What are the required steps to convert base 10 integer
number 1 011 101 010 111 127 to signed binary code (in base 2)?
- A signed integer, written in base ten, or a decimal system number, is a number written using the digits 0 through 9 and the sign, which can be positive (+) or negative (-). If positive, the sign is usually not written. A number written in base two, or binary, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 011 101 010 111 127 ÷ 2 = 505 550 505 055 563 + 1;
- 505 550 505 055 563 ÷ 2 = 252 775 252 527 781 + 1;
- 252 775 252 527 781 ÷ 2 = 126 387 626 263 890 + 1;
- 126 387 626 263 890 ÷ 2 = 63 193 813 131 945 + 0;
- 63 193 813 131 945 ÷ 2 = 31 596 906 565 972 + 1;
- 31 596 906 565 972 ÷ 2 = 15 798 453 282 986 + 0;
- 15 798 453 282 986 ÷ 2 = 7 899 226 641 493 + 0;
- 7 899 226 641 493 ÷ 2 = 3 949 613 320 746 + 1;
- 3 949 613 320 746 ÷ 2 = 1 974 806 660 373 + 0;
- 1 974 806 660 373 ÷ 2 = 987 403 330 186 + 1;
- 987 403 330 186 ÷ 2 = 493 701 665 093 + 0;
- 493 701 665 093 ÷ 2 = 246 850 832 546 + 1;
- 246 850 832 546 ÷ 2 = 123 425 416 273 + 0;
- 123 425 416 273 ÷ 2 = 61 712 708 136 + 1;
- 61 712 708 136 ÷ 2 = 30 856 354 068 + 0;
- 30 856 354 068 ÷ 2 = 15 428 177 034 + 0;
- 15 428 177 034 ÷ 2 = 7 714 088 517 + 0;
- 7 714 088 517 ÷ 2 = 3 857 044 258 + 1;
- 3 857 044 258 ÷ 2 = 1 928 522 129 + 0;
- 1 928 522 129 ÷ 2 = 964 261 064 + 1;
- 964 261 064 ÷ 2 = 482 130 532 + 0;
- 482 130 532 ÷ 2 = 241 065 266 + 0;
- 241 065 266 ÷ 2 = 120 532 633 + 0;
- 120 532 633 ÷ 2 = 60 266 316 + 1;
- 60 266 316 ÷ 2 = 30 133 158 + 0;
- 30 133 158 ÷ 2 = 15 066 579 + 0;
- 15 066 579 ÷ 2 = 7 533 289 + 1;
- 7 533 289 ÷ 2 = 3 766 644 + 1;
- 3 766 644 ÷ 2 = 1 883 322 + 0;
- 1 883 322 ÷ 2 = 941 661 + 0;
- 941 661 ÷ 2 = 470 830 + 1;
- 470 830 ÷ 2 = 235 415 + 0;
- 235 415 ÷ 2 = 117 707 + 1;
- 117 707 ÷ 2 = 58 853 + 1;
- 58 853 ÷ 2 = 29 426 + 1;
- 29 426 ÷ 2 = 14 713 + 0;
- 14 713 ÷ 2 = 7 356 + 1;
- 7 356 ÷ 2 = 3 678 + 0;
- 3 678 ÷ 2 = 1 839 + 0;
- 1 839 ÷ 2 = 919 + 1;
- 919 ÷ 2 = 459 + 1;
- 459 ÷ 2 = 229 + 1;
- 229 ÷ 2 = 114 + 1;
- 114 ÷ 2 = 57 + 0;
- 57 ÷ 2 = 28 + 1;
- 28 ÷ 2 = 14 + 0;
- 14 ÷ 2 = 7 + 0;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 011 101 010 111 127(10) = 11 1001 0111 1001 0111 0100 1100 1000 1010 0010 1010 1001 0111(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 50.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) is reserved for the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 50,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:
1 011 101 010 111 127(10) Base 10 integer number converted and written as a signed binary code (in base 2):
1 011 101 010 111 127(10) = 0000 0000 0000 0011 1001 0111 1001 0111 0100 1100 1000 1010 0010 1010 1001 0111
Spaces were used to group digits: for binary, by 4, for decimal, by 3.