Convert -9 022 270 416 445 046 026 to a Signed Binary (Base 2)

How to convert -9 022 270 416 445 046 026(10), a signed base 10 integer number? How to write it as a signed binary code in base 2

What are the required steps to convert base 10 integer
number -9 022 270 416 445 046 026 to signed binary code (in base 2)?

  • A signed integer, written in base ten, or a decimal system number, is a number written using the digits 0 through 9 and the sign, which can be positive (+) or negative (-). If positive, the sign is usually not written. A number written in base two, or binary, is a number written using only the digits 0 and 1.

1. Start with the positive version of the number:

|-9 022 270 416 445 046 026| = 9 022 270 416 445 046 026

2. Divide the number repeatedly by 2:

Keep track of each remainder.

Stop when you get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 9 022 270 416 445 046 026 ÷ 2 = 4 511 135 208 222 523 013 + 0;
  • 4 511 135 208 222 523 013 ÷ 2 = 2 255 567 604 111 261 506 + 1;
  • 2 255 567 604 111 261 506 ÷ 2 = 1 127 783 802 055 630 753 + 0;
  • 1 127 783 802 055 630 753 ÷ 2 = 563 891 901 027 815 376 + 1;
  • 563 891 901 027 815 376 ÷ 2 = 281 945 950 513 907 688 + 0;
  • 281 945 950 513 907 688 ÷ 2 = 140 972 975 256 953 844 + 0;
  • 140 972 975 256 953 844 ÷ 2 = 70 486 487 628 476 922 + 0;
  • 70 486 487 628 476 922 ÷ 2 = 35 243 243 814 238 461 + 0;
  • 35 243 243 814 238 461 ÷ 2 = 17 621 621 907 119 230 + 1;
  • 17 621 621 907 119 230 ÷ 2 = 8 810 810 953 559 615 + 0;
  • 8 810 810 953 559 615 ÷ 2 = 4 405 405 476 779 807 + 1;
  • 4 405 405 476 779 807 ÷ 2 = 2 202 702 738 389 903 + 1;
  • 2 202 702 738 389 903 ÷ 2 = 1 101 351 369 194 951 + 1;
  • 1 101 351 369 194 951 ÷ 2 = 550 675 684 597 475 + 1;
  • 550 675 684 597 475 ÷ 2 = 275 337 842 298 737 + 1;
  • 275 337 842 298 737 ÷ 2 = 137 668 921 149 368 + 1;
  • 137 668 921 149 368 ÷ 2 = 68 834 460 574 684 + 0;
  • 68 834 460 574 684 ÷ 2 = 34 417 230 287 342 + 0;
  • 34 417 230 287 342 ÷ 2 = 17 208 615 143 671 + 0;
  • 17 208 615 143 671 ÷ 2 = 8 604 307 571 835 + 1;
  • 8 604 307 571 835 ÷ 2 = 4 302 153 785 917 + 1;
  • 4 302 153 785 917 ÷ 2 = 2 151 076 892 958 + 1;
  • 2 151 076 892 958 ÷ 2 = 1 075 538 446 479 + 0;
  • 1 075 538 446 479 ÷ 2 = 537 769 223 239 + 1;
  • 537 769 223 239 ÷ 2 = 268 884 611 619 + 1;
  • 268 884 611 619 ÷ 2 = 134 442 305 809 + 1;
  • 134 442 305 809 ÷ 2 = 67 221 152 904 + 1;
  • 67 221 152 904 ÷ 2 = 33 610 576 452 + 0;
  • 33 610 576 452 ÷ 2 = 16 805 288 226 + 0;
  • 16 805 288 226 ÷ 2 = 8 402 644 113 + 0;
  • 8 402 644 113 ÷ 2 = 4 201 322 056 + 1;
  • 4 201 322 056 ÷ 2 = 2 100 661 028 + 0;
  • 2 100 661 028 ÷ 2 = 1 050 330 514 + 0;
  • 1 050 330 514 ÷ 2 = 525 165 257 + 0;
  • 525 165 257 ÷ 2 = 262 582 628 + 1;
  • 262 582 628 ÷ 2 = 131 291 314 + 0;
  • 131 291 314 ÷ 2 = 65 645 657 + 0;
  • 65 645 657 ÷ 2 = 32 822 828 + 1;
  • 32 822 828 ÷ 2 = 16 411 414 + 0;
  • 16 411 414 ÷ 2 = 8 205 707 + 0;
  • 8 205 707 ÷ 2 = 4 102 853 + 1;
  • 4 102 853 ÷ 2 = 2 051 426 + 1;
  • 2 051 426 ÷ 2 = 1 025 713 + 0;
  • 1 025 713 ÷ 2 = 512 856 + 1;
  • 512 856 ÷ 2 = 256 428 + 0;
  • 256 428 ÷ 2 = 128 214 + 0;
  • 128 214 ÷ 2 = 64 107 + 0;
  • 64 107 ÷ 2 = 32 053 + 1;
  • 32 053 ÷ 2 = 16 026 + 1;
  • 16 026 ÷ 2 = 8 013 + 0;
  • 8 013 ÷ 2 = 4 006 + 1;
  • 4 006 ÷ 2 = 2 003 + 0;
  • 2 003 ÷ 2 = 1 001 + 1;
  • 1 001 ÷ 2 = 500 + 1;
  • 500 ÷ 2 = 250 + 0;
  • 250 ÷ 2 = 125 + 0;
  • 125 ÷ 2 = 62 + 1;
  • 62 ÷ 2 = 31 + 0;
  • 31 ÷ 2 = 15 + 1;
  • 15 ÷ 2 = 7 + 1;
  • 7 ÷ 2 = 3 + 1;
  • 3 ÷ 2 = 1 + 1;
  • 1 ÷ 2 = 0 + 1;

3. Construct the base 2 representation of the positive number:

Take all the remainders starting from the bottom of the list constructed above.

9 022 270 416 445 046 026(10) = 111 1101 0011 0101 1000 1011 0010 0100 0100 0111 1011 1000 1111 1101 0000 1010(2)


4. Determine the signed binary number bit length:

  • The base 2 number's actual length, in bits: 63.

  • A signed binary's bit length must be equal to a power of 2, as of:
  • 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
  • The first bit (the leftmost) is reserved for the sign:
  • 0 = positive integer number, 1 = negative integer number

The least number that is:


1) a power of 2

2) and is larger than the actual length, 63,

3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)


=== is: 64.


5. Get the positive binary computer representation on 64 bits (8 Bytes):

If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:


9 022 270 416 445 046 026(10) = 0111 1101 0011 0101 1000 1011 0010 0100 0100 0111 1011 1000 1111 1101 0000 1010

6. Get the negative integer number representation:

To get the negative integer number representation on 64 bits (8 Bytes),


... change the first bit (the leftmost), from 0 to 1...


-9 022 270 416 445 046 026(10) Base 10 integer number converted and written as a signed binary code (in base 2):

-9 022 270 416 445 046 026(10) = 1111 1101 0011 0101 1000 1011 0010 0100 0100 0111 1011 1000 1111 1101 0000 1010

Spaces were used to group digits: for binary, by 4, for decimal, by 3.

How to convert signed base 10 integers in decimal to binary code system

Follow the steps below to convert a signed base ten integer number to signed binary:

  • 1. In a signed binary, first bit (the leftmost) is reserved for sign: 0 = positive integer number, 1 = positive integer number. If the number to be converted is negative, start with its positive version.
  • 2. Divide repeatedly by 2 the positive integer number keeping track of each remainder. STOP when we get a quotient that is ZERO.
  • 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Binary numbers represented in computer language have a length of 4, 8, 16, 32, 64, ... bits (power of 2) - if needed, fill in extra '0' bits in front of the base 2 number (to the left), up to the right length; this way the first bit (the leftmost one) is always '0', as for a positive representation.
  • 5. To get the negative reprezentation of the number, simply switch the first bit (the leftmost one), from '0' to '1'.

Example: convert the negative number -63 from decimal system (base ten) to signed binary code system:

  • 1. Start with the positive version of the number: |-63| = 63;
  • 2. Divide repeatedly 63 by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder
    • 63 ÷ 2 = 31 + 1
    • 31 ÷ 2 = 15 + 1
    • 15 ÷ 2 = 7 + 1
    • 7 ÷ 2 = 3 + 1
    • 3 ÷ 2 = 1 + 1
    • 1 ÷ 2 = 0 + 1
  • 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above:
    63(10) = 11 1111(2)
  • 4. The actual length of base 2 representation number is 6, so the positive binary computer representation length of the signed binary will take in this case 8 bits (the least power of 2 higher than 6) - add extra '0's in front (to the left), up to the required length; this way the first bit (the leftmost one) is to be '0', as for a positive number:
    63(10) = 0011 1111(2)
  • 5. To get the negative integer number representation simply change the first bit (the leftmost), from '0' to '1':
    -63(10) = 1011 1111
  • Number -63(10), signed integer, converted from decimal system (base 10) to signed binary = 1011 1111