1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 3 654 832 ÷ 2 = 1 827 416 + 0;
- 1 827 416 ÷ 2 = 913 708 + 0;
- 913 708 ÷ 2 = 456 854 + 0;
- 456 854 ÷ 2 = 228 427 + 0;
- 228 427 ÷ 2 = 114 213 + 1;
- 114 213 ÷ 2 = 57 106 + 1;
- 57 106 ÷ 2 = 28 553 + 0;
- 28 553 ÷ 2 = 14 276 + 1;
- 14 276 ÷ 2 = 7 138 + 0;
- 7 138 ÷ 2 = 3 569 + 0;
- 3 569 ÷ 2 = 1 784 + 1;
- 1 784 ÷ 2 = 892 + 0;
- 892 ÷ 2 = 446 + 0;
- 446 ÷ 2 = 223 + 0;
- 223 ÷ 2 = 111 + 1;
- 111 ÷ 2 = 55 + 1;
- 55 ÷ 2 = 27 + 1;
- 27 ÷ 2 = 13 + 1;
- 13 ÷ 2 = 6 + 1;
- 6 ÷ 2 = 3 + 0;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
3 654 832(10) = 11 0111 1100 0100 1011 0000(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 22.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) indicates the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 22,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
4. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.
Number 3 654 832(10), a signed integer number (with sign), converted from decimal system (from base 10) and written as a signed binary in two's complement representation:
3 654 832(10) = 0000 0000 0011 0111 1100 0100 1011 0000
Spaces were used to group digits: for binary, by 4, for decimal, by 3.