1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 920 426 435 ÷ 2 = 460 213 217 + 1;
- 460 213 217 ÷ 2 = 230 106 608 + 1;
- 230 106 608 ÷ 2 = 115 053 304 + 0;
- 115 053 304 ÷ 2 = 57 526 652 + 0;
- 57 526 652 ÷ 2 = 28 763 326 + 0;
- 28 763 326 ÷ 2 = 14 381 663 + 0;
- 14 381 663 ÷ 2 = 7 190 831 + 1;
- 7 190 831 ÷ 2 = 3 595 415 + 1;
- 3 595 415 ÷ 2 = 1 797 707 + 1;
- 1 797 707 ÷ 2 = 898 853 + 1;
- 898 853 ÷ 2 = 449 426 + 1;
- 449 426 ÷ 2 = 224 713 + 0;
- 224 713 ÷ 2 = 112 356 + 1;
- 112 356 ÷ 2 = 56 178 + 0;
- 56 178 ÷ 2 = 28 089 + 0;
- 28 089 ÷ 2 = 14 044 + 1;
- 14 044 ÷ 2 = 7 022 + 0;
- 7 022 ÷ 2 = 3 511 + 0;
- 3 511 ÷ 2 = 1 755 + 1;
- 1 755 ÷ 2 = 877 + 1;
- 877 ÷ 2 = 438 + 1;
- 438 ÷ 2 = 219 + 0;
- 219 ÷ 2 = 109 + 1;
- 109 ÷ 2 = 54 + 1;
- 54 ÷ 2 = 27 + 0;
- 27 ÷ 2 = 13 + 1;
- 13 ÷ 2 = 6 + 1;
- 6 ÷ 2 = 3 + 0;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
920 426 435(10) = 11 0110 1101 1100 1001 0111 1100 0011(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 30.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 30,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
4. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.
Decimal Number 920 426 435(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.