1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 2 935 701 423 ÷ 2 = 1 467 850 711 + 1;
- 1 467 850 711 ÷ 2 = 733 925 355 + 1;
- 733 925 355 ÷ 2 = 366 962 677 + 1;
- 366 962 677 ÷ 2 = 183 481 338 + 1;
- 183 481 338 ÷ 2 = 91 740 669 + 0;
- 91 740 669 ÷ 2 = 45 870 334 + 1;
- 45 870 334 ÷ 2 = 22 935 167 + 0;
- 22 935 167 ÷ 2 = 11 467 583 + 1;
- 11 467 583 ÷ 2 = 5 733 791 + 1;
- 5 733 791 ÷ 2 = 2 866 895 + 1;
- 2 866 895 ÷ 2 = 1 433 447 + 1;
- 1 433 447 ÷ 2 = 716 723 + 1;
- 716 723 ÷ 2 = 358 361 + 1;
- 358 361 ÷ 2 = 179 180 + 1;
- 179 180 ÷ 2 = 89 590 + 0;
- 89 590 ÷ 2 = 44 795 + 0;
- 44 795 ÷ 2 = 22 397 + 1;
- 22 397 ÷ 2 = 11 198 + 1;
- 11 198 ÷ 2 = 5 599 + 0;
- 5 599 ÷ 2 = 2 799 + 1;
- 2 799 ÷ 2 = 1 399 + 1;
- 1 399 ÷ 2 = 699 + 1;
- 699 ÷ 2 = 349 + 1;
- 349 ÷ 2 = 174 + 1;
- 174 ÷ 2 = 87 + 0;
- 87 ÷ 2 = 43 + 1;
- 43 ÷ 2 = 21 + 1;
- 21 ÷ 2 = 10 + 1;
- 10 ÷ 2 = 5 + 0;
- 5 ÷ 2 = 2 + 1;
- 2 ÷ 2 = 1 + 0;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
2 935 701 423(10) = 1010 1110 1111 1011 0011 1111 1010 1111(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 32.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 32,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 64.
4. Get the positive binary computer representation on 64 bits (8 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 64.
Decimal Number 2 935 701 423(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.