1;
  • 39 690 ÷ 2 = 19 845 + 0;
  • 19 845 ÷ 2 = 9 922 + 1;
  • 9 922 ÷ 2 = 4 961 + 0;
  • 4 961 ÷ 2 = 2 480 + 1;
  • 2 480 ÷ 2 = 1 240 + 0;
  • 1 240 ÷ 2 = 620 + 0;
  • 620 ÷ 2 = 310 + 0;
  • 310 ÷ 2 = 155 + 0;
  • 155 ÷ 2 = 77 + 1;
  • 77 ÷ 2 = 38 + 1;
  • 38 ÷ 2 = 19 + 0;
  • 19 ÷ 2 = 9 + 1;
  • 9 ÷ 2 = 4 + 1;
  • 4 ÷ 2 = 2 + 0;
  • 2 ÷ 2 = 1 + 0;
  • 1 ÷ 2 = 0 + 1;

2. Construct the base 2 representation of the positive number:

Take all the remainders starting from the bottom of the list constructed above.

10 654 388 378 748(10) = 1001 1011 0000 1010 1011 0000 1000 1101 1100 0111 1100(2)


3. Determine the signed binary number bit length:

  • The base 2 number's actual length, in bits: 44.

  • A signed binary's bit length must be equal to a power of 2, as of:
  • 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
  • The first bit (the leftmost) is reserved for the sign:
  • 0 = positive integer number, 1 = negative integer number

The least number that is:


1) a power of 2

2) and is larger than the actual length, 44,

3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)


=== is: 64.


4. Get the positive binary computer representation on 64 bits (8 Bytes):

If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:


10 654 388 378 748(10) Base 10 integer number converted and written as a signed binary code (in base 2):

10 654 388 378 748(10) = 0000 0000 0000 0000 0000 1001 1011 0000 1010 1011 0000 1000 1101 1100 0111 1100

Spaces were used to group digits: for binary, by 4, for decimal, by 3.


How to convert signed base 10 integers in decimal to binary code system

Follow the steps below to convert a signed base ten integer number to signed binary:

  • 1. In a signed binary, first bit (the leftmost) is reserved for sign: 0 = positive integer number, 1 = positive integer number. If the number to be converted is negative, start with its positive version.
  • 2. Divide repeatedly by 2 the positive integer number keeping track of each remainder. STOP when we get a quotient that is ZERO.
  • 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Binary numbers represented in computer language have a length of 4, 8, 16, 32, 64, ... bits (power of 2) - if needed, fill in extra '0' bits in front of the base 2 number (to the left), up to the right length; this way the first bit (the leftmost one) is always '0', as for a positive representation.
  • 5. To get the negative reprezentation of the number, simply switch the first bit (the leftmost one), from '0' to '1'.

Example: convert the negative number -63 from decimal system (base ten) to signed binary code system:

  • 1. Start with the positive version of the number: |-63| = 63;
  • 2. Divide repeatedly 63 by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder
    • 63 ÷ 2 = 31 + 1
    • 31 ÷ 2 = 15 + 1
    • 15 ÷ 2 = 7 + 1
    • 7 ÷ 2 = 3 + 1
    • 3 ÷ 2 = 1 + 1
    • 1 ÷ 2 = 0 + 1
  • 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above:
    63(10) = 11 1111(2)
  • 4. The actual length of base 2 representation number is 6, so the positive binary computer representation length of the signed binary will take in this case 8 bits (the least power of 2 higher than 6) - add extra '0's in front (to the left), up to the required length; this way the first bit (the leftmost one) is to be '0', as for a positive number:
    63(10) = 0011 1111(2)
  • 5. To get the negative integer number representation simply change the first bit (the leftmost), from '0' to '1':
    -63(10) = 1011 1111
  • Number -63(10), signed integer, converted from decimal system (base 10) to signed binary = 1011 1111