1. Divide the number repeatedly by 2:
Keep track of each remainder.
We stop when we get a quotient that is equal to zero.
- division = quotient + remainder;
- 2 017 029 515 ÷ 2 = 1 008 514 757 + 1;
- 1 008 514 757 ÷ 2 = 504 257 378 + 1;
- 504 257 378 ÷ 2 = 252 128 689 + 0;
- 252 128 689 ÷ 2 = 126 064 344 + 1;
- 126 064 344 ÷ 2 = 63 032 172 + 0;
- 63 032 172 ÷ 2 = 31 516 086 + 0;
- 31 516 086 ÷ 2 = 15 758 043 + 0;
- 15 758 043 ÷ 2 = 7 879 021 + 1;
- 7 879 021 ÷ 2 = 3 939 510 + 1;
- 3 939 510 ÷ 2 = 1 969 755 + 0;
- 1 969 755 ÷ 2 = 984 877 + 1;
- 984 877 ÷ 2 = 492 438 + 1;
- 492 438 ÷ 2 = 246 219 + 0;
- 246 219 ÷ 2 = 123 109 + 1;
- 123 109 ÷ 2 = 61 554 + 1;
- 61 554 ÷ 2 = 30 777 + 0;
- 30 777 ÷ 2 = 15 388 + 1;
- 15 388 ÷ 2 = 7 694 + 0;
- 7 694 ÷ 2 = 3 847 + 0;
- 3 847 ÷ 2 = 1 923 + 1;
- 1 923 ÷ 2 = 961 + 1;
- 961 ÷ 2 = 480 + 1;
- 480 ÷ 2 = 240 + 0;
- 240 ÷ 2 = 120 + 0;
- 120 ÷ 2 = 60 + 0;
- 60 ÷ 2 = 30 + 0;
- 30 ÷ 2 = 15 + 0;
- 15 ÷ 2 = 7 + 1;
- 7 ÷ 2 = 3 + 1;
- 3 ÷ 2 = 1 + 1;
- 1 ÷ 2 = 0 + 1;
2. Construct the base 2 representation of the positive number:
Take all the remainders starting from the bottom of the list constructed above.
2 017 029 515(10) = 111 1000 0011 1001 0110 1101 1000 1011(2)
3. Determine the signed binary number bit length:
The base 2 number's actual length, in bits: 31.
- A signed binary's bit length must be equal to a power of 2, as of:
- 21 = 2; 22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64; ...
- The first bit (the leftmost) indicates the sign:
- 0 = positive integer number, 1 = negative integer number
The least number that is:
1) a power of 2
2) and is larger than the actual length, 31,
3) so that the first bit (leftmost) could be zero
(we deal with a positive number at this moment)
=== is: 32.
4. Get the positive binary computer representation on 32 bits (4 Bytes):
If needed, add extra 0s in front (to the left) of the base 2 number, up to the required length, 32.
Decimal Number 2 017 029 515(10) converted to signed binary in two's complement representation:
Spaces were used to group digits: for binary, by 4, for decimal, by 3.