What are the required steps to convert base 10 integer
number 1 011 011 100 110 932 to signed binary code (in base 2)?
- A signed integer, written in base ten, or a decimal system number, is a number written using the digits 0 through 9 and the sign, which can be positive (+) or negative (-). If positive, the sign is usually not written. A number written in base two, or binary, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 011 011 100 110 932 ÷ 2 = 505 505 550 055 466 + 0;
- 505 505 550 055 466 ÷ 2 = 252 752 775 027 733 + 0;
- 252 752 775 027 733 ÷ 2 = 126 376 387 513 866 + 1;
- 126 376 387 513 866 ÷ 2 = 63 188 193 756 933 + 0;
- 63 188 193 756 933 ÷ 2 = 31 594 096 878 466 + 1;
- 31 594 096 878 466 ÷ 2 = 15 797 048 439 233 + 0;
- 15 797 048 439 233 ÷ 2 = 7 898 524 219 616 + 1;
- 7 898 524 219 616 ÷ 2 = 3 949 262 109 808 + 0;
- 3 949 262 109 808 ÷ 2 = 1 974 631 054 904 + 0;
- 1 974 631 054 904 ÷ 2 = 987 315 527 452 + 0;
- 987 315 527 452 ÷ 2 = 493 657 763 726 + 0;
- 493 657 763 726 ÷ 2 = 246 828 881 863 + 0;
- 246 828 881 863 ÷ 2 = 123 414 440 931 + 1;
- 123 414 440 931 ÷ 2 = 61 707 220 465 + 1;
- 61 707 220 465 ÷ 2 = 30 853 610 232 + 1;
- 30 853 610 232 ÷ 2 = 15 426 805 116 + 0;
- 15 426 805 116 ÷ 2 = 7 713 402 558 + 0;
- 7 713 402 558 ÷ 2 = 3 856 701 279 + 0;
- 3 856 701 279 ÷ 2 = 1 928 350 639 + 1;
- 1 928 350 639 ÷ 2 = 964 175 319 + 1;
- 964 175 319 ÷ 2 = 482 087 659 + 1;
- 482 087 659 ÷ 2 = 241 043 829 + 1;
- 241 043 829 ÷ 2 = 120 521 914 + 1;
- 120 521 914 ÷ 2 = 60 260 957 + 0;
- 60 260 957 ÷ 2 = 30 130 478 + 1;
- 30 130 478 ÷ 2 = 15 065 239 + 0;
- 15 065 239 ÷ 2 = 7 532 619 + 1;
- 7 532 619 ÷ 2 = 3 766 309 + 1;
- 3 766 309 ÷ 2 = 1 883 154 + 1;
- 1 883 154 ÷ 2 = 941 577 + 0;
- 941 577 ÷ 2 = 470 788 + 1;
- 470 788 ÷ 2 = 235 394 + 0;
- 235 394 ÷ 2 = 117 697 + 0;
- 117 697 ÷ 2 = 58 848 + 1;
- 58 848 ÷ 2 = 29 424 + 0;
- 29 424 ÷ 2 = 14 712 + 0;
- 14 712 ÷ 2 = 7 356 + 0;
- 7 356 ÷ 2 = 3 678 + 0;
- 3 678 ÷ 2 = 1 839 + 0;
- 1 839 ÷ 2 = 919 + 1;
- 919 ÷ 2 = 459 + 1;
- 459 ÷ 2 = 229 + 1;
- 229 ÷ 2 = 114 + 1;
- 114 ÷ 2 = 57 + 0;
- 57 ÷ 2 = 28 + 1;
- 28 ÷ 2 = 14 + 0;
- 14 ÷ 2 = 7 + 0;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 011 011 100 110 932(10) = 11 1001 0111 1000 0010 0101 1101 0111 1100 0111 0000 0101 0100(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 50.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) is reserved for the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 50,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:
1 011 011 100 110 932(10) Base 10 integer number converted and written as a signed binary code (in base 2):
1 011 011 100 110 932(10) = 0000 0000 0000 0011 1001 0111 1000 0010 0101 1101 0111 1100 0111 0000 0101 0100
Spaces were used to group digits: for binary, by 4, for decimal, by 3.