1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 010 000 010 110 085 ÷ 2 = 505 000 005 055 042 + 1;
- 505 000 005 055 042 ÷ 2 = 252 500 002 527 521 + 0;
- 252 500 002 527 521 ÷ 2 = 126 250 001 263 760 + 1;
- 126 250 001 263 760 ÷ 2 = 63 125 000 631 880 + 0;
- 63 125 000 631 880 ÷ 2 = 31 562 500 315 940 + 0;
- 31 562 500 315 940 ÷ 2 = 15 781 250 157 970 + 0;
- 15 781 250 157 970 ÷ 2 = 7 890 625 078 985 + 0;
- 7 890 625 078 985 ÷ 2 = 3 945 312 539 492 + 1;
- 3 945 312 539 492 ÷ 2 = 1 972 656 269 746 + 0;
- 1 972 656 269 746 ÷ 2 = 986 328 134 873 + 0;
- 986 328 134 873 ÷ 2 = 493 164 067 436 + 1;
- 493 164 067 436 ÷ 2 = 246 582 033 718 + 0;
- 246 582 033 718 ÷ 2 = 123 291 016 859 + 0;
- 123 291 016 859 ÷ 2 = 61 645 508 429 + 1;
- 61 645 508 429 ÷ 2 = 30 822 754 214 + 1;
- 30 822 754 214 ÷ 2 = 15 411 377 107 + 0;
- 15 411 377 107 ÷ 2 = 7 705 688 553 + 1;
- 7 705 688 553 ÷ 2 = 3 852 844 276 + 1;
- 3 852 844 276 ÷ 2 = 1 926 422 138 + 0;
- 1 926 422 138 ÷ 2 = 963 211 069 + 0;
- 963 211 069 ÷ 2 = 481 605 534 + 1;
- 481 605 534 ÷ 2 = 240 802 767 + 0;
- 240 802 767 ÷ 2 = 120 401 383 + 1;
- 120 401 383 ÷ 2 = 60 200 691 + 1;
- 60 200 691 ÷ 2 = 30 100 345 + 1;
- 30 100 345 ÷ 2 = 15 050 172 + 1;
- 15 050 172 ÷ 2 = 7 525 086 + 0;
- 7 525 086 ÷ 2 = 3 762 543 + 0;
- 3 762 543 ÷ 2 = 1 881 271 + 1;
- 1 881 271 ÷ 2 = 940 635 + 1;
- 940 635 ÷ 2 = 470 317 + 1;
- 470 317 ÷ 2 = 235 158 + 1;
- 235 158 ÷ 2 = 117 579 + 0;
- 117 579 ÷ 2 = 58 789 + 1;
- 58 789 ÷ 2 = 29 394 + 1;
- 29 394 ÷ 2 = 14 697 + 0;
- 14 697 ÷ 2 = 7 348 + 1;
- 7 348 ÷ 2 = 3 674 + 0;
- 3 674 ÷ 2 = 1 837 + 0;
- 1 837 ÷ 2 = 918 + 1;
- 918 ÷ 2 = 459 + 0;
- 459 ÷ 2 = 229 + 1;
- 229 ÷ 2 = 114 + 1;
- 114 ÷ 2 = 57 + 0;
- 57 ÷ 2 = 28 + 1;
- 28 ÷ 2 = 14 + 0;
- 14 ÷ 2 = 7 + 0;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 010 000 010 110 085(10) = 11 1001 0110 1001 0110 1111 0011 1101 0011 0110 0100 1000 0101(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 50.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) is reserved for the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 50,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:
Number 1 010 000 010 110 085(10), a signed integer number (with sign),
converted from decimal system (from base 10)
and written as a signed binary (in base 2):
1 010 000 010 110 085(10) = 0000 0000 0000 0011 1001 0110 1001 0110 1111 0011 1101 0011 0110 0100 1000 0101
Spaces were used to group digits: for binary, by 4, for decimal, by 3.