What are the required steps to convert base 10 integer
number 1 000 101 011 011 619 to signed binary code (in base 2)?
- A signed integer, written in base ten, or a decimal system number, is a number written using the digits 0 through 9 and the sign, which can be positive (+) or negative (-). If positive, the sign is usually not written. A number written in base two, or binary, is a number written using only the digits 0 and 1.
1. Divide the number repeatedly by 2:
Keep track of each remainder.
Stop when you get a quotient that is equal to zero.
- division = quotient + remainder;
- 1 000 101 011 011 619 ÷ 2 = 500 050 505 505 809 + 1;
- 500 050 505 505 809 ÷ 2 = 250 025 252 752 904 + 1;
- 250 025 252 752 904 ÷ 2 = 125 012 626 376 452 + 0;
- 125 012 626 376 452 ÷ 2 = 62 506 313 188 226 + 0;
- 62 506 313 188 226 ÷ 2 = 31 253 156 594 113 + 0;
- 31 253 156 594 113 ÷ 2 = 15 626 578 297 056 + 1;
- 15 626 578 297 056 ÷ 2 = 7 813 289 148 528 + 0;
- 7 813 289 148 528 ÷ 2 = 3 906 644 574 264 + 0;
- 3 906 644 574 264 ÷ 2 = 1 953 322 287 132 + 0;
- 1 953 322 287 132 ÷ 2 = 976 661 143 566 + 0;
- 976 661 143 566 ÷ 2 = 488 330 571 783 + 0;
- 488 330 571 783 ÷ 2 = 244 165 285 891 + 1;
- 244 165 285 891 ÷ 2 = 122 082 642 945 + 1;
- 122 082 642 945 ÷ 2 = 61 041 321 472 + 1;
- 61 041 321 472 ÷ 2 = 30 520 660 736 + 0;
- 30 520 660 736 ÷ 2 = 15 260 330 368 + 0;
- 15 260 330 368 ÷ 2 = 7 630 165 184 + 0;
- 7 630 165 184 ÷ 2 = 3 815 082 592 + 0;
- 3 815 082 592 ÷ 2 = 1 907 541 296 + 0;
- 1 907 541 296 ÷ 2 = 953 770 648 + 0;
- 953 770 648 ÷ 2 = 476 885 324 + 0;
- 476 885 324 ÷ 2 = 238 442 662 + 0;
- 238 442 662 ÷ 2 = 119 221 331 + 0;
- 119 221 331 ÷ 2 = 59 610 665 + 1;
- 59 610 665 ÷ 2 = 29 805 332 + 1;
- 29 805 332 ÷ 2 = 14 902 666 + 0;
- 14 902 666 ÷ 2 = 7 451 333 + 0;
- 7 451 333 ÷ 2 = 3 725 666 + 1;
- 3 725 666 ÷ 2 = 1 862 833 + 0;
- 1 862 833 ÷ 2 = 931 416 + 1;
- 931 416 ÷ 2 = 465 708 + 0;
- 465 708 ÷ 2 = 232 854 + 0;
- 232 854 ÷ 2 = 116 427 + 0;
- 116 427 ÷ 2 = 58 213 + 1;
- 58 213 ÷ 2 = 29 106 + 1;
- 29 106 ÷ 2 = 14 553 + 0;
- 14 553 ÷ 2 = 7 276 + 1;
- 7 276 ÷ 2 = 3 638 + 0;
- 3 638 ÷ 2 = 1 819 + 0;
- 1 819 ÷ 2 = 909 + 1;
- 909 ÷ 2 = 454 + 1;
- 454 ÷ 2 = 227 + 0;
- 227 ÷ 2 = 113 + 1;
- 113 ÷ 2 = 56 + 1;
- 56 ÷ 2 = 28 + 0;
- 28 ÷ 2 = 14 + 0;
- 14 ÷ 2 = 7 + 0;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
1 000 101 011 011 619(10) = 11 1000 1101 1001 0110 0010 1001 1000 0000 0011 1000 0010 0011(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 50.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) is reserved for the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 50,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:
1 000 101 011 011 619(10) Base 10 integer number converted and written as a signed binary code (in base 2):
1 000 101 011 011 619(10) = 0000 0000 0000 0011 1000 1101 1001 0110 0010 1001 1000 0000 0011 1000 0010 0011
Spaces were used to group digits: for binary, by 4, for decimal, by 3.