1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 2 147 283 592 ÷ 2 = 1 073 641 796 + 0;
- 1 073 641 796 ÷ 2 = 536 820 898 + 0;
- 536 820 898 ÷ 2 = 268 410 449 + 0;
- 268 410 449 ÷ 2 = 134 205 224 + 1;
- 134 205 224 ÷ 2 = 67 102 612 + 0;
- 67 102 612 ÷ 2 = 33 551 306 + 0;
- 33 551 306 ÷ 2 = 16 775 653 + 0;
- 16 775 653 ÷ 2 = 8 387 826 + 1;
- 8 387 826 ÷ 2 = 4 193 913 + 0;
- 4 193 913 ÷ 2 = 2 096 956 + 1;
- 2 096 956 ÷ 2 = 1 048 478 + 0;
- 1 048 478 ÷ 2 = 524 239 + 0;
- 524 239 ÷ 2 = 262 119 + 1;
- 262 119 ÷ 2 = 131 059 + 1;
- 131 059 ÷ 2 = 65 529 + 1;
- 65 529 ÷ 2 = 32 764 + 1;
- 32 764 ÷ 2 = 16 382 + 0;
- 16 382 ÷ 2 = 8 191 + 0;
- 8 191 ÷ 2 = 4 095 + 1;
- 4 095 ÷ 2 = 2 047 + 1;
- 2 047 ÷ 2 = 1 023 + 1;
- 1 023 ÷ 2 = 511 + 1;
- 511 ÷ 2 = 255 + 1;
- 255 ÷ 2 = 127 + 1;
- 127 ÷ 2 = 63 + 1;
- 63 ÷ 2 = 31 + 1;
- 31 ÷ 2 = 15 + 1;
- 15 ÷ 2 = 7 + 1;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
2 147 283 592(10) = 111 1111 1111 1100 1111 0010 1000 1000(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 31.
A signed binary's bit length must be equal to a power of 2, as of:
21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
The first bit (the leftmost) indicates the sign:
0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 31,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
4. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.
Number 2 147 283 592(10), a signed integer number (with sign), converted from decimal system (from base 10) and written as a signed binary in two's complement representation:
2 147 283 592(10) = 0111 1111 1111 1100 1111 0010 1000 1000
Spaces were used to group digits: for binary, by 4, for decimal, by 3.