1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 237 649 826 ÷ 2 = 118 824 913 + 0;
- 118 824 913 ÷ 2 = 59 412 456 + 1;
- 59 412 456 ÷ 2 = 29 706 228 + 0;
- 29 706 228 ÷ 2 = 14 853 114 + 0;
- 14 853 114 ÷ 2 = 7 426 557 + 0;
- 7 426 557 ÷ 2 = 3 713 278 + 1;
- 3 713 278 ÷ 2 = 1 856 639 + 0;
- 1 856 639 ÷ 2 = 928 319 + 1;
- 928 319 ÷ 2 = 464 159 + 1;
- 464 159 ÷ 2 = 232 079 + 1;
- 232 079 ÷ 2 = 116 039 + 1;
- 116 039 ÷ 2 = 58 019 + 1;
- 58 019 ÷ 2 = 29 009 + 1;
- 29 009 ÷ 2 = 14 504 + 1;
- 14 504 ÷ 2 = 7 252 + 0;
- 7 252 ÷ 2 = 3 626 + 0;
- 3 626 ÷ 2 = 1 813 + 0;
- 1 813 ÷ 2 = 906 + 1;
- 906 ÷ 2 = 453 + 0;
- 453 ÷ 2 = 226 + 1;
- 226 ÷ 2 = 113 + 0;
- 113 ÷ 2 = 56 + 1;
- 56 ÷ 2 = 28 + 0;
- 28 ÷ 2 = 14 + 0;
- 14 ÷ 2 = 7 + 0;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
237 649 826(10) = 1110 0010 1010 0011 1111 1010 0010(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 28.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 28,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
4. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.
Decimal Number 237 649 826(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.