1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 101 000 010 101 187 ÷ 2 = 50 500 005 050 593 + 1;
- 50 500 005 050 593 ÷ 2 = 25 250 002 525 296 + 1;
- 25 250 002 525 296 ÷ 2 = 12 625 001 262 648 + 0;
- 12 625 001 262 648 ÷ 2 = 6 312 500 631 324 + 0;
- 6 312 500 631 324 ÷ 2 = 3 156 250 315 662 + 0;
- 3 156 250 315 662 ÷ 2 = 1 578 125 157 831 + 0;
- 1 578 125 157 831 ÷ 2 = 789 062 578 915 + 1;
- 789 062 578 915 ÷ 2 = 394 531 289 457 + 1;
- 394 531 289 457 ÷ 2 = 197 265 644 728 + 1;
- 197 265 644 728 ÷ 2 = 98 632 822 364 + 0;
- 98 632 822 364 ÷ 2 = 49 316 411 182 + 0;
- 49 316 411 182 ÷ 2 = 24 658 205 591 + 0;
- 24 658 205 591 ÷ 2 = 12 329 102 795 + 1;
- 12 329 102 795 ÷ 2 = 6 164 551 397 + 1;
- 6 164 551 397 ÷ 2 = 3 082 275 698 + 1;
- 3 082 275 698 ÷ 2 = 1 541 137 849 + 0;
- 1 541 137 849 ÷ 2 = 770 568 924 + 1;
- 770 568 924 ÷ 2 = 385 284 462 + 0;
- 385 284 462 ÷ 2 = 192 642 231 + 0;
- 192 642 231 ÷ 2 = 96 321 115 + 1;
- 96 321 115 ÷ 2 = 48 160 557 + 1;
- 48 160 557 ÷ 2 = 24 080 278 + 1;
- 24 080 278 ÷ 2 = 12 040 139 + 0;
- 12 040 139 ÷ 2 = 6 020 069 + 1;
- 6 020 069 ÷ 2 = 3 010 034 + 1;
- 3 010 034 ÷ 2 = 1 505 017 + 0;
- 1 505 017 ÷ 2 = 752 508 + 1;
- 752 508 ÷ 2 = 376 254 + 0;
- 376 254 ÷ 2 = 188 127 + 0;
- 188 127 ÷ 2 = 94 063 + 1;
- 94 063 ÷ 2 = 47 031 + 1;
- 47 031 ÷ 2 = 23 515 + 1;
- 23 515 ÷ 2 = 11 757 + 1;
- 11 757 ÷ 2 = 5 878 + 1;
- 5 878 ÷ 2 = 2 939 + 0;
- 2 939 ÷ 2 = 1 469 + 1;
- 1 469 ÷ 2 = 734 + 1;
- 734 ÷ 2 = 367 + 0;
- 367 ÷ 2 = 183 + 1;
- 183 ÷ 2 = 91 + 1;
- 91 ÷ 2 = 45 + 1;
- 45 ÷ 2 = 22 + 1;
- 22 ÷ 2 = 11 + 0;
- 11 ÷ 2 = 5 + 1;
- 5 ÷ 2 = 2 + 1;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
101 000 010 101 187(10) = 101 1011 1101 1011 1110 0101 1011 1001 0111 0001 1100 0011(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 47.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) is reserved for the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 47,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:
Number 101 000 010 101 187(10), a signed integer number (with sign),
converted from decimal system (from base 10)
and written as a signed binary (in base 2):
101 000 010 101 187(10) = 0000 0000 0000 0000 0101 1011 1101 1011 1110 0101 1011 1001 0111 0001 1100 0011
Spaces were used to group digits: for binary, by 4, for decimal, by 3.