1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 3 749 999 956 ÷ 2 = 1 874 999 978 + 0;
- 1 874 999 978 ÷ 2 = 937 499 989 + 0;
- 937 499 989 ÷ 2 = 468 749 994 + 1;
- 468 749 994 ÷ 2 = 234 374 997 + 0;
- 234 374 997 ÷ 2 = 117 187 498 + 1;
- 117 187 498 ÷ 2 = 58 593 749 + 0;
- 58 593 749 ÷ 2 = 29 296 874 + 1;
- 29 296 874 ÷ 2 = 14 648 437 + 0;
- 14 648 437 ÷ 2 = 7 324 218 + 1;
- 7 324 218 ÷ 2 = 3 662 109 + 0;
- 3 662 109 ÷ 2 = 1 831 054 + 1;
- 1 831 054 ÷ 2 = 915 527 + 0;
- 915 527 ÷ 2 = 457 763 + 1;
- 457 763 ÷ 2 = 228 881 + 1;
- 228 881 ÷ 2 = 114 440 + 1;
- 114 440 ÷ 2 = 57 220 + 0;
- 57 220 ÷ 2 = 28 610 + 0;
- 28 610 ÷ 2 = 14 305 + 0;
- 14 305 ÷ 2 = 7 152 + 1;
- 7 152 ÷ 2 = 3 576 + 0;
- 3 576 ÷ 2 = 1 788 + 0;
- 1 788 ÷ 2 = 894 + 0;
- 894 ÷ 2 = 447 + 0;
- 447 ÷ 2 = 223 + 1;
- 223 ÷ 2 = 111 + 1;
- 111 ÷ 2 = 55 + 1;
- 55 ÷ 2 = 27 + 1;
- 27 ÷ 2 = 13 + 1;
- 13 ÷ 2 = 6 + 1;
- 6 ÷ 2 = 3 + 0;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
3 749 999 956(10) = 1101 1111 1000 0100 0111 0101 0101 0100(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 32.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 32,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Decimal Number 3 749 999 956(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.