Convert -6 148 914 691 236 516 976 to a Signed Binary (Base 2)

How to convert -6 148 914 691 236 516 976(10), a signed base 10 integer number? How to write it as a signed binary code in base 2

What are the required steps to convert base 10 integer
number -6 148 914 691 236 516 976 to signed binary code (in base 2)?

  • A signed integer, written in base ten, or a decimal system number, is a number written using the digits 0 through 9 and the sign, which can be positive (+) or negative (-). If positive, the sign is usually not written. A number written in base two, or binary, is a number written using only the digits 0 and 1.

1. Start with the positive version of the number:

|-6 148 914 691 236 516 976| = 6 148 914 691 236 516 976

2. Divide the number repeatedly by 2:

Keep track of each remainder.

Stop when you get a quotient that is equal to zero.


  • division = quotient + remainder;
  • 6 148 914 691 236 516 976 ÷ 2 = 3 074 457 345 618 258 488 + 0;
  • 3 074 457 345 618 258 488 ÷ 2 = 1 537 228 672 809 129 244 + 0;
  • 1 537 228 672 809 129 244 ÷ 2 = 768 614 336 404 564 622 + 0;
  • 768 614 336 404 564 622 ÷ 2 = 384 307 168 202 282 311 + 0;
  • 384 307 168 202 282 311 ÷ 2 = 192 153 584 101 141 155 + 1;
  • 192 153 584 101 141 155 ÷ 2 = 96 076 792 050 570 577 + 1;
  • 96 076 792 050 570 577 ÷ 2 = 48 038 396 025 285 288 + 1;
  • 48 038 396 025 285 288 ÷ 2 = 24 019 198 012 642 644 + 0;
  • 24 019 198 012 642 644 ÷ 2 = 12 009 599 006 321 322 + 0;
  • 12 009 599 006 321 322 ÷ 2 = 6 004 799 503 160 661 + 0;
  • 6 004 799 503 160 661 ÷ 2 = 3 002 399 751 580 330 + 1;
  • 3 002 399 751 580 330 ÷ 2 = 1 501 199 875 790 165 + 0;
  • 1 501 199 875 790 165 ÷ 2 = 750 599 937 895 082 + 1;
  • 750 599 937 895 082 ÷ 2 = 375 299 968 947 541 + 0;
  • 375 299 968 947 541 ÷ 2 = 187 649 984 473 770 + 1;
  • 187 649 984 473 770 ÷ 2 = 93 824 992 236 885 + 0;
  • 93 824 992 236 885 ÷ 2 = 46 912 496 118 442 + 1;
  • 46 912 496 118 442 ÷ 2 = 23 456 248 059 221 + 0;
  • 23 456 248 059 221 ÷ 2 = 11 728 124 029 610 + 1;
  • 11 728 124 029 610 ÷ 2 = 5 864 062 014 805 + 0;
  • 5 864 062 014 805 ÷ 2 = 2 932 031 007 402 + 1;
  • 2 932 031 007 402 ÷ 2 = 1 466 015 503 701 + 0;
  • 1 466 015 503 701 ÷ 2 = 733 007 751 850 + 1;
  • 733 007 751 850 ÷ 2 = 366 503 875 925 + 0;
  • 366 503 875 925 ÷ 2 = 183 251 937 962 + 1;
  • 183 251 937 962 ÷ 2 = 91 625 968 981 + 0;
  • 91 625 968 981 ÷ 2 = 45 812 984 490 + 1;
  • 45 812 984 490 ÷ 2 = 22 906 492 245 + 0;
  • 22 906 492 245 ÷ 2 = 11 453 246 122 + 1;
  • 11 453 246 122 ÷ 2 = 5 726 623 061 + 0;
  • 5 726 623 061 ÷ 2 = 2 863 311 530 + 1;
  • 2 863 311 530 ÷ 2 = 1 431 655 765 + 0;
  • 1 431 655 765 ÷ 2 = 715 827 882 + 1;
  • 715 827 882 ÷ 2 = 357 913 941 + 0;
  • 357 913 941 ÷ 2 = 178 956 970 + 1;
  • 178 956 970 ÷ 2 = 89 478 485 + 0;
  • 89 478 485 ÷ 2 = 44 739 242 + 1;
  • 44 739 242 ÷ 2 = 22 369 621 + 0;
  • 22 369 621 ÷ 2 = 11 184 810 + 1;
  • 11 184 810 ÷ 2 = 5 592 405 + 0;
  • 5 592 405 ÷ 2 = 2 796 202 + 1;
  • 2 796 202 ÷ 2 = 1 398 101 + 0;
  • 1 398 101 ÷ 2 = 699 050 + 1;
  • 699 050 ÷ 2 = 349 525 + 0;
  • 349 525 ÷ 2 = 174 762 + 1;
  • 174 762 ÷ 2 = 87 381 + 0;
  • 87 381 ÷ 2 = 43 690 + 1;
  • 43 690 ÷ 2 = 21 845 + 0;
  • 21 845 ÷ 2 = 10 922 + 1;
  • 10 922 ÷ 2 = 5 461 + 0;
  • 5 461 ÷ 2 = 2 730 + 1;
  • 2 730 ÷ 2 = 1 365 + 0;
  • 1 365 ÷ 2 = 682 + 1;
  • 682 ÷ 2 = 341 + 0;
  • 341 ÷ 2 = 170 + 1;
  • 170 ÷ 2 = 85 + 0;
  • 85 ÷ 2 = 42 + 1;
  • 42 ÷ 2 = 21 + 0;
  • 21 ÷ 2 = 10 + 1;
  • 10 ÷ 2 = 5 + 0;
  • 5 ÷ 2 = 2 + 1;
  • 2 ÷ 2 = 1 + 0;
  • 1 ÷ 2 = 0 + 1;

3. Construct the base 2 representation of the positive number:

Take all the remainders starting from the bottom of the list constructed above.

6 148 914 691 236 516 976(10) = 101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0100 0111 0000(2)


4. Determine the signed binary number bit length:

  • The base 2 number's actual length, in bits: 63.

  • A signed binary's bit length must be equal to a power of 2, as of:
  • 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
  • The first bit (the leftmost) is reserved for the sign:
  • 0 = positive integer number, 1 = negative integer number

The least number that is:


1) a power of 2

2) and is larger than the actual length, 63,

3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)


=== is: 64.


5. Get the positive binary computer representation on 64 bits (8 Bytes):

If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64:


6 148 914 691 236 516 976(10) = 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0100 0111 0000

6. Get the negative integer number representation:

To get the negative integer number representation on 64 bits (8 Bytes),


... change the first bit (the leftmost), from 0 to 1...


-6 148 914 691 236 516 976(10) Base 10 integer number converted and written as a signed binary code (in base 2):

-6 148 914 691 236 516 976(10) = 1101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0101 0100 0111 0000

Spaces were used to group digits: for binary, by 4, for decimal, by 3.


How to convert signed base 10 integers in decimal to binary code system

Follow the steps below to convert a signed base ten integer number to signed binary:

  • 1. In a signed binary, first bit (the leftmost) is reserved for sign: 0 = positive integer number, 1 = positive integer number. If the number to be converted is negative, start with its positive version.
  • 2. Divide repeatedly by 2 the positive integer number keeping track of each remainder. STOP when we get a quotient that is ZERO.
  • 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above. Thus, the last remainder of the divisions becomes the first symbol (the leftmost) of the base two number, while the first remainder becomes the last symbol (the rightmost).
  • 4. Binary numbers represented in computer language have a length of 4, 8, 16, 32, 64, ... bits (power of 2) - if needed, fill in extra '0' bits in front of the base 2 number (to the left), up to the right length; this way the first bit (the leftmost one) is always '0', as for a positive representation.
  • 5. To get the negative reprezentation of the number, simply switch the first bit (the leftmost one), from '0' to '1'.

Example: convert the negative number -63 from decimal system (base ten) to signed binary code system:

  • 1. Start with the positive version of the number: |-63| = 63;
  • 2. Divide repeatedly 63 by 2, keeping track of each remainder, until we get a quotient that is equal to zero:
    • division = quotient + remainder
    • 63 ÷ 2 = 31 + 1
    • 31 ÷ 2 = 15 + 1
    • 15 ÷ 2 = 7 + 1
    • 7 ÷ 2 = 3 + 1
    • 3 ÷ 2 = 1 + 1
    • 1 ÷ 2 = 0 + 1
  • 3. Construct the base 2 representation of the positive number, by taking all the remainders starting from the bottom of the list constructed above:
    63(10) = 11 1111(2)
  • 4. The actual length of base 2 representation number is 6, so the positive binary computer representation length of the signed binary will take in this case 8 bits (the least power of 2 higher than 6) - add extra '0's in front (to the left), up to the required length; this way the first bit (the leftmost one) is to be '0', as for a positive number:
    63(10) = 0011 1111(2)
  • 5. To get the negative integer number representation simply change the first bit (the leftmost), from '0' to '1':
    -63(10) = 1011 1111
  • Number -63(10), signed integer, converted from decimal system (base 10) to signed binary = 1011 1111