1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 001 110 001 110 017 ÷ 2 = 500 555 000 555 008 + 1;
- 500 555 000 555 008 ÷ 2 = 250 277 500 277 504 + 0;
- 250 277 500 277 504 ÷ 2 = 125 138 750 138 752 + 0;
- 125 138 750 138 752 ÷ 2 = 62 569 375 069 376 + 0;
- 62 569 375 069 376 ÷ 2 = 31 284 687 534 688 + 0;
- 31 284 687 534 688 ÷ 2 = 15 642 343 767 344 + 0;
- 15 642 343 767 344 ÷ 2 = 7 821 171 883 672 + 0;
- 7 821 171 883 672 ÷ 2 = 3 910 585 941 836 + 0;
- 3 910 585 941 836 ÷ 2 = 1 955 292 970 918 + 0;
- 1 955 292 970 918 ÷ 2 = 977 646 485 459 + 0;
- 977 646 485 459 ÷ 2 = 488 823 242 729 + 1;
- 488 823 242 729 ÷ 2 = 244 411 621 364 + 1;
- 244 411 621 364 ÷ 2 = 122 205 810 682 + 0;
- 122 205 810 682 ÷ 2 = 61 102 905 341 + 0;
- 61 102 905 341 ÷ 2 = 30 551 452 670 + 1;
- 30 551 452 670 ÷ 2 = 15 275 726 335 + 0;
- 15 275 726 335 ÷ 2 = 7 637 863 167 + 1;
- 7 637 863 167 ÷ 2 = 3 818 931 583 + 1;
- 3 818 931 583 ÷ 2 = 1 909 465 791 + 1;
- 1 909 465 791 ÷ 2 = 954 732 895 + 1;
- 954 732 895 ÷ 2 = 477 366 447 + 1;
- 477 366 447 ÷ 2 = 238 683 223 + 1;
- 238 683 223 ÷ 2 = 119 341 611 + 1;
- 119 341 611 ÷ 2 = 59 670 805 + 1;
- 59 670 805 ÷ 2 = 29 835 402 + 1;
- 29 835 402 ÷ 2 = 14 917 701 + 0;
- 14 917 701 ÷ 2 = 7 458 850 + 1;
- 7 458 850 ÷ 2 = 3 729 425 + 0;
- 3 729 425 ÷ 2 = 1 864 712 + 1;
- 1 864 712 ÷ 2 = 932 356 + 0;
- 932 356 ÷ 2 = 466 178 + 0;
- 466 178 ÷ 2 = 233 089 + 0;
- 233 089 ÷ 2 = 116 544 + 1;
- 116 544 ÷ 2 = 58 272 + 0;
- 58 272 ÷ 2 = 29 136 + 0;
- 29 136 ÷ 2 = 14 568 + 0;
- 14 568 ÷ 2 = 7 284 + 0;
- 7 284 ÷ 2 = 3 642 + 0;
- 3 642 ÷ 2 = 1 821 + 0;
- 1 821 ÷ 2 = 910 + 1;
- 910 ÷ 2 = 455 + 0;
- 455 ÷ 2 = 227 + 1;
- 227 ÷ 2 = 113 + 1;
- 113 ÷ 2 = 56 + 1;
- 56 ÷ 2 = 28 + 0;
- 28 ÷ 2 = 14 + 0;
- 14 ÷ 2 = 7 + 0;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 001 110 001 110 017(10) = 11 1000 1110 1000 0001 0001 0101 1111 1111 0100 1100 0000 0001(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 50.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) is reserved for the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 50,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:
Number 1 001 110 001 110 017(10), a signed integer number (with sign),
converted from decimal system (from base 10)
and written as a signed binary (in base 2):
1 001 110 001 110 017(10) = 0000 0000 0000 0011 1000 1110 1000 0001 0001 0101 1111 1111 0100 1100 0000 0001
Spaces were used to group digits: for binary, by 4, for decimal, by 3.