Convert 10 103 311 756 143 to a Signed Binary (Base 2)

How to convert 10 103 311 756 143(10), a signed base 10 integer number? How to write it as a signed binary code in base 2

What are the required steps to convert base 10 integer
number 10 103 311 756 143 to signed binary code (in base 2)?

  • A signed integer, written in base ten, or a decimal system number, is a number written using the digits 0 through 9 and the sign, which can be positive (+) or negative (-). If positive, the sign is usually not written. A number written in base two, or binary, is a number written using only the digits 0 and 1.

1. Divide the number repeatedly by 2:

Keep track of each remainder.

Stop when you get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 10 103 311 756 143 ÷ 2 = 5 051 655 878 071 + 1;
  • 5 051 655 878 071 ÷ 2 = 2 525 827 939 035 + 1;
  • 2 525 827 939 035 ÷ 2 = 1 262 913 969 517 + 1;
  • 1 262 913 969 517 ÷ 2 = 631 456 984 758 + 1;
  • 631 456 984 758 ÷ 2 = 315 728 492 379 + 0;
  • 315 728 492 379 ÷ 2 = 157 864 246 189 + 1;
  • 157 864 246 189 ÷ 2 = 78 932 123 094 + 1;
  • 78 932 123 094 ÷ 2 = 39 466 061 547 + 0;
  • 39 466 061 547 ÷ 2 = 19 733 030 773 + 1;
  • 19 733 030 773 ÷ 2 = 9 866 515 386 + 1;
  • 9 866 515 386 ÷ 2 = 4 933 257 693 + 0;
  • 4 933 257 693 ÷ 2 = 2 466 628 846 + 1;
  • 2 466 628 846 ÷ 2 = 1 233 314 423 + 0;
  • 1 233 314 423 ÷ 2 = 616 657 211 + 1;
  • 616 657 211 ÷ 2 = 308 328 605 + 1;
  • 308 328 605 ÷ 2 = 154 164 302 + 1;
  • 154 164 302 ÷ 2 = 77 082 151 + 0;
  • 77 082 151 ÷ 2 = 38 541 075 + 1;
  • 38 541 075 ÷ 2 = 19 270 537 + 1;
  • 19 270 537 ÷ 2 = 9 635 268 + 1;
  • 9 635 268 ÷ 2 = 4 817 634 + 0;
  • 4 817 634 ÷ 2 = 2 408 817 + 0;
  • 2 408 817 ÷ 2 = 1 204 408 + 1;
  • 1 204 408 ÷ 2 = 602 204 + 0;
  • 602 204 ÷ 2 = 301 102 + 0;
  • 301 102 ÷ 2 = 150 551 + 0;
  • 150 551 ÷ 2 = 75 275 + 1;
  • 75 275 ÷ 2 = 37 637 + 1;
  • 37 637 ÷ 2 = 18 818 + 1;
  • 18 818 ÷ 2 = 9 409 + 0;
  • 9 409 ÷ 2 = 4 704 + 1;
  • 4 704 ÷ 2 = 2 352 + 0;
  • 2 352 ÷ 2 = 1 176 + 0;
  • 1 176 ÷ 2 = 588 + 0;
  • 588 ÷ 2 = 294 + 0;
  • 294 ÷ 2 = 147 + 0;
  • 147 ÷ 2 = 73 + 1;
  • 73 ÷ 2 = 36 + 1;
  • 36 ÷ 2 = 18 + 0;
  • 18 ÷ 2 = 9 + 0;
  • 9 ÷ 2 = 4 + 1;
  • 4 ÷ 2 = 2 + 0;
  • 2 ÷ 2 = 1 + 0;
  • 1 ÷ 2 = 0 + 1;

2. Construct the base 2 representation of the positive number:

Take all the remainders starting from the bottom of the list constructed above.

10 103 311 756 143(10) = 1001 0011 0000 0101 1100 0100 1110 1110 1011 0110 1111(2)


3. Determine the signed binary number bit length:

  • The base 2 number's actual length, in bits: 44.

  • A signed binary's bit length must be equal to a power of 2, as of:
  • 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
  • The first bit (the leftmost) is reserved for the sign:
  • 0 = positive integer number, 1 = negative integer number

The least number that is:


1) a power of 2

2) and is larger than the actual length, 44,

3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)


=== is: 64.


4. Get the positive binary computer representation on 64 bits (8 Bytes):

If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:


10 103 311 756 143(10) Base 10 integer number converted and written as a signed binary code (in base 2):

10 103 311 756 143(10) = 0000 0000 0000 0000 0000 1001 0011 0000 0101 1100 0100 1110 1110 1011 0110 1111

Spaces were used to group digits: for binary, by 4, for decimal, by 3.

How to convert signed base 10 integers in decimal to binary code system

Follow the steps below to convert a signed base ten integer number to signed binary:

  • 1. In a signed binary, first bit (the leftmost) is reserved for sign: 0 = positive integer number, 1 = positive integer number. If the number to be converted is negative, start with its positive version.
  • 2. Divide repeatedly by 2 the positive integer number keeping track of each remainder. STOP when we get a quotient that is ZERO.
  • 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Binary numbers represented in computer language have a length of 4, 8, 16, 32, 64, ... bits (power of 2) - if needed, fill in extra '0' bits in front of the base 2 number (to the left), up to the right length; this way the first bit (the leftmost one) is always '0', as for a positive representation.
  • 5. To get the negative reprezentation of the number, simply switch the first bit (the leftmost one), from '0' to '1'.

Example: convert the negative number -63 from decimal system (base ten) to signed binary code system:

  • 1. Start with the positive version of the number: |-63| = 63;
  • 2. Divide repeatedly 63 by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder
    • 63 ÷ 2 = 31 + 1
    • 31 ÷ 2 = 15 + 1
    • 15 ÷ 2 = 7 + 1
    • 7 ÷ 2 = 3 + 1
    • 3 ÷ 2 = 1 + 1
    • 1 ÷ 2 = 0 + 1
  • 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above:
    63(10) = 11 1111(2)
  • 4. The actual length of base 2 representation number is 6, so the positive binary computer representation length of the signed binary will take in this case 8 bits (the least power of 2 higher than 6) - add extra '0's in front (to the left), up to the required length; this way the first bit (the leftmost one) is to be '0', as for a positive number:
    63(10) = 0011 1111(2)
  • 5. To get the negative integer number representation simply change the first bit (the leftmost), from '0' to '1':
    -63(10) = 1011 1111
  • Number -63(10), signed integer, converted from decimal system (base 10) to signed binary = 1011 1111