2. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 200 076 ÷ 2 = 100 038 + 0;
- 100 038 ÷ 2 = 50 019 + 0;
- 50 019 ÷ 2 = 25 009 + 1;
- 25 009 ÷ 2 = 12 504 + 1;
- 12 504 ÷ 2 = 6 252 + 0;
- 6 252 ÷ 2 = 3 126 + 0;
- 3 126 ÷ 2 = 1 563 + 0;
- 1 563 ÷ 2 = 781 + 1;
- 781 ÷ 2 = 390 + 1;
- 390 ÷ 2 = 195 + 0;
- 195 ÷ 2 = 97 + 1;
- 97 ÷ 2 = 48 + 1;
- 48 ÷ 2 = 24 + 0;
- 24 ÷ 2 = 12 + 0;
- 12 ÷ 2 = 6 + 0;
- 6 ÷ 2 = 3 + 0;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
3. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
200 076(10) = 11 0000 1101 1000 1100(2)
4. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 18.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) is reserved for the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 18,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
5. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32:
200 076(10) = 0000 0000 0000 0011 0000 1101 1000 1100
6. Get the negative integer number representation:
To get the negative integer number representation on 32 bits (4 Bytes),
... change the first bit (the leftmost), from 0 to 1...
Number -200 076(10), a signed integer number (with sign),
converted from decimal system (from base 10)
and written as a signed binary (in base 2):
-200 076(10) = 1000 0000 0000 0011 0000 1101 1000 1100
Spaces were used to group digits: for binary, by 4, for decimal, by 3.