1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 8 111 190 ÷ 2 = 4 055 595 + 0;
- 4 055 595 ÷ 2 = 2 027 797 + 1;
- 2 027 797 ÷ 2 = 1 013 898 + 1;
- 1 013 898 ÷ 2 = 506 949 + 0;
- 506 949 ÷ 2 = 253 474 + 1;
- 253 474 ÷ 2 = 126 737 + 0;
- 126 737 ÷ 2 = 63 368 + 1;
- 63 368 ÷ 2 = 31 684 + 0;
- 31 684 ÷ 2 = 15 842 + 0;
- 15 842 ÷ 2 = 7 921 + 0;
- 7 921 ÷ 2 = 3 960 + 1;
- 3 960 ÷ 2 = 1 980 + 0;
- 1 980 ÷ 2 = 990 + 0;
- 990 ÷ 2 = 495 + 0;
- 495 ÷ 2 = 247 + 1;
- 247 ÷ 2 = 123 + 1;
- 123 ÷ 2 = 61 + 1;
- 61 ÷ 2 = 30 + 1;
- 30 ÷ 2 = 15 + 0;
- 15 ÷ 2 = 7 + 1;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
8 111 190(10) = 111 1011 1100 0100 0101 0110(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 23.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 23,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
4. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.
Decimal Number 8 111 190(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.