Convert -9 123 123 123 000 000 314 to a Signed Binary (Base 2)

How to convert -9 123 123 123 000 000 314(10), a signed base 10 integer number? How to write it as a signed binary code in base 2

What are the required steps to convert base 10 integer
number -9 123 123 123 000 000 314 to signed binary code (in base 2)?

  • A signed integer, written in base ten, or a decimal system number, is a number written using the digits 0 through 9 and the sign, which can be positive (+) or negative (-). If positive, the sign is usually not written. A number written in base two, or binary, is a number written using only the digits 0 and 1.

1. Start with the positive version of the number:

|-9 123 123 123 000 000 314| = 9 123 123 123 000 000 314

2. Divide the number repeatedly by 2:

Keep track of each remainder.

Stop when you get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 9 123 123 123 000 000 314 ÷ 2 = 4 561 561 561 500 000 157 + 0;
  • 4 561 561 561 500 000 157 ÷ 2 = 2 280 780 780 750 000 078 + 1;
  • 2 280 780 780 750 000 078 ÷ 2 = 1 140 390 390 375 000 039 + 0;
  • 1 140 390 390 375 000 039 ÷ 2 = 570 195 195 187 500 019 + 1;
  • 570 195 195 187 500 019 ÷ 2 = 285 097 597 593 750 009 + 1;
  • 285 097 597 593 750 009 ÷ 2 = 142 548 798 796 875 004 + 1;
  • 142 548 798 796 875 004 ÷ 2 = 71 274 399 398 437 502 + 0;
  • 71 274 399 398 437 502 ÷ 2 = 35 637 199 699 218 751 + 0;
  • 35 637 199 699 218 751 ÷ 2 = 17 818 599 849 609 375 + 1;
  • 17 818 599 849 609 375 ÷ 2 = 8 909 299 924 804 687 + 1;
  • 8 909 299 924 804 687 ÷ 2 = 4 454 649 962 402 343 + 1;
  • 4 454 649 962 402 343 ÷ 2 = 2 227 324 981 201 171 + 1;
  • 2 227 324 981 201 171 ÷ 2 = 1 113 662 490 600 585 + 1;
  • 1 113 662 490 600 585 ÷ 2 = 556 831 245 300 292 + 1;
  • 556 831 245 300 292 ÷ 2 = 278 415 622 650 146 + 0;
  • 278 415 622 650 146 ÷ 2 = 139 207 811 325 073 + 0;
  • 139 207 811 325 073 ÷ 2 = 69 603 905 662 536 + 1;
  • 69 603 905 662 536 ÷ 2 = 34 801 952 831 268 + 0;
  • 34 801 952 831 268 ÷ 2 = 17 400 976 415 634 + 0;
  • 17 400 976 415 634 ÷ 2 = 8 700 488 207 817 + 0;
  • 8 700 488 207 817 ÷ 2 = 4 350 244 103 908 + 1;
  • 4 350 244 103 908 ÷ 2 = 2 175 122 051 954 + 0;
  • 2 175 122 051 954 ÷ 2 = 1 087 561 025 977 + 0;
  • 1 087 561 025 977 ÷ 2 = 543 780 512 988 + 1;
  • 543 780 512 988 ÷ 2 = 271 890 256 494 + 0;
  • 271 890 256 494 ÷ 2 = 135 945 128 247 + 0;
  • 135 945 128 247 ÷ 2 = 67 972 564 123 + 1;
  • 67 972 564 123 ÷ 2 = 33 986 282 061 + 1;
  • 33 986 282 061 ÷ 2 = 16 993 141 030 + 1;
  • 16 993 141 030 ÷ 2 = 8 496 570 515 + 0;
  • 8 496 570 515 ÷ 2 = 4 248 285 257 + 1;
  • 4 248 285 257 ÷ 2 = 2 124 142 628 + 1;
  • 2 124 142 628 ÷ 2 = 1 062 071 314 + 0;
  • 1 062 071 314 ÷ 2 = 531 035 657 + 0;
  • 531 035 657 ÷ 2 = 265 517 828 + 1;
  • 265 517 828 ÷ 2 = 132 758 914 + 0;
  • 132 758 914 ÷ 2 = 66 379 457 + 0;
  • 66 379 457 ÷ 2 = 33 189 728 + 1;
  • 33 189 728 ÷ 2 = 16 594 864 + 0;
  • 16 594 864 ÷ 2 = 8 297 432 + 0;
  • 8 297 432 ÷ 2 = 4 148 716 + 0;
  • 4 148 716 ÷ 2 = 2 074 358 + 0;
  • 2 074 358 ÷ 2 = 1 037 179 + 0;
  • 1 037 179 ÷ 2 = 518 589 + 1;
  • 518 589 ÷ 2 = 259 294 + 1;
  • 259 294 ÷ 2 = 129 647 + 0;
  • 129 647 ÷ 2 = 64 823 + 1;
  • 64 823 ÷ 2 = 32 411 + 1;
  • 32 411 ÷ 2 = 16 205 + 1;
  • 16 205 ÷ 2 = 8 102 + 1;
  • 8 102 ÷ 2 = 4 051 + 0;
  • 4 051 ÷ 2 = 2 025 + 1;
  • 2 025 ÷ 2 = 1 012 + 1;
  • 1 012 ÷ 2 = 506 + 0;
  • 506 ÷ 2 = 253 + 0;
  • 253 ÷ 2 = 126 + 1;
  • 126 ÷ 2 = 63 + 0;
  • 63 ÷ 2 = 31 + 1;
  • 31 ÷ 2 = 15 + 1;
  • 15 ÷ 2 = 7 + 1;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

3. Construct the base 2 representation of the positive number:

Take all the remainders starting from the bottom of the list constructed above.

9 123 123 123 000 000 314(10) = 111 1110 1001 1011 1101 1000 0010 0100 1101 1100 1001 0001 0011 1111 0011 1010(2)


4. Determine the signed binary number bit length:

  • The base 2 number's actual length, in bits: 63.

  • A signed binary's bit length must be equal to a power of 2, as of:
  • 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
  • The first bit (the leftmost) is reserved for the sign:
  • 0 = positive integer number, 1 = negative integer number

The least number that is:


1) a power of 2

2) and is larger than the actual length, 63,

3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)


=== is: 64.


5. Get the positive binary computer representation on 64 bits (8 Bytes):

If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:


9 123 123 123 000 000 314(10) = 0111 1110 1001 1011 1101 1000 0010 0100 1101 1100 1001 0001 0011 1111 0011 1010

6. Get the negative integer number representation:

To get the negative integer number representation on 64 bits (8 Bytes),


... change the first bit (the leftmost), from 0 to 1...


-9 123 123 123 000 000 314(10) Base 10 integer number converted and written as a signed binary code (in base 2):

-9 123 123 123 000 000 314(10) = 1111 1110 1001 1011 1101 1000 0010 0100 1101 1100 1001 0001 0011 1111 0011 1010

Spaces were used to group digits: for binary, by 4, for decimal, by 3.


How to convert signed base 10 integers in decimal to binary code system

Follow the steps below to convert a signed base ten integer number to signed binary:

  • 1. In a signed binary, first bit (the leftmost) is reserved for sign: 0 = positive integer number, 1 = positive integer number. If the number to be converted is negative, start with its positive version.
  • 2. Divide repeatedly by 2 the positive integer number keeping track of each remainder. STOP when we get a quotient that is ZERO.
  • 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Binary numbers represented in computer language have a length of 4, 8, 16, 32, 64, ... bits (power of 2) - if needed, fill in extra '0' bits in front of the base 2 number (to the left), up to the right length; this way the first bit (the leftmost one) is always '0', as for a positive representation.
  • 5. To get the negative reprezentation of the number, simply switch the first bit (the leftmost one), from '0' to '1'.

Example: convert the negative number -63 from decimal system (base ten) to signed binary code system:

  • 1. Start with the positive version of the number: |-63| = 63;
  • 2. Divide repeatedly 63 by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder
    • 63 ÷ 2 = 31 + 1
    • 31 ÷ 2 = 15 + 1
    • 15 ÷ 2 = 7 + 1
    • 7 ÷ 2 = 3 + 1
    • 3 ÷ 2 = 1 + 1
    • 1 ÷ 2 = 0 + 1
  • 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above:
    63(10) = 11 1111(2)
  • 4. The actual length of base 2 representation number is 6, so the positive binary computer representation length of the signed binary will take in this case 8 bits (the least power of 2 higher than 6) - add extra '0's in front (to the left), up to the required length; this way the first bit (the leftmost one) is to be '0', as for a positive number:
    63(10) = 0011 1111(2)
  • 5. To get the negative integer number representation simply change the first bit (the leftmost), from '0' to '1':
    -63(10) = 1011 1111
  • Number -63(10), signed integer, converted from decimal system (base 10) to signed binary = 1011 1111